How is changing a field to readonly a breaking change












2















I have a class library Foo, currently in version 1.0.0.



Another library Foo.Extensions of version 1.0.0, has Foo 1.0.0 as a dependency.



Both libraries try to adhere to semantic versioning, i.e. a program using Foo.Extensions 1.0.0, should be upgrade Foo to version 1.0.1 without breaking functionality of Foo.Extensions.



To avoid any breakage, I'm concerned about making updates to Foo in a source and binary compatibility way.



The Breaking Change Rules states that




Adding readonly to a field




is disallowed.



When is this a breaking change for e.g.



public class Foo
{
private int bar;
}


My best guess would be in some sort of reflection scenario, as I've experienced some (de)serializers to require properties to at least have a private setter.



How does this relates to removing a private setter from a property?



public class Foo2
{
public int Bar2 { get; private set; }
}









share|improve this question




















  • 2





    If you made that change, what do you think it might break? Keep in mind the doc you liked to is for a framework - so they are concerned with ensuring that API changes don't break the callers to the API.

    – mjwills
    Nov 22 '18 at 21:51













  • Adding to the previous comment, your example isnt the greatest, considering that bar isnt part of the public API of your example class.

    – Jota.Toledo
    Nov 22 '18 at 22:11








  • 1





    Also, given the quote you linked to was in the context of signatures (i.e. method signatures) you may consider updating the question to show an actual method signature. I also strongly suspect that the context implies that the field is not private (since otherwise it wouldn't form part of the signature).

    – mjwills
    Nov 22 '18 at 22:31













  • If there's an IncrementBar() method in the Foo class that increments bar, that will not work anymore; ergo, Breaking Change.

    – Yatin
    Nov 22 '18 at 23:05






  • 1





    @mjwills, I agree, and even I couldn't think of another scenario where this change would be a breaking change.

    – Yatin
    Nov 23 '18 at 0:44
















2















I have a class library Foo, currently in version 1.0.0.



Another library Foo.Extensions of version 1.0.0, has Foo 1.0.0 as a dependency.



Both libraries try to adhere to semantic versioning, i.e. a program using Foo.Extensions 1.0.0, should be upgrade Foo to version 1.0.1 without breaking functionality of Foo.Extensions.



To avoid any breakage, I'm concerned about making updates to Foo in a source and binary compatibility way.



The Breaking Change Rules states that




Adding readonly to a field




is disallowed.



When is this a breaking change for e.g.



public class Foo
{
private int bar;
}


My best guess would be in some sort of reflection scenario, as I've experienced some (de)serializers to require properties to at least have a private setter.



How does this relates to removing a private setter from a property?



public class Foo2
{
public int Bar2 { get; private set; }
}









share|improve this question




















  • 2





    If you made that change, what do you think it might break? Keep in mind the doc you liked to is for a framework - so they are concerned with ensuring that API changes don't break the callers to the API.

    – mjwills
    Nov 22 '18 at 21:51













  • Adding to the previous comment, your example isnt the greatest, considering that bar isnt part of the public API of your example class.

    – Jota.Toledo
    Nov 22 '18 at 22:11








  • 1





    Also, given the quote you linked to was in the context of signatures (i.e. method signatures) you may consider updating the question to show an actual method signature. I also strongly suspect that the context implies that the field is not private (since otherwise it wouldn't form part of the signature).

    – mjwills
    Nov 22 '18 at 22:31













  • If there's an IncrementBar() method in the Foo class that increments bar, that will not work anymore; ergo, Breaking Change.

    – Yatin
    Nov 22 '18 at 23:05






  • 1





    @mjwills, I agree, and even I couldn't think of another scenario where this change would be a breaking change.

    – Yatin
    Nov 23 '18 at 0:44














2












2








2








I have a class library Foo, currently in version 1.0.0.



Another library Foo.Extensions of version 1.0.0, has Foo 1.0.0 as a dependency.



Both libraries try to adhere to semantic versioning, i.e. a program using Foo.Extensions 1.0.0, should be upgrade Foo to version 1.0.1 without breaking functionality of Foo.Extensions.



To avoid any breakage, I'm concerned about making updates to Foo in a source and binary compatibility way.



The Breaking Change Rules states that




Adding readonly to a field




is disallowed.



When is this a breaking change for e.g.



public class Foo
{
private int bar;
}


My best guess would be in some sort of reflection scenario, as I've experienced some (de)serializers to require properties to at least have a private setter.



How does this relates to removing a private setter from a property?



public class Foo2
{
public int Bar2 { get; private set; }
}









share|improve this question
















I have a class library Foo, currently in version 1.0.0.



Another library Foo.Extensions of version 1.0.0, has Foo 1.0.0 as a dependency.



Both libraries try to adhere to semantic versioning, i.e. a program using Foo.Extensions 1.0.0, should be upgrade Foo to version 1.0.1 without breaking functionality of Foo.Extensions.



To avoid any breakage, I'm concerned about making updates to Foo in a source and binary compatibility way.



The Breaking Change Rules states that




Adding readonly to a field




is disallowed.



When is this a breaking change for e.g.



public class Foo
{
private int bar;
}


My best guess would be in some sort of reflection scenario, as I've experienced some (de)serializers to require properties to at least have a private setter.



How does this relates to removing a private setter from a property?



public class Foo2
{
public int Bar2 { get; private set; }
}






c#






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 23 '18 at 7:37







Jonas Nyrup

















asked Nov 22 '18 at 21:43









Jonas NyrupJonas Nyrup

560310




560310








  • 2





    If you made that change, what do you think it might break? Keep in mind the doc you liked to is for a framework - so they are concerned with ensuring that API changes don't break the callers to the API.

    – mjwills
    Nov 22 '18 at 21:51













  • Adding to the previous comment, your example isnt the greatest, considering that bar isnt part of the public API of your example class.

    – Jota.Toledo
    Nov 22 '18 at 22:11








  • 1





    Also, given the quote you linked to was in the context of signatures (i.e. method signatures) you may consider updating the question to show an actual method signature. I also strongly suspect that the context implies that the field is not private (since otherwise it wouldn't form part of the signature).

    – mjwills
    Nov 22 '18 at 22:31













  • If there's an IncrementBar() method in the Foo class that increments bar, that will not work anymore; ergo, Breaking Change.

    – Yatin
    Nov 22 '18 at 23:05






  • 1





    @mjwills, I agree, and even I couldn't think of another scenario where this change would be a breaking change.

    – Yatin
    Nov 23 '18 at 0:44














  • 2





    If you made that change, what do you think it might break? Keep in mind the doc you liked to is for a framework - so they are concerned with ensuring that API changes don't break the callers to the API.

    – mjwills
    Nov 22 '18 at 21:51













  • Adding to the previous comment, your example isnt the greatest, considering that bar isnt part of the public API of your example class.

    – Jota.Toledo
    Nov 22 '18 at 22:11








  • 1





    Also, given the quote you linked to was in the context of signatures (i.e. method signatures) you may consider updating the question to show an actual method signature. I also strongly suspect that the context implies that the field is not private (since otherwise it wouldn't form part of the signature).

    – mjwills
    Nov 22 '18 at 22:31













  • If there's an IncrementBar() method in the Foo class that increments bar, that will not work anymore; ergo, Breaking Change.

    – Yatin
    Nov 22 '18 at 23:05






  • 1





    @mjwills, I agree, and even I couldn't think of another scenario where this change would be a breaking change.

    – Yatin
    Nov 23 '18 at 0:44








2




2





If you made that change, what do you think it might break? Keep in mind the doc you liked to is for a framework - so they are concerned with ensuring that API changes don't break the callers to the API.

– mjwills
Nov 22 '18 at 21:51







If you made that change, what do you think it might break? Keep in mind the doc you liked to is for a framework - so they are concerned with ensuring that API changes don't break the callers to the API.

– mjwills
Nov 22 '18 at 21:51















Adding to the previous comment, your example isnt the greatest, considering that bar isnt part of the public API of your example class.

– Jota.Toledo
Nov 22 '18 at 22:11







Adding to the previous comment, your example isnt the greatest, considering that bar isnt part of the public API of your example class.

– Jota.Toledo
Nov 22 '18 at 22:11






1




1





Also, given the quote you linked to was in the context of signatures (i.e. method signatures) you may consider updating the question to show an actual method signature. I also strongly suspect that the context implies that the field is not private (since otherwise it wouldn't form part of the signature).

– mjwills
Nov 22 '18 at 22:31







Also, given the quote you linked to was in the context of signatures (i.e. method signatures) you may consider updating the question to show an actual method signature. I also strongly suspect that the context implies that the field is not private (since otherwise it wouldn't form part of the signature).

– mjwills
Nov 22 '18 at 22:31















If there's an IncrementBar() method in the Foo class that increments bar, that will not work anymore; ergo, Breaking Change.

– Yatin
Nov 22 '18 at 23:05





If there's an IncrementBar() method in the Foo class that increments bar, that will not work anymore; ergo, Breaking Change.

– Yatin
Nov 22 '18 at 23:05




1




1





@mjwills, I agree, and even I couldn't think of another scenario where this change would be a breaking change.

– Yatin
Nov 23 '18 at 0:44





@mjwills, I agree, and even I couldn't think of another scenario where this change would be a breaking change.

– Yatin
Nov 23 '18 at 0:44












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