AngularJS radio button groups with name attribute not initializing properly

up vote
0
down vote

favorite

The radio buttons group doesn't seem to initialize property inside a ng-repeat block if we specify the name attribute to the group. It seems working for the last set of radio groups, but not for the rest. Also, it works fine if I remove the name attribute. Per [AngularJS documentation][1], the name attribute is not needed if we use it with ngModel. But it doesn't say we must not use it. And I need to specify a name attribute.

Please refer to the example below:

var m = angular.module("MyApp", );



m.controller("MyController", ["$scope", function($scope) {

  

  $scope.myArr = [{

    name: "Obj 1",

    status: "a"

  }, {

    name: "Obj 2",

    status: "b"

  }, {

    name: "Obj 3",

    status: "c"

  }];

}]);

body {

  background-color: #1D1F20;

}

 

.row {

  margin-bottom: 15px;

}



.demo {

  background: green;

  color: white;

  padding: 10px;

  border-radius: 3px;

  min-width: 200px;

}

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>

<div ng-app="MyApp" ng-controller="MyController" class="demo">

    <div ng-repeat="eachItem in myArr" class="row">

        

        <span>{{eachItem.name}} => </span>

        

        <label> a

          <input name="status-$index" type="radio" ng-model="eachItem.status" value="a">

        </label>

        

        <label> b

          <input name="status-$index" type="radio" ng-model="eachItem.status" value="b">

        </label>

        

        <label> c

          <input name="status-$index" type="radio" ng-model="eachItem.status" value="c">

        </label>

        

    </div>

</div>

edited Nov 19 at 17:33

asked Nov 19 at 17:15

Manoj Shrestha

1,39411832

1

Try <input name="status-{{ $index }}" type="radio" ng-model="eachItem.status" value="a">
– Mickers
Nov 19 at 17:31

Awesome. That worked. Thanks @Mickers.
– Manoj Shrestha
Nov 19 at 17:37

add a comment |

up vote
0
down vote

favorite

Please refer to the example below:

var m = angular.module("MyApp", );



m.controller("MyController", ["$scope", function($scope) {

  

  $scope.myArr = [{

    name: "Obj 1",

    status: "a"

  }, {

    name: "Obj 2",

    status: "b"

  }, {

    name: "Obj 3",

    status: "c"

  }];

}]);

body {

  background-color: #1D1F20;

}

 

.row {

  margin-bottom: 15px;

}



.demo {

  background: green;

  color: white;

  padding: 10px;

  border-radius: 3px;

  min-width: 200px;

}

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>

<div ng-app="MyApp" ng-controller="MyController" class="demo">

    <div ng-repeat="eachItem in myArr" class="row">

        

        <span>{{eachItem.name}} => </span>

        

        <label> a

          <input name="status-$index" type="radio" ng-model="eachItem.status" value="a">

        </label>

        

        <label> b

          <input name="status-$index" type="radio" ng-model="eachItem.status" value="b">

        </label>

        

        <label> c

          <input name="status-$index" type="radio" ng-model="eachItem.status" value="c">

        </label>

        

    </div>

</div>

edited Nov 19 at 17:33

asked Nov 19 at 17:15

Manoj Shrestha

1,39411832

1

Try <input name="status-{{ $index }}" type="radio" ng-model="eachItem.status" value="a">
– Mickers
Nov 19 at 17:31

Awesome. That worked. Thanks @Mickers.
– Manoj Shrestha
Nov 19 at 17:37

add a comment |

up vote
0
down vote

favorite

Please refer to the example below:

var m = angular.module("MyApp", );



m.controller("MyController", ["$scope", function($scope) {

  

  $scope.myArr = [{

    name: "Obj 1",

    status: "a"

  }, {

    name: "Obj 2",

    status: "b"

  }, {

    name: "Obj 3",

    status: "c"

  }];

}]);

body {

  background-color: #1D1F20;

}

 

.row {

  margin-bottom: 15px;

}



.demo {

  background: green;

  color: white;

  padding: 10px;

  border-radius: 3px;

  min-width: 200px;

}

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>

<div ng-app="MyApp" ng-controller="MyController" class="demo">

    <div ng-repeat="eachItem in myArr" class="row">

        

        <span>{{eachItem.name}} => </span>

        

        <label> a

          <input name="status-$index" type="radio" ng-model="eachItem.status" value="a">

        </label>

        

        <label> b

          <input name="status-$index" type="radio" ng-model="eachItem.status" value="b">

        </label>

        

        <label> c

          <input name="status-$index" type="radio" ng-model="eachItem.status" value="c">

        </label>

        

    </div>

</div>

edited Nov 19 at 17:33

asked Nov 19 at 17:15

Manoj Shrestha

1,39411832

Please refer to the example below:

var m = angular.module("MyApp", );



m.controller("MyController", ["$scope", function($scope) {

  

  $scope.myArr = [{

    name: "Obj 1",

    status: "a"

  }, {

    name: "Obj 2",

    status: "b"

  }, {

    name: "Obj 3",

    status: "c"

  }];

}]);

body {

  background-color: #1D1F20;

}

 

.row {

  margin-bottom: 15px;

}



.demo {

  background: green;

  color: white;

  padding: 10px;

  border-radius: 3px;

  min-width: 200px;

}

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>

<div ng-app="MyApp" ng-controller="MyController" class="demo">

    <div ng-repeat="eachItem in myArr" class="row">

        

        <span>{{eachItem.name}} => </span>

        

        <label> a

          <input name="status-$index" type="radio" ng-model="eachItem.status" value="a">

        </label>

        

        <label> b

          <input name="status-$index" type="radio" ng-model="eachItem.status" value="b">

        </label>

        

        <label> c

          <input name="status-$index" type="radio" ng-model="eachItem.status" value="c">

        </label>

        

    </div>

</div>

var m = angular.module("MyApp", );



m.controller("MyController", ["$scope", function($scope) {

  

  $scope.myArr = [{

    name: "Obj 1",

    status: "a"

  }, {

    name: "Obj 2",

    status: "b"

  }, {

    name: "Obj 3",

    status: "c"

  }];

}]);

body {

  background-color: #1D1F20;

}

 

.row {

  margin-bottom: 15px;

}



.demo {

  background: green;

  color: white;

  padding: 10px;

  border-radius: 3px;

  min-width: 200px;

}

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>

<div ng-app="MyApp" ng-controller="MyController" class="demo">

    <div ng-repeat="eachItem in myArr" class="row">

        

        <span>{{eachItem.name}} => </span>

        

        <label> a

          <input name="status-$index" type="radio" ng-model="eachItem.status" value="a">

        </label>

        

        <label> b

          <input name="status-$index" type="radio" ng-model="eachItem.status" value="b">

        </label>

        

        <label> c

          <input name="status-$index" type="radio" ng-model="eachItem.status" value="c">

        </label>

        

    </div>

</div>

var m = angular.module("MyApp", );



m.controller("MyController", ["$scope", function($scope) {

  

  $scope.myArr = [{

    name: "Obj 1",

    status: "a"

  }, {

    name: "Obj 2",

    status: "b"

  }, {

    name: "Obj 3",

    status: "c"

  }];

}]);

body {

  background-color: #1D1F20;

}

 

.row {

  margin-bottom: 15px;

}



.demo {

  background: green;

  color: white;

  padding: 10px;

  border-radius: 3px;

  min-width: 200px;

}

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>

<div ng-app="MyApp" ng-controller="MyController" class="demo">

    <div ng-repeat="eachItem in myArr" class="row">

        

        <span>{{eachItem.name}} => </span>

        

        <label> a

          <input name="status-$index" type="radio" ng-model="eachItem.status" value="a">

        </label>

        

        <label> b

          <input name="status-$index" type="radio" ng-model="eachItem.status" value="b">

        </label>

        

        <label> c

          <input name="status-$index" type="radio" ng-model="eachItem.status" value="c">

        </label>

        

    </div>

</div>

angularjs angularjs-ng-repeat radio-group

edited Nov 19 at 17:33

asked Nov 19 at 17:15

Manoj Shrestha

1,39411832

edited Nov 19 at 17:33

asked Nov 19 at 17:15

Manoj Shrestha

1,39411832

edited Nov 19 at 17:33

asked Nov 19 at 17:15

Manoj Shrestha

1,39411832

asked Nov 19 at 17:15

Manoj Shrestha

1,39411832

asked Nov 19 at 17:15

Manoj Shrestha

1,39411832

1

Try <input name="status-{{ $index }}" type="radio" ng-model="eachItem.status" value="a">
– Mickers
Nov 19 at 17:31

Awesome. That worked. Thanks @Mickers.
– Manoj Shrestha
Nov 19 at 17:37

add a comment |

1

Try <input name="status-{{ $index }}" type="radio" ng-model="eachItem.status" value="a">
– Mickers
Nov 19 at 17:31

Awesome. That worked. Thanks @Mickers.
– Manoj Shrestha
Nov 19 at 17:37

Try <input name="status-{{ $index }}" type="radio" ng-model="eachItem.status" value="a">
– Mickers
Nov 19 at 17:31

Awesome. That worked. Thanks @Mickers.
– Manoj Shrestha
Nov 19 at 17:37

add a comment |

1 Answer
1

active

oldest

votes

up vote
1
down vote

accepted

Your code looks fine except the place where you are setting the name attribute to input.

$index in template will be evaluated only if you enclose it inside curly brackets.
EX: {{$index}} else you will get $index in the name. You should use:

 <div ng-repeat="eachItem in myArr track by $index" class="row">

   <input name="status-{{$index}}" type="radio" ng-model="eachItem.status" value="a">...

 </div>

answered Nov 20 at 21:28

nkuma_12

53712

add a comment |

Your Answer

StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});

}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53379646%2fangularjs-radio-button-groups-with-name-attribute-not-initializing-properly%23new-answer', 'question_page');
}
);

Post as a guest

Name

Required, but never shown

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
1
down vote

accepted

Your code looks fine except the place where you are setting the name attribute to input.

$index in template will be evaluated only if you enclose it inside curly brackets.
EX: {{$index}} else you will get $index in the name. You should use:

 <div ng-repeat="eachItem in myArr track by $index" class="row">

   <input name="status-{{$index}}" type="radio" ng-model="eachItem.status" value="a">...

 </div>

answered Nov 20 at 21:28

nkuma_12

53712

add a comment |

up vote
1
down vote

accepted

Your code looks fine except the place where you are setting the name attribute to input.

$index in template will be evaluated only if you enclose it inside curly brackets.
EX: {{$index}} else you will get $index in the name. You should use:

 <div ng-repeat="eachItem in myArr track by $index" class="row">

   <input name="status-{{$index}}" type="radio" ng-model="eachItem.status" value="a">...

 </div>

answered Nov 20 at 21:28

nkuma_12

53712

add a comment |

up vote
1
down vote

accepted

Your code looks fine except the place where you are setting the name attribute to input.

$index in template will be evaluated only if you enclose it inside curly brackets.
EX: {{$index}} else you will get $index in the name. You should use:

 <div ng-repeat="eachItem in myArr track by $index" class="row">

   <input name="status-{{$index}}" type="radio" ng-model="eachItem.status" value="a">...

 </div>

answered Nov 20 at 21:28

nkuma_12

53712

Your code looks fine except the place where you are setting the name attribute to input.

$index in template will be evaluated only if you enclose it inside curly brackets.
EX: {{$index}} else you will get $index in the name. You should use:

 <div ng-repeat="eachItem in myArr track by $index" class="row">

   <input name="status-{{$index}}" type="radio" ng-model="eachItem.status" value="a">...

 </div>

answered Nov 20 at 21:28

nkuma_12

53712

answered Nov 20 at 21:28

nkuma_12

53712

answered Nov 20 at 21:28

nkuma_12

53712

answered Nov 20 at 21:28

nkuma_12

53712

add a comment |

draft saved

draft discarded

Thanks for contributing an answer to Stack Overflow!

Please be sure to answer the question. Provide details and share your research!

But avoid …

Asking for help, clarification, or responding to other answers.

Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

Some of your past answers have not been well-received, and you're in danger of being blocked from answering.

Please pay close attention to the following guidance:

Please be sure to answer the question. Provide details and share your research!

But avoid …

Asking for help, clarification, or responding to other answers.

Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Name

Required, but never shown

Name

Required, but never shown

This page is only for reference, If you need detailed information, please check here

搜尋此網誌

Nsryjdtyk