Randomize strings in a list












1















Dim myRandom As New Random

Dim myList As New List(Of String)(New String() {"A", "B", "C"})

myList.OrderBy(Function(i) myRandom.Next).ToList()

For k As Integer = 0 To 2

    MessageBox.Show(myList.Item(k))

Next


When you run the code, you will see that the MessageBoxes show A,B,C.



I want MessageBoxes show B,C,A or C,B,A or A,C,B or A,B,C or B,A,C or C,A,B according to randomized result.



Note: Using Linq is a must.






vb.net winforms linq random







share|improve this question




















  • 1





    https://stackoverflow.com/questions/108819/best-way-to-randomize-an-array-with-net

    – mahlatse
    Nov 22 '18 at 9:40
















1















Dim myRandom As New Random

Dim myList As New List(Of String)(New String() {"A", "B", "C"})

myList.OrderBy(Function(i) myRandom.Next).ToList()

For k As Integer = 0 To 2

    MessageBox.Show(myList.Item(k))

Next


When you run the code, you will see that the MessageBoxes show A,B,C.



I want MessageBoxes show B,C,A or C,B,A or A,C,B or A,B,C or B,A,C or C,A,B according to randomized result.



Note: Using Linq is a must.






vb.net winforms linq random







share|improve this question




















  • 1





    https://stackoverflow.com/questions/108819/best-way-to-randomize-an-array-with-net

    – mahlatse
    Nov 22 '18 at 9:40














1












1








1








Dim myRandom As New Random

Dim myList As New List(Of String)(New String() {"A", "B", "C"})

myList.OrderBy(Function(i) myRandom.Next).ToList()

For k As Integer = 0 To 2

    MessageBox.Show(myList.Item(k))

Next


When you run the code, you will see that the MessageBoxes show A,B,C.



I want MessageBoxes show B,C,A or C,B,A or A,C,B or A,B,C or B,A,C or C,A,B according to randomized result.



Note: Using Linq is a must.






vb.net winforms linq random







share|improve this question
















Dim myRandom As New Random

Dim myList As New List(Of String)(New String() {"A", "B", "C"})

myList.OrderBy(Function(i) myRandom.Next).ToList()

For k As Integer = 0 To 2

    MessageBox.Show(myList.Item(k))

Next


When you run the code, you will see that the MessageBoxes show A,B,C.



I want MessageBoxes show B,C,A or C,B,A or A,C,B or A,B,C or B,A,C or C,A,B according to randomized result.



Note: Using Linq is a must.






vb.net winforms linq random




vb.net winforms linq random






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 22 '18 at 16:27







Danny Scofield

















asked Nov 22 '18 at 9:24









Danny ScofieldDanny Scofield

113




113








  • 1





    https://stackoverflow.com/questions/108819/best-way-to-randomize-an-array-with-net

    – mahlatse
    Nov 22 '18 at 9:40














  • 1





    https://stackoverflow.com/questions/108819/best-way-to-randomize-an-array-with-net

    – mahlatse
    Nov 22 '18 at 9:40








1




1





https://stackoverflow.com/questions/108819/best-way-to-randomize-an-array-with-net

– mahlatse
Nov 22 '18 at 9:40





https://stackoverflow.com/questions/108819/best-way-to-randomize-an-array-with-net

– mahlatse
Nov 22 '18 at 9:40












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The issue is that your code doesn't make any changes to myList. A LINQ query ALWAYS generates a new list. You need to assign the result of ToList back to your myList variable, i.e.



myList = myList.OrderBy(Function(i) myRandom.Next).ToList()





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    active

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    4














    The issue is that your code doesn't make any changes to myList. A LINQ query ALWAYS generates a new list. You need to assign the result of ToList back to your myList variable, i.e.



    myList = myList.OrderBy(Function(i) myRandom.Next).ToList()





    share|improve this answer




























      4














      The issue is that your code doesn't make any changes to myList. A LINQ query ALWAYS generates a new list. You need to assign the result of ToList back to your myList variable, i.e.



      myList = myList.OrderBy(Function(i) myRandom.Next).ToList()





      share|improve this answer


























        4












        4








        4







        The issue is that your code doesn't make any changes to myList. A LINQ query ALWAYS generates a new list. You need to assign the result of ToList back to your myList variable, i.e.



        myList = myList.OrderBy(Function(i) myRandom.Next).ToList()





        share|improve this answer













        The issue is that your code doesn't make any changes to myList. A LINQ query ALWAYS generates a new list. You need to assign the result of ToList back to your myList variable, i.e.



        myList = myList.OrderBy(Function(i) myRandom.Next).ToList()






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 22 '18 at 11:23









        jmcilhinneyjmcilhinney

        25.6k22032




        25.6k22032






























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