lstrip and rstrip non blank character from string
How do you strip characters (not necessarily white space i.e. blanks) from the start and end of a String in Scala?
The Python analogue to what I am looking for is lstrip and rstrip.
This is the desired functionality:
ltrim("{blah blah}", "{") should equal("blah blah}")
ltrim("blah blah", "{") should equal("blah blah") // no exception
rtrim("blah blah}", "}") should equal("blah blah")
scala
edited Nov 25 '18 at 17:14
Xavier Guihot
7,59892536
asked Nov 25 '18 at 16:46
Omkar NeogiOmkar Neogi
139211
add a comment |
How do you strip characters (not necessarily white space i.e. blanks) from the start and end of a String in Scala?
The Python analogue to what I am looking for is lstrip and rstrip.
This is the desired functionality:
ltrim("{blah blah}", "{") should equal("blah blah}")
ltrim("blah blah", "{") should equal("blah blah") // no exception
rtrim("blah blah}", "}") should equal("blah blah")
scala
edited Nov 25 '18 at 17:14
Xavier Guihot
7,59892536
asked Nov 25 '18 at 16:46
Omkar NeogiOmkar Neogi
139211
add a comment |
How do you strip characters (not necessarily white space i.e. blanks) from the start and end of a String in Scala?
The Python analogue to what I am looking for is lstrip and rstrip.
This is the desired functionality:
ltrim("{blah blah}", "{") should equal("blah blah}")
ltrim("blah blah", "{") should equal("blah blah") // no exception
rtrim("blah blah}", "}") should equal("blah blah")
scala
edited Nov 25 '18 at 17:14
Xavier Guihot
7,59892536
asked Nov 25 '18 at 16:46
Omkar NeogiOmkar Neogi
139211
How do you strip characters (not necessarily white space i.e. blanks) from the start and end of a String in Scala?
The Python analogue to what I am looking for is lstrip and rstrip.
This is the desired functionality:
ltrim("{blah blah}", "{") should equal("blah blah}")
ltrim("blah blah", "{") should equal("blah blah") // no exception
rtrim("blah blah}", "}") should equal("blah blah")
scala
scala
edited Nov 25 '18 at 17:14
Xavier Guihot
7,59892536
asked Nov 25 '18 at 16:46
Omkar NeogiOmkar Neogi
139211
edited Nov 25 '18 at 17:14
Xavier Guihot
7,59892536
asked Nov 25 '18 at 16:46
Omkar NeogiOmkar Neogi
139211
edited Nov 25 '18 at 17:14
Xavier Guihot
7,59892536
edited Nov 25 '18 at 17:14
Xavier Guihot
7,59892536
edited Nov 25 '18 at 17:14
Xavier Guihot
7,59892536
7,59892536
asked Nov 25 '18 at 16:46
Omkar NeogiOmkar Neogi
139211
asked Nov 25 '18 at 16:46
Omkar NeogiOmkar Neogi
139211
asked Nov 25 '18 at 16:46
Omkar NeogiOmkar Neogi
139211
139211
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You could use dropWhile if you want to remove a specific character from the beginning of a String:
"{{blah blah}".dropWhile(_ == '{')
// "blah blah}"
This drops any character from the left of the String which fulfills the given predicate which in this case is being equal to the character to remove.
In order to remove a character from the right, since there is not yet a dropWhileRight equivalent in the standard library, one way could consist in a double reverse:
"{{blah blah}".reverse.dropWhile(_ == '}').reverse
// {{blah blah
or slightly more efficients:
"{{blah blah}}".dropRight("{{blah blah}}".reverse.segmentLength(_ == '}'))
// {{blah blah
"{{blah blah}}".stripSuffix("{{blah blah}}".reverse.takeWhile(_ == '}'))
// {{blah blah
answered Nov 25 '18 at 16:54
Xavier GuihotXavier Guihot
7,59892536
add a comment |
Use regular expressions functions
scala> "{blah blah}".replaceAll("""^[{]+""","")
res35: String = blah blah}
scala> "{{blah blah}".replaceAll("""^[{]+""","")
res36: String = blah blah}
scala> "blah blah}".replaceAll("""^[{]+""","")
res37: String = blah blah}
scala> "blah blah}".replaceAll("""[}]+$""","")
res38: String = blah blah
scala>
answered Nov 26 '18 at 11:52
stack0114106stack0114106
4,4002422
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You could use dropWhile if you want to remove a specific character from the beginning of a String:
"{{blah blah}".dropWhile(_ == '{')
// "blah blah}"
This drops any character from the left of the String which fulfills the given predicate which in this case is being equal to the character to remove.
In order to remove a character from the right, since there is not yet a dropWhileRight equivalent in the standard library, one way could consist in a double reverse:
"{{blah blah}".reverse.dropWhile(_ == '}').reverse
// {{blah blah
or slightly more efficients:
"{{blah blah}}".dropRight("{{blah blah}}".reverse.segmentLength(_ == '}'))
// {{blah blah
"{{blah blah}}".stripSuffix("{{blah blah}}".reverse.takeWhile(_ == '}'))
// {{blah blah
answered Nov 25 '18 at 16:54
Xavier GuihotXavier Guihot
7,59892536
add a comment |
You could use dropWhile if you want to remove a specific character from the beginning of a String:
"{{blah blah}".dropWhile(_ == '{')
// "blah blah}"
This drops any character from the left of the String which fulfills the given predicate which in this case is being equal to the character to remove.
In order to remove a character from the right, since there is not yet a dropWhileRight equivalent in the standard library, one way could consist in a double reverse:
"{{blah blah}".reverse.dropWhile(_ == '}').reverse
// {{blah blah
or slightly more efficients:
"{{blah blah}}".dropRight("{{blah blah}}".reverse.segmentLength(_ == '}'))
// {{blah blah
"{{blah blah}}".stripSuffix("{{blah blah}}".reverse.takeWhile(_ == '}'))
// {{blah blah
answered Nov 25 '18 at 16:54
Xavier GuihotXavier Guihot
7,59892536
add a comment |
You could use dropWhile if you want to remove a specific character from the beginning of a String:
"{{blah blah}".dropWhile(_ == '{')
// "blah blah}"
This drops any character from the left of the String which fulfills the given predicate which in this case is being equal to the character to remove.
In order to remove a character from the right, since there is not yet a dropWhileRight equivalent in the standard library, one way could consist in a double reverse:
"{{blah blah}".reverse.dropWhile(_ == '}').reverse
// {{blah blah
or slightly more efficients:
"{{blah blah}}".dropRight("{{blah blah}}".reverse.segmentLength(_ == '}'))
// {{blah blah
"{{blah blah}}".stripSuffix("{{blah blah}}".reverse.takeWhile(_ == '}'))
// {{blah blah
answered Nov 25 '18 at 16:54
Xavier GuihotXavier Guihot
7,59892536
You could use dropWhile if you want to remove a specific character from the beginning of a String:
"{{blah blah}".dropWhile(_ == '{')
// "blah blah}"
This drops any character from the left of the String which fulfills the given predicate which in this case is being equal to the character to remove.
In order to remove a character from the right, since there is not yet a dropWhileRight equivalent in the standard library, one way could consist in a double reverse:
"{{blah blah}".reverse.dropWhile(_ == '}').reverse
// {{blah blah
or slightly more efficients:
"{{blah blah}}".dropRight("{{blah blah}}".reverse.segmentLength(_ == '}'))
// {{blah blah
"{{blah blah}}".stripSuffix("{{blah blah}}".reverse.takeWhile(_ == '}'))
// {{blah blah
answered Nov 25 '18 at 16:54
Xavier GuihotXavier Guihot
7,59892536
edited Nov 25 '18 at 17:29
answered Nov 25 '18 at 16:54
Xavier GuihotXavier Guihot
7,59892536
answered Nov 25 '18 at 16:54
Xavier GuihotXavier Guihot
7,59892536
answered Nov 25 '18 at 16:54
Xavier GuihotXavier Guihot
7,59892536
7,59892536
add a comment |
add a comment |
Use regular expressions functions
scala> "{blah blah}".replaceAll("""^[{]+""","")
res35: String = blah blah}
scala> "{{blah blah}".replaceAll("""^[{]+""","")
res36: String = blah blah}
scala> "blah blah}".replaceAll("""^[{]+""","")
res37: String = blah blah}
scala> "blah blah}".replaceAll("""[}]+$""","")
res38: String = blah blah
scala>
answered Nov 26 '18 at 11:52
stack0114106stack0114106
4,4002422
add a comment |
Use regular expressions functions
scala> "{blah blah}".replaceAll("""^[{]+""","")
res35: String = blah blah}
scala> "{{blah blah}".replaceAll("""^[{]+""","")
res36: String = blah blah}
scala> "blah blah}".replaceAll("""^[{]+""","")
res37: String = blah blah}
scala> "blah blah}".replaceAll("""[}]+$""","")
res38: String = blah blah
scala>
answered Nov 26 '18 at 11:52
stack0114106stack0114106
4,4002422
add a comment |
Use regular expressions functions
scala> "{blah blah}".replaceAll("""^[{]+""","")
res35: String = blah blah}
scala> "{{blah blah}".replaceAll("""^[{]+""","")
res36: String = blah blah}
scala> "blah blah}".replaceAll("""^[{]+""","")
res37: String = blah blah}
scala> "blah blah}".replaceAll("""[}]+$""","")
res38: String = blah blah
scala>
answered Nov 26 '18 at 11:52
stack0114106stack0114106
4,4002422
Use regular expressions functions
scala> "{blah blah}".replaceAll("""^[{]+""","")
res35: String = blah blah}
scala> "{{blah blah}".replaceAll("""^[{]+""","")
res36: String = blah blah}
scala> "blah blah}".replaceAll("""^[{]+""","")
res37: String = blah blah}
scala> "blah blah}".replaceAll("""[}]+$""","")
res38: String = blah blah
scala>
answered Nov 26 '18 at 11:52
stack0114106stack0114106
4,4002422
edited Nov 26 '18 at 13:38
answered Nov 26 '18 at 11:52
stack0114106stack0114106
4,4002422
answered Nov 26 '18 at 11:52
stack0114106stack0114106
4,4002422
answered Nov 26 '18 at 11:52
stack0114106stack0114106
4,4002422
4,4002422
add a comment |
add a comment |
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