Multiple assignment at once in java
In python you can do this:
def f():
return 1, 2, 3
(foo, bar, baz) = f()
Is there an equivalent in java?
java assign
asked Nov 16 '14 at 13:15
qedqed
9,9341269118
add a comment |
In python you can do this:
def f():
return 1, 2, 3
(foo, bar, baz) = f()
Is there an equivalent in java?
java assign
asked Nov 16 '14 at 13:15
qedqed
9,9341269118
add a comment |
In python you can do this:
def f():
return 1, 2, 3
(foo, bar, baz) = f()
Is there an equivalent in java?
java assign
asked Nov 16 '14 at 13:15
qedqed
9,9341269118
In python you can do this:
def f():
return 1, 2, 3
(foo, bar, baz) = f()
Is there an equivalent in java?
java assign
java assign
asked Nov 16 '14 at 13:15
qedqed
9,9341269118
asked Nov 16 '14 at 13:15
qedqed
9,9341269118
edited Nov 16 '14 at 13:40
qed
asked Nov 16 '14 at 13:15
qedqed
9,9341269118
asked Nov 16 '14 at 13:15
qedqed
9,9341269118
asked Nov 16 '14 at 13:15
qedqed
9,9341269118
9,9341269118
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
tl;dr: No, there isn't such a thing in Java.
You can assign initial values to variables like this:
int foo = 1, bar = 2;
But if your want (1, 2, 3) to be the result of a method call, this is not possible in Java. Java does not allow returning multiple values.
Python allows this:
def foo():
return 1, 2, 3
a, b, c = foo()
The main point, why this does not work in Java is, that the left hand side (LHS) of the assignment must be one variable:
Wrapper wrapper = WrapperGenrator.generateWrapper();
You can not assign to a tuple on the LHS as you can in Python.
add a comment |
If you want (1,2,3) to be the result of a method call, you can use an array:
int arr = {1,2,3};
answered Nov 16 '14 at 13:20
EranEran
288k37467557
1
What about the type of this array? What if is more complex thanint?
– user1907906
Nov 16 '14 at 13:21
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
tl;dr: No, there isn't such a thing in Java.
You can assign initial values to variables like this:
int foo = 1, bar = 2;
But if your want (1, 2, 3) to be the result of a method call, this is not possible in Java. Java does not allow returning multiple values.
Python allows this:
def foo():
return 1, 2, 3
a, b, c = foo()
The main point, why this does not work in Java is, that the left hand side (LHS) of the assignment must be one variable:
Wrapper wrapper = WrapperGenrator.generateWrapper();
You can not assign to a tuple on the LHS as you can in Python.
add a comment |
tl;dr: No, there isn't such a thing in Java.
You can assign initial values to variables like this:
int foo = 1, bar = 2;
But if your want (1, 2, 3) to be the result of a method call, this is not possible in Java. Java does not allow returning multiple values.
Python allows this:
def foo():
return 1, 2, 3
a, b, c = foo()
The main point, why this does not work in Java is, that the left hand side (LHS) of the assignment must be one variable:
Wrapper wrapper = WrapperGenrator.generateWrapper();
You can not assign to a tuple on the LHS as you can in Python.
add a comment |
tl;dr: No, there isn't such a thing in Java.
You can assign initial values to variables like this:
int foo = 1, bar = 2;
But if your want (1, 2, 3) to be the result of a method call, this is not possible in Java. Java does not allow returning multiple values.
Python allows this:
def foo():
return 1, 2, 3
a, b, c = foo()
The main point, why this does not work in Java is, that the left hand side (LHS) of the assignment must be one variable:
Wrapper wrapper = WrapperGenrator.generateWrapper();
You can not assign to a tuple on the LHS as you can in Python.
tl;dr: No, there isn't such a thing in Java.
You can assign initial values to variables like this:
int foo = 1, bar = 2;
But if your want (1, 2, 3) to be the result of a method call, this is not possible in Java. Java does not allow returning multiple values.
Python allows this:
def foo():
return 1, 2, 3
a, b, c = foo()
The main point, why this does not work in Java is, that the left hand side (LHS) of the assignment must be one variable:
Wrapper wrapper = WrapperGenrator.generateWrapper();
You can not assign to a tuple on the LHS as you can in Python.
edited Nov 16 '14 at 13:27
answered Nov 16 '14 at 13:16
user1907906
add a comment |
add a comment |
If you want (1,2,3) to be the result of a method call, you can use an array:
int arr = {1,2,3};
answered Nov 16 '14 at 13:20
EranEran
288k37467557
1
What about the type of this array? What if is more complex thanint?
– user1907906
Nov 16 '14 at 13:21
add a comment |
If you want (1,2,3) to be the result of a method call, you can use an array:
int arr = {1,2,3};
answered Nov 16 '14 at 13:20
EranEran
288k37467557
1
What about the type of this array? What if is more complex thanint?
– user1907906
Nov 16 '14 at 13:21
add a comment |
If you want (1,2,3) to be the result of a method call, you can use an array:
int arr = {1,2,3};
answered Nov 16 '14 at 13:20
EranEran
288k37467557
If you want (1,2,3) to be the result of a method call, you can use an array:
int arr = {1,2,3};
answered Nov 16 '14 at 13:20
EranEran
288k37467557
answered Nov 16 '14 at 13:20
EranEran
288k37467557
answered Nov 16 '14 at 13:20
EranEran
288k37467557
answered Nov 16 '14 at 13:20
EranEran
288k37467557
288k37467557
1
What about the type of this array? What if is more complex thanint?
– user1907906
Nov 16 '14 at 13:21
add a comment |
1
What about the type of this array? What if is more complex thanint?
– user1907906
Nov 16 '14 at 13:21
1
1
What about the type of this array? What if is more complex than
int?– user1907906
Nov 16 '14 at 13:21
What about the type of this array? What if is more complex than
int?– user1907906
Nov 16 '14 at 13:21
add a comment |
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