How to stop Promise.all loop when it rejects
0
I'm having a hard time trying to stop the loop in promise.all if one promise rejects it. Here's how I did it. Is there something wrong with this?
Promise.all(myArray.map((obj) => {
this.someFunction(obj);
}))
Here's the function I call..
someFunction(){
return new Promise(function (resolve, reject) {
....
reject()
})}
react-native promise
asked Nov 22 '18 at 11:18
kkumberkkumber
167
add a comment |
0
I'm having a hard time trying to stop the loop in promise.all if one promise rejects it. Here's how I did it. Is there something wrong with this?
Promise.all(myArray.map((obj) => {
this.someFunction(obj);
}))
Here's the function I call..
someFunction(){
return new Promise(function (resolve, reject) {
....
reject()
})}
react-native promise
asked Nov 22 '18 at 11:18
kkumberkkumber
167
1
Promise.alldoes not "loop" anything
– Bergi
Nov 22 '18 at 13:24
The map returns an array and it is created "instantly",Promise.allwill resolve if all promises in the array are resolved and will reject if one rejects. What exactly are you trying to achieve?
– koox00
Nov 22 '18 at 14:54
add a comment |
0
0
0
I'm having a hard time trying to stop the loop in promise.all if one promise rejects it. Here's how I did it. Is there something wrong with this?
Promise.all(myArray.map((obj) => {
this.someFunction(obj);
}))
Here's the function I call..
someFunction(){
return new Promise(function (resolve, reject) {
....
reject()
})}
react-native promise
asked Nov 22 '18 at 11:18
kkumberkkumber
167
I'm having a hard time trying to stop the loop in promise.all if one promise rejects it. Here's how I did it. Is there something wrong with this?
Promise.all(myArray.map((obj) => {
this.someFunction(obj);
}))
Here's the function I call..
someFunction(){
return new Promise(function (resolve, reject) {
....
reject()
})}
react-native promise
react-native promise
asked Nov 22 '18 at 11:18
kkumberkkumber
167
asked Nov 22 '18 at 11:18
kkumberkkumber
167
asked Nov 22 '18 at 11:18
kkumberkkumber
167
asked Nov 22 '18 at 11:18
kkumberkkumber
167
asked Nov 22 '18 at 11:18
kkumberkkumber
167
167
1
Promise.alldoes not "loop" anything
– Bergi
Nov 22 '18 at 13:24
The map returns an array and it is created "instantly",Promise.allwill resolve if all promises in the array are resolved and will reject if one rejects. What exactly are you trying to achieve?
– koox00
Nov 22 '18 at 14:54
add a comment |
1
Promise.alldoes not "loop" anything
– Bergi
Nov 22 '18 at 13:24
The map returns an array and it is created "instantly",Promise.allwill resolve if all promises in the array are resolved and will reject if one rejects. What exactly are you trying to achieve?
– koox00
Nov 22 '18 at 14:54
1
1
Promise.all does not "loop" anything– Bergi
Nov 22 '18 at 13:24
Promise.all does not "loop" anything– Bergi
Nov 22 '18 at 13:24
The map returns an array and it is created "instantly",
Promise.all will resolve if all promises in the array are resolved and will reject if one rejects. What exactly are you trying to achieve?– koox00
Nov 22 '18 at 14:54
The map returns an array and it is created "instantly",
Promise.all will resolve if all promises in the array are resolved and will reject if one rejects. What exactly are you trying to achieve?– koox00
Nov 22 '18 at 14:54
add a comment |
2 Answers
2
active
oldest
votes
0
I have updated my code, it is tested and it works on my machine with the mock data I feed it with. I am not exactly sure how the rest of your code is structured but it is something likes this: Oh and you cannot break out of a map, but we will use a simple for loop because we can break out of that:
function someFunction(){
return new Promise(function (resolve, reject) {
// I will be rejeccting a boolean
// If you are resolving something, resolve it as true
reject(false)
})}
async function shouldStopLoop(){
// the boolean will come here
// if it is false, the catch block will return
// if it is true, the try block will return
let stopLoop = null;
let result = null;
try {
result = await someFunction();
return result
} catch(error) {
stopLoop = error;
return stopLoop;
}
}
function mayReturnPromiseAll() {
let myArray = ['stuf to loop over...']
let arraytoGoInPrimiseAll = ;
// Array.prototype.map cannot be stopped
// Thats why we will use a for loop and we will push the data we need
// into another array
for (var i = 0; i < myArray.length; i++) {
if (!this.someFunction(obj)) {
break;
} else {
// push things in arraytoGoInPrimiseAll
}
}
if(arraytoGoInPrimiseAll.length > 0){
return Promise.all(arraytoGoInPrimiseAll)
} else {
// do something else
}
};
answered Nov 22 '18 at 11:30
squeekyDavesqueekyDave
407215
still works the same. I'm expecting to stop the loop once the promise encountered rejection. Is there a way for this?
– kkumber
Nov 22 '18 at 12:52
add a comment |
0
Try this:
const arrayOfFunctions = myArray.map(obj => this.someFunction(obj))
Promise.all(arrayOfFunctions).then(values => {
console.log(values);
}).catch(error => {
console.log(error)
});
answered Nov 22 '18 at 23:12
DiamantDiamant
10817
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
I have updated my code, it is tested and it works on my machine with the mock data I feed it with. I am not exactly sure how the rest of your code is structured but it is something likes this: Oh and you cannot break out of a map, but we will use a simple for loop because we can break out of that:
function someFunction(){
return new Promise(function (resolve, reject) {
// I will be rejeccting a boolean
// If you are resolving something, resolve it as true
reject(false)
})}
async function shouldStopLoop(){
// the boolean will come here
// if it is false, the catch block will return
// if it is true, the try block will return
let stopLoop = null;
let result = null;
try {
result = await someFunction();
return result
} catch(error) {
stopLoop = error;
return stopLoop;
}
}
function mayReturnPromiseAll() {
let myArray = ['stuf to loop over...']
let arraytoGoInPrimiseAll = ;
// Array.prototype.map cannot be stopped
// Thats why we will use a for loop and we will push the data we need
// into another array
for (var i = 0; i < myArray.length; i++) {
if (!this.someFunction(obj)) {
break;
} else {
// push things in arraytoGoInPrimiseAll
}
}
if(arraytoGoInPrimiseAll.length > 0){
return Promise.all(arraytoGoInPrimiseAll)
} else {
// do something else
}
};
answered Nov 22 '18 at 11:30
squeekyDavesqueekyDave
407215
still works the same. I'm expecting to stop the loop once the promise encountered rejection. Is there a way for this?
– kkumber
Nov 22 '18 at 12:52
add a comment |
0
I have updated my code, it is tested and it works on my machine with the mock data I feed it with. I am not exactly sure how the rest of your code is structured but it is something likes this: Oh and you cannot break out of a map, but we will use a simple for loop because we can break out of that:
function someFunction(){
return new Promise(function (resolve, reject) {
// I will be rejeccting a boolean
// If you are resolving something, resolve it as true
reject(false)
})}
async function shouldStopLoop(){
// the boolean will come here
// if it is false, the catch block will return
// if it is true, the try block will return
let stopLoop = null;
let result = null;
try {
result = await someFunction();
return result
} catch(error) {
stopLoop = error;
return stopLoop;
}
}
function mayReturnPromiseAll() {
let myArray = ['stuf to loop over...']
let arraytoGoInPrimiseAll = ;
// Array.prototype.map cannot be stopped
// Thats why we will use a for loop and we will push the data we need
// into another array
for (var i = 0; i < myArray.length; i++) {
if (!this.someFunction(obj)) {
break;
} else {
// push things in arraytoGoInPrimiseAll
}
}
if(arraytoGoInPrimiseAll.length > 0){
return Promise.all(arraytoGoInPrimiseAll)
} else {
// do something else
}
};
answered Nov 22 '18 at 11:30
squeekyDavesqueekyDave
407215
still works the same. I'm expecting to stop the loop once the promise encountered rejection. Is there a way for this?
– kkumber
Nov 22 '18 at 12:52
add a comment |
0
0
0
I have updated my code, it is tested and it works on my machine with the mock data I feed it with. I am not exactly sure how the rest of your code is structured but it is something likes this: Oh and you cannot break out of a map, but we will use a simple for loop because we can break out of that:
function someFunction(){
return new Promise(function (resolve, reject) {
// I will be rejeccting a boolean
// If you are resolving something, resolve it as true
reject(false)
})}
async function shouldStopLoop(){
// the boolean will come here
// if it is false, the catch block will return
// if it is true, the try block will return
let stopLoop = null;
let result = null;
try {
result = await someFunction();
return result
} catch(error) {
stopLoop = error;
return stopLoop;
}
}
function mayReturnPromiseAll() {
let myArray = ['stuf to loop over...']
let arraytoGoInPrimiseAll = ;
// Array.prototype.map cannot be stopped
// Thats why we will use a for loop and we will push the data we need
// into another array
for (var i = 0; i < myArray.length; i++) {
if (!this.someFunction(obj)) {
break;
} else {
// push things in arraytoGoInPrimiseAll
}
}
if(arraytoGoInPrimiseAll.length > 0){
return Promise.all(arraytoGoInPrimiseAll)
} else {
// do something else
}
};
answered Nov 22 '18 at 11:30
squeekyDavesqueekyDave
407215
I have updated my code, it is tested and it works on my machine with the mock data I feed it with. I am not exactly sure how the rest of your code is structured but it is something likes this: Oh and you cannot break out of a map, but we will use a simple for loop because we can break out of that:
function someFunction(){
return new Promise(function (resolve, reject) {
// I will be rejeccting a boolean
// If you are resolving something, resolve it as true
reject(false)
})}
async function shouldStopLoop(){
// the boolean will come here
// if it is false, the catch block will return
// if it is true, the try block will return
let stopLoop = null;
let result = null;
try {
result = await someFunction();
return result
} catch(error) {
stopLoop = error;
return stopLoop;
}
}
function mayReturnPromiseAll() {
let myArray = ['stuf to loop over...']
let arraytoGoInPrimiseAll = ;
// Array.prototype.map cannot be stopped
// Thats why we will use a for loop and we will push the data we need
// into another array
for (var i = 0; i < myArray.length; i++) {
if (!this.someFunction(obj)) {
break;
} else {
// push things in arraytoGoInPrimiseAll
}
}
if(arraytoGoInPrimiseAll.length > 0){
return Promise.all(arraytoGoInPrimiseAll)
} else {
// do something else
}
};
answered Nov 22 '18 at 11:30
squeekyDavesqueekyDave
407215
edited Nov 22 '18 at 15:16
answered Nov 22 '18 at 11:30
squeekyDavesqueekyDave
407215
answered Nov 22 '18 at 11:30
squeekyDavesqueekyDave
407215
answered Nov 22 '18 at 11:30
squeekyDavesqueekyDave
407215
407215
still works the same. I'm expecting to stop the loop once the promise encountered rejection. Is there a way for this?
– kkumber
Nov 22 '18 at 12:52
add a comment |
still works the same. I'm expecting to stop the loop once the promise encountered rejection. Is there a way for this?
– kkumber
Nov 22 '18 at 12:52
still works the same. I'm expecting to stop the loop once the promise encountered rejection. Is there a way for this?
– kkumber
Nov 22 '18 at 12:52
still works the same. I'm expecting to stop the loop once the promise encountered rejection. Is there a way for this?
– kkumber
Nov 22 '18 at 12:52
add a comment |
0
Try this:
const arrayOfFunctions = myArray.map(obj => this.someFunction(obj))
Promise.all(arrayOfFunctions).then(values => {
console.log(values);
}).catch(error => {
console.log(error)
});
answered Nov 22 '18 at 23:12
DiamantDiamant
10817
add a comment |
0
Try this:
const arrayOfFunctions = myArray.map(obj => this.someFunction(obj))
Promise.all(arrayOfFunctions).then(values => {
console.log(values);
}).catch(error => {
console.log(error)
});
answered Nov 22 '18 at 23:12
DiamantDiamant
10817
add a comment |
0
0
0
Try this:
const arrayOfFunctions = myArray.map(obj => this.someFunction(obj))
Promise.all(arrayOfFunctions).then(values => {
console.log(values);
}).catch(error => {
console.log(error)
});
answered Nov 22 '18 at 23:12
DiamantDiamant
10817
Try this:
const arrayOfFunctions = myArray.map(obj => this.someFunction(obj))
Promise.all(arrayOfFunctions).then(values => {
console.log(values);
}).catch(error => {
console.log(error)
});
answered Nov 22 '18 at 23:12
DiamantDiamant
10817
answered Nov 22 '18 at 23:12
DiamantDiamant
10817
answered Nov 22 '18 at 23:12
DiamantDiamant
10817
answered Nov 22 '18 at 23:12
DiamantDiamant
10817
10817
add a comment |
add a comment |
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1
Promise.alldoes not "loop" anything– Bergi
Nov 22 '18 at 13:24
The map returns an array and it is created "instantly",
Promise.allwill resolve if all promises in the array are resolved and will reject if one rejects. What exactly are you trying to achieve?– koox00
Nov 22 '18 at 14:54