Select-Object append after variable












0















I have weird behavior.
This line works just fine (output => te001): 



Get-Content $SourceTxtDbFile | ConvertFrom-String -Delimiter "_" -PropertyNames DbVersion, ScriptNumber | Where-Object {$_.DbVersion -eq "1.2.0.0"} | Select-Object {"te"+$_.ScriptNumber }


but I need to be after the $_ variable so this doesn't work (blank output):



Get-Content $SourceTxtDbFile | ConvertFrom-String -Delimiter "_" -PropertyNames DbVersion, ScriptNumber | Where-Object {$_.DbVersion -eq "1.2.0.0"} | Select-Object {$_.ScriptNumber + "te"}


Why?






powershell







share|improve this question























  • Is there an object named 001te (taking your example) present?

    – TobyU
    Nov 22 '18 at 13:25











  • No there is not...

    – Stefan0309
    Nov 22 '18 at 13:29











  • Then how should that possible work? What do you want to achieve at the end?

    – TobyU
    Nov 22 '18 at 13:29











  • Well, I have Get-Content that reads the file. I am doing here a split by '_' and I am asking Where-Object {$_DbVersion -eq "1.2.0.0"} select those objects..those lines..It perfectly works without appended string at the end..

    – Stefan0309
    Nov 22 '18 at 13:33











  • I just think that it isnt right concatenation at the end as it at the begging..maybe I need to put some escape char or something..

    – Stefan0309
    Nov 22 '18 at 13:35
















0















I have weird behavior.
This line works just fine (output => te001): 



Get-Content $SourceTxtDbFile | ConvertFrom-String -Delimiter "_" -PropertyNames DbVersion, ScriptNumber | Where-Object {$_.DbVersion -eq "1.2.0.0"} | Select-Object {"te"+$_.ScriptNumber }


but I need to be after the $_ variable so this doesn't work (blank output):



Get-Content $SourceTxtDbFile | ConvertFrom-String -Delimiter "_" -PropertyNames DbVersion, ScriptNumber | Where-Object {$_.DbVersion -eq "1.2.0.0"} | Select-Object {$_.ScriptNumber + "te"}


Why?






powershell







share|improve this question























  • Is there an object named 001te (taking your example) present?

    – TobyU
    Nov 22 '18 at 13:25











  • No there is not...

    – Stefan0309
    Nov 22 '18 at 13:29











  • Then how should that possible work? What do you want to achieve at the end?

    – TobyU
    Nov 22 '18 at 13:29











  • Well, I have Get-Content that reads the file. I am doing here a split by '_' and I am asking Where-Object {$_DbVersion -eq "1.2.0.0"} select those objects..those lines..It perfectly works without appended string at the end..

    – Stefan0309
    Nov 22 '18 at 13:33











  • I just think that it isnt right concatenation at the end as it at the begging..maybe I need to put some escape char or something..

    – Stefan0309
    Nov 22 '18 at 13:35














0












0








0








I have weird behavior.
This line works just fine (output => te001): 



Get-Content $SourceTxtDbFile | ConvertFrom-String -Delimiter "_" -PropertyNames DbVersion, ScriptNumber | Where-Object {$_.DbVersion -eq "1.2.0.0"} | Select-Object {"te"+$_.ScriptNumber }


but I need to be after the $_ variable so this doesn't work (blank output):



Get-Content $SourceTxtDbFile | ConvertFrom-String -Delimiter "_" -PropertyNames DbVersion, ScriptNumber | Where-Object {$_.DbVersion -eq "1.2.0.0"} | Select-Object {$_.ScriptNumber + "te"}


Why?






powershell







share|improve this question














I have weird behavior.
This line works just fine (output => te001): 



Get-Content $SourceTxtDbFile | ConvertFrom-String -Delimiter "_" -PropertyNames DbVersion, ScriptNumber | Where-Object {$_.DbVersion -eq "1.2.0.0"} | Select-Object {"te"+$_.ScriptNumber }


but I need to be after the $_ variable so this doesn't work (blank output):



Get-Content $SourceTxtDbFile | ConvertFrom-String -Delimiter "_" -PropertyNames DbVersion, ScriptNumber | Where-Object {$_.DbVersion -eq "1.2.0.0"} | Select-Object {$_.ScriptNumber + "te"}


Why?






powershell




powershell






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 22 '18 at 13:22









Stefan0309Stefan0309

363425




363425













  • Is there an object named 001te (taking your example) present?

    – TobyU
    Nov 22 '18 at 13:25











  • No there is not...

    – Stefan0309
    Nov 22 '18 at 13:29











  • Then how should that possible work? What do you want to achieve at the end?

    – TobyU
    Nov 22 '18 at 13:29











  • Well, I have Get-Content that reads the file. I am doing here a split by '_' and I am asking Where-Object {$_DbVersion -eq "1.2.0.0"} select those objects..those lines..It perfectly works without appended string at the end..

    – Stefan0309
    Nov 22 '18 at 13:33











  • I just think that it isnt right concatenation at the end as it at the begging..maybe I need to put some escape char or something..

    – Stefan0309
    Nov 22 '18 at 13:35



















  • Is there an object named 001te (taking your example) present?

    – TobyU
    Nov 22 '18 at 13:25











  • No there is not...

    – Stefan0309
    Nov 22 '18 at 13:29











  • Then how should that possible work? What do you want to achieve at the end?

    – TobyU
    Nov 22 '18 at 13:29











  • Well, I have Get-Content that reads the file. I am doing here a split by '_' and I am asking Where-Object {$_DbVersion -eq "1.2.0.0"} select those objects..those lines..It perfectly works without appended string at the end..

    – Stefan0309
    Nov 22 '18 at 13:33











  • I just think that it isnt right concatenation at the end as it at the begging..maybe I need to put some escape char or something..

    – Stefan0309
    Nov 22 '18 at 13:35

















Is there an object named 001te (taking your example) present?

– TobyU
Nov 22 '18 at 13:25





Is there an object named 001te (taking your example) present?

– TobyU
Nov 22 '18 at 13:25













No there is not...

– Stefan0309
Nov 22 '18 at 13:29





No there is not...

– Stefan0309
Nov 22 '18 at 13:29













Then how should that possible work? What do you want to achieve at the end?

– TobyU
Nov 22 '18 at 13:29





Then how should that possible work? What do you want to achieve at the end?

– TobyU
Nov 22 '18 at 13:29













Well, I have Get-Content that reads the file. I am doing here a split by '_' and I am asking Where-Object {$_DbVersion -eq "1.2.0.0"} select those objects..those lines..It perfectly works without appended string at the end..

– Stefan0309
Nov 22 '18 at 13:33





Well, I have Get-Content that reads the file. I am doing here a split by '_' and I am asking Where-Object {$_DbVersion -eq "1.2.0.0"} select those objects..those lines..It perfectly works without appended string at the end..

– Stefan0309
Nov 22 '18 at 13:33













I just think that it isnt right concatenation at the end as it at the begging..maybe I need to put some escape char or something..

– Stefan0309
Nov 22 '18 at 13:35





I just think that it isnt right concatenation at the end as it at the begging..maybe I need to put some escape char or something..

– Stefan0309
Nov 22 '18 at 13:35












1 Answer
1






active

oldest

votes


















1














Change



$_.ScriptNumber + "te"


to



"$($_.ScriptNumber)te"


so that $_.ScriptNumber is used as a string instead of an integer






share|improve this answer


























  • @TobyU I rushed to give you a vote up, but I ahve Invalid parameters in my output. Just saying Invalid parameters CHANGE {LOGON | PORT | USER} I dont know what is that..

    – Stefan0309
    Nov 22 '18 at 14:18











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














Change



$_.ScriptNumber + "te"


to



"$($_.ScriptNumber)te"


so that $_.ScriptNumber is used as a string instead of an integer






share|improve this answer


























  • @TobyU I rushed to give you a vote up, but I ahve Invalid parameters in my output. Just saying Invalid parameters CHANGE {LOGON | PORT | USER} I dont know what is that..

    – Stefan0309
    Nov 22 '18 at 14:18
















1














Change



$_.ScriptNumber + "te"


to



"$($_.ScriptNumber)te"


so that $_.ScriptNumber is used as a string instead of an integer






share|improve this answer


























  • @TobyU I rushed to give you a vote up, but I ahve Invalid parameters in my output. Just saying Invalid parameters CHANGE {LOGON | PORT | USER} I dont know what is that..

    – Stefan0309
    Nov 22 '18 at 14:18














1












1








1







Change



$_.ScriptNumber + "te"


to



"$($_.ScriptNumber)te"


so that $_.ScriptNumber is used as a string instead of an integer






share|improve this answer















Change



$_.ScriptNumber + "te"


to



"$($_.ScriptNumber)te"


so that $_.ScriptNumber is used as a string instead of an integer







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 22 '18 at 14:17

























answered Nov 22 '18 at 13:42









TobyUTobyU

2,3031921




2,3031921













  • @TobyU I rushed to give you a vote up, but I ahve Invalid parameters in my output. Just saying Invalid parameters CHANGE {LOGON | PORT | USER} I dont know what is that..

    – Stefan0309
    Nov 22 '18 at 14:18



















  • @TobyU I rushed to give you a vote up, but I ahve Invalid parameters in my output. Just saying Invalid parameters CHANGE {LOGON | PORT | USER} I dont know what is that..

    – Stefan0309
    Nov 22 '18 at 14:18

















@TobyU I rushed to give you a vote up, but I ahve Invalid parameters in my output. Just saying Invalid parameters CHANGE {LOGON | PORT | USER} I dont know what is that..

– Stefan0309
Nov 22 '18 at 14:18





@TobyU I rushed to give you a vote up, but I ahve Invalid parameters in my output. Just saying Invalid parameters CHANGE {LOGON | PORT | USER} I dont know what is that..

– Stefan0309
Nov 22 '18 at 14:18


















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