CallerFilePathAttribute not returning file path with valid directory separators on azure's linux container...












0















I have the following method in a netcore2.1 web app:



public static void Information(string message, [CallerFilePath] string filePath = "")
{
var fileNameWithoutExtn = Path.GetFileNameWithoutExtension(filePath);
. . .
}


When running on azure app service (windows host) it behaves as expected:




filePath =
C:websrcproductionMyWebsiteControllersChallengeController.cs



fileNameWithoutExtn = ChallengeController







But, when I run this on azure's linux container app service:




filePath =
C:websrcproductionMyWebsiteControllersChallengeController.cs



fileNameWithoutExtn =
C:websrcproductionMyWebsiteControllersChallengeController




And




Path.DirectorySeparatorChar = /



Path.AltDirectorySeparatorChar = /



Path.PathSeparator = :



Path.VolumeSeparatorChar = /




Why is CallerFilePath giving me a path which does not match with DirectorySeparatorChar or AltDirectorySeparatorChar ?



PS: I posted the same in msdn forum but did not get any response, hence posting here. I will update here if I hear there.










share|improve this question



























    0















    I have the following method in a netcore2.1 web app:



    public static void Information(string message, [CallerFilePath] string filePath = "")
    {
    var fileNameWithoutExtn = Path.GetFileNameWithoutExtension(filePath);
    . . .
    }


    When running on azure app service (windows host) it behaves as expected:




    filePath =
    C:websrcproductionMyWebsiteControllersChallengeController.cs



    fileNameWithoutExtn = ChallengeController







    But, when I run this on azure's linux container app service:




    filePath =
    C:websrcproductionMyWebsiteControllersChallengeController.cs



    fileNameWithoutExtn =
    C:websrcproductionMyWebsiteControllersChallengeController




    And




    Path.DirectorySeparatorChar = /



    Path.AltDirectorySeparatorChar = /



    Path.PathSeparator = :



    Path.VolumeSeparatorChar = /




    Why is CallerFilePath giving me a path which does not match with DirectorySeparatorChar or AltDirectorySeparatorChar ?



    PS: I posted the same in msdn forum but did not get any response, hence posting here. I will update here if I hear there.










    share|improve this question

























      0












      0








      0








      I have the following method in a netcore2.1 web app:



      public static void Information(string message, [CallerFilePath] string filePath = "")
      {
      var fileNameWithoutExtn = Path.GetFileNameWithoutExtension(filePath);
      . . .
      }


      When running on azure app service (windows host) it behaves as expected:




      filePath =
      C:websrcproductionMyWebsiteControllersChallengeController.cs



      fileNameWithoutExtn = ChallengeController







      But, when I run this on azure's linux container app service:




      filePath =
      C:websrcproductionMyWebsiteControllersChallengeController.cs



      fileNameWithoutExtn =
      C:websrcproductionMyWebsiteControllersChallengeController




      And




      Path.DirectorySeparatorChar = /



      Path.AltDirectorySeparatorChar = /



      Path.PathSeparator = :



      Path.VolumeSeparatorChar = /




      Why is CallerFilePath giving me a path which does not match with DirectorySeparatorChar or AltDirectorySeparatorChar ?



      PS: I posted the same in msdn forum but did not get any response, hence posting here. I will update here if I hear there.










      share|improve this question














      I have the following method in a netcore2.1 web app:



      public static void Information(string message, [CallerFilePath] string filePath = "")
      {
      var fileNameWithoutExtn = Path.GetFileNameWithoutExtension(filePath);
      . . .
      }


      When running on azure app service (windows host) it behaves as expected:




      filePath =
      C:websrcproductionMyWebsiteControllersChallengeController.cs



      fileNameWithoutExtn = ChallengeController







      But, when I run this on azure's linux container app service:




      filePath =
      C:websrcproductionMyWebsiteControllersChallengeController.cs



      fileNameWithoutExtn =
      C:websrcproductionMyWebsiteControllersChallengeController




      And




      Path.DirectorySeparatorChar = /



      Path.AltDirectorySeparatorChar = /



      Path.PathSeparator = :



      Path.VolumeSeparatorChar = /




      Why is CallerFilePath giving me a path which does not match with DirectorySeparatorChar or AltDirectorySeparatorChar ?



      PS: I posted the same in msdn forum but did not get any response, hence posting here. I will update here if I hear there.







      linux azure azure-web-app-service






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 23 '18 at 9:28









      TanyTany

      545317




      545317
























          1 Answer
          1






          active

          oldest

          votes


















          1














          This is because:



          a) Linux uses '' as directory separator, while Windows uses '/'

          b) CallerFilePath returns the path on compile time. The code was compiled on Windows, not on Linux.



          So you get filePath = C:websrcproductionMyWebsiteControllersChallengeController.cs



          A workaround for this is write your own method to get file name, like:



              static void Main(string args)
          {
          char DirectorySeparatorChar='\';

          string path = @"C:websrcproductionMyWebsiteControllersChallengeController.cs";

          string fileName = GetFileNameWithoutExtension(path, DirectorySeparatorChar);

          }

          public static String GetFileName(String path,char DirectorySeparatorChar)
          {
          if (path != null)
          {
          int length = path.Length;
          for (int i = length; --i >= 0;)
          {
          char ch = path[i];
          if (ch == DirectorySeparatorChar )
          return path.Substring(i + 1, length - i - 1);

          }
          }
          return path;
          }

          public static String GetFileNameWithoutExtension(String path, char DirectorySeparatorChar)
          {
          path = GetFileName(path, DirectorySeparatorChar);
          if (path != null)
          {
          int i;
          if ((i = path.LastIndexOf('.')) == -1)
          return path;
          else
          return path.Substring(0, i);
          }
          return null;
          }`





          share|improve this answer
























          • Thanks. I missed the part 'CallerFilePath returns the path on compile time'. Now, this is clear.

            – Tany
            Nov 26 '18 at 7:06













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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          This is because:



          a) Linux uses '' as directory separator, while Windows uses '/'

          b) CallerFilePath returns the path on compile time. The code was compiled on Windows, not on Linux.



          So you get filePath = C:websrcproductionMyWebsiteControllersChallengeController.cs



          A workaround for this is write your own method to get file name, like:



              static void Main(string args)
          {
          char DirectorySeparatorChar='\';

          string path = @"C:websrcproductionMyWebsiteControllersChallengeController.cs";

          string fileName = GetFileNameWithoutExtension(path, DirectorySeparatorChar);

          }

          public static String GetFileName(String path,char DirectorySeparatorChar)
          {
          if (path != null)
          {
          int length = path.Length;
          for (int i = length; --i >= 0;)
          {
          char ch = path[i];
          if (ch == DirectorySeparatorChar )
          return path.Substring(i + 1, length - i - 1);

          }
          }
          return path;
          }

          public static String GetFileNameWithoutExtension(String path, char DirectorySeparatorChar)
          {
          path = GetFileName(path, DirectorySeparatorChar);
          if (path != null)
          {
          int i;
          if ((i = path.LastIndexOf('.')) == -1)
          return path;
          else
          return path.Substring(0, i);
          }
          return null;
          }`





          share|improve this answer
























          • Thanks. I missed the part 'CallerFilePath returns the path on compile time'. Now, this is clear.

            – Tany
            Nov 26 '18 at 7:06


















          1














          This is because:



          a) Linux uses '' as directory separator, while Windows uses '/'

          b) CallerFilePath returns the path on compile time. The code was compiled on Windows, not on Linux.



          So you get filePath = C:websrcproductionMyWebsiteControllersChallengeController.cs



          A workaround for this is write your own method to get file name, like:



              static void Main(string args)
          {
          char DirectorySeparatorChar='\';

          string path = @"C:websrcproductionMyWebsiteControllersChallengeController.cs";

          string fileName = GetFileNameWithoutExtension(path, DirectorySeparatorChar);

          }

          public static String GetFileName(String path,char DirectorySeparatorChar)
          {
          if (path != null)
          {
          int length = path.Length;
          for (int i = length; --i >= 0;)
          {
          char ch = path[i];
          if (ch == DirectorySeparatorChar )
          return path.Substring(i + 1, length - i - 1);

          }
          }
          return path;
          }

          public static String GetFileNameWithoutExtension(String path, char DirectorySeparatorChar)
          {
          path = GetFileName(path, DirectorySeparatorChar);
          if (path != null)
          {
          int i;
          if ((i = path.LastIndexOf('.')) == -1)
          return path;
          else
          return path.Substring(0, i);
          }
          return null;
          }`





          share|improve this answer
























          • Thanks. I missed the part 'CallerFilePath returns the path on compile time'. Now, this is clear.

            – Tany
            Nov 26 '18 at 7:06
















          1












          1








          1







          This is because:



          a) Linux uses '' as directory separator, while Windows uses '/'

          b) CallerFilePath returns the path on compile time. The code was compiled on Windows, not on Linux.



          So you get filePath = C:websrcproductionMyWebsiteControllersChallengeController.cs



          A workaround for this is write your own method to get file name, like:



              static void Main(string args)
          {
          char DirectorySeparatorChar='\';

          string path = @"C:websrcproductionMyWebsiteControllersChallengeController.cs";

          string fileName = GetFileNameWithoutExtension(path, DirectorySeparatorChar);

          }

          public static String GetFileName(String path,char DirectorySeparatorChar)
          {
          if (path != null)
          {
          int length = path.Length;
          for (int i = length; --i >= 0;)
          {
          char ch = path[i];
          if (ch == DirectorySeparatorChar )
          return path.Substring(i + 1, length - i - 1);

          }
          }
          return path;
          }

          public static String GetFileNameWithoutExtension(String path, char DirectorySeparatorChar)
          {
          path = GetFileName(path, DirectorySeparatorChar);
          if (path != null)
          {
          int i;
          if ((i = path.LastIndexOf('.')) == -1)
          return path;
          else
          return path.Substring(0, i);
          }
          return null;
          }`





          share|improve this answer













          This is because:



          a) Linux uses '' as directory separator, while Windows uses '/'

          b) CallerFilePath returns the path on compile time. The code was compiled on Windows, not on Linux.



          So you get filePath = C:websrcproductionMyWebsiteControllersChallengeController.cs



          A workaround for this is write your own method to get file name, like:



              static void Main(string args)
          {
          char DirectorySeparatorChar='\';

          string path = @"C:websrcproductionMyWebsiteControllersChallengeController.cs";

          string fileName = GetFileNameWithoutExtension(path, DirectorySeparatorChar);

          }

          public static String GetFileName(String path,char DirectorySeparatorChar)
          {
          if (path != null)
          {
          int length = path.Length;
          for (int i = length; --i >= 0;)
          {
          char ch = path[i];
          if (ch == DirectorySeparatorChar )
          return path.Substring(i + 1, length - i - 1);

          }
          }
          return path;
          }

          public static String GetFileNameWithoutExtension(String path, char DirectorySeparatorChar)
          {
          path = GetFileName(path, DirectorySeparatorChar);
          if (path != null)
          {
          int i;
          if ((i = path.LastIndexOf('.')) == -1)
          return path;
          else
          return path.Substring(0, i);
          }
          return null;
          }`






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 26 '18 at 6:47









          Joey CaiJoey Cai

          5,037129




          5,037129













          • Thanks. I missed the part 'CallerFilePath returns the path on compile time'. Now, this is clear.

            – Tany
            Nov 26 '18 at 7:06





















          • Thanks. I missed the part 'CallerFilePath returns the path on compile time'. Now, this is clear.

            – Tany
            Nov 26 '18 at 7:06



















          Thanks. I missed the part 'CallerFilePath returns the path on compile time'. Now, this is clear.

          – Tany
          Nov 26 '18 at 7:06







          Thanks. I missed the part 'CallerFilePath returns the path on compile time'. Now, this is clear.

          – Tany
          Nov 26 '18 at 7:06






















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