Python NameError: name 'isAnagram' is not defined











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-4
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I want to print whether a number is an anagram or not from the user input. I get an error saying nameError. Error message



And this is my code for checking an input for an anagram.



n = input("Enter a long number")
factor = 2
factor_anagram = False
while factor < 10:
if isAnagram(n, factor):
print(n, "is an anagram with factor", factor)
factor_anagram = True
factor += 1
if not factor_anagram:
print("No")


Do I need to create a class? I tried creating an isAnagram class as well. But my implementation did not solve the issue.










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  • 1




    Where do you define isAnagram?
    – Carcigenicate
    Nov 18 at 14:24










  • There is no built-in isAnagram function. You have to define one your own.
    – Austin
    Nov 18 at 14:25










  • You don't need to create a class. You need to create a function :D
    – Canh
    Nov 18 at 14:27















up vote
-4
down vote

favorite












I want to print whether a number is an anagram or not from the user input. I get an error saying nameError. Error message



And this is my code for checking an input for an anagram.



n = input("Enter a long number")
factor = 2
factor_anagram = False
while factor < 10:
if isAnagram(n, factor):
print(n, "is an anagram with factor", factor)
factor_anagram = True
factor += 1
if not factor_anagram:
print("No")


Do I need to create a class? I tried creating an isAnagram class as well. But my implementation did not solve the issue.










share|improve this question




















  • 1




    Where do you define isAnagram?
    – Carcigenicate
    Nov 18 at 14:24










  • There is no built-in isAnagram function. You have to define one your own.
    – Austin
    Nov 18 at 14:25










  • You don't need to create a class. You need to create a function :D
    – Canh
    Nov 18 at 14:27













up vote
-4
down vote

favorite









up vote
-4
down vote

favorite











I want to print whether a number is an anagram or not from the user input. I get an error saying nameError. Error message



And this is my code for checking an input for an anagram.



n = input("Enter a long number")
factor = 2
factor_anagram = False
while factor < 10:
if isAnagram(n, factor):
print(n, "is an anagram with factor", factor)
factor_anagram = True
factor += 1
if not factor_anagram:
print("No")


Do I need to create a class? I tried creating an isAnagram class as well. But my implementation did not solve the issue.










share|improve this question















I want to print whether a number is an anagram or not from the user input. I get an error saying nameError. Error message



And this is my code for checking an input for an anagram.



n = input("Enter a long number")
factor = 2
factor_anagram = False
while factor < 10:
if isAnagram(n, factor):
print(n, "is an anagram with factor", factor)
factor_anagram = True
factor += 1
if not factor_anagram:
print("No")


Do I need to create a class? I tried creating an isAnagram class as well. But my implementation did not solve the issue.







python python-3.7






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edited Nov 18 at 14:34

























asked Nov 18 at 14:22









Chaite

86




86








  • 1




    Where do you define isAnagram?
    – Carcigenicate
    Nov 18 at 14:24










  • There is no built-in isAnagram function. You have to define one your own.
    – Austin
    Nov 18 at 14:25










  • You don't need to create a class. You need to create a function :D
    – Canh
    Nov 18 at 14:27














  • 1




    Where do you define isAnagram?
    – Carcigenicate
    Nov 18 at 14:24










  • There is no built-in isAnagram function. You have to define one your own.
    – Austin
    Nov 18 at 14:25










  • You don't need to create a class. You need to create a function :D
    – Canh
    Nov 18 at 14:27








1




1




Where do you define isAnagram?
– Carcigenicate
Nov 18 at 14:24




Where do you define isAnagram?
– Carcigenicate
Nov 18 at 14:24












There is no built-in isAnagram function. You have to define one your own.
– Austin
Nov 18 at 14:25




There is no built-in isAnagram function. You have to define one your own.
– Austin
Nov 18 at 14:25












You don't need to create a class. You need to create a function :D
– Canh
Nov 18 at 14:27




You don't need to create a class. You need to create a function :D
– Canh
Nov 18 at 14:27












2 Answers
2






active

oldest

votes

















up vote
0
down vote



accepted










You are trying to use isAnagram(n, factor) as a built in function like print("xyz"). isAnagram() is not a built in function, so you will have to define it at the top of your code. It can look like this:



def isAnagram(n, factor):
if (whatever comparison needs to be made here):
return True
else:
return False


Now when you call the isAnagram function, either True or False will be returned.






share|improve this answer








New contributor




Harry Weinman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

























    up vote
    0
    down vote













    isAnagram does not exist in the default Python library - you have to define it yourself. From the way you're attempting to use it, you want to create a function



    def is_anagram(n, factor):
    # Your code here
    # return True or False


    You can then do something like if is_anagram(n, factor):.






    share|improve this answer























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      0
      down vote



      accepted










      You are trying to use isAnagram(n, factor) as a built in function like print("xyz"). isAnagram() is not a built in function, so you will have to define it at the top of your code. It can look like this:



      def isAnagram(n, factor):
      if (whatever comparison needs to be made here):
      return True
      else:
      return False


      Now when you call the isAnagram function, either True or False will be returned.






      share|improve this answer








      New contributor




      Harry Weinman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






















        up vote
        0
        down vote



        accepted










        You are trying to use isAnagram(n, factor) as a built in function like print("xyz"). isAnagram() is not a built in function, so you will have to define it at the top of your code. It can look like this:



        def isAnagram(n, factor):
        if (whatever comparison needs to be made here):
        return True
        else:
        return False


        Now when you call the isAnagram function, either True or False will be returned.






        share|improve this answer








        New contributor




        Harry Weinman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.




















          up vote
          0
          down vote



          accepted







          up vote
          0
          down vote



          accepted






          You are trying to use isAnagram(n, factor) as a built in function like print("xyz"). isAnagram() is not a built in function, so you will have to define it at the top of your code. It can look like this:



          def isAnagram(n, factor):
          if (whatever comparison needs to be made here):
          return True
          else:
          return False


          Now when you call the isAnagram function, either True or False will be returned.






          share|improve this answer








          New contributor




          Harry Weinman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.









          You are trying to use isAnagram(n, factor) as a built in function like print("xyz"). isAnagram() is not a built in function, so you will have to define it at the top of your code. It can look like this:



          def isAnagram(n, factor):
          if (whatever comparison needs to be made here):
          return True
          else:
          return False


          Now when you call the isAnagram function, either True or False will be returned.







          share|improve this answer








          New contributor




          Harry Weinman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.









          share|improve this answer



          share|improve this answer






          New contributor




          Harry Weinman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.









          answered Nov 18 at 14:31









          Harry Weinman

          313




          313




          New contributor




          Harry Weinman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.





          New contributor





          Harry Weinman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.






          Harry Weinman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.
























              up vote
              0
              down vote













              isAnagram does not exist in the default Python library - you have to define it yourself. From the way you're attempting to use it, you want to create a function



              def is_anagram(n, factor):
              # Your code here
              # return True or False


              You can then do something like if is_anagram(n, factor):.






              share|improve this answer



























                up vote
                0
                down vote













                isAnagram does not exist in the default Python library - you have to define it yourself. From the way you're attempting to use it, you want to create a function



                def is_anagram(n, factor):
                # Your code here
                # return True or False


                You can then do something like if is_anagram(n, factor):.






                share|improve this answer

























                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote









                  isAnagram does not exist in the default Python library - you have to define it yourself. From the way you're attempting to use it, you want to create a function



                  def is_anagram(n, factor):
                  # Your code here
                  # return True or False


                  You can then do something like if is_anagram(n, factor):.






                  share|improve this answer














                  isAnagram does not exist in the default Python library - you have to define it yourself. From the way you're attempting to use it, you want to create a function



                  def is_anagram(n, factor):
                  # Your code here
                  # return True or False


                  You can then do something like if is_anagram(n, factor):.







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 18 at 14:31

























                  answered Nov 18 at 14:29









                  Moralous

                  73111




                  73111






























                       

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