Passing array unsigned in a function recursion in C
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How do I use array as argument in recursion?
The procedure
void divide(int arr, int i, int j, int max, int min){
//Deklarasi
int min1, min2, max1, max2, k;//Algoritma
//1 Elemen
if(i == j){
min = arr[i];
max = arr[i];
}
else{
//2 Elemen
if(i == j-1){
if (arr[i] > arr[j]){
max = arr[i];
min = arr[j];
}
else{
max = arr[j];
min = arr[i];
}
}
//>2 Elemen
else{
k = (i+j)/2;
divide(arr[j],i,k,max1,min1);
divide(arr[j],k+1,j,max2,min2);
min = (min1>min2) ? (min2) : (min1);
max = (max1>max2) ? (max1) : (max2);
}
}
}
The main
int main(){
int i,j,min,max,x;
i = 1;
scanf("%d",&j);
//Input the array
int arr[j];
for(x=0;x<j;x++){
scanf("%d",&arr[x]);
}
divide(arr[j],i,j,max,min);
printf("%d %d", min, max);
}
when I execute the code, I can input the size and the array, but the program can't run(error)
Please help me, how do I pass array in a function?
c
asked Nov 20 at 1:29
Ananda Vj
64
add a comment |
up vote
-1
down vote
favorite
How do I use array as argument in recursion?
The procedure
void divide(int arr, int i, int j, int max, int min){
//Deklarasi
int min1, min2, max1, max2, k;//Algoritma
//1 Elemen
if(i == j){
min = arr[i];
max = arr[i];
}
else{
//2 Elemen
if(i == j-1){
if (arr[i] > arr[j]){
max = arr[i];
min = arr[j];
}
else{
max = arr[j];
min = arr[i];
}
}
//>2 Elemen
else{
k = (i+j)/2;
divide(arr[j],i,k,max1,min1);
divide(arr[j],k+1,j,max2,min2);
min = (min1>min2) ? (min2) : (min1);
max = (max1>max2) ? (max1) : (max2);
}
}
}
The main
int main(){
int i,j,min,max,x;
i = 1;
scanf("%d",&j);
//Input the array
int arr[j];
for(x=0;x<j;x++){
scanf("%d",&arr[x]);
}
divide(arr[j],i,j,max,min);
printf("%d %d", min, max);
}
when I execute the code, I can input the size and the array, but the program can't run(error)
Please help me, how do I pass array in a function?
c
asked Nov 20 at 1:29
Ananda Vj
64
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
How do I use array as argument in recursion?
The procedure
void divide(int arr, int i, int j, int max, int min){
//Deklarasi
int min1, min2, max1, max2, k;//Algoritma
//1 Elemen
if(i == j){
min = arr[i];
max = arr[i];
}
else{
//2 Elemen
if(i == j-1){
if (arr[i] > arr[j]){
max = arr[i];
min = arr[j];
}
else{
max = arr[j];
min = arr[i];
}
}
//>2 Elemen
else{
k = (i+j)/2;
divide(arr[j],i,k,max1,min1);
divide(arr[j],k+1,j,max2,min2);
min = (min1>min2) ? (min2) : (min1);
max = (max1>max2) ? (max1) : (max2);
}
}
}
The main
int main(){
int i,j,min,max,x;
i = 1;
scanf("%d",&j);
//Input the array
int arr[j];
for(x=0;x<j;x++){
scanf("%d",&arr[x]);
}
divide(arr[j],i,j,max,min);
printf("%d %d", min, max);
}
when I execute the code, I can input the size and the array, but the program can't run(error)
Please help me, how do I pass array in a function?
c
asked Nov 20 at 1:29
Ananda Vj
64
How do I use array as argument in recursion?
The procedure
void divide(int arr, int i, int j, int max, int min){
//Deklarasi
int min1, min2, max1, max2, k;//Algoritma
//1 Elemen
if(i == j){
min = arr[i];
max = arr[i];
}
else{
//2 Elemen
if(i == j-1){
if (arr[i] > arr[j]){
max = arr[i];
min = arr[j];
}
else{
max = arr[j];
min = arr[i];
}
}
//>2 Elemen
else{
k = (i+j)/2;
divide(arr[j],i,k,max1,min1);
divide(arr[j],k+1,j,max2,min2);
min = (min1>min2) ? (min2) : (min1);
max = (max1>max2) ? (max1) : (max2);
}
}
}
The main
int main(){
int i,j,min,max,x;
i = 1;
scanf("%d",&j);
//Input the array
int arr[j];
for(x=0;x<j;x++){
scanf("%d",&arr[x]);
}
divide(arr[j],i,j,max,min);
printf("%d %d", min, max);
}
when I execute the code, I can input the size and the array, but the program can't run(error)
Please help me, how do I pass array in a function?
c
c
asked Nov 20 at 1:29
Ananda Vj
64
asked Nov 20 at 1:29
Ananda Vj
64
edited Nov 20 at 2:01
asked Nov 20 at 1:29
Ananda Vj
64
asked Nov 20 at 1:29
Ananda Vj
64
asked Nov 20 at 1:29
Ananda Vj
64
64
add a comment |
add a comment |
1 Answer
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oldest
votes
up vote
1
down vote
accepted
When you call divide, you need to pass arr, not arr[j]. arr[j] is just a single element of the array. Also you may want to pass in your min and max as pointers so that you actually get the new values in your main function.
answered Nov 20 at 1:37
ahota
37128
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
When you call divide, you need to pass arr, not arr[j]. arr[j] is just a single element of the array. Also you may want to pass in your min and max as pointers so that you actually get the new values in your main function.
answered Nov 20 at 1:37
ahota
37128
add a comment |
up vote
1
down vote
accepted
When you call divide, you need to pass arr, not arr[j]. arr[j] is just a single element of the array. Also you may want to pass in your min and max as pointers so that you actually get the new values in your main function.
answered Nov 20 at 1:37
ahota
37128
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
When you call divide, you need to pass arr, not arr[j]. arr[j] is just a single element of the array. Also you may want to pass in your min and max as pointers so that you actually get the new values in your main function.
answered Nov 20 at 1:37
ahota
37128
When you call divide, you need to pass arr, not arr[j]. arr[j] is just a single element of the array. Also you may want to pass in your min and max as pointers so that you actually get the new values in your main function.
answered Nov 20 at 1:37
ahota
37128
answered Nov 20 at 1:37
ahota
37128
answered Nov 20 at 1:37
ahota
37128
answered Nov 20 at 1:37
ahota
37128
37128
add a comment |
add a comment |
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