Rearrange array elements in cmd
2
I have an array in my batch file which looks like this:
"port[0] ="
"port[1] = 0"
"port[2] = 3"
"port[3] = 2"
Is there any nice and elegant way to move values one element back, so it'll look like this?:
"port[0] = 0"
"port[1] = 3"
"port[2] = 2"
"port[3] ="
I want something other than just SET port[0] = %port[1]%, etc?
batch-file cmd
edited Nov 24 '18 at 12:40
double-beep
2,39641027
asked Nov 23 '18 at 21:39
John DoeJohn Doe
274
add a comment |
2
I have an array in my batch file which looks like this:
"port[0] ="
"port[1] = 0"
"port[2] = 3"
"port[3] = 2"
Is there any nice and elegant way to move values one element back, so it'll look like this?:
"port[0] = 0"
"port[1] = 3"
"port[2] = 2"
"port[3] ="
I want something other than just SET port[0] = %port[1]%, etc?
batch-file cmd
edited Nov 24 '18 at 12:40
double-beep
2,39641027
asked Nov 23 '18 at 21:39
John DoeJohn Doe
274
2
don't put spaces around the equal sign...
– npocmaka
Nov 23 '18 at 21:48
2
%port[0]%would not exist because without a value it would be undefined. The same would also be true for%port[3]%after the modification.
– Compo
Nov 23 '18 at 21:59
guys thank you for pointing this out, but TBH i just showed this as an example, not the exact code =)
– John Doe
Nov 23 '18 at 22:02
add a comment |
2
2
2
I have an array in my batch file which looks like this:
"port[0] ="
"port[1] = 0"
"port[2] = 3"
"port[3] = 2"
Is there any nice and elegant way to move values one element back, so it'll look like this?:
"port[0] = 0"
"port[1] = 3"
"port[2] = 2"
"port[3] ="
I want something other than just SET port[0] = %port[1]%, etc?
batch-file cmd
edited Nov 24 '18 at 12:40
double-beep
2,39641027
asked Nov 23 '18 at 21:39
John DoeJohn Doe
274
I have an array in my batch file which looks like this:
"port[0] ="
"port[1] = 0"
"port[2] = 3"
"port[3] = 2"
Is there any nice and elegant way to move values one element back, so it'll look like this?:
"port[0] = 0"
"port[1] = 3"
"port[2] = 2"
"port[3] ="
I want something other than just SET port[0] = %port[1]%, etc?
batch-file cmd
batch-file cmd
edited Nov 24 '18 at 12:40
double-beep
2,39641027
asked Nov 23 '18 at 21:39
John DoeJohn Doe
274
edited Nov 24 '18 at 12:40
double-beep
2,39641027
asked Nov 23 '18 at 21:39
John DoeJohn Doe
274
edited Nov 24 '18 at 12:40
double-beep
2,39641027
edited Nov 24 '18 at 12:40
double-beep
2,39641027
edited Nov 24 '18 at 12:40
double-beep
2,39641027
2,39641027
asked Nov 23 '18 at 21:39
John DoeJohn Doe
274
asked Nov 23 '18 at 21:39
John DoeJohn Doe
274
asked Nov 23 '18 at 21:39
John DoeJohn Doe
274
274
2
don't put spaces around the equal sign...
– npocmaka
Nov 23 '18 at 21:48
2
%port[0]%would not exist because without a value it would be undefined. The same would also be true for%port[3]%after the modification.
– Compo
Nov 23 '18 at 21:59
guys thank you for pointing this out, but TBH i just showed this as an example, not the exact code =)
– John Doe
Nov 23 '18 at 22:02
add a comment |
2
don't put spaces around the equal sign...
– npocmaka
Nov 23 '18 at 21:48
2
%port[0]%would not exist because without a value it would be undefined. The same would also be true for%port[3]%after the modification.
– Compo
Nov 23 '18 at 21:59
guys thank you for pointing this out, but TBH i just showed this as an example, not the exact code =)
– John Doe
Nov 23 '18 at 22:02
2
2
don't put spaces around the equal sign...
– npocmaka
Nov 23 '18 at 21:48
don't put spaces around the equal sign...
– npocmaka
Nov 23 '18 at 21:48
2
2
%port[0]% would not exist because without a value it would be undefined. The same would also be true for %port[3]% after the modification.– Compo
Nov 23 '18 at 21:59
%port[0]% would not exist because without a value it would be undefined. The same would also be true for %port[3]% after the modification.– Compo
Nov 23 '18 at 21:59
guys thank you for pointing this out, but TBH i just showed this as an example, not the exact code =)
– John Doe
Nov 23 '18 at 22:02
guys thank you for pointing this out, but TBH i just showed this as an example, not the exact code =)
– John Doe
Nov 23 '18 at 22:02
add a comment |
1 Answer
1
active
oldest
votes
2
:: Q:Test20181123SO_53453204.cmd
@Echo off&SetLocal EnableDelayedExpansion
set "port[0]=" &Rem this clears/deletes the variable
set "port[1]=0"
set "port[2]=3"
set "port[3]=2"
For /L %%L in (1,1,3) do (
set /A "New=%%L-1,Last=%%L"
set "port[!New!]=!port[%%L]!"
)
:: finally reset the last entry
set "port[%Last%]="
set port[
> Q:Test20181123SO_53453204.cmd
port[0]=0
port[1]=3
port[2]=2
answered Nov 23 '18 at 22:03
LotPingsLotPings
19.2k61532
Tracking of the last element in the loop:Last=%%Lis redundant. The last element is predetermined.
– sst
Nov 24 '18 at 2:56
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
:: Q:Test20181123SO_53453204.cmd
@Echo off&SetLocal EnableDelayedExpansion
set "port[0]=" &Rem this clears/deletes the variable
set "port[1]=0"
set "port[2]=3"
set "port[3]=2"
For /L %%L in (1,1,3) do (
set /A "New=%%L-1,Last=%%L"
set "port[!New!]=!port[%%L]!"
)
:: finally reset the last entry
set "port[%Last%]="
set port[
> Q:Test20181123SO_53453204.cmd
port[0]=0
port[1]=3
port[2]=2
answered Nov 23 '18 at 22:03
LotPingsLotPings
19.2k61532
Tracking of the last element in the loop:Last=%%Lis redundant. The last element is predetermined.
– sst
Nov 24 '18 at 2:56
add a comment |
2
:: Q:Test20181123SO_53453204.cmd
@Echo off&SetLocal EnableDelayedExpansion
set "port[0]=" &Rem this clears/deletes the variable
set "port[1]=0"
set "port[2]=3"
set "port[3]=2"
For /L %%L in (1,1,3) do (
set /A "New=%%L-1,Last=%%L"
set "port[!New!]=!port[%%L]!"
)
:: finally reset the last entry
set "port[%Last%]="
set port[
> Q:Test20181123SO_53453204.cmd
port[0]=0
port[1]=3
port[2]=2
answered Nov 23 '18 at 22:03
LotPingsLotPings
19.2k61532
Tracking of the last element in the loop:Last=%%Lis redundant. The last element is predetermined.
– sst
Nov 24 '18 at 2:56
add a comment |
2
2
2
:: Q:Test20181123SO_53453204.cmd
@Echo off&SetLocal EnableDelayedExpansion
set "port[0]=" &Rem this clears/deletes the variable
set "port[1]=0"
set "port[2]=3"
set "port[3]=2"
For /L %%L in (1,1,3) do (
set /A "New=%%L-1,Last=%%L"
set "port[!New!]=!port[%%L]!"
)
:: finally reset the last entry
set "port[%Last%]="
set port[
> Q:Test20181123SO_53453204.cmd
port[0]=0
port[1]=3
port[2]=2
answered Nov 23 '18 at 22:03
LotPingsLotPings
19.2k61532
:: Q:Test20181123SO_53453204.cmd
@Echo off&SetLocal EnableDelayedExpansion
set "port[0]=" &Rem this clears/deletes the variable
set "port[1]=0"
set "port[2]=3"
set "port[3]=2"
For /L %%L in (1,1,3) do (
set /A "New=%%L-1,Last=%%L"
set "port[!New!]=!port[%%L]!"
)
:: finally reset the last entry
set "port[%Last%]="
set port[
> Q:Test20181123SO_53453204.cmd
port[0]=0
port[1]=3
port[2]=2
answered Nov 23 '18 at 22:03
LotPingsLotPings
19.2k61532
answered Nov 23 '18 at 22:03
LotPingsLotPings
19.2k61532
answered Nov 23 '18 at 22:03
LotPingsLotPings
19.2k61532
answered Nov 23 '18 at 22:03
LotPingsLotPings
19.2k61532
19.2k61532
Tracking of the last element in the loop:Last=%%Lis redundant. The last element is predetermined.
– sst
Nov 24 '18 at 2:56
add a comment |
Tracking of the last element in the loop:Last=%%Lis redundant. The last element is predetermined.
– sst
Nov 24 '18 at 2:56
Tracking of the last element in the loop:
Last=%%L is redundant. The last element is predetermined.– sst
Nov 24 '18 at 2:56
Tracking of the last element in the loop:
Last=%%L is redundant. The last element is predetermined.– sst
Nov 24 '18 at 2:56
add a comment |
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2
don't put spaces around the equal sign...
– npocmaka
Nov 23 '18 at 21:48
2
%port[0]%would not exist because without a value it would be undefined. The same would also be true for%port[3]%after the modification.– Compo
Nov 23 '18 at 21:59
guys thank you for pointing this out, but TBH i just showed this as an example, not the exact code =)
– John Doe
Nov 23 '18 at 22:02