How to show that randperm() in matlab is fair












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Suppose, I wanted to show (empirically) that randperm(n,k) from matlab indeed produces uniformly distributed random samples of size k from a set N of n elements. How can I plot the number of occurences divided by the total number of k-subsets drawn from N, after drawing repeatedly?










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    0















    Suppose, I wanted to show (empirically) that randperm(n,k) from matlab indeed produces uniformly distributed random samples of size k from a set N of n elements. How can I plot the number of occurences divided by the total number of k-subsets drawn from N, after drawing repeatedly?










    share|improve this question

























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      Suppose, I wanted to show (empirically) that randperm(n,k) from matlab indeed produces uniformly distributed random samples of size k from a set N of n elements. How can I plot the number of occurences divided by the total number of k-subsets drawn from N, after drawing repeatedly?










      share|improve this question














      Suppose, I wanted to show (empirically) that randperm(n,k) from matlab indeed produces uniformly distributed random samples of size k from a set N of n elements. How can I plot the number of occurences divided by the total number of k-subsets drawn from N, after drawing repeatedly?







      matlab probability combinatorics






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      asked Nov 23 '18 at 9:24









      Christian SingerChristian Singer

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      125210
























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          You can simply use the indices drawn from randperm to increment a counter vector.



          n=1e5;
          k=1e4;
          maxiter = 1e5;

          % This array will be used to count the number of times each integer has been drawn
          count=zeros(n,1);

          for ii=1:maxiter
          p=randperm(n,k);
          % p is a vector of k distinct integers in the 1:n range
          % the array count will be incremented at indices given by p
          count(p)=count(p)+1;
          end

          % A total of k*maxiter integers has been drawn and they should be evenly
          % distributed over n values
          % The following vector should have values close to 1 for large values of maxiter
          prob = count*n/(k*maxiter);





          share|improve this answer


























          • @Ander Biguri done

            – Brice
            Nov 23 '18 at 11:33











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          You can simply use the indices drawn from randperm to increment a counter vector.



          n=1e5;
          k=1e4;
          maxiter = 1e5;

          % This array will be used to count the number of times each integer has been drawn
          count=zeros(n,1);

          for ii=1:maxiter
          p=randperm(n,k);
          % p is a vector of k distinct integers in the 1:n range
          % the array count will be incremented at indices given by p
          count(p)=count(p)+1;
          end

          % A total of k*maxiter integers has been drawn and they should be evenly
          % distributed over n values
          % The following vector should have values close to 1 for large values of maxiter
          prob = count*n/(k*maxiter);





          share|improve this answer


























          • @Ander Biguri done

            – Brice
            Nov 23 '18 at 11:33
















          1














          You can simply use the indices drawn from randperm to increment a counter vector.



          n=1e5;
          k=1e4;
          maxiter = 1e5;

          % This array will be used to count the number of times each integer has been drawn
          count=zeros(n,1);

          for ii=1:maxiter
          p=randperm(n,k);
          % p is a vector of k distinct integers in the 1:n range
          % the array count will be incremented at indices given by p
          count(p)=count(p)+1;
          end

          % A total of k*maxiter integers has been drawn and they should be evenly
          % distributed over n values
          % The following vector should have values close to 1 for large values of maxiter
          prob = count*n/(k*maxiter);





          share|improve this answer


























          • @Ander Biguri done

            – Brice
            Nov 23 '18 at 11:33














          1












          1








          1







          You can simply use the indices drawn from randperm to increment a counter vector.



          n=1e5;
          k=1e4;
          maxiter = 1e5;

          % This array will be used to count the number of times each integer has been drawn
          count=zeros(n,1);

          for ii=1:maxiter
          p=randperm(n,k);
          % p is a vector of k distinct integers in the 1:n range
          % the array count will be incremented at indices given by p
          count(p)=count(p)+1;
          end

          % A total of k*maxiter integers has been drawn and they should be evenly
          % distributed over n values
          % The following vector should have values close to 1 for large values of maxiter
          prob = count*n/(k*maxiter);





          share|improve this answer















          You can simply use the indices drawn from randperm to increment a counter vector.



          n=1e5;
          k=1e4;
          maxiter = 1e5;

          % This array will be used to count the number of times each integer has been drawn
          count=zeros(n,1);

          for ii=1:maxiter
          p=randperm(n,k);
          % p is a vector of k distinct integers in the 1:n range
          % the array count will be incremented at indices given by p
          count(p)=count(p)+1;
          end

          % A total of k*maxiter integers has been drawn and they should be evenly
          % distributed over n values
          % The following vector should have values close to 1 for large values of maxiter
          prob = count*n/(k*maxiter);






          share|improve this answer














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          share|improve this answer








          edited Nov 23 '18 at 11:32

























          answered Nov 23 '18 at 9:34









          BriceBrice

          1,400110




          1,400110













          • @Ander Biguri done

            – Brice
            Nov 23 '18 at 11:33



















          • @Ander Biguri done

            – Brice
            Nov 23 '18 at 11:33

















          @Ander Biguri done

          – Brice
          Nov 23 '18 at 11:33





          @Ander Biguri done

          – Brice
          Nov 23 '18 at 11:33




















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