[JS][AJAX] second ajax does not work. Why?











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0
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I have little problem :) The first ajax returns the correct value.
Then I extract the text from the first answer and I want to send this text to another ajax file. but the second one sends an empty value. Why?
So this is my code:



var fileName = "record.wav";
var formdata = new FormData();
formdata.append('file', blob);
$.ajax({
url: "sendFileAudio.php",
type: 'POST',
data: formdata,
// async: true,
cache: false,
contentType: false,
processData: false,
beforeSend: function() {
$("#loaderStt").show();
},
success: function(data) {
console.log(data);
var messagesContainerOther = $(".messages");
messagesContainerOther.append(
data
);
var audioRsp = $(data).text();
var pytanie = audioRsp.valueOf();
// alert(typeof audioRsp);
document.getElementById("wiadomosc").innerHTML = pytanie;
// var pytanie = $("#wiadomosc").text();
$.ajax({
url: "sendMessageSamara.php",
type: 'POST',
data: pytanie,
beforeSend: function() {
$("#loader").show();
},
success: function(data) {
// console.log(data);
// alert("2"+ref);
console.log("poszło");
console.log(pytanie);
var messagesContainerOther = $(".messages");
messagesContainerOther.append(
data
);
messagesContainerOther.finish().animate({
scrollTop: messagesContainerOther.prop("scrollHeight")
},
250
);
},
complete: function(data) {
$("#loader").hide();
},
});
},
complete: function(data) {
$("#loaderStt").hide();
},
});









share|improve this question




























    up vote
    0
    down vote

    favorite












    I have little problem :) The first ajax returns the correct value.
    Then I extract the text from the first answer and I want to send this text to another ajax file. but the second one sends an empty value. Why?
    So this is my code:



    var fileName = "record.wav";
    var formdata = new FormData();
    formdata.append('file', blob);
    $.ajax({
    url: "sendFileAudio.php",
    type: 'POST',
    data: formdata,
    // async: true,
    cache: false,
    contentType: false,
    processData: false,
    beforeSend: function() {
    $("#loaderStt").show();
    },
    success: function(data) {
    console.log(data);
    var messagesContainerOther = $(".messages");
    messagesContainerOther.append(
    data
    );
    var audioRsp = $(data).text();
    var pytanie = audioRsp.valueOf();
    // alert(typeof audioRsp);
    document.getElementById("wiadomosc").innerHTML = pytanie;
    // var pytanie = $("#wiadomosc").text();
    $.ajax({
    url: "sendMessageSamara.php",
    type: 'POST',
    data: pytanie,
    beforeSend: function() {
    $("#loader").show();
    },
    success: function(data) {
    // console.log(data);
    // alert("2"+ref);
    console.log("poszło");
    console.log(pytanie);
    var messagesContainerOther = $(".messages");
    messagesContainerOther.append(
    data
    );
    messagesContainerOther.finish().animate({
    scrollTop: messagesContainerOther.prop("scrollHeight")
    },
    250
    );
    },
    complete: function(data) {
    $("#loader").hide();
    },
    });
    },
    complete: function(data) {
    $("#loaderStt").hide();
    },
    });









    share|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I have little problem :) The first ajax returns the correct value.
      Then I extract the text from the first answer and I want to send this text to another ajax file. but the second one sends an empty value. Why?
      So this is my code:



      var fileName = "record.wav";
      var formdata = new FormData();
      formdata.append('file', blob);
      $.ajax({
      url: "sendFileAudio.php",
      type: 'POST',
      data: formdata,
      // async: true,
      cache: false,
      contentType: false,
      processData: false,
      beforeSend: function() {
      $("#loaderStt").show();
      },
      success: function(data) {
      console.log(data);
      var messagesContainerOther = $(".messages");
      messagesContainerOther.append(
      data
      );
      var audioRsp = $(data).text();
      var pytanie = audioRsp.valueOf();
      // alert(typeof audioRsp);
      document.getElementById("wiadomosc").innerHTML = pytanie;
      // var pytanie = $("#wiadomosc").text();
      $.ajax({
      url: "sendMessageSamara.php",
      type: 'POST',
      data: pytanie,
      beforeSend: function() {
      $("#loader").show();
      },
      success: function(data) {
      // console.log(data);
      // alert("2"+ref);
      console.log("poszło");
      console.log(pytanie);
      var messagesContainerOther = $(".messages");
      messagesContainerOther.append(
      data
      );
      messagesContainerOther.finish().animate({
      scrollTop: messagesContainerOther.prop("scrollHeight")
      },
      250
      );
      },
      complete: function(data) {
      $("#loader").hide();
      },
      });
      },
      complete: function(data) {
      $("#loaderStt").hide();
      },
      });









      share|improve this question















      I have little problem :) The first ajax returns the correct value.
      Then I extract the text from the first answer and I want to send this text to another ajax file. but the second one sends an empty value. Why?
      So this is my code:



      var fileName = "record.wav";
      var formdata = new FormData();
      formdata.append('file', blob);
      $.ajax({
      url: "sendFileAudio.php",
      type: 'POST',
      data: formdata,
      // async: true,
      cache: false,
      contentType: false,
      processData: false,
      beforeSend: function() {
      $("#loaderStt").show();
      },
      success: function(data) {
      console.log(data);
      var messagesContainerOther = $(".messages");
      messagesContainerOther.append(
      data
      );
      var audioRsp = $(data).text();
      var pytanie = audioRsp.valueOf();
      // alert(typeof audioRsp);
      document.getElementById("wiadomosc").innerHTML = pytanie;
      // var pytanie = $("#wiadomosc").text();
      $.ajax({
      url: "sendMessageSamara.php",
      type: 'POST',
      data: pytanie,
      beforeSend: function() {
      $("#loader").show();
      },
      success: function(data) {
      // console.log(data);
      // alert("2"+ref);
      console.log("poszło");
      console.log(pytanie);
      var messagesContainerOther = $(".messages");
      messagesContainerOther.append(
      data
      );
      messagesContainerOther.finish().animate({
      scrollTop: messagesContainerOther.prop("scrollHeight")
      },
      250
      );
      },
      complete: function(data) {
      $("#loader").hide();
      },
      });
      },
      complete: function(data) {
      $("#loaderStt").hide();
      },
      });






      javascript jquery ajax






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      edited Nov 19 at 22:28









      charlietfl

      138k1286118




      138k1286118










      asked Nov 19 at 22:25









      Michal Robak

      31




      31
























          1 Answer
          1






          active

          oldest

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          up vote
          0
          down vote



          accepted










          You aren't sending a key/value pair in the second request, only a value



          Change



          data: pytanie


          to



          data: {somePropertyName: pytanie}


          And receive that in php with:



          $_POST['somePropertyName'];





          share|improve this answer





















          • What exactly isn't working? Is request being made? inspect it in browser dev tools network and see what is sent is what you expect, status etc
            – charlietfl
            Nov 19 at 22:50










          • i add before: contentType: 'text/plain', haha :)
            – Michal Robak
            Nov 19 at 22:51











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          0
          down vote



          accepted










          You aren't sending a key/value pair in the second request, only a value



          Change



          data: pytanie


          to



          data: {somePropertyName: pytanie}


          And receive that in php with:



          $_POST['somePropertyName'];





          share|improve this answer





















          • What exactly isn't working? Is request being made? inspect it in browser dev tools network and see what is sent is what you expect, status etc
            – charlietfl
            Nov 19 at 22:50










          • i add before: contentType: 'text/plain', haha :)
            – Michal Robak
            Nov 19 at 22:51















          up vote
          0
          down vote



          accepted










          You aren't sending a key/value pair in the second request, only a value



          Change



          data: pytanie


          to



          data: {somePropertyName: pytanie}


          And receive that in php with:



          $_POST['somePropertyName'];





          share|improve this answer





















          • What exactly isn't working? Is request being made? inspect it in browser dev tools network and see what is sent is what you expect, status etc
            – charlietfl
            Nov 19 at 22:50










          • i add before: contentType: 'text/plain', haha :)
            – Michal Robak
            Nov 19 at 22:51













          up vote
          0
          down vote



          accepted







          up vote
          0
          down vote



          accepted






          You aren't sending a key/value pair in the second request, only a value



          Change



          data: pytanie


          to



          data: {somePropertyName: pytanie}


          And receive that in php with:



          $_POST['somePropertyName'];





          share|improve this answer












          You aren't sending a key/value pair in the second request, only a value



          Change



          data: pytanie


          to



          data: {somePropertyName: pytanie}


          And receive that in php with:



          $_POST['somePropertyName'];






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 19 at 22:33









          charlietfl

          138k1286118




          138k1286118












          • What exactly isn't working? Is request being made? inspect it in browser dev tools network and see what is sent is what you expect, status etc
            – charlietfl
            Nov 19 at 22:50










          • i add before: contentType: 'text/plain', haha :)
            – Michal Robak
            Nov 19 at 22:51


















          • What exactly isn't working? Is request being made? inspect it in browser dev tools network and see what is sent is what you expect, status etc
            – charlietfl
            Nov 19 at 22:50










          • i add before: contentType: 'text/plain', haha :)
            – Michal Robak
            Nov 19 at 22:51
















          What exactly isn't working? Is request being made? inspect it in browser dev tools network and see what is sent is what you expect, status etc
          – charlietfl
          Nov 19 at 22:50




          What exactly isn't working? Is request being made? inspect it in browser dev tools network and see what is sent is what you expect, status etc
          – charlietfl
          Nov 19 at 22:50












          i add before: contentType: 'text/plain', haha :)
          – Michal Robak
          Nov 19 at 22:51




          i add before: contentType: 'text/plain', haha :)
          – Michal Robak
          Nov 19 at 22:51


















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