Is it possible to convert 19.5V 3.33A to 12V 5.5A?
I have a laptop charger which has 19.5 V 3.33 A output. I want to use it for raspberry, which needs 5V and 2.5A and for monitor which needs 12V 3A. Is that charger strong enough to run the whole system? Is it possible to convert 19.5V 3.33A with a buck step down to 12V 5.5A which will be connected to monitor and then use an another step down to 5V 2.5A to feed the raspberry, or I have wrong idea about everything? Sorry I do not know much about electrical engineering.
Thanks!
raspberry-pi buck charger step-down laptop
New contributor
add a comment |
I have a laptop charger which has 19.5 V 3.33 A output. I want to use it for raspberry, which needs 5V and 2.5A and for monitor which needs 12V 3A. Is that charger strong enough to run the whole system? Is it possible to convert 19.5V 3.33A with a buck step down to 12V 5.5A which will be connected to monitor and then use an another step down to 5V 2.5A to feed the raspberry, or I have wrong idea about everything? Sorry I do not know much about electrical engineering.
Thanks!
raspberry-pi buck charger step-down laptop
New contributor
This is a bad idea. You'd be better off using power supplies designed for each output, or for suitable combined 5v/12v output.
– Chris Stratton
3 hours ago
Welcome to EE.SE! Keep in mind that "Is it possible ...?" is a yes/no question. In this case, the answer is "Yes". If you're asking us to design it for you, that would be too broad. You would need to specify something about the level of performance you expect as well as what constraints you have on the implementation. What is your specific question?
– Dave Tweed♦
2 hours ago
People who know nothing about EE nor basic Grade X11 physics should stick to buying solutions.
– Tony EE rocketscientist
2 hours ago
A rpi doesn't need 2.5 Amps tho.
– Passerby
1 hour ago
Tibor - Hi, "I have a laptop charger which has 19.5 V 3.33 A output" Just a warning that some laptop chargers sold on Ebay, Amazon, AliExpress etc. which claim to have a quoted current rating, don't really have that rating and can have poor quality or even unsafe internal construction.
– SamGibson
1 hour ago
add a comment |
I have a laptop charger which has 19.5 V 3.33 A output. I want to use it for raspberry, which needs 5V and 2.5A and for monitor which needs 12V 3A. Is that charger strong enough to run the whole system? Is it possible to convert 19.5V 3.33A with a buck step down to 12V 5.5A which will be connected to monitor and then use an another step down to 5V 2.5A to feed the raspberry, or I have wrong idea about everything? Sorry I do not know much about electrical engineering.
Thanks!
raspberry-pi buck charger step-down laptop
New contributor
I have a laptop charger which has 19.5 V 3.33 A output. I want to use it for raspberry, which needs 5V and 2.5A and for monitor which needs 12V 3A. Is that charger strong enough to run the whole system? Is it possible to convert 19.5V 3.33A with a buck step down to 12V 5.5A which will be connected to monitor and then use an another step down to 5V 2.5A to feed the raspberry, or I have wrong idea about everything? Sorry I do not know much about electrical engineering.
Thanks!
raspberry-pi buck charger step-down laptop
raspberry-pi buck charger step-down laptop
New contributor
New contributor
New contributor
asked 3 hours ago
Tibor Galambos
132
132
New contributor
New contributor
This is a bad idea. You'd be better off using power supplies designed for each output, or for suitable combined 5v/12v output.
– Chris Stratton
3 hours ago
Welcome to EE.SE! Keep in mind that "Is it possible ...?" is a yes/no question. In this case, the answer is "Yes". If you're asking us to design it for you, that would be too broad. You would need to specify something about the level of performance you expect as well as what constraints you have on the implementation. What is your specific question?
– Dave Tweed♦
2 hours ago
People who know nothing about EE nor basic Grade X11 physics should stick to buying solutions.
– Tony EE rocketscientist
2 hours ago
A rpi doesn't need 2.5 Amps tho.
– Passerby
1 hour ago
Tibor - Hi, "I have a laptop charger which has 19.5 V 3.33 A output" Just a warning that some laptop chargers sold on Ebay, Amazon, AliExpress etc. which claim to have a quoted current rating, don't really have that rating and can have poor quality or even unsafe internal construction.
– SamGibson
1 hour ago
add a comment |
This is a bad idea. You'd be better off using power supplies designed for each output, or for suitable combined 5v/12v output.
– Chris Stratton
3 hours ago
Welcome to EE.SE! Keep in mind that "Is it possible ...?" is a yes/no question. In this case, the answer is "Yes". If you're asking us to design it for you, that would be too broad. You would need to specify something about the level of performance you expect as well as what constraints you have on the implementation. What is your specific question?
– Dave Tweed♦
2 hours ago
People who know nothing about EE nor basic Grade X11 physics should stick to buying solutions.
– Tony EE rocketscientist
2 hours ago
A rpi doesn't need 2.5 Amps tho.
– Passerby
1 hour ago
Tibor - Hi, "I have a laptop charger which has 19.5 V 3.33 A output" Just a warning that some laptop chargers sold on Ebay, Amazon, AliExpress etc. which claim to have a quoted current rating, don't really have that rating and can have poor quality or even unsafe internal construction.
– SamGibson
1 hour ago
This is a bad idea. You'd be better off using power supplies designed for each output, or for suitable combined 5v/12v output.
– Chris Stratton
3 hours ago
This is a bad idea. You'd be better off using power supplies designed for each output, or for suitable combined 5v/12v output.
– Chris Stratton
3 hours ago
Welcome to EE.SE! Keep in mind that "Is it possible ...?" is a yes/no question. In this case, the answer is "Yes". If you're asking us to design it for you, that would be too broad. You would need to specify something about the level of performance you expect as well as what constraints you have on the implementation. What is your specific question?
– Dave Tweed♦
2 hours ago
Welcome to EE.SE! Keep in mind that "Is it possible ...?" is a yes/no question. In this case, the answer is "Yes". If you're asking us to design it for you, that would be too broad. You would need to specify something about the level of performance you expect as well as what constraints you have on the implementation. What is your specific question?
– Dave Tweed♦
2 hours ago
People who know nothing about EE nor basic Grade X11 physics should stick to buying solutions.
– Tony EE rocketscientist
2 hours ago
People who know nothing about EE nor basic Grade X11 physics should stick to buying solutions.
– Tony EE rocketscientist
2 hours ago
A rpi doesn't need 2.5 Amps tho.
– Passerby
1 hour ago
A rpi doesn't need 2.5 Amps tho.
– Passerby
1 hour ago
Tibor - Hi, "I have a laptop charger which has 19.5 V 3.33 A output" Just a warning that some laptop chargers sold on Ebay, Amazon, AliExpress etc. which claim to have a quoted current rating, don't really have that rating and can have poor quality or even unsafe internal construction.
– SamGibson
1 hour ago
Tibor - Hi, "I have a laptop charger which has 19.5 V 3.33 A output" Just a warning that some laptop chargers sold on Ebay, Amazon, AliExpress etc. which claim to have a quoted current rating, don't really have that rating and can have poor quality or even unsafe internal construction.
– SamGibson
1 hour ago
add a comment |
2 Answers
2
active
oldest
votes
Yes, it is possible
power of laptop charger is = 19.5 * 3.33 = 65 Watts
your loads power:
raspberry pi = 5*2.5 = 12.5 watts
Display = 12 * 3 = 36 watts
total power = 48.5 watts
Total power < power of charger,
you can use it. it will work
Thank you very much!
– Tibor Galambos
3 hours ago
Conversation of energy is not violated, sure. But actually implementing it will require some effort and will probably not turn out economical.
– Chris Stratton
2 hours ago
DC-DC converters are pretty cheap. If you can convert 19.5 V to 12 V with 80% efficiency, and then 12 V to 5 V with 80% efficiency, the numbers work out almost exactly. You get 4.33A @ 12V, the monitor takes 3A, and the remaining 1.33A converts to 5V @ 2.55A. Of course, if you convert directly from 19.5V to 5V, you get almost 3.2A to play with.
– Dave Tweed♦
2 hours ago
add a comment |
The answer to your header question is NO!
Input 19.5x3.33 = 64.935 Watts.
Output 12x5.5 = 66 Watts.
So your new output power is higher then your input power which is against the law of conservation of energy.
But according to your question details your equipment requires only 48.5 Watts.
That is do-able but only if your buck step down converter (or converters) has/have at least 75% efficiency.
But as Chris Stratton already said: it is better to use supplies which are dedicated for the circuits. You will be spending time and effort on something special, whilst there are cheap, ready made solutions. The idiom "penny wise, pound foolish" comes to mind.
sounds like an interesting project Tibor is trying, and he'll probably learn a lot. "it is better to use supplies which are dedicated for the circuits" assumes he isn't doing this to "just" learn more for fun
– Blundell
1 hour ago
add a comment |
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2 Answers
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2 Answers
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votes
Yes, it is possible
power of laptop charger is = 19.5 * 3.33 = 65 Watts
your loads power:
raspberry pi = 5*2.5 = 12.5 watts
Display = 12 * 3 = 36 watts
total power = 48.5 watts
Total power < power of charger,
you can use it. it will work
Thank you very much!
– Tibor Galambos
3 hours ago
Conversation of energy is not violated, sure. But actually implementing it will require some effort and will probably not turn out economical.
– Chris Stratton
2 hours ago
DC-DC converters are pretty cheap. If you can convert 19.5 V to 12 V with 80% efficiency, and then 12 V to 5 V with 80% efficiency, the numbers work out almost exactly. You get 4.33A @ 12V, the monitor takes 3A, and the remaining 1.33A converts to 5V @ 2.55A. Of course, if you convert directly from 19.5V to 5V, you get almost 3.2A to play with.
– Dave Tweed♦
2 hours ago
add a comment |
Yes, it is possible
power of laptop charger is = 19.5 * 3.33 = 65 Watts
your loads power:
raspberry pi = 5*2.5 = 12.5 watts
Display = 12 * 3 = 36 watts
total power = 48.5 watts
Total power < power of charger,
you can use it. it will work
Thank you very much!
– Tibor Galambos
3 hours ago
Conversation of energy is not violated, sure. But actually implementing it will require some effort and will probably not turn out economical.
– Chris Stratton
2 hours ago
DC-DC converters are pretty cheap. If you can convert 19.5 V to 12 V with 80% efficiency, and then 12 V to 5 V with 80% efficiency, the numbers work out almost exactly. You get 4.33A @ 12V, the monitor takes 3A, and the remaining 1.33A converts to 5V @ 2.55A. Of course, if you convert directly from 19.5V to 5V, you get almost 3.2A to play with.
– Dave Tweed♦
2 hours ago
add a comment |
Yes, it is possible
power of laptop charger is = 19.5 * 3.33 = 65 Watts
your loads power:
raspberry pi = 5*2.5 = 12.5 watts
Display = 12 * 3 = 36 watts
total power = 48.5 watts
Total power < power of charger,
you can use it. it will work
Yes, it is possible
power of laptop charger is = 19.5 * 3.33 = 65 Watts
your loads power:
raspberry pi = 5*2.5 = 12.5 watts
Display = 12 * 3 = 36 watts
total power = 48.5 watts
Total power < power of charger,
you can use it. it will work
answered 3 hours ago
Satish Singupuram
5989
5989
Thank you very much!
– Tibor Galambos
3 hours ago
Conversation of energy is not violated, sure. But actually implementing it will require some effort and will probably not turn out economical.
– Chris Stratton
2 hours ago
DC-DC converters are pretty cheap. If you can convert 19.5 V to 12 V with 80% efficiency, and then 12 V to 5 V with 80% efficiency, the numbers work out almost exactly. You get 4.33A @ 12V, the monitor takes 3A, and the remaining 1.33A converts to 5V @ 2.55A. Of course, if you convert directly from 19.5V to 5V, you get almost 3.2A to play with.
– Dave Tweed♦
2 hours ago
add a comment |
Thank you very much!
– Tibor Galambos
3 hours ago
Conversation of energy is not violated, sure. But actually implementing it will require some effort and will probably not turn out economical.
– Chris Stratton
2 hours ago
DC-DC converters are pretty cheap. If you can convert 19.5 V to 12 V with 80% efficiency, and then 12 V to 5 V with 80% efficiency, the numbers work out almost exactly. You get 4.33A @ 12V, the monitor takes 3A, and the remaining 1.33A converts to 5V @ 2.55A. Of course, if you convert directly from 19.5V to 5V, you get almost 3.2A to play with.
– Dave Tweed♦
2 hours ago
Thank you very much!
– Tibor Galambos
3 hours ago
Thank you very much!
– Tibor Galambos
3 hours ago
Conversation of energy is not violated, sure. But actually implementing it will require some effort and will probably not turn out economical.
– Chris Stratton
2 hours ago
Conversation of energy is not violated, sure. But actually implementing it will require some effort and will probably not turn out economical.
– Chris Stratton
2 hours ago
DC-DC converters are pretty cheap. If you can convert 19.5 V to 12 V with 80% efficiency, and then 12 V to 5 V with 80% efficiency, the numbers work out almost exactly. You get 4.33A @ 12V, the monitor takes 3A, and the remaining 1.33A converts to 5V @ 2.55A. Of course, if you convert directly from 19.5V to 5V, you get almost 3.2A to play with.
– Dave Tweed♦
2 hours ago
DC-DC converters are pretty cheap. If you can convert 19.5 V to 12 V with 80% efficiency, and then 12 V to 5 V with 80% efficiency, the numbers work out almost exactly. You get 4.33A @ 12V, the monitor takes 3A, and the remaining 1.33A converts to 5V @ 2.55A. Of course, if you convert directly from 19.5V to 5V, you get almost 3.2A to play with.
– Dave Tweed♦
2 hours ago
add a comment |
The answer to your header question is NO!
Input 19.5x3.33 = 64.935 Watts.
Output 12x5.5 = 66 Watts.
So your new output power is higher then your input power which is against the law of conservation of energy.
But according to your question details your equipment requires only 48.5 Watts.
That is do-able but only if your buck step down converter (or converters) has/have at least 75% efficiency.
But as Chris Stratton already said: it is better to use supplies which are dedicated for the circuits. You will be spending time and effort on something special, whilst there are cheap, ready made solutions. The idiom "penny wise, pound foolish" comes to mind.
sounds like an interesting project Tibor is trying, and he'll probably learn a lot. "it is better to use supplies which are dedicated for the circuits" assumes he isn't doing this to "just" learn more for fun
– Blundell
1 hour ago
add a comment |
The answer to your header question is NO!
Input 19.5x3.33 = 64.935 Watts.
Output 12x5.5 = 66 Watts.
So your new output power is higher then your input power which is against the law of conservation of energy.
But according to your question details your equipment requires only 48.5 Watts.
That is do-able but only if your buck step down converter (or converters) has/have at least 75% efficiency.
But as Chris Stratton already said: it is better to use supplies which are dedicated for the circuits. You will be spending time and effort on something special, whilst there are cheap, ready made solutions. The idiom "penny wise, pound foolish" comes to mind.
sounds like an interesting project Tibor is trying, and he'll probably learn a lot. "it is better to use supplies which are dedicated for the circuits" assumes he isn't doing this to "just" learn more for fun
– Blundell
1 hour ago
add a comment |
The answer to your header question is NO!
Input 19.5x3.33 = 64.935 Watts.
Output 12x5.5 = 66 Watts.
So your new output power is higher then your input power which is against the law of conservation of energy.
But according to your question details your equipment requires only 48.5 Watts.
That is do-able but only if your buck step down converter (or converters) has/have at least 75% efficiency.
But as Chris Stratton already said: it is better to use supplies which are dedicated for the circuits. You will be spending time and effort on something special, whilst there are cheap, ready made solutions. The idiom "penny wise, pound foolish" comes to mind.
The answer to your header question is NO!
Input 19.5x3.33 = 64.935 Watts.
Output 12x5.5 = 66 Watts.
So your new output power is higher then your input power which is against the law of conservation of energy.
But according to your question details your equipment requires only 48.5 Watts.
That is do-able but only if your buck step down converter (or converters) has/have at least 75% efficiency.
But as Chris Stratton already said: it is better to use supplies which are dedicated for the circuits. You will be spending time and effort on something special, whilst there are cheap, ready made solutions. The idiom "penny wise, pound foolish" comes to mind.
answered 2 hours ago
Oldfart
7,8262825
7,8262825
sounds like an interesting project Tibor is trying, and he'll probably learn a lot. "it is better to use supplies which are dedicated for the circuits" assumes he isn't doing this to "just" learn more for fun
– Blundell
1 hour ago
add a comment |
sounds like an interesting project Tibor is trying, and he'll probably learn a lot. "it is better to use supplies which are dedicated for the circuits" assumes he isn't doing this to "just" learn more for fun
– Blundell
1 hour ago
sounds like an interesting project Tibor is trying, and he'll probably learn a lot. "it is better to use supplies which are dedicated for the circuits" assumes he isn't doing this to "just" learn more for fun
– Blundell
1 hour ago
sounds like an interesting project Tibor is trying, and he'll probably learn a lot. "it is better to use supplies which are dedicated for the circuits" assumes he isn't doing this to "just" learn more for fun
– Blundell
1 hour ago
add a comment |
Tibor Galambos is a new contributor. Be nice, and check out our Code of Conduct.
Tibor Galambos is a new contributor. Be nice, and check out our Code of Conduct.
Tibor Galambos is a new contributor. Be nice, and check out our Code of Conduct.
Tibor Galambos is a new contributor. Be nice, and check out our Code of Conduct.
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This is a bad idea. You'd be better off using power supplies designed for each output, or for suitable combined 5v/12v output.
– Chris Stratton
3 hours ago
Welcome to EE.SE! Keep in mind that "Is it possible ...?" is a yes/no question. In this case, the answer is "Yes". If you're asking us to design it for you, that would be too broad. You would need to specify something about the level of performance you expect as well as what constraints you have on the implementation. What is your specific question?
– Dave Tweed♦
2 hours ago
People who know nothing about EE nor basic Grade X11 physics should stick to buying solutions.
– Tony EE rocketscientist
2 hours ago
A rpi doesn't need 2.5 Amps tho.
– Passerby
1 hour ago
Tibor - Hi, "I have a laptop charger which has 19.5 V 3.33 A output" Just a warning that some laptop chargers sold on Ebay, Amazon, AliExpress etc. which claim to have a quoted current rating, don't really have that rating and can have poor quality or even unsafe internal construction.
– SamGibson
1 hour ago