Jquery dynamic click
$begingroup$
Hi I have two set of button for every package , one for insert data into DB and other for delete data from DB . When I click SELECT button data will be insert through ajax and hide SELECT button and display SELECTED button. When I click on SELECTED button data will be deleted from DB through ajax call, SELECTED button will be hide and SELECT button will be appear . All the select & selected button within a php while loop so button are having same name but incremental ID . When I click on one single SELECT button , other button also showing me SELECTED. I need something to track the each button ID when I click , This is my script
<div class="col-sm-2"><a class="btn btn-primary select-btn select-btn-broadcast" id="<?php echo $id ; ?>" onClick="addintoListBroadcast(this)"> Select </a>
<a class="btn btn-primary active-button active-button-broadcast" id="<?php echo $id ; ?>" onClick="deleteintoListBroadcast(this)" style="display: none;"> Selected </a></div>
$('.select-btn-broadcast').click(function (e)
{
var pkgId = this.id;
//alert(pkgId);
$('.select-btn-broadcast').hide();
$('.active-button-broadcast'.id).show();
});
$('.active-button-broadcast').click(function (e)
{
$('.select-btn-broadcast'.show();
$('.active-button-broadcast').hide();
});
php jquery ajax
asked 59 secs ago
Tapati PaulTapati Paul
1
New contributor
Tapati Paul is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$
add a comment |
$begingroup$
Hi I have two set of button for every package , one for insert data into DB and other for delete data from DB . When I click SELECT button data will be insert through ajax and hide SELECT button and display SELECTED button. When I click on SELECTED button data will be deleted from DB through ajax call, SELECTED button will be hide and SELECT button will be appear . All the select & selected button within a php while loop so button are having same name but incremental ID . When I click on one single SELECT button , other button also showing me SELECTED. I need something to track the each button ID when I click , This is my script
<div class="col-sm-2"><a class="btn btn-primary select-btn select-btn-broadcast" id="<?php echo $id ; ?>" onClick="addintoListBroadcast(this)"> Select </a>
<a class="btn btn-primary active-button active-button-broadcast" id="<?php echo $id ; ?>" onClick="deleteintoListBroadcast(this)" style="display: none;"> Selected </a></div>
$('.select-btn-broadcast').click(function (e)
{
var pkgId = this.id;
//alert(pkgId);
$('.select-btn-broadcast').hide();
$('.active-button-broadcast'.id).show();
});
$('.active-button-broadcast').click(function (e)
{
$('.select-btn-broadcast'.show();
$('.active-button-broadcast').hide();
});
php jquery ajax
asked 59 secs ago
Tapati PaulTapati Paul
1
New contributor
Tapati Paul is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Hi I have two set of button for every package , one for insert data into DB and other for delete data from DB . When I click SELECT button data will be insert through ajax and hide SELECT button and display SELECTED button. When I click on SELECTED button data will be deleted from DB through ajax call, SELECTED button will be hide and SELECT button will be appear . All the select & selected button within a php while loop so button are having same name but incremental ID . When I click on one single SELECT button , other button also showing me SELECTED. I need something to track the each button ID when I click , This is my script
<div class="col-sm-2"><a class="btn btn-primary select-btn select-btn-broadcast" id="<?php echo $id ; ?>" onClick="addintoListBroadcast(this)"> Select </a>
<a class="btn btn-primary active-button active-button-broadcast" id="<?php echo $id ; ?>" onClick="deleteintoListBroadcast(this)" style="display: none;"> Selected </a></div>
$('.select-btn-broadcast').click(function (e)
{
var pkgId = this.id;
//alert(pkgId);
$('.select-btn-broadcast').hide();
$('.active-button-broadcast'.id).show();
});
$('.active-button-broadcast').click(function (e)
{
$('.select-btn-broadcast'.show();
$('.active-button-broadcast').hide();
});
php jquery ajax
asked 59 secs ago
Tapati PaulTapati Paul
1
New contributor
Tapati Paul is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Hi I have two set of button for every package , one for insert data into DB and other for delete data from DB . When I click SELECT button data will be insert through ajax and hide SELECT button and display SELECTED button. When I click on SELECTED button data will be deleted from DB through ajax call, SELECTED button will be hide and SELECT button will be appear . All the select & selected button within a php while loop so button are having same name but incremental ID . When I click on one single SELECT button , other button also showing me SELECTED. I need something to track the each button ID when I click , This is my script
<div class="col-sm-2"><a class="btn btn-primary select-btn select-btn-broadcast" id="<?php echo $id ; ?>" onClick="addintoListBroadcast(this)"> Select </a>
<a class="btn btn-primary active-button active-button-broadcast" id="<?php echo $id ; ?>" onClick="deleteintoListBroadcast(this)" style="display: none;"> Selected </a></div>
$('.select-btn-broadcast').click(function (e)
{
var pkgId = this.id;
//alert(pkgId);
$('.select-btn-broadcast').hide();
$('.active-button-broadcast'.id).show();
});
$('.active-button-broadcast').click(function (e)
{
$('.select-btn-broadcast'.show();
$('.active-button-broadcast').hide();
});
php jquery ajax
php jquery ajax
asked 59 secs ago
Tapati PaulTapati Paul
1
New contributor
Tapati Paul is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 59 secs ago
Tapati PaulTapati Paul
1
New contributor
Tapati Paul is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 59 secs ago
Tapati PaulTapati Paul
1
New contributor
Tapati Paul is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 59 secs ago
Tapati PaulTapati Paul
1
asked 59 secs ago
Tapati PaulTapati Paul
1
1
New contributor
Tapati Paul is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Tapati Paul is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Tapati Paul is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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