Iter through XML tags and get tag inside that attribute - Python
up vote
0
down vote
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I'm looking for child tag values in xml data, my code below gets me all the values for tags "color" inside "info" in xml data, but I'm looking for a iteration,
if color = yellow, i need to get it's rank only.
****My Code:****
xmldata = '''
<FullGroup>
<color>General</color>
<link>url</link>
<three>test</three>
<four>
<info>
<color>yellow</color>
<rank>100</rank>
<place>first</place>
</info>
<info>
<color>red</color>
<rank>500</rank>
<place>second</place>
</info>
</four>
</FullGroup>'''
xml = ElementTree.fromstring(xmldata)
for color in xml.findall('.//info/color'):
print color.text
output:
yellow
red
Required output:
100
Thanks in Advance ..
python xml
asked Nov 19 at 22:39
Sai Kiran
104
add a comment |
up vote
0
down vote
favorite
I'm looking for child tag values in xml data, my code below gets me all the values for tags "color" inside "info" in xml data, but I'm looking for a iteration,
if color = yellow, i need to get it's rank only.
****My Code:****
xmldata = '''
<FullGroup>
<color>General</color>
<link>url</link>
<three>test</three>
<four>
<info>
<color>yellow</color>
<rank>100</rank>
<place>first</place>
</info>
<info>
<color>red</color>
<rank>500</rank>
<place>second</place>
</info>
</four>
</FullGroup>'''
xml = ElementTree.fromstring(xmldata)
for color in xml.findall('.//info/color'):
print color.text
output:
yellow
red
Required output:
100
Thanks in Advance ..
python xml
asked Nov 19 at 22:39
Sai Kiran
104
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I'm looking for child tag values in xml data, my code below gets me all the values for tags "color" inside "info" in xml data, but I'm looking for a iteration,
if color = yellow, i need to get it's rank only.
****My Code:****
xmldata = '''
<FullGroup>
<color>General</color>
<link>url</link>
<three>test</three>
<four>
<info>
<color>yellow</color>
<rank>100</rank>
<place>first</place>
</info>
<info>
<color>red</color>
<rank>500</rank>
<place>second</place>
</info>
</four>
</FullGroup>'''
xml = ElementTree.fromstring(xmldata)
for color in xml.findall('.//info/color'):
print color.text
output:
yellow
red
Required output:
100
Thanks in Advance ..
python xml
asked Nov 19 at 22:39
Sai Kiran
104
I'm looking for child tag values in xml data, my code below gets me all the values for tags "color" inside "info" in xml data, but I'm looking for a iteration,
if color = yellow, i need to get it's rank only.
****My Code:****
xmldata = '''
<FullGroup>
<color>General</color>
<link>url</link>
<three>test</three>
<four>
<info>
<color>yellow</color>
<rank>100</rank>
<place>first</place>
</info>
<info>
<color>red</color>
<rank>500</rank>
<place>second</place>
</info>
</four>
</FullGroup>'''
xml = ElementTree.fromstring(xmldata)
for color in xml.findall('.//info/color'):
print color.text
output:
yellow
red
Required output:
100
Thanks in Advance ..
python xml
python xml
asked Nov 19 at 22:39
Sai Kiran
104
asked Nov 19 at 22:39
Sai Kiran
104
asked Nov 19 at 22:39
Sai Kiran
104
asked Nov 19 at 22:39
Sai Kiran
104
asked Nov 19 at 22:39
Sai Kiran
104
104
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
1
down vote
You could use zip() like so:
for color, rank in zip(xml.findall('.//info/color'), xml.findall('.//info/rank')):
if color.text == 'yellow':
print(rank.text)
answered Nov 19 at 23:20
Red Cricket
4,20983382
AttributeError: 'str' object has no attribute 'findall'.... Error, is it reading xml data as string ?
– Sai Kiran
Nov 20 at 16:44
add a comment |
up vote
1
down vote
Your XPath expression is wrong. To get the rank children of all info elements which have a child named color with the text() value "yellow", change
xml = ElementTree.fromstring(xmldata)
for color in xml.findall('.//info/color'):
print color.text
to
xml = ElementTree.fromstring(xmldata)
for curRank in xml.findall('.//info[color="yellow"]/rank'):
print curRank.text
Output is:
100
answered Nov 20 at 0:00
zx485
13.1k122845
Thanks, working !!
– Sai Kiran
Nov 20 at 17:00
Thank you !! Done
– Sai Kiran
Nov 21 at 16:58
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
You could use zip() like so:
for color, rank in zip(xml.findall('.//info/color'), xml.findall('.//info/rank')):
if color.text == 'yellow':
print(rank.text)
answered Nov 19 at 23:20
Red Cricket
4,20983382
AttributeError: 'str' object has no attribute 'findall'.... Error, is it reading xml data as string ?
– Sai Kiran
Nov 20 at 16:44
add a comment |
up vote
1
down vote
You could use zip() like so:
for color, rank in zip(xml.findall('.//info/color'), xml.findall('.//info/rank')):
if color.text == 'yellow':
print(rank.text)
answered Nov 19 at 23:20
Red Cricket
4,20983382
AttributeError: 'str' object has no attribute 'findall'.... Error, is it reading xml data as string ?
– Sai Kiran
Nov 20 at 16:44
add a comment |
up vote
1
down vote
up vote
1
down vote
You could use zip() like so:
for color, rank in zip(xml.findall('.//info/color'), xml.findall('.//info/rank')):
if color.text == 'yellow':
print(rank.text)
answered Nov 19 at 23:20
Red Cricket
4,20983382
You could use zip() like so:
for color, rank in zip(xml.findall('.//info/color'), xml.findall('.//info/rank')):
if color.text == 'yellow':
print(rank.text)
answered Nov 19 at 23:20
Red Cricket
4,20983382
answered Nov 19 at 23:20
Red Cricket
4,20983382
answered Nov 19 at 23:20
Red Cricket
4,20983382
answered Nov 19 at 23:20
Red Cricket
4,20983382
4,20983382
AttributeError: 'str' object has no attribute 'findall'.... Error, is it reading xml data as string ?
– Sai Kiran
Nov 20 at 16:44
add a comment |
AttributeError: 'str' object has no attribute 'findall'.... Error, is it reading xml data as string ?
– Sai Kiran
Nov 20 at 16:44
AttributeError: 'str' object has no attribute 'findall'.... Error, is it reading xml data as string ?
– Sai Kiran
Nov 20 at 16:44
AttributeError: 'str' object has no attribute 'findall'.... Error, is it reading xml data as string ?
– Sai Kiran
Nov 20 at 16:44
add a comment |
up vote
1
down vote
Your XPath expression is wrong. To get the rank children of all info elements which have a child named color with the text() value "yellow", change
xml = ElementTree.fromstring(xmldata)
for color in xml.findall('.//info/color'):
print color.text
to
xml = ElementTree.fromstring(xmldata)
for curRank in xml.findall('.//info[color="yellow"]/rank'):
print curRank.text
Output is:
100
answered Nov 20 at 0:00
zx485
13.1k122845
Thanks, working !!
– Sai Kiran
Nov 20 at 17:00
Thank you !! Done
– Sai Kiran
Nov 21 at 16:58
add a comment |
up vote
1
down vote
Your XPath expression is wrong. To get the rank children of all info elements which have a child named color with the text() value "yellow", change
xml = ElementTree.fromstring(xmldata)
for color in xml.findall('.//info/color'):
print color.text
to
xml = ElementTree.fromstring(xmldata)
for curRank in xml.findall('.//info[color="yellow"]/rank'):
print curRank.text
Output is:
100
answered Nov 20 at 0:00
zx485
13.1k122845
Thanks, working !!
– Sai Kiran
Nov 20 at 17:00
Thank you !! Done
– Sai Kiran
Nov 21 at 16:58
add a comment |
up vote
1
down vote
up vote
1
down vote
Your XPath expression is wrong. To get the rank children of all info elements which have a child named color with the text() value "yellow", change
xml = ElementTree.fromstring(xmldata)
for color in xml.findall('.//info/color'):
print color.text
to
xml = ElementTree.fromstring(xmldata)
for curRank in xml.findall('.//info[color="yellow"]/rank'):
print curRank.text
Output is:
100
answered Nov 20 at 0:00
zx485
13.1k122845
Your XPath expression is wrong. To get the rank children of all info elements which have a child named color with the text() value "yellow", change
xml = ElementTree.fromstring(xmldata)
for color in xml.findall('.//info/color'):
print color.text
to
xml = ElementTree.fromstring(xmldata)
for curRank in xml.findall('.//info[color="yellow"]/rank'):
print curRank.text
Output is:
100
answered Nov 20 at 0:00
zx485
13.1k122845
answered Nov 20 at 0:00
zx485
13.1k122845
answered Nov 20 at 0:00
zx485
13.1k122845
answered Nov 20 at 0:00
zx485
13.1k122845
13.1k122845
Thanks, working !!
– Sai Kiran
Nov 20 at 17:00
Thank you !! Done
– Sai Kiran
Nov 21 at 16:58
add a comment |
Thanks, working !!
– Sai Kiran
Nov 20 at 17:00
Thank you !! Done
– Sai Kiran
Nov 21 at 16:58
Thanks, working !!
– Sai Kiran
Nov 20 at 17:00
Thanks, working !!
– Sai Kiran
Nov 20 at 17:00
Thank you !! Done
– Sai Kiran
Nov 21 at 16:58
Thank you !! Done
– Sai Kiran
Nov 21 at 16:58
add a comment |
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