Create new bounded number data types in Haskell
0
I need to create a data type, that represents only the real numbers between 0 and 1. How would i go about that? Expected Behavior:
0 :: DataType ===> DataType 0
(-1) :: DataType ===> Error
haskell types numbers
edited Nov 22 '18 at 15:13
chi
74.1k284140
asked Nov 22 '18 at 14:27
AgilixAgilix
11711
|
show 1 more comment
0
I need to create a data type, that represents only the real numbers between 0 and 1. How would i go about that? Expected Behavior:
0 :: DataType ===> DataType 0
(-1) :: DataType ===> Error
haskell types numbers
edited Nov 22 '18 at 15:13
chi
74.1k284140
asked Nov 22 '18 at 14:27
AgilixAgilix
11711
6
You could write aninstance Num DataTypeand definefromIntegerso that it errors out on invalid values. I'm not sure if that's a good idea, but it's the only way to achieve your goal.
– chi
Nov 22 '18 at 14:38
@chi I actually suspect a transcription error there, given that it's ascribing function types to literals. Not impossible, but I suspect that it's actually about creating a function to behave in such a way.
– Carl
Nov 22 '18 at 14:50
@Carl I'm pretty sure the above->represents "evaluates to", not function arrow. My comment assumed that interpretation, otherwise the question makes no sense. I'm now replacing them with==>to avoid confusion.
– chi
Nov 22 '18 at 15:12
1
Beyondinstance Num DataType, for real numbers we would also needinstance Fractional DataType, and define a partialfromRationalto reject invalid numbers.
– chi
Nov 22 '18 at 15:16
1
Have you considered using smart constructors. Might by a good idea here. wiki.haskell.org/Smart_constructors
– Luis Morillo
Nov 23 '18 at 8:49
|
show 1 more comment
0
0
0
I need to create a data type, that represents only the real numbers between 0 and 1. How would i go about that? Expected Behavior:
0 :: DataType ===> DataType 0
(-1) :: DataType ===> Error
haskell types numbers
edited Nov 22 '18 at 15:13
chi
74.1k284140
asked Nov 22 '18 at 14:27
AgilixAgilix
11711
I need to create a data type, that represents only the real numbers between 0 and 1. How would i go about that? Expected Behavior:
0 :: DataType ===> DataType 0
(-1) :: DataType ===> Error
haskell types numbers
haskell types numbers
edited Nov 22 '18 at 15:13
chi
74.1k284140
asked Nov 22 '18 at 14:27
AgilixAgilix
11711
edited Nov 22 '18 at 15:13
chi
74.1k284140
asked Nov 22 '18 at 14:27
AgilixAgilix
11711
edited Nov 22 '18 at 15:13
chi
74.1k284140
edited Nov 22 '18 at 15:13
chi
74.1k284140
edited Nov 22 '18 at 15:13
chi
74.1k284140
74.1k284140
asked Nov 22 '18 at 14:27
AgilixAgilix
11711
asked Nov 22 '18 at 14:27
AgilixAgilix
11711
asked Nov 22 '18 at 14:27
AgilixAgilix
11711
11711
6
You could write aninstance Num DataTypeand definefromIntegerso that it errors out on invalid values. I'm not sure if that's a good idea, but it's the only way to achieve your goal.
– chi
Nov 22 '18 at 14:38
@chi I actually suspect a transcription error there, given that it's ascribing function types to literals. Not impossible, but I suspect that it's actually about creating a function to behave in such a way.
– Carl
Nov 22 '18 at 14:50
@Carl I'm pretty sure the above->represents "evaluates to", not function arrow. My comment assumed that interpretation, otherwise the question makes no sense. I'm now replacing them with==>to avoid confusion.
– chi
Nov 22 '18 at 15:12
1
Beyondinstance Num DataType, for real numbers we would also needinstance Fractional DataType, and define a partialfromRationalto reject invalid numbers.
– chi
Nov 22 '18 at 15:16
1
Have you considered using smart constructors. Might by a good idea here. wiki.haskell.org/Smart_constructors
– Luis Morillo
Nov 23 '18 at 8:49
|
show 1 more comment
6
You could write aninstance Num DataTypeand definefromIntegerso that it errors out on invalid values. I'm not sure if that's a good idea, but it's the only way to achieve your goal.
– chi
Nov 22 '18 at 14:38
@chi I actually suspect a transcription error there, given that it's ascribing function types to literals. Not impossible, but I suspect that it's actually about creating a function to behave in such a way.
– Carl
Nov 22 '18 at 14:50
@Carl I'm pretty sure the above->represents "evaluates to", not function arrow. My comment assumed that interpretation, otherwise the question makes no sense. I'm now replacing them with==>to avoid confusion.
– chi
Nov 22 '18 at 15:12
1
Beyondinstance Num DataType, for real numbers we would also needinstance Fractional DataType, and define a partialfromRationalto reject invalid numbers.
– chi
Nov 22 '18 at 15:16
1
Have you considered using smart constructors. Might by a good idea here. wiki.haskell.org/Smart_constructors
– Luis Morillo
Nov 23 '18 at 8:49
6
6
You could write an
instance Num DataType and define fromInteger so that it errors out on invalid values. I'm not sure if that's a good idea, but it's the only way to achieve your goal.– chi
Nov 22 '18 at 14:38
You could write an
instance Num DataType and define fromInteger so that it errors out on invalid values. I'm not sure if that's a good idea, but it's the only way to achieve your goal.– chi
Nov 22 '18 at 14:38
@chi I actually suspect a transcription error there, given that it's ascribing function types to literals. Not impossible, but I suspect that it's actually about creating a function to behave in such a way.
– Carl
Nov 22 '18 at 14:50
@chi I actually suspect a transcription error there, given that it's ascribing function types to literals. Not impossible, but I suspect that it's actually about creating a function to behave in such a way.
– Carl
Nov 22 '18 at 14:50
@Carl I'm pretty sure the above
-> represents "evaluates to", not function arrow. My comment assumed that interpretation, otherwise the question makes no sense. I'm now replacing them with ==> to avoid confusion.– chi
Nov 22 '18 at 15:12
@Carl I'm pretty sure the above
-> represents "evaluates to", not function arrow. My comment assumed that interpretation, otherwise the question makes no sense. I'm now replacing them with ==> to avoid confusion.– chi
Nov 22 '18 at 15:12
1
1
Beyond
instance Num DataType, for real numbers we would also need instance Fractional DataType, and define a partial fromRational to reject invalid numbers.– chi
Nov 22 '18 at 15:16
Beyond
instance Num DataType, for real numbers we would also need instance Fractional DataType, and define a partial fromRational to reject invalid numbers.– chi
Nov 22 '18 at 15:16
1
1
Have you considered using smart constructors. Might by a good idea here. wiki.haskell.org/Smart_constructors
– Luis Morillo
Nov 23 '18 at 8:49
Have you considered using smart constructors. Might by a good idea here. wiki.haskell.org/Smart_constructors
– Luis Morillo
Nov 23 '18 at 8:49
|
show 1 more comment
0
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6
You could write an
instance Num DataTypeand definefromIntegerso that it errors out on invalid values. I'm not sure if that's a good idea, but it's the only way to achieve your goal.– chi
Nov 22 '18 at 14:38
@chi I actually suspect a transcription error there, given that it's ascribing function types to literals. Not impossible, but I suspect that it's actually about creating a function to behave in such a way.
– Carl
Nov 22 '18 at 14:50
@Carl I'm pretty sure the above
->represents "evaluates to", not function arrow. My comment assumed that interpretation, otherwise the question makes no sense. I'm now replacing them with==>to avoid confusion.– chi
Nov 22 '18 at 15:12
1
Beyond
instance Num DataType, for real numbers we would also needinstance Fractional DataType, and define a partialfromRationalto reject invalid numbers.– chi
Nov 22 '18 at 15:16
1
Have you considered using smart constructors. Might by a good idea here. wiki.haskell.org/Smart_constructors
– Luis Morillo
Nov 23 '18 at 8:49