How do I make a variable recognized in a string variable?
0
I have the following bash script
#!/bin/bash
Sunday="
'$number'apples
'$number'oranges"
Monday="
'$number'bananas"
# ... you get my drift
Wednesday="
'$number'bananas
'$number'oranges"
# ... Until Saturday
range={1..3}
function GetDay()
{
if [ $(date +%A) == "Sunday" ]; then Day=$Sunday
elif [ $(date +%A) == "Monday" ]; then Day=$Monday
elif [ $(date +%A) == "Tuesday" ]; then Day=$Tuesday
elif [ $(date +%A) == "Wednesday" ]; then Day=$Wednesday
elif [ $(date +%A) == "Thursday" ]; then Day=$Thurday
elif [ $(date +%A) == "Friday" ]; then Day=$Friday
elif [ $(date +%A) == "Saturday" ]; then Day=$Saturday
fi
}
function CountFruits()
{
for number in $range
do
GetDay
for day in $Day
do
echo $day
done
done
}
Since its Wednesday I want it to output
1 bananas
1 oranges
2 bananas
2 oranges
3 bananas
3 oranges
How do I make this script work. It seems to be having troubles recognizing my range. It outputs
'' bananas
'' oranges
If I use the range directly with for number in {1..3} instead of the variable reference for number in $range
'' bananas
'' oranges
'' bananas
'' oranges
'' bananas
'' oranges
string bash variables terminal gnu
asked Nov 21 '18 at 13:07
Bret JosephBret Joseph
3410
add a comment |
0
I have the following bash script
#!/bin/bash
Sunday="
'$number'apples
'$number'oranges"
Monday="
'$number'bananas"
# ... you get my drift
Wednesday="
'$number'bananas
'$number'oranges"
# ... Until Saturday
range={1..3}
function GetDay()
{
if [ $(date +%A) == "Sunday" ]; then Day=$Sunday
elif [ $(date +%A) == "Monday" ]; then Day=$Monday
elif [ $(date +%A) == "Tuesday" ]; then Day=$Tuesday
elif [ $(date +%A) == "Wednesday" ]; then Day=$Wednesday
elif [ $(date +%A) == "Thursday" ]; then Day=$Thurday
elif [ $(date +%A) == "Friday" ]; then Day=$Friday
elif [ $(date +%A) == "Saturday" ]; then Day=$Saturday
fi
}
function CountFruits()
{
for number in $range
do
GetDay
for day in $Day
do
echo $day
done
done
}
Since its Wednesday I want it to output
1 bananas
1 oranges
2 bananas
2 oranges
3 bananas
3 oranges
How do I make this script work. It seems to be having troubles recognizing my range. It outputs
'' bananas
'' oranges
If I use the range directly with for number in {1..3} instead of the variable reference for number in $range
'' bananas
'' oranges
'' bananas
'' oranges
'' bananas
'' oranges
string bash variables terminal gnu
asked Nov 21 '18 at 13:07
Bret JosephBret Joseph
3410
2
You'll be more likely to get a response if you create a minimum viable concrete example of your question instead of posting your entire script. Also, try pasting your code into shellcheck.net to get some automatic suggestions of fixes.
– jeremysprofile
Nov 21 '18 at 14:06
@jeremysprofile actually I had tried to simplify my script. The real script is different from this. Here I was trying to represent my script. Thanks for the suggestion and I will check out the website
– Bret Joseph
Nov 22 '18 at 15:11
add a comment |
0
0
0
I have the following bash script
#!/bin/bash
Sunday="
'$number'apples
'$number'oranges"
Monday="
'$number'bananas"
# ... you get my drift
Wednesday="
'$number'bananas
'$number'oranges"
# ... Until Saturday
range={1..3}
function GetDay()
{
if [ $(date +%A) == "Sunday" ]; then Day=$Sunday
elif [ $(date +%A) == "Monday" ]; then Day=$Monday
elif [ $(date +%A) == "Tuesday" ]; then Day=$Tuesday
elif [ $(date +%A) == "Wednesday" ]; then Day=$Wednesday
elif [ $(date +%A) == "Thursday" ]; then Day=$Thurday
elif [ $(date +%A) == "Friday" ]; then Day=$Friday
elif [ $(date +%A) == "Saturday" ]; then Day=$Saturday
fi
}
function CountFruits()
{
for number in $range
do
GetDay
for day in $Day
do
echo $day
done
done
}
Since its Wednesday I want it to output
1 bananas
1 oranges
2 bananas
2 oranges
3 bananas
3 oranges
How do I make this script work. It seems to be having troubles recognizing my range. It outputs
'' bananas
'' oranges
If I use the range directly with for number in {1..3} instead of the variable reference for number in $range
'' bananas
'' oranges
'' bananas
'' oranges
'' bananas
'' oranges
string bash variables terminal gnu
asked Nov 21 '18 at 13:07
Bret JosephBret Joseph
3410
I have the following bash script
#!/bin/bash
Sunday="
'$number'apples
'$number'oranges"
Monday="
'$number'bananas"
# ... you get my drift
Wednesday="
'$number'bananas
'$number'oranges"
# ... Until Saturday
range={1..3}
function GetDay()
{
if [ $(date +%A) == "Sunday" ]; then Day=$Sunday
elif [ $(date +%A) == "Monday" ]; then Day=$Monday
elif [ $(date +%A) == "Tuesday" ]; then Day=$Tuesday
elif [ $(date +%A) == "Wednesday" ]; then Day=$Wednesday
elif [ $(date +%A) == "Thursday" ]; then Day=$Thurday
elif [ $(date +%A) == "Friday" ]; then Day=$Friday
elif [ $(date +%A) == "Saturday" ]; then Day=$Saturday
fi
}
function CountFruits()
{
for number in $range
do
GetDay
for day in $Day
do
echo $day
done
done
}
Since its Wednesday I want it to output
1 bananas
1 oranges
2 bananas
2 oranges
3 bananas
3 oranges
How do I make this script work. It seems to be having troubles recognizing my range. It outputs
'' bananas
'' oranges
If I use the range directly with for number in {1..3} instead of the variable reference for number in $range
'' bananas
'' oranges
'' bananas
'' oranges
'' bananas
'' oranges
string bash variables terminal gnu
string bash variables terminal gnu
asked Nov 21 '18 at 13:07
Bret JosephBret Joseph
3410
asked Nov 21 '18 at 13:07
Bret JosephBret Joseph
3410
asked Nov 21 '18 at 13:07
Bret JosephBret Joseph
3410
asked Nov 21 '18 at 13:07
Bret JosephBret Joseph
3410
asked Nov 21 '18 at 13:07
Bret JosephBret Joseph
3410
3410
2
You'll be more likely to get a response if you create a minimum viable concrete example of your question instead of posting your entire script. Also, try pasting your code into shellcheck.net to get some automatic suggestions of fixes.
– jeremysprofile
Nov 21 '18 at 14:06
@jeremysprofile actually I had tried to simplify my script. The real script is different from this. Here I was trying to represent my script. Thanks for the suggestion and I will check out the website
– Bret Joseph
Nov 22 '18 at 15:11
add a comment |
2
You'll be more likely to get a response if you create a minimum viable concrete example of your question instead of posting your entire script. Also, try pasting your code into shellcheck.net to get some automatic suggestions of fixes.
– jeremysprofile
Nov 21 '18 at 14:06
@jeremysprofile actually I had tried to simplify my script. The real script is different from this. Here I was trying to represent my script. Thanks for the suggestion and I will check out the website
– Bret Joseph
Nov 22 '18 at 15:11
2
2
You'll be more likely to get a response if you create a minimum viable concrete example of your question instead of posting your entire script. Also, try pasting your code into shellcheck.net to get some automatic suggestions of fixes.
– jeremysprofile
Nov 21 '18 at 14:06
You'll be more likely to get a response if you create a minimum viable concrete example of your question instead of posting your entire script. Also, try pasting your code into shellcheck.net to get some automatic suggestions of fixes.
– jeremysprofile
Nov 21 '18 at 14:06
@jeremysprofile actually I had tried to simplify my script. The real script is different from this. Here I was trying to represent my script. Thanks for the suggestion and I will check out the website
– Bret Joseph
Nov 22 '18 at 15:11
@jeremysprofile actually I had tried to simplify my script. The real script is different from this. Here I was trying to represent my script. Thanks for the suggestion and I will check out the website
– Bret Joseph
Nov 22 '18 at 15:11
add a comment |
1 Answer
1
active
oldest
votes
2
The immediate problem is that $number in each of your day variables is expanded immediately, so the value of Sunday is actually
'' apples
'' oranges
You would need to use single quotes on the outside to prevent expansion; the inner quotes are just regular characters.
However, this won't work, because the string $number inside the variable is just literal text as well; it won't be expanded with the current value of $number when $Day or $day expands.
What you need is a function:
dailyList () {
# $1 - day of the week
# $2 - a number
case $1 in
Sunday) fruits=(apples oranges) ;;
Monday) fruits=(bananas) ;;
# etc
esac
for f in "${fruits[@]}"; do
printf '%d %s' "$2" "$f"
done
}
Then, call that from your loop:
CountFruits () {
for number in "$@"
do
dailyList "$(date +%A)" "$number"
done
}
CountFruits {1..3}
answered Nov 21 '18 at 14:07
chepnerchepner
246k32233325
I love the way you put the code. The only problem with this would be that I actually wanted the code to be likefruits=('x' apples), in case I want to append the x in an array, like iffruits=('x' apples and 'x' oranges). Like you said if I put quotes it will make'x' apples and 'x' oranges'text which was my problem. So it seems there is no way around not making the array string text without using quotes
– Bret Joseph
Nov 21 '18 at 15:42
That's different from what you asked for in the question. Would updating the call toprintfbe sufficient?
– chepner
Nov 21 '18 at 17:30
add a comment |
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1 Answer
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oldest
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1 Answer
1
active
oldest
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active
oldest
votes
active
oldest
votes
2
The immediate problem is that $number in each of your day variables is expanded immediately, so the value of Sunday is actually
'' apples
'' oranges
You would need to use single quotes on the outside to prevent expansion; the inner quotes are just regular characters.
However, this won't work, because the string $number inside the variable is just literal text as well; it won't be expanded with the current value of $number when $Day or $day expands.
What you need is a function:
dailyList () {
# $1 - day of the week
# $2 - a number
case $1 in
Sunday) fruits=(apples oranges) ;;
Monday) fruits=(bananas) ;;
# etc
esac
for f in "${fruits[@]}"; do
printf '%d %s' "$2" "$f"
done
}
Then, call that from your loop:
CountFruits () {
for number in "$@"
do
dailyList "$(date +%A)" "$number"
done
}
CountFruits {1..3}
answered Nov 21 '18 at 14:07
chepnerchepner
246k32233325
I love the way you put the code. The only problem with this would be that I actually wanted the code to be likefruits=('x' apples), in case I want to append the x in an array, like iffruits=('x' apples and 'x' oranges). Like you said if I put quotes it will make'x' apples and 'x' oranges'text which was my problem. So it seems there is no way around not making the array string text without using quotes
– Bret Joseph
Nov 21 '18 at 15:42
That's different from what you asked for in the question. Would updating the call toprintfbe sufficient?
– chepner
Nov 21 '18 at 17:30
add a comment |
2
The immediate problem is that $number in each of your day variables is expanded immediately, so the value of Sunday is actually
'' apples
'' oranges
You would need to use single quotes on the outside to prevent expansion; the inner quotes are just regular characters.
However, this won't work, because the string $number inside the variable is just literal text as well; it won't be expanded with the current value of $number when $Day or $day expands.
What you need is a function:
dailyList () {
# $1 - day of the week
# $2 - a number
case $1 in
Sunday) fruits=(apples oranges) ;;
Monday) fruits=(bananas) ;;
# etc
esac
for f in "${fruits[@]}"; do
printf '%d %s' "$2" "$f"
done
}
Then, call that from your loop:
CountFruits () {
for number in "$@"
do
dailyList "$(date +%A)" "$number"
done
}
CountFruits {1..3}
answered Nov 21 '18 at 14:07
chepnerchepner
246k32233325
I love the way you put the code. The only problem with this would be that I actually wanted the code to be likefruits=('x' apples), in case I want to append the x in an array, like iffruits=('x' apples and 'x' oranges). Like you said if I put quotes it will make'x' apples and 'x' oranges'text which was my problem. So it seems there is no way around not making the array string text without using quotes
– Bret Joseph
Nov 21 '18 at 15:42
That's different from what you asked for in the question. Would updating the call toprintfbe sufficient?
– chepner
Nov 21 '18 at 17:30
add a comment |
2
2
2
The immediate problem is that $number in each of your day variables is expanded immediately, so the value of Sunday is actually
'' apples
'' oranges
You would need to use single quotes on the outside to prevent expansion; the inner quotes are just regular characters.
However, this won't work, because the string $number inside the variable is just literal text as well; it won't be expanded with the current value of $number when $Day or $day expands.
What you need is a function:
dailyList () {
# $1 - day of the week
# $2 - a number
case $1 in
Sunday) fruits=(apples oranges) ;;
Monday) fruits=(bananas) ;;
# etc
esac
for f in "${fruits[@]}"; do
printf '%d %s' "$2" "$f"
done
}
Then, call that from your loop:
CountFruits () {
for number in "$@"
do
dailyList "$(date +%A)" "$number"
done
}
CountFruits {1..3}
answered Nov 21 '18 at 14:07
chepnerchepner
246k32233325
The immediate problem is that $number in each of your day variables is expanded immediately, so the value of Sunday is actually
'' apples
'' oranges
You would need to use single quotes on the outside to prevent expansion; the inner quotes are just regular characters.
However, this won't work, because the string $number inside the variable is just literal text as well; it won't be expanded with the current value of $number when $Day or $day expands.
What you need is a function:
dailyList () {
# $1 - day of the week
# $2 - a number
case $1 in
Sunday) fruits=(apples oranges) ;;
Monday) fruits=(bananas) ;;
# etc
esac
for f in "${fruits[@]}"; do
printf '%d %s' "$2" "$f"
done
}
Then, call that from your loop:
CountFruits () {
for number in "$@"
do
dailyList "$(date +%A)" "$number"
done
}
CountFruits {1..3}
answered Nov 21 '18 at 14:07
chepnerchepner
246k32233325
answered Nov 21 '18 at 14:07
chepnerchepner
246k32233325
answered Nov 21 '18 at 14:07
chepnerchepner
246k32233325
answered Nov 21 '18 at 14:07
chepnerchepner
246k32233325
246k32233325
I love the way you put the code. The only problem with this would be that I actually wanted the code to be likefruits=('x' apples), in case I want to append the x in an array, like iffruits=('x' apples and 'x' oranges). Like you said if I put quotes it will make'x' apples and 'x' oranges'text which was my problem. So it seems there is no way around not making the array string text without using quotes
– Bret Joseph
Nov 21 '18 at 15:42
That's different from what you asked for in the question. Would updating the call toprintfbe sufficient?
– chepner
Nov 21 '18 at 17:30
add a comment |
I love the way you put the code. The only problem with this would be that I actually wanted the code to be likefruits=('x' apples), in case I want to append the x in an array, like iffruits=('x' apples and 'x' oranges). Like you said if I put quotes it will make'x' apples and 'x' oranges'text which was my problem. So it seems there is no way around not making the array string text without using quotes
– Bret Joseph
Nov 21 '18 at 15:42
That's different from what you asked for in the question. Would updating the call toprintfbe sufficient?
– chepner
Nov 21 '18 at 17:30
I love the way you put the code. The only problem with this would be that I actually wanted the code to be like
fruits=('x' apples), in case I want to append the x in an array, like if fruits=('x' apples and 'x' oranges). Like you said if I put quotes it will make 'x' apples and 'x' oranges' text which was my problem. So it seems there is no way around not making the array string text without using quotes– Bret Joseph
Nov 21 '18 at 15:42
I love the way you put the code. The only problem with this would be that I actually wanted the code to be like
fruits=('x' apples), in case I want to append the x in an array, like if fruits=('x' apples and 'x' oranges). Like you said if I put quotes it will make 'x' apples and 'x' oranges' text which was my problem. So it seems there is no way around not making the array string text without using quotes– Bret Joseph
Nov 21 '18 at 15:42
That's different from what you asked for in the question. Would updating the call to
printf be sufficient?– chepner
Nov 21 '18 at 17:30
That's different from what you asked for in the question. Would updating the call to
printf be sufficient?– chepner
Nov 21 '18 at 17:30
add a comment |
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2
You'll be more likely to get a response if you create a minimum viable concrete example of your question instead of posting your entire script. Also, try pasting your code into shellcheck.net to get some automatic suggestions of fixes.
– jeremysprofile
Nov 21 '18 at 14:06
@jeremysprofile actually I had tried to simplify my script. The real script is different from this. Here I was trying to represent my script. Thanks for the suggestion and I will check out the website
– Bret Joseph
Nov 22 '18 at 15:11