Nsryjdtyk

I have a test-persistence.xml file in the src/test/resources location. The content of this file is:

<?xml version="1.0" encoding="UTF-8"?>

<persistence xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.0"

             xmlns="http://java.sun.com/xml/ns/persistence"

             xsi:schemaLocation="http://java.sun.com/xml/ns/persistence

                                http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">

    <persistence-unit name="mmTest" transaction-type="RESOURCE_LOCAL">

        <properties>

            <property name="javax.persistence.jdbc.driver" value="org.h2.Driver"/>

            <property name="javax.persistence.jdbc.url" value="jdbc:h2:mem:test;DB_CLOSE_DELAY=-1;DB_CLOSE_ON_EXIT=FALSE"/>

            <property name="javax.persistence.jdbc.user" value="sa"/>

            <property name="javax.persistence.jdbc.password" value=""/>

            <property name="hibernate.hbm2ddl.auto" value="create-drop"/>

            <property name="hibernate.dialect" value="org.hibernate.dialect.H2Dialect"/>

        </properties>

    </persistence-unit>

</persistence>

My Spring configuration looks like below:

<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">

    <property name="packagesToScan" value="com.sample"/>

    <property name="persistenceUnitName" value="mmTest"/>

    <property name="persistenceUnitManager" ref="persistenceUnitManager"/>

    <property name="jpaVendorAdapter" ref="jpaVendorAdapter"/>

</bean>

<bean id="persistenceUnitManager" class="org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager">

    <property name="persistenceXmlLocation" value="classpath*:test-persistence.xml"/>

</bean>

<bean id="jpaVendorAdapter" class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">

    <property name="showSql" value="true"/>

</bean>

<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">

    <property name="entityManagerFactory" ref="entityManagerFactory"/>

</bean>

When I try to run a JUnit test with this context configuration set I get the exception:

java.lang.IllegalArgumentException: Unknown entity:
com.sample.SampleEntity

Is it possible to have persistence.xml file for tests and configure Spring to scan for classes with @Entity? I do not want to use JPA specific class discovery like jar-file or listed classes. I want to use Spring to discover those classes.

The strange thing is when I move test-persistence.xml to the location: /src/main/resources/META-INF then everything works correctly. However, I do not want to have test specific configuration inside src/main.

Currently I solved the problem by specifying DataSource instead of persistenceUnitManager and persistenceUnitName.

But I would like to know how to solve it without using DataSource.