downloading a docx file from ajaxResponse











up vote
3
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So I tried to download a docx document as a report . by converting ajax response to a blob then an url ! the result is a document word that display a message , " we're sorry . we can't open because we found a problem with it's content .
there the main :
onDownloadReport: function (oEvent) {



var oAjaxBody = {
SessionId: this.getModel("sessionModel").getData().SessionId,
CustomerName: encodeURIComponent(this.getModel("sessionModel").getData().CustomerName.split("n")[0]),
TenantInfo: encodeURIComponent(this.getModel("sessionModel").getData().TenantInfo)
};
var sServiceUrl = "/SDC_XS_TEMP/APPL/SDC/services/serviceRuntime/xsjs/SDC_REPORT_GENERATE_MM.xsjs";

var me = this;
$.ajax({
url: sServiceUrl,
type: "POST",
responseType:'arraybuffer',
contentType: "application/json",
data: JSON.stringify(oAjaxBody),
// dataType: "json",
success: function (oAjaxResponse) {
var content = oAjaxResponse;
var fileName = 'rapport.docx'; // You can use the .txt extension if you want
me.downloadwithpost(fileName, content);
},
error: function (oError) {
console.log("failure");
}

});


and this is the function



downloadwithpost: function (filename, content) {
var link = document.createElement('a');
var bytes = new Array(content.length);
// var bytes = new Array(content.length);
for (var i = 0; i < content.length; i++) {
bytes[i] = content.charCodeAt(i);
}
var byteArray = new Uint8Array(bytes);
var blob = new Blob([byteArray], {
type: "application/vnd.openxmlformats-officedocument.wordprocessingml.document"
});
var url = URL.createObjectURL(blob);
var oItem = {
documentId: url,
fileName: "rapport.docx",
thumbnailUrl: "",
url: url,
selected: true
};
var oUploadCollection = this.getView().byId("uploadCollection");
var newItem = new sap.m.UploadCollectionItem(oItem);
oUploadCollection.addItem(newItem);
oUploadCollection.downloadItem(newItem, true);
}









share|improve this question
























  • Just wondering if the document is an existing document, or if you're generating it?
    – Jorg
    Nov 20 at 11:30















up vote
3
down vote

favorite












So I tried to download a docx document as a report . by converting ajax response to a blob then an url ! the result is a document word that display a message , " we're sorry . we can't open because we found a problem with it's content .
there the main :
onDownloadReport: function (oEvent) {



var oAjaxBody = {
SessionId: this.getModel("sessionModel").getData().SessionId,
CustomerName: encodeURIComponent(this.getModel("sessionModel").getData().CustomerName.split("n")[0]),
TenantInfo: encodeURIComponent(this.getModel("sessionModel").getData().TenantInfo)
};
var sServiceUrl = "/SDC_XS_TEMP/APPL/SDC/services/serviceRuntime/xsjs/SDC_REPORT_GENERATE_MM.xsjs";

var me = this;
$.ajax({
url: sServiceUrl,
type: "POST",
responseType:'arraybuffer',
contentType: "application/json",
data: JSON.stringify(oAjaxBody),
// dataType: "json",
success: function (oAjaxResponse) {
var content = oAjaxResponse;
var fileName = 'rapport.docx'; // You can use the .txt extension if you want
me.downloadwithpost(fileName, content);
},
error: function (oError) {
console.log("failure");
}

});


and this is the function



downloadwithpost: function (filename, content) {
var link = document.createElement('a');
var bytes = new Array(content.length);
// var bytes = new Array(content.length);
for (var i = 0; i < content.length; i++) {
bytes[i] = content.charCodeAt(i);
}
var byteArray = new Uint8Array(bytes);
var blob = new Blob([byteArray], {
type: "application/vnd.openxmlformats-officedocument.wordprocessingml.document"
});
var url = URL.createObjectURL(blob);
var oItem = {
documentId: url,
fileName: "rapport.docx",
thumbnailUrl: "",
url: url,
selected: true
};
var oUploadCollection = this.getView().byId("uploadCollection");
var newItem = new sap.m.UploadCollectionItem(oItem);
oUploadCollection.addItem(newItem);
oUploadCollection.downloadItem(newItem, true);
}









share|improve this question
























  • Just wondering if the document is an existing document, or if you're generating it?
    – Jorg
    Nov 20 at 11:30













up vote
3
down vote

favorite









up vote
3
down vote

favorite











So I tried to download a docx document as a report . by converting ajax response to a blob then an url ! the result is a document word that display a message , " we're sorry . we can't open because we found a problem with it's content .
there the main :
onDownloadReport: function (oEvent) {



var oAjaxBody = {
SessionId: this.getModel("sessionModel").getData().SessionId,
CustomerName: encodeURIComponent(this.getModel("sessionModel").getData().CustomerName.split("n")[0]),
TenantInfo: encodeURIComponent(this.getModel("sessionModel").getData().TenantInfo)
};
var sServiceUrl = "/SDC_XS_TEMP/APPL/SDC/services/serviceRuntime/xsjs/SDC_REPORT_GENERATE_MM.xsjs";

var me = this;
$.ajax({
url: sServiceUrl,
type: "POST",
responseType:'arraybuffer',
contentType: "application/json",
data: JSON.stringify(oAjaxBody),
// dataType: "json",
success: function (oAjaxResponse) {
var content = oAjaxResponse;
var fileName = 'rapport.docx'; // You can use the .txt extension if you want
me.downloadwithpost(fileName, content);
},
error: function (oError) {
console.log("failure");
}

});


and this is the function



downloadwithpost: function (filename, content) {
var link = document.createElement('a');
var bytes = new Array(content.length);
// var bytes = new Array(content.length);
for (var i = 0; i < content.length; i++) {
bytes[i] = content.charCodeAt(i);
}
var byteArray = new Uint8Array(bytes);
var blob = new Blob([byteArray], {
type: "application/vnd.openxmlformats-officedocument.wordprocessingml.document"
});
var url = URL.createObjectURL(blob);
var oItem = {
documentId: url,
fileName: "rapport.docx",
thumbnailUrl: "",
url: url,
selected: true
};
var oUploadCollection = this.getView().byId("uploadCollection");
var newItem = new sap.m.UploadCollectionItem(oItem);
oUploadCollection.addItem(newItem);
oUploadCollection.downloadItem(newItem, true);
}









share|improve this question















So I tried to download a docx document as a report . by converting ajax response to a blob then an url ! the result is a document word that display a message , " we're sorry . we can't open because we found a problem with it's content .
there the main :
onDownloadReport: function (oEvent) {



var oAjaxBody = {
SessionId: this.getModel("sessionModel").getData().SessionId,
CustomerName: encodeURIComponent(this.getModel("sessionModel").getData().CustomerName.split("n")[0]),
TenantInfo: encodeURIComponent(this.getModel("sessionModel").getData().TenantInfo)
};
var sServiceUrl = "/SDC_XS_TEMP/APPL/SDC/services/serviceRuntime/xsjs/SDC_REPORT_GENERATE_MM.xsjs";

var me = this;
$.ajax({
url: sServiceUrl,
type: "POST",
responseType:'arraybuffer',
contentType: "application/json",
data: JSON.stringify(oAjaxBody),
// dataType: "json",
success: function (oAjaxResponse) {
var content = oAjaxResponse;
var fileName = 'rapport.docx'; // You can use the .txt extension if you want
me.downloadwithpost(fileName, content);
},
error: function (oError) {
console.log("failure");
}

});


and this is the function



downloadwithpost: function (filename, content) {
var link = document.createElement('a');
var bytes = new Array(content.length);
// var bytes = new Array(content.length);
for (var i = 0; i < content.length; i++) {
bytes[i] = content.charCodeAt(i);
}
var byteArray = new Uint8Array(bytes);
var blob = new Blob([byteArray], {
type: "application/vnd.openxmlformats-officedocument.wordprocessingml.document"
});
var url = URL.createObjectURL(blob);
var oItem = {
documentId: url,
fileName: "rapport.docx",
thumbnailUrl: "",
url: url,
selected: true
};
var oUploadCollection = this.getView().byId("uploadCollection");
var newItem = new sap.m.UploadCollectionItem(oItem);
oUploadCollection.addItem(newItem);
oUploadCollection.downloadItem(newItem, true);
}






javascript ajax sapui5






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edited Nov 19 at 10:31









Eugene Mihaylin

9621424




9621424










asked Nov 19 at 9:59









Alexis sanchez

161




161












  • Just wondering if the document is an existing document, or if you're generating it?
    – Jorg
    Nov 20 at 11:30


















  • Just wondering if the document is an existing document, or if you're generating it?
    – Jorg
    Nov 20 at 11:30
















Just wondering if the document is an existing document, or if you're generating it?
– Jorg
Nov 20 at 11:30




Just wondering if the document is an existing document, or if you're generating it?
– Jorg
Nov 20 at 11:30












2 Answers
2






active

oldest

votes

















up vote
0
down vote













Take a look at this example, I worked with an hexadecimal data format, but you can change it as you see fit. Let me know if you need any help with this example or have any questions.



   doAfterSuccess: function(result, fileName, fileType) {       
var filedata = result.ARRAY[0].FILEDATA; // get data from response
// ------------------------------- hex data, rapport, docx
var createdFile = this.createFile(filedata, fileName, fileType);
this.downloadFile(createdFile, fileName, fileType);
},

createFile: function(hexContent, filename, type) {
var data = this.convertHexToBinary(hexContent); // skip if your data is not hex
var file = new Blob([data], {
name: filename,
type: type
});
return file;
},

convertHexToBinary: function(hexContent) {
return new Uint8Array(hexContent.match(/.{2}/g).map(function(e)
{
return parseInt(e, 16);
}));
},
downloadFile: function(file, filename, type){
if (window.navigator.msSaveOrOpenBlob)
window.navigator.msSaveOrOpenBlob(file, filename);
else { // Others
var a = document.createElement("a"),
url = URL.createObjectURL(file);
a.href = url;
a.download = filename + "." + type;
document.body.appendChild(a);
a.click();
setTimeout(function() {
document.body.removeChild(a);
window.URL.revokeObjectURL(url);
}, 0);
}
},





share|improve this answer




























    up vote
    0
    down vote













    function downloadDoc(filename, sServiceUrl, oAjaxBody){
    var xhr = new XMLHttpRequest();
    xhr.open('POST', sServiceUrl, true);
    xhr.responseType = 'blob';
    xhr.send(JSON.stringify(oAjaxBody));
    xhr.onreadystatechange = function(){
    if (xhr.readyState == 4){
    //$.unblockUI();
    if(xhr.status == 200) {
    var blob = new Blob([xhr.response], { type: 'application/vnd.openxmlformats-officedocument.wordprocessingml.document' });
    if (navigator.msSaveOrOpenBlob)
    navigator.msSaveOrOpenBlob(blob, filename);
    else {
    var link = document.createElement('a');
    var URL = window.URL || window.webkitURL;
    var downloadUrl = URL.createObjectURL(blob);
    link.href = downloadUrl;
    link.style = "display: none";
    link.download = filename;
    document.body.appendChild(link);
    link.click();
    setTimeout(function(){
    document.body.removeChild(link);
    window.URL.revokeObjectURL(downloadUrl);
    }, 100);
    }
    }
    else {
    console.log("failure");
    }
    }
    }
    }





    share|improve this answer























    • so as params , we don't have an url , just an oAjaxResponse .
      – Alexis sanchez
      Nov 19 at 10:27










    • the major problem is to convert an oajax reponse to blob
      – Alexis sanchez
      Nov 19 at 10:40










    • Why use XMLHttpRequest? Please refer to stackoverflow.com/questions/17657184/…
      – Miller Cy Chan
      Nov 20 at 7:28











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    2 Answers
    2






    active

    oldest

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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote













    Take a look at this example, I worked with an hexadecimal data format, but you can change it as you see fit. Let me know if you need any help with this example or have any questions.



       doAfterSuccess: function(result, fileName, fileType) {       
    var filedata = result.ARRAY[0].FILEDATA; // get data from response
    // ------------------------------- hex data, rapport, docx
    var createdFile = this.createFile(filedata, fileName, fileType);
    this.downloadFile(createdFile, fileName, fileType);
    },

    createFile: function(hexContent, filename, type) {
    var data = this.convertHexToBinary(hexContent); // skip if your data is not hex
    var file = new Blob([data], {
    name: filename,
    type: type
    });
    return file;
    },

    convertHexToBinary: function(hexContent) {
    return new Uint8Array(hexContent.match(/.{2}/g).map(function(e)
    {
    return parseInt(e, 16);
    }));
    },
    downloadFile: function(file, filename, type){
    if (window.navigator.msSaveOrOpenBlob)
    window.navigator.msSaveOrOpenBlob(file, filename);
    else { // Others
    var a = document.createElement("a"),
    url = URL.createObjectURL(file);
    a.href = url;
    a.download = filename + "." + type;
    document.body.appendChild(a);
    a.click();
    setTimeout(function() {
    document.body.removeChild(a);
    window.URL.revokeObjectURL(url);
    }, 0);
    }
    },





    share|improve this answer

























      up vote
      0
      down vote













      Take a look at this example, I worked with an hexadecimal data format, but you can change it as you see fit. Let me know if you need any help with this example or have any questions.



         doAfterSuccess: function(result, fileName, fileType) {       
      var filedata = result.ARRAY[0].FILEDATA; // get data from response
      // ------------------------------- hex data, rapport, docx
      var createdFile = this.createFile(filedata, fileName, fileType);
      this.downloadFile(createdFile, fileName, fileType);
      },

      createFile: function(hexContent, filename, type) {
      var data = this.convertHexToBinary(hexContent); // skip if your data is not hex
      var file = new Blob([data], {
      name: filename,
      type: type
      });
      return file;
      },

      convertHexToBinary: function(hexContent) {
      return new Uint8Array(hexContent.match(/.{2}/g).map(function(e)
      {
      return parseInt(e, 16);
      }));
      },
      downloadFile: function(file, filename, type){
      if (window.navigator.msSaveOrOpenBlob)
      window.navigator.msSaveOrOpenBlob(file, filename);
      else { // Others
      var a = document.createElement("a"),
      url = URL.createObjectURL(file);
      a.href = url;
      a.download = filename + "." + type;
      document.body.appendChild(a);
      a.click();
      setTimeout(function() {
      document.body.removeChild(a);
      window.URL.revokeObjectURL(url);
      }, 0);
      }
      },





      share|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        Take a look at this example, I worked with an hexadecimal data format, but you can change it as you see fit. Let me know if you need any help with this example or have any questions.



           doAfterSuccess: function(result, fileName, fileType) {       
        var filedata = result.ARRAY[0].FILEDATA; // get data from response
        // ------------------------------- hex data, rapport, docx
        var createdFile = this.createFile(filedata, fileName, fileType);
        this.downloadFile(createdFile, fileName, fileType);
        },

        createFile: function(hexContent, filename, type) {
        var data = this.convertHexToBinary(hexContent); // skip if your data is not hex
        var file = new Blob([data], {
        name: filename,
        type: type
        });
        return file;
        },

        convertHexToBinary: function(hexContent) {
        return new Uint8Array(hexContent.match(/.{2}/g).map(function(e)
        {
        return parseInt(e, 16);
        }));
        },
        downloadFile: function(file, filename, type){
        if (window.navigator.msSaveOrOpenBlob)
        window.navigator.msSaveOrOpenBlob(file, filename);
        else { // Others
        var a = document.createElement("a"),
        url = URL.createObjectURL(file);
        a.href = url;
        a.download = filename + "." + type;
        document.body.appendChild(a);
        a.click();
        setTimeout(function() {
        document.body.removeChild(a);
        window.URL.revokeObjectURL(url);
        }, 0);
        }
        },





        share|improve this answer












        Take a look at this example, I worked with an hexadecimal data format, but you can change it as you see fit. Let me know if you need any help with this example or have any questions.



           doAfterSuccess: function(result, fileName, fileType) {       
        var filedata = result.ARRAY[0].FILEDATA; // get data from response
        // ------------------------------- hex data, rapport, docx
        var createdFile = this.createFile(filedata, fileName, fileType);
        this.downloadFile(createdFile, fileName, fileType);
        },

        createFile: function(hexContent, filename, type) {
        var data = this.convertHexToBinary(hexContent); // skip if your data is not hex
        var file = new Blob([data], {
        name: filename,
        type: type
        });
        return file;
        },

        convertHexToBinary: function(hexContent) {
        return new Uint8Array(hexContent.match(/.{2}/g).map(function(e)
        {
        return parseInt(e, 16);
        }));
        },
        downloadFile: function(file, filename, type){
        if (window.navigator.msSaveOrOpenBlob)
        window.navigator.msSaveOrOpenBlob(file, filename);
        else { // Others
        var a = document.createElement("a"),
        url = URL.createObjectURL(file);
        a.href = url;
        a.download = filename + "." + type;
        document.body.appendChild(a);
        a.click();
        setTimeout(function() {
        document.body.removeChild(a);
        window.URL.revokeObjectURL(url);
        }, 0);
        }
        },






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 20 at 6:34









        Matthijs Mennens

        1,039216




        1,039216
























            up vote
            0
            down vote













            function downloadDoc(filename, sServiceUrl, oAjaxBody){
            var xhr = new XMLHttpRequest();
            xhr.open('POST', sServiceUrl, true);
            xhr.responseType = 'blob';
            xhr.send(JSON.stringify(oAjaxBody));
            xhr.onreadystatechange = function(){
            if (xhr.readyState == 4){
            //$.unblockUI();
            if(xhr.status == 200) {
            var blob = new Blob([xhr.response], { type: 'application/vnd.openxmlformats-officedocument.wordprocessingml.document' });
            if (navigator.msSaveOrOpenBlob)
            navigator.msSaveOrOpenBlob(blob, filename);
            else {
            var link = document.createElement('a');
            var URL = window.URL || window.webkitURL;
            var downloadUrl = URL.createObjectURL(blob);
            link.href = downloadUrl;
            link.style = "display: none";
            link.download = filename;
            document.body.appendChild(link);
            link.click();
            setTimeout(function(){
            document.body.removeChild(link);
            window.URL.revokeObjectURL(downloadUrl);
            }, 100);
            }
            }
            else {
            console.log("failure");
            }
            }
            }
            }





            share|improve this answer























            • so as params , we don't have an url , just an oAjaxResponse .
              – Alexis sanchez
              Nov 19 at 10:27










            • the major problem is to convert an oajax reponse to blob
              – Alexis sanchez
              Nov 19 at 10:40










            • Why use XMLHttpRequest? Please refer to stackoverflow.com/questions/17657184/…
              – Miller Cy Chan
              Nov 20 at 7:28















            up vote
            0
            down vote













            function downloadDoc(filename, sServiceUrl, oAjaxBody){
            var xhr = new XMLHttpRequest();
            xhr.open('POST', sServiceUrl, true);
            xhr.responseType = 'blob';
            xhr.send(JSON.stringify(oAjaxBody));
            xhr.onreadystatechange = function(){
            if (xhr.readyState == 4){
            //$.unblockUI();
            if(xhr.status == 200) {
            var blob = new Blob([xhr.response], { type: 'application/vnd.openxmlformats-officedocument.wordprocessingml.document' });
            if (navigator.msSaveOrOpenBlob)
            navigator.msSaveOrOpenBlob(blob, filename);
            else {
            var link = document.createElement('a');
            var URL = window.URL || window.webkitURL;
            var downloadUrl = URL.createObjectURL(blob);
            link.href = downloadUrl;
            link.style = "display: none";
            link.download = filename;
            document.body.appendChild(link);
            link.click();
            setTimeout(function(){
            document.body.removeChild(link);
            window.URL.revokeObjectURL(downloadUrl);
            }, 100);
            }
            }
            else {
            console.log("failure");
            }
            }
            }
            }





            share|improve this answer























            • so as params , we don't have an url , just an oAjaxResponse .
              – Alexis sanchez
              Nov 19 at 10:27










            • the major problem is to convert an oajax reponse to blob
              – Alexis sanchez
              Nov 19 at 10:40










            • Why use XMLHttpRequest? Please refer to stackoverflow.com/questions/17657184/…
              – Miller Cy Chan
              Nov 20 at 7:28













            up vote
            0
            down vote










            up vote
            0
            down vote









            function downloadDoc(filename, sServiceUrl, oAjaxBody){
            var xhr = new XMLHttpRequest();
            xhr.open('POST', sServiceUrl, true);
            xhr.responseType = 'blob';
            xhr.send(JSON.stringify(oAjaxBody));
            xhr.onreadystatechange = function(){
            if (xhr.readyState == 4){
            //$.unblockUI();
            if(xhr.status == 200) {
            var blob = new Blob([xhr.response], { type: 'application/vnd.openxmlformats-officedocument.wordprocessingml.document' });
            if (navigator.msSaveOrOpenBlob)
            navigator.msSaveOrOpenBlob(blob, filename);
            else {
            var link = document.createElement('a');
            var URL = window.URL || window.webkitURL;
            var downloadUrl = URL.createObjectURL(blob);
            link.href = downloadUrl;
            link.style = "display: none";
            link.download = filename;
            document.body.appendChild(link);
            link.click();
            setTimeout(function(){
            document.body.removeChild(link);
            window.URL.revokeObjectURL(downloadUrl);
            }, 100);
            }
            }
            else {
            console.log("failure");
            }
            }
            }
            }





            share|improve this answer














            function downloadDoc(filename, sServiceUrl, oAjaxBody){
            var xhr = new XMLHttpRequest();
            xhr.open('POST', sServiceUrl, true);
            xhr.responseType = 'blob';
            xhr.send(JSON.stringify(oAjaxBody));
            xhr.onreadystatechange = function(){
            if (xhr.readyState == 4){
            //$.unblockUI();
            if(xhr.status == 200) {
            var blob = new Blob([xhr.response], { type: 'application/vnd.openxmlformats-officedocument.wordprocessingml.document' });
            if (navigator.msSaveOrOpenBlob)
            navigator.msSaveOrOpenBlob(blob, filename);
            else {
            var link = document.createElement('a');
            var URL = window.URL || window.webkitURL;
            var downloadUrl = URL.createObjectURL(blob);
            link.href = downloadUrl;
            link.style = "display: none";
            link.download = filename;
            document.body.appendChild(link);
            link.click();
            setTimeout(function(){
            document.body.removeChild(link);
            window.URL.revokeObjectURL(downloadUrl);
            }, 100);
            }
            }
            else {
            console.log("failure");
            }
            }
            }
            }






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 20 at 8:10

























            answered Nov 19 at 10:19









            Miller Cy Chan

            1669




            1669












            • so as params , we don't have an url , just an oAjaxResponse .
              – Alexis sanchez
              Nov 19 at 10:27










            • the major problem is to convert an oajax reponse to blob
              – Alexis sanchez
              Nov 19 at 10:40










            • Why use XMLHttpRequest? Please refer to stackoverflow.com/questions/17657184/…
              – Miller Cy Chan
              Nov 20 at 7:28


















            • so as params , we don't have an url , just an oAjaxResponse .
              – Alexis sanchez
              Nov 19 at 10:27










            • the major problem is to convert an oajax reponse to blob
              – Alexis sanchez
              Nov 19 at 10:40










            • Why use XMLHttpRequest? Please refer to stackoverflow.com/questions/17657184/…
              – Miller Cy Chan
              Nov 20 at 7:28
















            so as params , we don't have an url , just an oAjaxResponse .
            – Alexis sanchez
            Nov 19 at 10:27




            so as params , we don't have an url , just an oAjaxResponse .
            – Alexis sanchez
            Nov 19 at 10:27












            the major problem is to convert an oajax reponse to blob
            – Alexis sanchez
            Nov 19 at 10:40




            the major problem is to convert an oajax reponse to blob
            – Alexis sanchez
            Nov 19 at 10:40












            Why use XMLHttpRequest? Please refer to stackoverflow.com/questions/17657184/…
            – Miller Cy Chan
            Nov 20 at 7:28




            Why use XMLHttpRequest? Please refer to stackoverflow.com/questions/17657184/…
            – Miller Cy Chan
            Nov 20 at 7:28


















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