Best way to split key:value pair into two pairs in a dictionary

Best way to split key:value pair into two pairs in a dictionary - python

up vote
1
down vote

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So let's say i have a dictionary as:

d={'a-b':[1,2,3],'c-d':[4,5,6]}

And i want to split the keys, i.e 'a-b' into two keys as 'a' and 'b', and keep same value for both etc...

So desired output should be:

{'a': [1, 2, 3], 'b': [1, 2, 3], 'c': [4, 5, 6], 'd': [4, 5, 6]}

I know i can do (Thanks to @Netwave):

d={'a-b':[1,2,3],'c-d':[4,5,6]}

newd={}

for k,v in d.items():

    x,y=k.split('-')

    newd[x]=v

    newd[y]=v

print(newd)

#{'a': [1, 2, 3], 'b': [1, 2, 3], 'c': [4, 5, 6], 'd': [4, 5, 6]}

But i don't think that's efficient,

So i am hoping one of you can give a better solution.

edited Nov 19 at 6:02

asked Nov 19 at 5:59

U9-Forward

10.1k2834

1

Efficient according to... ? You are doing the bare minimum here so what are you hoping for?
– Julien
Nov 19 at 6:14

@Julien Am... i am hoping for a shorter, more efficient way of doing this, like maybe in a dictionary comprehension or something...
– U9-Forward
Nov 19 at 6:16

add a comment |

up vote
1
down vote

favorite

So let's say i have a dictionary as:

d={'a-b':[1,2,3],'c-d':[4,5,6]}

And i want to split the keys, i.e 'a-b' into two keys as 'a' and 'b', and keep same value for both etc...

So desired output should be:

{'a': [1, 2, 3], 'b': [1, 2, 3], 'c': [4, 5, 6], 'd': [4, 5, 6]}

I know i can do (Thanks to @Netwave):

d={'a-b':[1,2,3],'c-d':[4,5,6]}

newd={}

for k,v in d.items():

    x,y=k.split('-')

    newd[x]=v

    newd[y]=v

print(newd)

#{'a': [1, 2, 3], 'b': [1, 2, 3], 'c': [4, 5, 6], 'd': [4, 5, 6]}

But i don't think that's efficient,

So i am hoping one of you can give a better solution.

edited Nov 19 at 6:02

asked Nov 19 at 5:59

U9-Forward

10.1k2834

1

Efficient according to... ? You are doing the bare minimum here so what are you hoping for?
– Julien
Nov 19 at 6:14

@Julien Am... i am hoping for a shorter, more efficient way of doing this, like maybe in a dictionary comprehension or something...
– U9-Forward
Nov 19 at 6:16

add a comment |

up vote
1
down vote

favorite

So let's say i have a dictionary as:

d={'a-b':[1,2,3],'c-d':[4,5,6]}

And i want to split the keys, i.e 'a-b' into two keys as 'a' and 'b', and keep same value for both etc...

So desired output should be:

{'a': [1, 2, 3], 'b': [1, 2, 3], 'c': [4, 5, 6], 'd': [4, 5, 6]}

I know i can do (Thanks to @Netwave):

d={'a-b':[1,2,3],'c-d':[4,5,6]}

newd={}

for k,v in d.items():

    x,y=k.split('-')

    newd[x]=v

    newd[y]=v

print(newd)

#{'a': [1, 2, 3], 'b': [1, 2, 3], 'c': [4, 5, 6], 'd': [4, 5, 6]}

But i don't think that's efficient,

So i am hoping one of you can give a better solution.

edited Nov 19 at 6:02

asked Nov 19 at 5:59

U9-Forward

10.1k2834

So let's say i have a dictionary as:

d={'a-b':[1,2,3],'c-d':[4,5,6]}

And i want to split the keys, i.e 'a-b' into two keys as 'a' and 'b', and keep same value for both etc...

So desired output should be:

{'a': [1, 2, 3], 'b': [1, 2, 3], 'c': [4, 5, 6], 'd': [4, 5, 6]}

I know i can do (Thanks to @Netwave):

d={'a-b':[1,2,3],'c-d':[4,5,6]}

newd={}

for k,v in d.items():

    x,y=k.split('-')

    newd[x]=v

    newd[y]=v

print(newd)

#{'a': [1, 2, 3], 'b': [1, 2, 3], 'c': [4, 5, 6], 'd': [4, 5, 6]}

But i don't think that's efficient,

So i am hoping one of you can give a better solution.

python python-3.x dictionary split key

edited Nov 19 at 6:02

asked Nov 19 at 5:59

U9-Forward

10.1k2834

edited Nov 19 at 6:02

asked Nov 19 at 5:59

U9-Forward

10.1k2834

edited Nov 19 at 6:02

asked Nov 19 at 5:59

U9-Forward

10.1k2834

asked Nov 19 at 5:59

U9-Forward

10.1k2834

asked Nov 19 at 5:59

U9-Forward

10.1k2834

1

Efficient according to... ? You are doing the bare minimum here so what are you hoping for?
– Julien
Nov 19 at 6:14

@Julien Am... i am hoping for a shorter, more efficient way of doing this, like maybe in a dictionary comprehension or something...
– U9-Forward
Nov 19 at 6:16

add a comment |

1

Efficient according to... ? You are doing the bare minimum here so what are you hoping for?
– Julien
Nov 19 at 6:14

@Julien Am... i am hoping for a shorter, more efficient way of doing this, like maybe in a dictionary comprehension or something...
– U9-Forward
Nov 19 at 6:16

Efficient according to... ? You are doing the bare minimum here so what are you hoping for?
– Julien
Nov 19 at 6:14

@Julien Am... i am hoping for a shorter, more efficient way of doing this, like maybe in a dictionary comprehension or something...
– U9-Forward
Nov 19 at 6:16

add a comment |

1 Answer
1

active

oldest

votes

up vote
4
down vote

accepted

Just use split once:

for k,v in d.items():

    x, y = k.split("-")

    newd[x] = v

    newd[y] = v

Or iterate through it:

for k,v in d.items():

    for new_k in k.split("-")

        newd[new_k] = v

As a dict comprehension:

{new_k : v for k,v in d.items() for new_k in k.split("-")}

edited Nov 19 at 6:01

answered Nov 19 at 6:00

Netwave

11.7k21942

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
4
down vote

accepted

Just use split once:

for k,v in d.items():

    x, y = k.split("-")

    newd[x] = v

    newd[y] = v

Or iterate through it:

for k,v in d.items():

    for new_k in k.split("-")

        newd[new_k] = v

As a dict comprehension:

{new_k : v for k,v in d.items() for new_k in k.split("-")}

edited Nov 19 at 6:01

answered Nov 19 at 6:00

Netwave

11.7k21942

add a comment |

up vote
4
down vote

accepted

Just use split once:

for k,v in d.items():

    x, y = k.split("-")

    newd[x] = v

    newd[y] = v

Or iterate through it:

for k,v in d.items():

    for new_k in k.split("-")

        newd[new_k] = v

As a dict comprehension:

{new_k : v for k,v in d.items() for new_k in k.split("-")}

edited Nov 19 at 6:01

answered Nov 19 at 6:00

Netwave

11.7k21942

add a comment |

up vote
4
down vote

accepted

Just use split once:

for k,v in d.items():

    x, y = k.split("-")

    newd[x] = v

    newd[y] = v

Or iterate through it:

for k,v in d.items():

    for new_k in k.split("-")

        newd[new_k] = v

As a dict comprehension:

{new_k : v for k,v in d.items() for new_k in k.split("-")}

edited Nov 19 at 6:01

answered Nov 19 at 6:00

Netwave

11.7k21942

Just use split once:

for k,v in d.items():

    x, y = k.split("-")

    newd[x] = v

    newd[y] = v

Or iterate through it:

for k,v in d.items():

    for new_k in k.split("-")

        newd[new_k] = v

As a dict comprehension:

{new_k : v for k,v in d.items() for new_k in k.split("-")}

edited Nov 19 at 6:01

answered Nov 19 at 6:00

Netwave

11.7k21942

edited Nov 19 at 6:01

answered Nov 19 at 6:00

Netwave

11.7k21942

answered Nov 19 at 6:00

Netwave

11.7k21942

answered Nov 19 at 6:00

Netwave

11.7k21942

add a comment |

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