How do you interpret/draw out the simplified circuits in Sedra's Microelectronics?
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I legitimately do not understand how the simplified drawings in this book are meant to be interpreted. Coming from a basic circuit analysis class which had everything explicitly drawn, I'm having a lot of trouble even interpreting the simplest circuits in this book and can't even get started with solving them.
Where do the arrows go?
This notation is briefly addressed in chapter 1 where it says that the arrows are connected together, but that wouldn't make any sense, since I is given a different value in the problem.
basic
asked 3 hours ago
mokanulmokanul
82
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I legitimately do not understand how the simplified drawings in this book are meant to be interpreted. Coming from a basic circuit analysis class which had everything explicitly drawn, I'm having a lot of trouble even interpreting the simplest circuits in this book and can't even get started with solving them.
Where do the arrows go?
This notation is briefly addressed in chapter 1 where it says that the arrows are connected together, but that wouldn't make any sense, since I is given a different value in the problem.
basic
asked 3 hours ago
mokanulmokanul
82
New contributor
mokanul is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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add a comment |
$begingroup$
I legitimately do not understand how the simplified drawings in this book are meant to be interpreted. Coming from a basic circuit analysis class which had everything explicitly drawn, I'm having a lot of trouble even interpreting the simplest circuits in this book and can't even get started with solving them.
Where do the arrows go?
This notation is briefly addressed in chapter 1 where it says that the arrows are connected together, but that wouldn't make any sense, since I is given a different value in the problem.
basic
asked 3 hours ago
mokanulmokanul
82
New contributor
mokanul is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I legitimately do not understand how the simplified drawings in this book are meant to be interpreted. Coming from a basic circuit analysis class which had everything explicitly drawn, I'm having a lot of trouble even interpreting the simplest circuits in this book and can't even get started with solving them.
Where do the arrows go?
This notation is briefly addressed in chapter 1 where it says that the arrows are connected together, but that wouldn't make any sense, since I is given a different value in the problem.
basic
basic
asked 3 hours ago
mokanulmokanul
82
New contributor
mokanul is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 hours ago
mokanulmokanul
82
New contributor
mokanul is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 hours ago
mokanulmokanul
82
New contributor
mokanul is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 hours ago
mokanulmokanul
82
asked 3 hours ago
mokanulmokanul
82
82
New contributor
mokanul is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
mokanul is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
mokanul is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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1 Answer
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It doesn't matter where the arrows go because they are separated from the circuit of interest by current sources.
For a more practical approach you may consider the arrows pointing up to a more positive supply while the arrows pointing down connect to a more negative supply. The important thing to realise is that 1 mA is coming from the top and I is departing to the bottom.
answered 3 hours ago
TransistorTransistor
82.6k779177
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1 Answer
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active
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1 Answer
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active
oldest
votes
active
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active
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votes
$begingroup$
It doesn't matter where the arrows go because they are separated from the circuit of interest by current sources.
For a more practical approach you may consider the arrows pointing up to a more positive supply while the arrows pointing down connect to a more negative supply. The important thing to realise is that 1 mA is coming from the top and I is departing to the bottom.
answered 3 hours ago
TransistorTransistor
82.6k779177
$endgroup$
add a comment |
$begingroup$
It doesn't matter where the arrows go because they are separated from the circuit of interest by current sources.
For a more practical approach you may consider the arrows pointing up to a more positive supply while the arrows pointing down connect to a more negative supply. The important thing to realise is that 1 mA is coming from the top and I is departing to the bottom.
answered 3 hours ago
TransistorTransistor
82.6k779177
$endgroup$
add a comment |
$begingroup$
It doesn't matter where the arrows go because they are separated from the circuit of interest by current sources.
For a more practical approach you may consider the arrows pointing up to a more positive supply while the arrows pointing down connect to a more negative supply. The important thing to realise is that 1 mA is coming from the top and I is departing to the bottom.
answered 3 hours ago
TransistorTransistor
82.6k779177
$endgroup$
It doesn't matter where the arrows go because they are separated from the circuit of interest by current sources.
For a more practical approach you may consider the arrows pointing up to a more positive supply while the arrows pointing down connect to a more negative supply. The important thing to realise is that 1 mA is coming from the top and I is departing to the bottom.
answered 3 hours ago
TransistorTransistor
82.6k779177
answered 3 hours ago
TransistorTransistor
82.6k779177
answered 3 hours ago
TransistorTransistor
82.6k779177
answered 3 hours ago
TransistorTransistor
82.6k779177
82.6k779177
add a comment |
add a comment |
mokanul is a new contributor. Be nice, and check out our Code of Conduct.
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