Splitting string from backslash
up vote
2
down vote
favorite
I'm trying to split a string from a backslash
a = 'anido_na.nSearch'
I'm trying to scrape anido_ from the string but had no luck using
a.split('\'), a.partition("\").
The string comes from Selenium's
driver.find_element_by_xpath(elem).text,
So I don't think there is anyway of scraping the string any other way.
python python-3.x selenium
edited Nov 19 at 14:29
Andersson
35.8k103066
asked Nov 19 at 14:20
Berkay
134
add a comment |
up vote
2
down vote
favorite
I'm trying to split a string from a backslash
a = 'anido_na.nSearch'
I'm trying to scrape anido_ from the string but had no luck using
a.split('\'), a.partition("\").
The string comes from Selenium's
driver.find_element_by_xpath(elem).text,
So I don't think there is anyway of scraping the string any other way.
python python-3.x selenium
edited Nov 19 at 14:29
Andersson
35.8k103066
asked Nov 19 at 14:20
Berkay
134
Share HTML code sample for the same link
– Andersson
Nov 19 at 14:24
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I'm trying to split a string from a backslash
a = 'anido_na.nSearch'
I'm trying to scrape anido_ from the string but had no luck using
a.split('\'), a.partition("\").
The string comes from Selenium's
driver.find_element_by_xpath(elem).text,
So I don't think there is anyway of scraping the string any other way.
python python-3.x selenium
edited Nov 19 at 14:29
Andersson
35.8k103066
asked Nov 19 at 14:20
Berkay
134
I'm trying to split a string from a backslash
a = 'anido_na.nSearch'
I'm trying to scrape anido_ from the string but had no luck using
a.split('\'), a.partition("\").
The string comes from Selenium's
driver.find_element_by_xpath(elem).text,
So I don't think there is anyway of scraping the string any other way.
python python-3.x selenium
python python-3.x selenium
edited Nov 19 at 14:29
Andersson
35.8k103066
asked Nov 19 at 14:20
Berkay
134
edited Nov 19 at 14:29
Andersson
35.8k103066
asked Nov 19 at 14:20
Berkay
134
edited Nov 19 at 14:29
Andersson
35.8k103066
edited Nov 19 at 14:29
Andersson
35.8k103066
edited Nov 19 at 14:29
Andersson
35.8k103066
35.8k103066
asked Nov 19 at 14:20
Berkay
134
asked Nov 19 at 14:20
Berkay
134
asked Nov 19 at 14:20
Berkay
134
134
Share HTML code sample for the same link
– Andersson
Nov 19 at 14:24
add a comment |
Share HTML code sample for the same link
– Andersson
Nov 19 at 14:24
Share HTML code sample for the same link
– Andersson
Nov 19 at 14:24
Share HTML code sample for the same link
– Andersson
Nov 19 at 14:24
add a comment |
1 Answer
1
active
oldest
votes
up vote
2
down vote
accepted
Try to split as
a = 'anido_na.nSearch'.split('n')[0]
to get "anido_" as output
answered Nov 19 at 14:24
Andersson
35.8k103066
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
Try to split as
a = 'anido_na.nSearch'.split('n')[0]
to get "anido_" as output
answered Nov 19 at 14:24
Andersson
35.8k103066
add a comment |
up vote
2
down vote
accepted
Try to split as
a = 'anido_na.nSearch'.split('n')[0]
to get "anido_" as output
answered Nov 19 at 14:24
Andersson
35.8k103066
add a comment |
up vote
2
down vote
accepted
up vote
2
down vote
accepted
Try to split as
a = 'anido_na.nSearch'.split('n')[0]
to get "anido_" as output
answered Nov 19 at 14:24
Andersson
35.8k103066
Try to split as
a = 'anido_na.nSearch'.split('n')[0]
to get "anido_" as output
answered Nov 19 at 14:24
Andersson
35.8k103066
answered Nov 19 at 14:24
Andersson
35.8k103066
answered Nov 19 at 14:24
Andersson
35.8k103066
answered Nov 19 at 14:24
Andersson
35.8k103066
35.8k103066
add a comment |
add a comment |
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Share HTML code sample for the same link
– Andersson
Nov 19 at 14:24