JS Double Fetch condition












0















I'm working in get a list from a local file. But the folder sometimes can change. So come here to ask you guys if it's correct, because I think there is a better way to do it, idk. Please help me :)



  fetch("./myJson.json")

     .then(res => { 

        if(res.status != 404)

           res.json() 

        else

           fetch("../myJson.json")

              .then(res => res.json())

              .then(data => console.log(data))

              .catch(err => console.error(err));

     })

     .then(data => console.log(data))

     .catch(err => console.error(err));


Thanks!






javascript fetch-api







share|improve this question




















  • 1





    You will need to return the nested promises from the callback

    – Bergi
    Nov 24 '18 at 16:12
















0















I'm working in get a list from a local file. But the folder sometimes can change. So come here to ask you guys if it's correct, because I think there is a better way to do it, idk. Please help me :)



  fetch("./myJson.json")

     .then(res => { 

        if(res.status != 404)

           res.json() 

        else

           fetch("../myJson.json")

              .then(res => res.json())

              .then(data => console.log(data))

              .catch(err => console.error(err));

     })

     .then(data => console.log(data))

     .catch(err => console.error(err));


Thanks!






javascript fetch-api







share|improve this question




















  • 1





    You will need to return the nested promises from the callback

    – Bergi
    Nov 24 '18 at 16:12














0












0








0








I'm working in get a list from a local file. But the folder sometimes can change. So come here to ask you guys if it's correct, because I think there is a better way to do it, idk. Please help me :)



  fetch("./myJson.json")

     .then(res => { 

        if(res.status != 404)

           res.json() 

        else

           fetch("../myJson.json")

              .then(res => res.json())

              .then(data => console.log(data))

              .catch(err => console.error(err));

     })

     .then(data => console.log(data))

     .catch(err => console.error(err));


Thanks!






javascript fetch-api







share|improve this question
















I'm working in get a list from a local file. But the folder sometimes can change. So come here to ask you guys if it's correct, because I think there is a better way to do it, idk. Please help me :)



  fetch("./myJson.json")

     .then(res => { 

        if(res.status != 404)

           res.json() 

        else

           fetch("../myJson.json")

              .then(res => res.json())

              .then(data => console.log(data))

              .catch(err => console.error(err));

     })

     .then(data => console.log(data))

     .catch(err => console.error(err));


Thanks!






javascript fetch-api




javascript fetch-api






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 24 '18 at 16:49









Bergi

374k60565897




374k60565897










asked Nov 24 '18 at 15:59









JohnsonJohnson

2371619




2371619








  • 1





    You will need to return the nested promises from the callback

    – Bergi
    Nov 24 '18 at 16:12














  • 1





    You will need to return the nested promises from the callback

    – Bergi
    Nov 24 '18 at 16:12








1




1





You will need to return the nested promises from the callback

– Bergi
Nov 24 '18 at 16:12





You will need to return the nested promises from the callback

– Bergi
Nov 24 '18 at 16:12












1 Answer
1






active

oldest

votes


















3














You will need to return the nested promises from the callback and use the promise chaining feature:



fetch("./myJson.json").then(res => { 

    if (res.ok)

        return res.json() 

    else

       return fetch("../myJson.json").then(res => res.json());

}).then(console.log, console.error);





share|improve this answer
























  • Nice Bergi!! Thanks!! Just a detail... If the first fetch fails, an error 404 shows up in console. Can I tell him that "if the first fetch fails, the second one will solve it. You don't have to show any error in console about this first fetch."

    – Johnson
    Nov 24 '18 at 16:39






  • 1





    The 404 will always show up in the console, you cannot prevent that from JS. You will need to use different console settings. Or actually handle the logic on the server side with a redirect.

    – Bergi
    Nov 24 '18 at 16:48













  • Hmmm got it ! Thanks a lot man :) !!

    – Johnson
    Nov 24 '18 at 17:00











Your Answer






StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53459904%2fjs-double-fetch-condition%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3














You will need to return the nested promises from the callback and use the promise chaining feature:



fetch("./myJson.json").then(res => { 

    if (res.ok)

        return res.json() 

    else

       return fetch("../myJson.json").then(res => res.json());

}).then(console.log, console.error);





share|improve this answer
























  • Nice Bergi!! Thanks!! Just a detail... If the first fetch fails, an error 404 shows up in console. Can I tell him that "if the first fetch fails, the second one will solve it. You don't have to show any error in console about this first fetch."

    – Johnson
    Nov 24 '18 at 16:39






  • 1





    The 404 will always show up in the console, you cannot prevent that from JS. You will need to use different console settings. Or actually handle the logic on the server side with a redirect.

    – Bergi
    Nov 24 '18 at 16:48













  • Hmmm got it ! Thanks a lot man :) !!

    – Johnson
    Nov 24 '18 at 17:00
















3














You will need to return the nested promises from the callback and use the promise chaining feature:



fetch("./myJson.json").then(res => { 

    if (res.ok)

        return res.json() 

    else

       return fetch("../myJson.json").then(res => res.json());

}).then(console.log, console.error);





share|improve this answer
























  • Nice Bergi!! Thanks!! Just a detail... If the first fetch fails, an error 404 shows up in console. Can I tell him that "if the first fetch fails, the second one will solve it. You don't have to show any error in console about this first fetch."

    – Johnson
    Nov 24 '18 at 16:39






  • 1





    The 404 will always show up in the console, you cannot prevent that from JS. You will need to use different console settings. Or actually handle the logic on the server side with a redirect.

    – Bergi
    Nov 24 '18 at 16:48













  • Hmmm got it ! Thanks a lot man :) !!

    – Johnson
    Nov 24 '18 at 17:00














3












3








3







You will need to return the nested promises from the callback and use the promise chaining feature:



fetch("./myJson.json").then(res => { 

    if (res.ok)

        return res.json() 

    else

       return fetch("../myJson.json").then(res => res.json());

}).then(console.log, console.error);





share|improve this answer













You will need to return the nested promises from the callback and use the promise chaining feature:



fetch("./myJson.json").then(res => { 

    if (res.ok)

        return res.json() 

    else

       return fetch("../myJson.json").then(res => res.json());

}).then(console.log, console.error);






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 24 '18 at 16:14









BergiBergi

374k60565897




374k60565897













  • Nice Bergi!! Thanks!! Just a detail... If the first fetch fails, an error 404 shows up in console. Can I tell him that "if the first fetch fails, the second one will solve it. You don't have to show any error in console about this first fetch."

    – Johnson
    Nov 24 '18 at 16:39






  • 1





    The 404 will always show up in the console, you cannot prevent that from JS. You will need to use different console settings. Or actually handle the logic on the server side with a redirect.

    – Bergi
    Nov 24 '18 at 16:48













  • Hmmm got it ! Thanks a lot man :) !!

    – Johnson
    Nov 24 '18 at 17:00



















  • Nice Bergi!! Thanks!! Just a detail... If the first fetch fails, an error 404 shows up in console. Can I tell him that "if the first fetch fails, the second one will solve it. You don't have to show any error in console about this first fetch."

    – Johnson
    Nov 24 '18 at 16:39






  • 1





    The 404 will always show up in the console, you cannot prevent that from JS. You will need to use different console settings. Or actually handle the logic on the server side with a redirect.

    – Bergi
    Nov 24 '18 at 16:48













  • Hmmm got it ! Thanks a lot man :) !!

    – Johnson
    Nov 24 '18 at 17:00

















Nice Bergi!! Thanks!! Just a detail... If the first fetch fails, an error 404 shows up in console. Can I tell him that "if the first fetch fails, the second one will solve it. You don't have to show any error in console about this first fetch."

– Johnson
Nov 24 '18 at 16:39





Nice Bergi!! Thanks!! Just a detail... If the first fetch fails, an error 404 shows up in console. Can I tell him that "if the first fetch fails, the second one will solve it. You don't have to show any error in console about this first fetch."

– Johnson
Nov 24 '18 at 16:39




1




1





The 404 will always show up in the console, you cannot prevent that from JS. You will need to use different console settings. Or actually handle the logic on the server side with a redirect.

– Bergi
Nov 24 '18 at 16:48







The 404 will always show up in the console, you cannot prevent that from JS. You will need to use different console settings. Or actually handle the logic on the server side with a redirect.

– Bergi
Nov 24 '18 at 16:48















Hmmm got it ! Thanks a lot man :) !!

– Johnson
Nov 24 '18 at 17:00





Hmmm got it ! Thanks a lot man :) !!

– Johnson
Nov 24 '18 at 17:00




















draft saved

draft discarded




















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid …



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53459904%2fjs-double-fetch-condition%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







-

Popular posts from this blog

Create new schema in PostgreSQL using DBeaver

Image
0 At the beginning of my current job I had limited access to DB but recently my role is changed to superuser, admin, and owner. My colleague who was the previous DB admin is able to create a schema or change the permissions as there is a permission tab in the properties and he can change permissions by clicking easily. Would you please let me know how I can create schema and change permissions as well? Why his dbeaver looks different from me? He can easily right click on the schema folder on top of all schemas on the left side column and select create new schema while I do not have that, like the following picture I found on the internet. postgresql database-schema dbeaver share | improve this question
Read more

Deepest pit of an array with Javascript: test on Codility

Image
0 $begingroup$ This is the question from a Codility test, as a task in an interview: DeepestPit - problem description A non-empty zero-indexed array A consisting of N integers is given. A pit in this array is any triplet of integers (P, Q, R) such that: ·         0 ≤ P < Q < R < N; ·         sequence [A[P], A[P+1], ..., A[Q]] is strictly decreasing, i.e. A[P] > A[P+1] > ... > A[Q]; ·         sequence A[Q], A[Q+1], ..., A[R] is strictly increasing, i.e. A[Q] < A[Q+1] < ... < A[R]. The depth of a pit (P, Q, R) is the number min {A[P] − A[Q], A[R] − A[Q]}. For example, consider array A consisting of 10 elements such that: A[0] = 0 A[1] = 1 A[2] = 3 A[3] = -2 A[4] = 0 A[5] = 1 A[6] = 0 A[7] = -3 A[8] = 2 A[9] = 3 Triplet (2, 3, 4) is
Read more

Fotorealismo

Image
Guerrino Boatto, Venice's St. Barnaba Church and canal Il fotorealismo è un genere di pittura basato sull'uso di una o più fotografie dalle quali l'artista prende le informazioni necessarie da utilizzare poi nel processo della creazione dell'opera, in genere ad olio o ad acrilico, al fine di avere un aspetto finale il più simile possibile alla fotografia. Indice 1 Storia 2 Lista dei fotorealisti 3 Note 4 Voci correlate 5 Altri progetti Storia | Il fotorealismo è un movimento che nasce negli Stati Uniti d'America alla fine degli anni sessanta [1] sulla scia della Pop Art [2] [3] [4] , e insieme condividono il carattere reazionario verso la travolgente ascesa dei media, che alla metà del ventesimo secolo si trasforma in un fenomeno di massa talmente imponente da minacciare il valore dell'immagine nell'arte. [5] [6] Ne consegue così che, colto il gesto d'inizio che fu della Pop Art, i fotorealisti aprono ad un
Read more