How to select only the fields without Display: none CSS property using JQuery?












1















Hi I am trying to select only the fields who's CSS property is not Display: "None".
Please have a look at the code and please let me know what an I doing wrong?



function (controlId) {
var returnValidFlag = true;



        //var requiredClass = $this.find('.required');
//console.log(requiredClass);

$('.required:not([display=none])').each(function () {
// Get 'this' HTML object's ID
var thisInputID = $(this).attr('id');

// Get 'this' error message
var thisErrorMessageID = thisInputID + 'ErrorMessage';
// console.log('Error ID: ' + thisErrorMessageID);

// Get the user input value
var thisInputValue = $(this).val();
console.log('Input ID: ' + thisInputValue + " " + thisErrorMessageID);

if (thisInputValue =='') {
returnValidFlag = false;
$('#' + thisErrorMessageID).show();
} else {
returnValidFlag = true;
$('#' + thisErrorMessageID).hide();
}
});

return returnValidFlag;
}









share|improve this question























  • Possible duplicate of Using jQuery, how do you find only visible elements and leave hidden elements alone?

    – billynoah
    Nov 26 '18 at 0:28
















1















Hi I am trying to select only the fields who's CSS property is not Display: "None".
Please have a look at the code and please let me know what an I doing wrong?



function (controlId) {
var returnValidFlag = true;



        //var requiredClass = $this.find('.required');
//console.log(requiredClass);

$('.required:not([display=none])').each(function () {
// Get 'this' HTML object's ID
var thisInputID = $(this).attr('id');

// Get 'this' error message
var thisErrorMessageID = thisInputID + 'ErrorMessage';
// console.log('Error ID: ' + thisErrorMessageID);

// Get the user input value
var thisInputValue = $(this).val();
console.log('Input ID: ' + thisInputValue + " " + thisErrorMessageID);

if (thisInputValue =='') {
returnValidFlag = false;
$('#' + thisErrorMessageID).show();
} else {
returnValidFlag = true;
$('#' + thisErrorMessageID).hide();
}
});

return returnValidFlag;
}









share|improve this question























  • Possible duplicate of Using jQuery, how do you find only visible elements and leave hidden elements alone?

    – billynoah
    Nov 26 '18 at 0:28














1












1








1








Hi I am trying to select only the fields who's CSS property is not Display: "None".
Please have a look at the code and please let me know what an I doing wrong?



function (controlId) {
var returnValidFlag = true;



        //var requiredClass = $this.find('.required');
//console.log(requiredClass);

$('.required:not([display=none])').each(function () {
// Get 'this' HTML object's ID
var thisInputID = $(this).attr('id');

// Get 'this' error message
var thisErrorMessageID = thisInputID + 'ErrorMessage';
// console.log('Error ID: ' + thisErrorMessageID);

// Get the user input value
var thisInputValue = $(this).val();
console.log('Input ID: ' + thisInputValue + " " + thisErrorMessageID);

if (thisInputValue =='') {
returnValidFlag = false;
$('#' + thisErrorMessageID).show();
} else {
returnValidFlag = true;
$('#' + thisErrorMessageID).hide();
}
});

return returnValidFlag;
}









share|improve this question














Hi I am trying to select only the fields who's CSS property is not Display: "None".
Please have a look at the code and please let me know what an I doing wrong?



function (controlId) {
var returnValidFlag = true;



        //var requiredClass = $this.find('.required');
//console.log(requiredClass);

$('.required:not([display=none])').each(function () {
// Get 'this' HTML object's ID
var thisInputID = $(this).attr('id');

// Get 'this' error message
var thisErrorMessageID = thisInputID + 'ErrorMessage';
// console.log('Error ID: ' + thisErrorMessageID);

// Get the user input value
var thisInputValue = $(this).val();
console.log('Input ID: ' + thisInputValue + " " + thisErrorMessageID);

if (thisInputValue =='') {
returnValidFlag = false;
$('#' + thisErrorMessageID).show();
} else {
returnValidFlag = true;
$('#' + thisErrorMessageID).hide();
}
});

return returnValidFlag;
}






jquery






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asked Nov 25 '18 at 23:49









Sarbraj DulaiSarbraj Dulai

305




305













  • Possible duplicate of Using jQuery, how do you find only visible elements and leave hidden elements alone?

    – billynoah
    Nov 26 '18 at 0:28



















  • Possible duplicate of Using jQuery, how do you find only visible elements and leave hidden elements alone?

    – billynoah
    Nov 26 '18 at 0:28

















Possible duplicate of Using jQuery, how do you find only visible elements and leave hidden elements alone?

– billynoah
Nov 26 '18 at 0:28





Possible duplicate of Using jQuery, how do you find only visible elements and leave hidden elements alone?

– billynoah
Nov 26 '18 at 0:28












2 Answers
2






active

oldest

votes


















1














You can use :visible selector.



display is not part of an element's attributes , it is a style property



$('.required:visible)').each(...





share|improve this answer































    0














    In jQuery, you can use filter.



    $('div').filter((index, node) => $(node).css('display') !== 'none')





    share|improve this answer























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      You can use :visible selector.



      display is not part of an element's attributes , it is a style property



      $('.required:visible)').each(...





      share|improve this answer




























        1














        You can use :visible selector.



        display is not part of an element's attributes , it is a style property



        $('.required:visible)').each(...





        share|improve this answer


























          1












          1








          1







          You can use :visible selector.



          display is not part of an element's attributes , it is a style property



          $('.required:visible)').each(...





          share|improve this answer













          You can use :visible selector.



          display is not part of an element's attributes , it is a style property



          $('.required:visible)').each(...






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 26 '18 at 0:01









          charlietflcharlietfl

          140k1389123




          140k1389123

























              0














              In jQuery, you can use filter.



              $('div').filter((index, node) => $(node).css('display') !== 'none')





              share|improve this answer




























                0














                In jQuery, you can use filter.



                $('div').filter((index, node) => $(node).css('display') !== 'none')





                share|improve this answer


























                  0












                  0








                  0







                  In jQuery, you can use filter.



                  $('div').filter((index, node) => $(node).css('display') !== 'none')





                  share|improve this answer













                  In jQuery, you can use filter.



                  $('div').filter((index, node) => $(node).css('display') !== 'none')






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 26 '18 at 0:13









                  user44user44

                  435318




                  435318






























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