Check which number is bigger within a function call

Check which number is bigger within a function call - vb.net

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0
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Say I'm using this piece of code

With TextBox

.Size = New Windows.Size(InsideRadius)

End With

I want to choose within the function call which size to use dependent on which is the biggest, If Inside Radius is the biggest then choose that, but if a number such as say 20 is bigger then pick that, all within the call.

So something like this

With TextBox

.Size = New Windows.Size(If (InsideRadius >= 20) Then InsideRadius Else 20 End If)

End With

but I'm unsure how to do this within vb.net, I'm sure it is possible but after some searching I think I'm not typing in the correct question to get what I am looking for. Hope you understand, thanks

asked Nov 19 at 14:26

fodger_rederer

Is InsideRadius a Size? It should be. Are you wanting width or height? docs.microsoft.com/en-us/dotnet/api/…
– dbasnett
Nov 19 at 15:35

Is this vba? vb.net and vba are not the same.
– Mary
Nov 19 at 19:57

add a comment |

up vote
0
down vote

favorite

Say I'm using this piece of code

With TextBox

.Size = New Windows.Size(InsideRadius)

End With

So something like this

With TextBox

.Size = New Windows.Size(If (InsideRadius >= 20) Then InsideRadius Else 20 End If)

End With

but I'm unsure how to do this within vb.net, I'm sure it is possible but after some searching I think I'm not typing in the correct question to get what I am looking for. Hope you understand, thanks

asked Nov 19 at 14:26

fodger_rederer

Is InsideRadius a Size? It should be. Are you wanting width or height? docs.microsoft.com/en-us/dotnet/api/…
– dbasnett
Nov 19 at 15:35

Is this vba? vb.net and vba are not the same.
– Mary
Nov 19 at 19:57

add a comment |

up vote
0
down vote

favorite

Say I'm using this piece of code

With TextBox

.Size = New Windows.Size(InsideRadius)

End With

So something like this

With TextBox

.Size = New Windows.Size(If (InsideRadius >= 20) Then InsideRadius Else 20 End If)

End With

but I'm unsure how to do this within vb.net, I'm sure it is possible but after some searching I think I'm not typing in the correct question to get what I am looking for. Hope you understand, thanks

asked Nov 19 at 14:26

fodger_rederer

Say I'm using this piece of code

With TextBox

.Size = New Windows.Size(InsideRadius)

End With

So something like this

With TextBox

.Size = New Windows.Size(If (InsideRadius >= 20) Then InsideRadius Else 20 End If)

End With

but I'm unsure how to do this within vb.net, I'm sure it is possible but after some searching I think I'm not typing in the correct question to get what I am looking for. Hope you understand, thanks

vb.net

asked Nov 19 at 14:26

fodger_rederer

asked Nov 19 at 14:26

fodger_rederer

asked Nov 19 at 14:26

fodger_rederer

asked Nov 19 at 14:26

fodger_rederer

asked Nov 19 at 14:26

fodger_rederer

Is InsideRadius a Size? It should be. Are you wanting width or height? docs.microsoft.com/en-us/dotnet/api/…
– dbasnett
Nov 19 at 15:35

Is this vba? vb.net and vba are not the same.
– Mary
Nov 19 at 19:57

add a comment |

Is InsideRadius a Size? It should be. Are you wanting width or height? docs.microsoft.com/en-us/dotnet/api/…
– dbasnett
Nov 19 at 15:35

Is this vba? vb.net and vba are not the same.
– Mary
Nov 19 at 19:57

Is InsideRadius a Size? It should be. Are you wanting width or height? docs.microsoft.com/en-us/dotnet/api/…
– dbasnett
Nov 19 at 15:35

Is this vba? vb.net and vba are not the same.
– Mary
Nov 19 at 19:57

add a comment |

2 Answers
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0
down vote

It is possible, it looks like a function that is called if:

If(Statement, True, False)

https://docs.microsoft.com/en-us/dotnet/visual-basic/language-reference/operators/if-operator

answered Nov 19 at 14:32

DaanV

3476

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0
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Math.Max()

Math.Max(InsideRadius, 20)

This will return whichever is the larger number.

TextBox.Size = New Windows.Size(Math.Max(InsideRadius, 20)

answered Nov 20 at 13:08

Gravitate

1,1611125

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
0
down vote

It is possible, it looks like a function that is called if:

If(Statement, True, False)

https://docs.microsoft.com/en-us/dotnet/visual-basic/language-reference/operators/if-operator

answered Nov 19 at 14:32

DaanV

3476

add a comment |

up vote
0
down vote

It is possible, it looks like a function that is called if:

If(Statement, True, False)

https://docs.microsoft.com/en-us/dotnet/visual-basic/language-reference/operators/if-operator

answered Nov 19 at 14:32

DaanV

3476

add a comment |

up vote
0
down vote

It is possible, it looks like a function that is called if:

If(Statement, True, False)

https://docs.microsoft.com/en-us/dotnet/visual-basic/language-reference/operators/if-operator

answered Nov 19 at 14:32

DaanV

3476

It is possible, it looks like a function that is called if:

If(Statement, True, False)

https://docs.microsoft.com/en-us/dotnet/visual-basic/language-reference/operators/if-operator

answered Nov 19 at 14:32

DaanV

3476

answered Nov 19 at 14:32

DaanV

3476

answered Nov 19 at 14:32

DaanV

3476

answered Nov 19 at 14:32

DaanV

3476

add a comment |

up vote
0
down vote

Math.Max()

Math.Max(InsideRadius, 20)

This will return whichever is the larger number.

TextBox.Size = New Windows.Size(Math.Max(InsideRadius, 20)

answered Nov 20 at 13:08

Gravitate

1,1611125

add a comment |

up vote
0
down vote

Math.Max()

Math.Max(InsideRadius, 20)

This will return whichever is the larger number.

TextBox.Size = New Windows.Size(Math.Max(InsideRadius, 20)

answered Nov 20 at 13:08

Gravitate

1,1611125

add a comment |

up vote
0
down vote

Math.Max()

Math.Max(InsideRadius, 20)

This will return whichever is the larger number.

TextBox.Size = New Windows.Size(Math.Max(InsideRadius, 20)

answered Nov 20 at 13:08

Gravitate

1,1611125

Math.Max()

Math.Max(InsideRadius, 20)

This will return whichever is the larger number.

TextBox.Size = New Windows.Size(Math.Max(InsideRadius, 20)

answered Nov 20 at 13:08

Gravitate

1,1611125

answered Nov 20 at 13:08

Gravitate

1,1611125

answered Nov 20 at 13:08

Gravitate

1,1611125

answered Nov 20 at 13:08

Gravitate

1,1611125

add a comment |

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