How to check if entire string matches regular expression in Javascript?
Is there a function in javascript which checks if entire string matches some regular expression
'00'.match(/^0|([1-9][0-9]*)$/g) for example returns ['0']
I know I can simply check if the matched part is equal to the string, but I'm just curious if such function already exists
edit:
'01'.match(/^0|1$/g) returns ['0', '1']
and '01'.match(/^(0|1)$/g) returns null as expected.
I though | has precedence over ^ or $. Can someone explain what /^0|1$/g actually matches?
javascript
asked Nov 25 '18 at 18:06
displayNamedisplayName
426318
add a comment |
Is there a function in javascript which checks if entire string matches some regular expression
'00'.match(/^0|([1-9][0-9]*)$/g) for example returns ['0']
I know I can simply check if the matched part is equal to the string, but I'm just curious if such function already exists
edit:
'01'.match(/^0|1$/g) returns ['0', '1']
and '01'.match(/^(0|1)$/g) returns null as expected.
I though | has precedence over ^ or $. Can someone explain what /^0|1$/g actually matches?
javascript
asked Nov 25 '18 at 18:06
displayNamedisplayName
426318
2
/^0|1$/gmatches a0at the beginning of the string or a1at the end of the string.
– Donat
Nov 25 '18 at 22:02
add a comment |
Is there a function in javascript which checks if entire string matches some regular expression
'00'.match(/^0|([1-9][0-9]*)$/g) for example returns ['0']
I know I can simply check if the matched part is equal to the string, but I'm just curious if such function already exists
edit:
'01'.match(/^0|1$/g) returns ['0', '1']
and '01'.match(/^(0|1)$/g) returns null as expected.
I though | has precedence over ^ or $. Can someone explain what /^0|1$/g actually matches?
javascript
asked Nov 25 '18 at 18:06
displayNamedisplayName
426318
Is there a function in javascript which checks if entire string matches some regular expression
'00'.match(/^0|([1-9][0-9]*)$/g) for example returns ['0']
I know I can simply check if the matched part is equal to the string, but I'm just curious if such function already exists
edit:
'01'.match(/^0|1$/g) returns ['0', '1']
and '01'.match(/^(0|1)$/g) returns null as expected.
I though | has precedence over ^ or $. Can someone explain what /^0|1$/g actually matches?
javascript
javascript
asked Nov 25 '18 at 18:06
displayNamedisplayName
426318
asked Nov 25 '18 at 18:06
displayNamedisplayName
426318
edited Dec 8 '18 at 10:35
displayName
asked Nov 25 '18 at 18:06
displayNamedisplayName
426318
asked Nov 25 '18 at 18:06
displayNamedisplayName
426318
asked Nov 25 '18 at 18:06
displayNamedisplayName
426318
426318
2
/^0|1$/gmatches a0at the beginning of the string or a1at the end of the string.
– Donat
Nov 25 '18 at 22:02
add a comment |
2
/^0|1$/gmatches a0at the beginning of the string or a1at the end of the string.
– Donat
Nov 25 '18 at 22:02
2
2
/^0|1$/g matches a 0 at the beginning of the string or a 1 at the end of the string.– Donat
Nov 25 '18 at 22:02
/^0|1$/g matches a 0 at the beginning of the string or a 1 at the end of the string.– Donat
Nov 25 '18 at 22:02
add a comment |
1 Answer
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I don't know what you exacty want to achieve. I suppose you want to match eiter zero or a number, not beginning with zero. Then try this:
'00'.match(/^(0|[1-9][0-9]*)$/g)
This does not match '00', but all the other cases.
answered Nov 25 '18 at 18:16
DonatDonat
848128
add a comment |
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1 Answer
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1 Answer
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active
oldest
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oldest
votes
active
oldest
votes
I don't know what you exacty want to achieve. I suppose you want to match eiter zero or a number, not beginning with zero. Then try this:
'00'.match(/^(0|[1-9][0-9]*)$/g)
This does not match '00', but all the other cases.
answered Nov 25 '18 at 18:16
DonatDonat
848128
add a comment |
I don't know what you exacty want to achieve. I suppose you want to match eiter zero or a number, not beginning with zero. Then try this:
'00'.match(/^(0|[1-9][0-9]*)$/g)
This does not match '00', but all the other cases.
answered Nov 25 '18 at 18:16
DonatDonat
848128
add a comment |
I don't know what you exacty want to achieve. I suppose you want to match eiter zero or a number, not beginning with zero. Then try this:
'00'.match(/^(0|[1-9][0-9]*)$/g)
This does not match '00', but all the other cases.
answered Nov 25 '18 at 18:16
DonatDonat
848128
I don't know what you exacty want to achieve. I suppose you want to match eiter zero or a number, not beginning with zero. Then try this:
'00'.match(/^(0|[1-9][0-9]*)$/g)
This does not match '00', but all the other cases.
answered Nov 25 '18 at 18:16
DonatDonat
848128
edited Nov 25 '18 at 21:54
answered Nov 25 '18 at 18:16
DonatDonat
848128
answered Nov 25 '18 at 18:16
DonatDonat
848128
answered Nov 25 '18 at 18:16
DonatDonat
848128
848128
add a comment |
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2
/^0|1$/gmatches a0at the beginning of the string or a1at the end of the string.– Donat
Nov 25 '18 at 22:02