django 2.13 login_required build-in decorator doesn't work
i work on Django 2.1.2 and i wanted decorated my view base on class. I apply login_required decorator in path
path('', login_required(CredentialsList.as_view()), name='credentials-list'),
when i send request to CredentialList it responds normally, it does not redirect me to the login screen. whether I omitted something from the configuration
LOGIN_URL='login/'
LOGIN_REDIRECT_URL = 'list/'
django login-required
asked Nov 20 '18 at 21:50
PiotroSan
65
add a comment |
i work on Django 2.1.2 and i wanted decorated my view base on class. I apply login_required decorator in path
path('', login_required(CredentialsList.as_view()), name='credentials-list'),
when i send request to CredentialList it responds normally, it does not redirect me to the login screen. whether I omitted something from the configuration
LOGIN_URL='login/'
LOGIN_REDIRECT_URL = 'list/'
django login-required
asked Nov 20 '18 at 21:50
PiotroSan
65
LOGIN_URLshould be an absolute URL, e.g.LOGIN_URL='/login/', or the name of URL patter, e.g.'login'.LOGIN_REDIRECT_URLis the same.
– Alasdair
Nov 20 '18 at 22:43
Thank, i notice, i run this project on another enviroment ( another linux ) where everything work fine and i notice that this must be absolute. Thanks Alasdair
– PiotroSan
Nov 21 '18 at 8:02
add a comment |
i work on Django 2.1.2 and i wanted decorated my view base on class. I apply login_required decorator in path
path('', login_required(CredentialsList.as_view()), name='credentials-list'),
when i send request to CredentialList it responds normally, it does not redirect me to the login screen. whether I omitted something from the configuration
LOGIN_URL='login/'
LOGIN_REDIRECT_URL = 'list/'
django login-required
asked Nov 20 '18 at 21:50
PiotroSan
65
i work on Django 2.1.2 and i wanted decorated my view base on class. I apply login_required decorator in path
path('', login_required(CredentialsList.as_view()), name='credentials-list'),
when i send request to CredentialList it responds normally, it does not redirect me to the login screen. whether I omitted something from the configuration
LOGIN_URL='login/'
LOGIN_REDIRECT_URL = 'list/'
django login-required
django login-required
asked Nov 20 '18 at 21:50
PiotroSan
65
asked Nov 20 '18 at 21:50
PiotroSan
65
asked Nov 20 '18 at 21:50
PiotroSan
65
asked Nov 20 '18 at 21:50
PiotroSan
65
asked Nov 20 '18 at 21:50
PiotroSan
65
65
LOGIN_URLshould be an absolute URL, e.g.LOGIN_URL='/login/', or the name of URL patter, e.g.'login'.LOGIN_REDIRECT_URLis the same.
– Alasdair
Nov 20 '18 at 22:43
Thank, i notice, i run this project on another enviroment ( another linux ) where everything work fine and i notice that this must be absolute. Thanks Alasdair
– PiotroSan
Nov 21 '18 at 8:02
add a comment |
LOGIN_URLshould be an absolute URL, e.g.LOGIN_URL='/login/', or the name of URL patter, e.g.'login'.LOGIN_REDIRECT_URLis the same.
– Alasdair
Nov 20 '18 at 22:43
Thank, i notice, i run this project on another enviroment ( another linux ) where everything work fine and i notice that this must be absolute. Thanks Alasdair
– PiotroSan
Nov 21 '18 at 8:02
LOGIN_URL should be an absolute URL, e.g. LOGIN_URL='/login/', or the name of URL patter, e.g. 'login'. LOGIN_REDIRECT_URL is the same.– Alasdair
Nov 20 '18 at 22:43
LOGIN_URL should be an absolute URL, e.g. LOGIN_URL='/login/', or the name of URL patter, e.g. 'login'. LOGIN_REDIRECT_URL is the same.– Alasdair
Nov 20 '18 at 22:43
Thank, i notice, i run this project on another enviroment ( another linux ) where everything work fine and i notice that this must be absolute. Thanks Alasdair
– PiotroSan
Nov 21 '18 at 8:02
Thank, i notice, i run this project on another enviroment ( another linux ) where everything work fine and i notice that this must be absolute. Thanks Alasdair
– PiotroSan
Nov 21 '18 at 8:02
add a comment |
2 Answers
2
active
oldest
votes
Instead you can use the LoginRequiredMixin or the decorator in your view. For example:
# views.py
from django.contrib.auth.mixins import LoginRequiredMixin
from django.contrib.auth.decorators import login_required
# For a class-based view
class CredentialsList(LoginRequiredMixin, TemplateView):
# For a function-based view
@login_required
def credentials_list(request):
and for your url remove the decorator:
path('', CredentialsList.as_view(), name='credentials-list'),
answered Nov 20 '18 at 22:08
Whodini
50913
You are right, but decorator on class in path is the simplest and faster way, now i think maybe yours is a better way, by the way, i have resolved reason (enviroment) and not resolved problem ( i don't know why enviroment) but I will probably have to create a new environment. Thanks for answer
– PiotroSan
Nov 21 '18 at 8:18
add a comment |
I run this project on another linux (ubuntu 16.04), where is another enviroment of course and everything work fine :|. I must check in home what was wrong, maybe must create another virualenv.
Thank you all for your help me!!!
answered Nov 21 '18 at 8:07
PiotroSan
65
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Instead you can use the LoginRequiredMixin or the decorator in your view. For example:
# views.py
from django.contrib.auth.mixins import LoginRequiredMixin
from django.contrib.auth.decorators import login_required
# For a class-based view
class CredentialsList(LoginRequiredMixin, TemplateView):
# For a function-based view
@login_required
def credentials_list(request):
and for your url remove the decorator:
path('', CredentialsList.as_view(), name='credentials-list'),
answered Nov 20 '18 at 22:08
Whodini
50913
You are right, but decorator on class in path is the simplest and faster way, now i think maybe yours is a better way, by the way, i have resolved reason (enviroment) and not resolved problem ( i don't know why enviroment) but I will probably have to create a new environment. Thanks for answer
– PiotroSan
Nov 21 '18 at 8:18
add a comment |
Instead you can use the LoginRequiredMixin or the decorator in your view. For example:
# views.py
from django.contrib.auth.mixins import LoginRequiredMixin
from django.contrib.auth.decorators import login_required
# For a class-based view
class CredentialsList(LoginRequiredMixin, TemplateView):
# For a function-based view
@login_required
def credentials_list(request):
and for your url remove the decorator:
path('', CredentialsList.as_view(), name='credentials-list'),
answered Nov 20 '18 at 22:08
Whodini
50913
You are right, but decorator on class in path is the simplest and faster way, now i think maybe yours is a better way, by the way, i have resolved reason (enviroment) and not resolved problem ( i don't know why enviroment) but I will probably have to create a new environment. Thanks for answer
– PiotroSan
Nov 21 '18 at 8:18
add a comment |
Instead you can use the LoginRequiredMixin or the decorator in your view. For example:
# views.py
from django.contrib.auth.mixins import LoginRequiredMixin
from django.contrib.auth.decorators import login_required
# For a class-based view
class CredentialsList(LoginRequiredMixin, TemplateView):
# For a function-based view
@login_required
def credentials_list(request):
and for your url remove the decorator:
path('', CredentialsList.as_view(), name='credentials-list'),
answered Nov 20 '18 at 22:08
Whodini
50913
Instead you can use the LoginRequiredMixin or the decorator in your view. For example:
# views.py
from django.contrib.auth.mixins import LoginRequiredMixin
from django.contrib.auth.decorators import login_required
# For a class-based view
class CredentialsList(LoginRequiredMixin, TemplateView):
# For a function-based view
@login_required
def credentials_list(request):
and for your url remove the decorator:
path('', CredentialsList.as_view(), name='credentials-list'),
answered Nov 20 '18 at 22:08
Whodini
50913
answered Nov 20 '18 at 22:08
Whodini
50913
answered Nov 20 '18 at 22:08
Whodini
50913
answered Nov 20 '18 at 22:08
Whodini
50913
50913
You are right, but decorator on class in path is the simplest and faster way, now i think maybe yours is a better way, by the way, i have resolved reason (enviroment) and not resolved problem ( i don't know why enviroment) but I will probably have to create a new environment. Thanks for answer
– PiotroSan
Nov 21 '18 at 8:18
add a comment |
You are right, but decorator on class in path is the simplest and faster way, now i think maybe yours is a better way, by the way, i have resolved reason (enviroment) and not resolved problem ( i don't know why enviroment) but I will probably have to create a new environment. Thanks for answer
– PiotroSan
Nov 21 '18 at 8:18
You are right, but decorator on class in path is the simplest and faster way, now i think maybe yours is a better way, by the way, i have resolved reason (enviroment) and not resolved problem ( i don't know why enviroment) but I will probably have to create a new environment. Thanks for answer
– PiotroSan
Nov 21 '18 at 8:18
You are right, but decorator on class in path is the simplest and faster way, now i think maybe yours is a better way, by the way, i have resolved reason (enviroment) and not resolved problem ( i don't know why enviroment) but I will probably have to create a new environment. Thanks for answer
– PiotroSan
Nov 21 '18 at 8:18
add a comment |
I run this project on another linux (ubuntu 16.04), where is another enviroment of course and everything work fine :|. I must check in home what was wrong, maybe must create another virualenv.
Thank you all for your help me!!!
answered Nov 21 '18 at 8:07
PiotroSan
65
add a comment |
I run this project on another linux (ubuntu 16.04), where is another enviroment of course and everything work fine :|. I must check in home what was wrong, maybe must create another virualenv.
Thank you all for your help me!!!
answered Nov 21 '18 at 8:07
PiotroSan
65
add a comment |
I run this project on another linux (ubuntu 16.04), where is another enviroment of course and everything work fine :|. I must check in home what was wrong, maybe must create another virualenv.
Thank you all for your help me!!!
answered Nov 21 '18 at 8:07
PiotroSan
65
I run this project on another linux (ubuntu 16.04), where is another enviroment of course and everything work fine :|. I must check in home what was wrong, maybe must create another virualenv.
Thank you all for your help me!!!
answered Nov 21 '18 at 8:07
PiotroSan
65
answered Nov 21 '18 at 8:07
PiotroSan
65
answered Nov 21 '18 at 8:07
PiotroSan
65
answered Nov 21 '18 at 8:07
PiotroSan
65
65
add a comment |
add a comment |
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LOGIN_URLshould be an absolute URL, e.g.LOGIN_URL='/login/', or the name of URL patter, e.g.'login'.LOGIN_REDIRECT_URLis the same.– Alasdair
Nov 20 '18 at 22:43
Thank, i notice, i run this project on another enviroment ( another linux ) where everything work fine and i notice that this must be absolute. Thanks Alasdair
– PiotroSan
Nov 21 '18 at 8:02