double to float without rounding python












0















say a = 580991.3636



When I b = np.float32(a)



b 580991.4



I'm after b 580991.3636



I'm hoping this is an easy one, any ideas?
I'm also assuming it is my misunderstanding of floats causing this.
I know python is dynamic when it comes to dtypes, but I need it to be in float32 for a specific library (python-pcl).






python-3.x floating-point







share|improve this question




















  • 2





    The closest float to 580991.3636 has exact value 580991.375 which would print as 580991.4

    – Patricia Shanahan
    Nov 25 '18 at 16:47
















0















say a = 580991.3636



When I b = np.float32(a)



b 580991.4



I'm after b 580991.3636



I'm hoping this is an easy one, any ideas?
I'm also assuming it is my misunderstanding of floats causing this.
I know python is dynamic when it comes to dtypes, but I need it to be in float32 for a specific library (python-pcl).






python-3.x floating-point







share|improve this question




















  • 2





    The closest float to 580991.3636 has exact value 580991.375 which would print as 580991.4

    – Patricia Shanahan
    Nov 25 '18 at 16:47














0












0








0








say a = 580991.3636



When I b = np.float32(a)



b 580991.4



I'm after b 580991.3636



I'm hoping this is an easy one, any ideas?
I'm also assuming it is my misunderstanding of floats causing this.
I know python is dynamic when it comes to dtypes, but I need it to be in float32 for a specific library (python-pcl).






python-3.x floating-point







share|improve this question
















say a = 580991.3636



When I b = np.float32(a)



b 580991.4



I'm after b 580991.3636



I'm hoping this is an easy one, any ideas?
I'm also assuming it is my misunderstanding of floats causing this.
I know python is dynamic when it comes to dtypes, but I need it to be in float32 for a specific library (python-pcl).






python-3.x floating-point




python-3.x floating-point






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 25 '18 at 19:04







Gary Nobles

















asked Nov 25 '18 at 16:39









Gary NoblesGary Nobles

358316




358316








  • 2





    The closest float to 580991.3636 has exact value 580991.375 which would print as 580991.4

    – Patricia Shanahan
    Nov 25 '18 at 16:47














  • 2





    The closest float to 580991.3636 has exact value 580991.375 which would print as 580991.4

    – Patricia Shanahan
    Nov 25 '18 at 16:47








2




2





The closest float to 580991.3636 has exact value 580991.375 which would print as 580991.4

– Patricia Shanahan
Nov 25 '18 at 16:47





The closest float to 580991.3636 has exact value 580991.375 which would print as 580991.4

– Patricia Shanahan
Nov 25 '18 at 16:47












1 Answer
1






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3














Float32 can only offer between 6 and 9 digits of precision.



Float32 works by storing the sign in 1 bit, the exponent in 8 bits and the value in 23 bits (also called the fraction). So you can represent a wide range of real numbers at the cost of precision.



If you need it to be more precise it has to be a double or use the python's library decimal.






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    1 Answer
    1






    active

    oldest

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    active

    oldest

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    active

    oldest

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    3














    Float32 can only offer between 6 and 9 digits of precision.



    Float32 works by storing the sign in 1 bit, the exponent in 8 bits and the value in 23 bits (also called the fraction). So you can represent a wide range of real numbers at the cost of precision.



    If you need it to be more precise it has to be a double or use the python's library decimal.






    share|improve this answer






























      3














      Float32 can only offer between 6 and 9 digits of precision.



      Float32 works by storing the sign in 1 bit, the exponent in 8 bits and the value in 23 bits (also called the fraction). So you can represent a wide range of real numbers at the cost of precision.



      If you need it to be more precise it has to be a double or use the python's library decimal.






      share|improve this answer




























        3












        3








        3







        Float32 can only offer between 6 and 9 digits of precision.



        Float32 works by storing the sign in 1 bit, the exponent in 8 bits and the value in 23 bits (also called the fraction). So you can represent a wide range of real numbers at the cost of precision.



        If you need it to be more precise it has to be a double or use the python's library decimal.






        share|improve this answer















        Float32 can only offer between 6 and 9 digits of precision.



        Float32 works by storing the sign in 1 bit, the exponent in 8 bits and the value in 23 bits (also called the fraction). So you can represent a wide range of real numbers at the cost of precision.



        If you need it to be more precise it has to be a double or use the python's library decimal.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 25 '18 at 16:50

























        answered Nov 25 '18 at 16:43









        user9849588user9849588

        48428




        48428
































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