Sending output to a dictionary
I'm just a beginner at this but was looking for some help. I'm trying to make a spot it game and I have a card generator (taken from: https://math.stackexchange.com/questions/1303497/what-is-the-algorithm-to-generate-the-cards-in-the-game-dobble-known-as-spo)
Im trying to send the print output to a dictionary where the card number is the key and the generated card ids are listed in a set as a value.
This is what I have so far:
nIm = 4
n = nIm - 1
r = range(n)
rp1 = range(n+1)
c = 0
a=dict={}
# First card
c+=1
for i in rp1:
a['Card %2d:' %c]=(i+1)
print(a)
print()
# n following cards
for j in r:
if j not in r:
c = c+1
a['Card %2d:' %c]=(1)
print(a)
for k in r:
a['Card %2d:' %c]=(n+2 + n*j +k)
print(a)
print()
Does anyone have any ideas how I can do this?
Thanks in advance!
python
asked Nov 24 '18 at 23:12
BeginnerBeginner
1
add a comment |
I'm just a beginner at this but was looking for some help. I'm trying to make a spot it game and I have a card generator (taken from: https://math.stackexchange.com/questions/1303497/what-is-the-algorithm-to-generate-the-cards-in-the-game-dobble-known-as-spo)
Im trying to send the print output to a dictionary where the card number is the key and the generated card ids are listed in a set as a value.
This is what I have so far:
nIm = 4
n = nIm - 1
r = range(n)
rp1 = range(n+1)
c = 0
a=dict={}
# First card
c+=1
for i in rp1:
a['Card %2d:' %c]=(i+1)
print(a)
print()
# n following cards
for j in r:
if j not in r:
c = c+1
a['Card %2d:' %c]=(1)
print(a)
for k in r:
a['Card %2d:' %c]=(n+2 + n*j +k)
print(a)
print()
Does anyone have any ideas how I can do this?
Thanks in advance!
python
asked Nov 24 '18 at 23:12
BeginnerBeginner
1
add a comment |
I'm just a beginner at this but was looking for some help. I'm trying to make a spot it game and I have a card generator (taken from: https://math.stackexchange.com/questions/1303497/what-is-the-algorithm-to-generate-the-cards-in-the-game-dobble-known-as-spo)
Im trying to send the print output to a dictionary where the card number is the key and the generated card ids are listed in a set as a value.
This is what I have so far:
nIm = 4
n = nIm - 1
r = range(n)
rp1 = range(n+1)
c = 0
a=dict={}
# First card
c+=1
for i in rp1:
a['Card %2d:' %c]=(i+1)
print(a)
print()
# n following cards
for j in r:
if j not in r:
c = c+1
a['Card %2d:' %c]=(1)
print(a)
for k in r:
a['Card %2d:' %c]=(n+2 + n*j +k)
print(a)
print()
Does anyone have any ideas how I can do this?
Thanks in advance!
python
asked Nov 24 '18 at 23:12
BeginnerBeginner
1
I'm just a beginner at this but was looking for some help. I'm trying to make a spot it game and I have a card generator (taken from: https://math.stackexchange.com/questions/1303497/what-is-the-algorithm-to-generate-the-cards-in-the-game-dobble-known-as-spo)
Im trying to send the print output to a dictionary where the card number is the key and the generated card ids are listed in a set as a value.
This is what I have so far:
nIm = 4
n = nIm - 1
r = range(n)
rp1 = range(n+1)
c = 0
a=dict={}
# First card
c+=1
for i in rp1:
a['Card %2d:' %c]=(i+1)
print(a)
print()
# n following cards
for j in r:
if j not in r:
c = c+1
a['Card %2d:' %c]=(1)
print(a)
for k in r:
a['Card %2d:' %c]=(n+2 + n*j +k)
print(a)
print()
Does anyone have any ideas how I can do this?
Thanks in advance!
python
python
asked Nov 24 '18 at 23:12
BeginnerBeginner
1
asked Nov 24 '18 at 23:12
BeginnerBeginner
1
asked Nov 24 '18 at 23:12
BeginnerBeginner
1
asked Nov 24 '18 at 23:12
BeginnerBeginner
1
asked Nov 24 '18 at 23:12
BeginnerBeginner
1
1
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
I looks like you are setting the key/value pairs to your dict ok with statements like:
a['Card %2d:' %c]=(i+1)
and
a['Card %2d:' %c]=(n+2 + n*j +k)
I do not see the ids you mention. Assuming your ids are in a list called ids you could add them to your dict like so:
a['ids'] = ids
Here's what a would look like afterwards.
print(a) # {'Card 2:': 4, 'ids': [1, 2, 3, 4, 5]}
This assumes ids = [1,2,3,4,5].
answered Nov 24 '18 at 23:17
Red CricketRed Cricket
4,511103386
add a comment |
You're pretty close to it. For each card, you first need to create an empty set as a value within the dict, and then call the set's "add" method to add each id to the set.
# First card
c+=1
a['Card %2d:' %c] = set()
for i in rp1:
a['Card %2d:' %c].add(i+1)
print(a)
print()
# n following cards
for j in r:
if j not in r:
c = c+1
a['Card %2d:' %c] = {1}
print(a)
for k in r:
a['Card %2d:' %c].add(n+2 + n*j +k)
print(a)
print()
Also, at the beginning where you have "a=dict={}", you can just say either
a = {}
or
a = dict()
Looks good! Later on you might take a look at "defaultdict" in the collections module which you could use to automatically create an empty set (or other kind of value) as a default value when the key doesn't exist yet in the dictionary. But what you have works fine.
answered Nov 24 '18 at 23:54
ehaymoreehaymore
1874
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
I looks like you are setting the key/value pairs to your dict ok with statements like:
a['Card %2d:' %c]=(i+1)
and
a['Card %2d:' %c]=(n+2 + n*j +k)
I do not see the ids you mention. Assuming your ids are in a list called ids you could add them to your dict like so:
a['ids'] = ids
Here's what a would look like afterwards.
print(a) # {'Card 2:': 4, 'ids': [1, 2, 3, 4, 5]}
This assumes ids = [1,2,3,4,5].
answered Nov 24 '18 at 23:17
Red CricketRed Cricket
4,511103386
add a comment |
I looks like you are setting the key/value pairs to your dict ok with statements like:
a['Card %2d:' %c]=(i+1)
and
a['Card %2d:' %c]=(n+2 + n*j +k)
I do not see the ids you mention. Assuming your ids are in a list called ids you could add them to your dict like so:
a['ids'] = ids
Here's what a would look like afterwards.
print(a) # {'Card 2:': 4, 'ids': [1, 2, 3, 4, 5]}
This assumes ids = [1,2,3,4,5].
answered Nov 24 '18 at 23:17
Red CricketRed Cricket
4,511103386
add a comment |
I looks like you are setting the key/value pairs to your dict ok with statements like:
a['Card %2d:' %c]=(i+1)
and
a['Card %2d:' %c]=(n+2 + n*j +k)
I do not see the ids you mention. Assuming your ids are in a list called ids you could add them to your dict like so:
a['ids'] = ids
Here's what a would look like afterwards.
print(a) # {'Card 2:': 4, 'ids': [1, 2, 3, 4, 5]}
This assumes ids = [1,2,3,4,5].
answered Nov 24 '18 at 23:17
Red CricketRed Cricket
4,511103386
I looks like you are setting the key/value pairs to your dict ok with statements like:
a['Card %2d:' %c]=(i+1)
and
a['Card %2d:' %c]=(n+2 + n*j +k)
I do not see the ids you mention. Assuming your ids are in a list called ids you could add them to your dict like so:
a['ids'] = ids
Here's what a would look like afterwards.
print(a) # {'Card 2:': 4, 'ids': [1, 2, 3, 4, 5]}
This assumes ids = [1,2,3,4,5].
answered Nov 24 '18 at 23:17
Red CricketRed Cricket
4,511103386
edited Nov 24 '18 at 23:27
answered Nov 24 '18 at 23:17
Red CricketRed Cricket
4,511103386
answered Nov 24 '18 at 23:17
Red CricketRed Cricket
4,511103386
answered Nov 24 '18 at 23:17
Red CricketRed Cricket
4,511103386
4,511103386
add a comment |
add a comment |
You're pretty close to it. For each card, you first need to create an empty set as a value within the dict, and then call the set's "add" method to add each id to the set.
# First card
c+=1
a['Card %2d:' %c] = set()
for i in rp1:
a['Card %2d:' %c].add(i+1)
print(a)
print()
# n following cards
for j in r:
if j not in r:
c = c+1
a['Card %2d:' %c] = {1}
print(a)
for k in r:
a['Card %2d:' %c].add(n+2 + n*j +k)
print(a)
print()
Also, at the beginning where you have "a=dict={}", you can just say either
a = {}
or
a = dict()
Looks good! Later on you might take a look at "defaultdict" in the collections module which you could use to automatically create an empty set (or other kind of value) as a default value when the key doesn't exist yet in the dictionary. But what you have works fine.
answered Nov 24 '18 at 23:54
ehaymoreehaymore
1874
add a comment |
You're pretty close to it. For each card, you first need to create an empty set as a value within the dict, and then call the set's "add" method to add each id to the set.
# First card
c+=1
a['Card %2d:' %c] = set()
for i in rp1:
a['Card %2d:' %c].add(i+1)
print(a)
print()
# n following cards
for j in r:
if j not in r:
c = c+1
a['Card %2d:' %c] = {1}
print(a)
for k in r:
a['Card %2d:' %c].add(n+2 + n*j +k)
print(a)
print()
Also, at the beginning where you have "a=dict={}", you can just say either
a = {}
or
a = dict()
Looks good! Later on you might take a look at "defaultdict" in the collections module which you could use to automatically create an empty set (or other kind of value) as a default value when the key doesn't exist yet in the dictionary. But what you have works fine.
answered Nov 24 '18 at 23:54
ehaymoreehaymore
1874
add a comment |
You're pretty close to it. For each card, you first need to create an empty set as a value within the dict, and then call the set's "add" method to add each id to the set.
# First card
c+=1
a['Card %2d:' %c] = set()
for i in rp1:
a['Card %2d:' %c].add(i+1)
print(a)
print()
# n following cards
for j in r:
if j not in r:
c = c+1
a['Card %2d:' %c] = {1}
print(a)
for k in r:
a['Card %2d:' %c].add(n+2 + n*j +k)
print(a)
print()
Also, at the beginning where you have "a=dict={}", you can just say either
a = {}
or
a = dict()
Looks good! Later on you might take a look at "defaultdict" in the collections module which you could use to automatically create an empty set (or other kind of value) as a default value when the key doesn't exist yet in the dictionary. But what you have works fine.
answered Nov 24 '18 at 23:54
ehaymoreehaymore
1874
You're pretty close to it. For each card, you first need to create an empty set as a value within the dict, and then call the set's "add" method to add each id to the set.
# First card
c+=1
a['Card %2d:' %c] = set()
for i in rp1:
a['Card %2d:' %c].add(i+1)
print(a)
print()
# n following cards
for j in r:
if j not in r:
c = c+1
a['Card %2d:' %c] = {1}
print(a)
for k in r:
a['Card %2d:' %c].add(n+2 + n*j +k)
print(a)
print()
Also, at the beginning where you have "a=dict={}", you can just say either
a = {}
or
a = dict()
Looks good! Later on you might take a look at "defaultdict" in the collections module which you could use to automatically create an empty set (or other kind of value) as a default value when the key doesn't exist yet in the dictionary. But what you have works fine.
answered Nov 24 '18 at 23:54
ehaymoreehaymore
1874
answered Nov 24 '18 at 23:54
ehaymoreehaymore
1874
answered Nov 24 '18 at 23:54
ehaymoreehaymore
1874
answered Nov 24 '18 at 23:54
ehaymoreehaymore
1874
1874
add a comment |
add a comment |
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