How can I deduce the hypotenuse from the information given?
up vote
2
down vote
favorite
I'm going into Machine Learning and am currently brushing up on some Calculus on Coursera. Everything was going smoothly until I got to this word problem:
A ladder rests against a wall. The top of the ladder touches the wall at height $12$ meters. The length of the ladder is $4$ meters longer than the distance from the base of the ladder to the wall. Find the length of the ladder.
I am confused as to how to deduce the hypotenuse from the information given above. And have sat here trying different things with no success. What am I missing?
calculus algebra-precalculus trigonometry
New contributor
add a comment |
up vote
2
down vote
favorite
I'm going into Machine Learning and am currently brushing up on some Calculus on Coursera. Everything was going smoothly until I got to this word problem:
A ladder rests against a wall. The top of the ladder touches the wall at height $12$ meters. The length of the ladder is $4$ meters longer than the distance from the base of the ladder to the wall. Find the length of the ladder.
I am confused as to how to deduce the hypotenuse from the information given above. And have sat here trying different things with no success. What am I missing?
calculus algebra-precalculus trigonometry
New contributor
I added the "algebra-precalculus" tag to your post. Cheers!
– Robert Lewis
3 hours ago
Draw a picture with the ladder. Label the sides of the triangle formed by the ladder, the wall, and the floor. If you call the base x, the ladder is x+4. Then use the Pythagorean theorem.
– Joel Pereira
3 hours ago
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I'm going into Machine Learning and am currently brushing up on some Calculus on Coursera. Everything was going smoothly until I got to this word problem:
A ladder rests against a wall. The top of the ladder touches the wall at height $12$ meters. The length of the ladder is $4$ meters longer than the distance from the base of the ladder to the wall. Find the length of the ladder.
I am confused as to how to deduce the hypotenuse from the information given above. And have sat here trying different things with no success. What am I missing?
calculus algebra-precalculus trigonometry
New contributor
I'm going into Machine Learning and am currently brushing up on some Calculus on Coursera. Everything was going smoothly until I got to this word problem:
A ladder rests against a wall. The top of the ladder touches the wall at height $12$ meters. The length of the ladder is $4$ meters longer than the distance from the base of the ladder to the wall. Find the length of the ladder.
I am confused as to how to deduce the hypotenuse from the information given above. And have sat here trying different things with no success. What am I missing?
calculus algebra-precalculus trigonometry
calculus algebra-precalculus trigonometry
New contributor
New contributor
edited 3 hours ago
Key Flex
7,11441229
7,11441229
New contributor
asked 3 hours ago
Edward Severinsen
1133
1133
New contributor
New contributor
I added the "algebra-precalculus" tag to your post. Cheers!
– Robert Lewis
3 hours ago
Draw a picture with the ladder. Label the sides of the triangle formed by the ladder, the wall, and the floor. If you call the base x, the ladder is x+4. Then use the Pythagorean theorem.
– Joel Pereira
3 hours ago
add a comment |
I added the "algebra-precalculus" tag to your post. Cheers!
– Robert Lewis
3 hours ago
Draw a picture with the ladder. Label the sides of the triangle formed by the ladder, the wall, and the floor. If you call the base x, the ladder is x+4. Then use the Pythagorean theorem.
– Joel Pereira
3 hours ago
I added the "algebra-precalculus" tag to your post. Cheers!
– Robert Lewis
3 hours ago
I added the "algebra-precalculus" tag to your post. Cheers!
– Robert Lewis
3 hours ago
Draw a picture with the ladder. Label the sides of the triangle formed by the ladder, the wall, and the floor. If you call the base x, the ladder is x+4. Then use the Pythagorean theorem.
– Joel Pereira
3 hours ago
Draw a picture with the ladder. Label the sides of the triangle formed by the ladder, the wall, and the floor. If you call the base x, the ladder is x+4. Then use the Pythagorean theorem.
– Joel Pereira
3 hours ago
add a comment |
2 Answers
2
active
oldest
votes
up vote
2
down vote
accepted
Let $d$ be the distance from the ladder to the wall, and $l$ the length of the ladder.
Then
$l = d + 4; tag 1$
since the wall is mos' likely perpendicular to the ground, we may deploy the Pythagorean theorem and write
$l^2 = (12)^2 + d^2; tag 2$
substituting (1) into (2) yields
$(d + 4)^2 = 144 + d^2, tag 3$
$d^2 + 8d + 16 = 144 + d^2, tag 4$
$8d + 16 = 144 Longrightarrow 8d = 128 Longrightarrow d = 16M Longrightarrow l = 20M. tag 5$
1
Oh my. I distributed the 2 exponent tod
and4
individually instead of multiplying the expression by itself. Not the first time this has gotten me.
– Edward Severinsen
3 hours ago
@EdwardSeverinsen: we're all learners, my friend!
– Robert Lewis
3 hours ago
add a comment |
up vote
3
down vote
Given the length of the wall as $12$.
Take the length of the base as $x$.
Since, the length of the ladder is $4$ times greater than the base we have $x+4$
Now according to the pythagorean theorem we have,
$$(x+4)^2=12^2+x^2$$
$$x^2+16+8x=144+x^2$$
$$8x=128$$
$$x=16$$
So, the length of the ladder $=x+4implies 16+4=20$
1
Nice graphic, +1!
– Robert Lewis
3 hours ago
1
@RobertLewis Thanks!
– Key Flex
3 hours ago
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
Let $d$ be the distance from the ladder to the wall, and $l$ the length of the ladder.
Then
$l = d + 4; tag 1$
since the wall is mos' likely perpendicular to the ground, we may deploy the Pythagorean theorem and write
$l^2 = (12)^2 + d^2; tag 2$
substituting (1) into (2) yields
$(d + 4)^2 = 144 + d^2, tag 3$
$d^2 + 8d + 16 = 144 + d^2, tag 4$
$8d + 16 = 144 Longrightarrow 8d = 128 Longrightarrow d = 16M Longrightarrow l = 20M. tag 5$
1
Oh my. I distributed the 2 exponent tod
and4
individually instead of multiplying the expression by itself. Not the first time this has gotten me.
– Edward Severinsen
3 hours ago
@EdwardSeverinsen: we're all learners, my friend!
– Robert Lewis
3 hours ago
add a comment |
up vote
2
down vote
accepted
Let $d$ be the distance from the ladder to the wall, and $l$ the length of the ladder.
Then
$l = d + 4; tag 1$
since the wall is mos' likely perpendicular to the ground, we may deploy the Pythagorean theorem and write
$l^2 = (12)^2 + d^2; tag 2$
substituting (1) into (2) yields
$(d + 4)^2 = 144 + d^2, tag 3$
$d^2 + 8d + 16 = 144 + d^2, tag 4$
$8d + 16 = 144 Longrightarrow 8d = 128 Longrightarrow d = 16M Longrightarrow l = 20M. tag 5$
1
Oh my. I distributed the 2 exponent tod
and4
individually instead of multiplying the expression by itself. Not the first time this has gotten me.
– Edward Severinsen
3 hours ago
@EdwardSeverinsen: we're all learners, my friend!
– Robert Lewis
3 hours ago
add a comment |
up vote
2
down vote
accepted
up vote
2
down vote
accepted
Let $d$ be the distance from the ladder to the wall, and $l$ the length of the ladder.
Then
$l = d + 4; tag 1$
since the wall is mos' likely perpendicular to the ground, we may deploy the Pythagorean theorem and write
$l^2 = (12)^2 + d^2; tag 2$
substituting (1) into (2) yields
$(d + 4)^2 = 144 + d^2, tag 3$
$d^2 + 8d + 16 = 144 + d^2, tag 4$
$8d + 16 = 144 Longrightarrow 8d = 128 Longrightarrow d = 16M Longrightarrow l = 20M. tag 5$
Let $d$ be the distance from the ladder to the wall, and $l$ the length of the ladder.
Then
$l = d + 4; tag 1$
since the wall is mos' likely perpendicular to the ground, we may deploy the Pythagorean theorem and write
$l^2 = (12)^2 + d^2; tag 2$
substituting (1) into (2) yields
$(d + 4)^2 = 144 + d^2, tag 3$
$d^2 + 8d + 16 = 144 + d^2, tag 4$
$8d + 16 = 144 Longrightarrow 8d = 128 Longrightarrow d = 16M Longrightarrow l = 20M. tag 5$
answered 3 hours ago
Robert Lewis
42.5k22862
42.5k22862
1
Oh my. I distributed the 2 exponent tod
and4
individually instead of multiplying the expression by itself. Not the first time this has gotten me.
– Edward Severinsen
3 hours ago
@EdwardSeverinsen: we're all learners, my friend!
– Robert Lewis
3 hours ago
add a comment |
1
Oh my. I distributed the 2 exponent tod
and4
individually instead of multiplying the expression by itself. Not the first time this has gotten me.
– Edward Severinsen
3 hours ago
@EdwardSeverinsen: we're all learners, my friend!
– Robert Lewis
3 hours ago
1
1
Oh my. I distributed the 2 exponent to
d
and 4
individually instead of multiplying the expression by itself. Not the first time this has gotten me.– Edward Severinsen
3 hours ago
Oh my. I distributed the 2 exponent to
d
and 4
individually instead of multiplying the expression by itself. Not the first time this has gotten me.– Edward Severinsen
3 hours ago
@EdwardSeverinsen: we're all learners, my friend!
– Robert Lewis
3 hours ago
@EdwardSeverinsen: we're all learners, my friend!
– Robert Lewis
3 hours ago
add a comment |
up vote
3
down vote
Given the length of the wall as $12$.
Take the length of the base as $x$.
Since, the length of the ladder is $4$ times greater than the base we have $x+4$
Now according to the pythagorean theorem we have,
$$(x+4)^2=12^2+x^2$$
$$x^2+16+8x=144+x^2$$
$$8x=128$$
$$x=16$$
So, the length of the ladder $=x+4implies 16+4=20$
1
Nice graphic, +1!
– Robert Lewis
3 hours ago
1
@RobertLewis Thanks!
– Key Flex
3 hours ago
add a comment |
up vote
3
down vote
Given the length of the wall as $12$.
Take the length of the base as $x$.
Since, the length of the ladder is $4$ times greater than the base we have $x+4$
Now according to the pythagorean theorem we have,
$$(x+4)^2=12^2+x^2$$
$$x^2+16+8x=144+x^2$$
$$8x=128$$
$$x=16$$
So, the length of the ladder $=x+4implies 16+4=20$
1
Nice graphic, +1!
– Robert Lewis
3 hours ago
1
@RobertLewis Thanks!
– Key Flex
3 hours ago
add a comment |
up vote
3
down vote
up vote
3
down vote
Given the length of the wall as $12$.
Take the length of the base as $x$.
Since, the length of the ladder is $4$ times greater than the base we have $x+4$
Now according to the pythagorean theorem we have,
$$(x+4)^2=12^2+x^2$$
$$x^2+16+8x=144+x^2$$
$$8x=128$$
$$x=16$$
So, the length of the ladder $=x+4implies 16+4=20$
Given the length of the wall as $12$.
Take the length of the base as $x$.
Since, the length of the ladder is $4$ times greater than the base we have $x+4$
Now according to the pythagorean theorem we have,
$$(x+4)^2=12^2+x^2$$
$$x^2+16+8x=144+x^2$$
$$8x=128$$
$$x=16$$
So, the length of the ladder $=x+4implies 16+4=20$
answered 3 hours ago
Key Flex
7,11441229
7,11441229
1
Nice graphic, +1!
– Robert Lewis
3 hours ago
1
@RobertLewis Thanks!
– Key Flex
3 hours ago
add a comment |
1
Nice graphic, +1!
– Robert Lewis
3 hours ago
1
@RobertLewis Thanks!
– Key Flex
3 hours ago
1
1
Nice graphic, +1!
– Robert Lewis
3 hours ago
Nice graphic, +1!
– Robert Lewis
3 hours ago
1
1
@RobertLewis Thanks!
– Key Flex
3 hours ago
@RobertLewis Thanks!
– Key Flex
3 hours ago
add a comment |
Edward Severinsen is a new contributor. Be nice, and check out our Code of Conduct.
Edward Severinsen is a new contributor. Be nice, and check out our Code of Conduct.
Edward Severinsen is a new contributor. Be nice, and check out our Code of Conduct.
Edward Severinsen is a new contributor. Be nice, and check out our Code of Conduct.
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I added the "algebra-precalculus" tag to your post. Cheers!
– Robert Lewis
3 hours ago
Draw a picture with the ladder. Label the sides of the triangle formed by the ladder, the wall, and the floor. If you call the base x, the ladder is x+4. Then use the Pythagorean theorem.
– Joel Pereira
3 hours ago