Nsryjdtyk

I am trying to multiply by a constant a series of number in a string. I have something like that:

my_string = 'AMOUNT="38000" AMOUNT="43000" AMOUNT="56399"'

I can easily do this:

my_new_string = re.sub('(?<=AMOUNT=")d+', lambda _:str(38000 *2), my_string)

This works, but that is not what I need.

What I need as an output as the following:

my_new_string = 'AMOUNT="76000" AMOUNT="86000" AMOUNT="112798"'

Does anyone have an idea on how to proceed? Thank you

You just need to make a little modification:

re.sub('(?<=AMOUNT=")d+', lambda match: str(int(match.group()) * 2), my_string)

The object being passed into lambda is the re.Match object with number you needed. Now you just need to extract the number with .group() method, convert to int * 2 and convert back to str.

You can access the matching group in the lambda, as

re.sub('(?<=AMOUNT=")d+', lambda m:str(int(m.group(0))*2), my_string)

You can define a custom function and use f-strings:

def splitter(x):

    key, val = x.split('=')

    return f'{key}="{int(val[1:-1])*2}"'



mystr = 'AMOUNT="38000" AMOUNT="43000" AMOUNT="56399"'



res = ' '.join(map(splitter, mystr.split()))



'AMOUNT="76000" AMOUNT="86000" AMOUNT="112798"'