How to get total duration for all object in a collection in MongoDB?
I am using MongoDB 3.4.18. I have the following collection name : student_details
. The data inside it looks like this :
{
_id : ObjectID(generated_id),
in_time : <student_registered_in_time>
student_id : 'abc',
out_time: <student_registered_out_time>,
date_r: <date_in_ISO_FORMAT>
} ,
{
_id : ObjectID(generated_id),
in_time : <student_registered_in_time>
student_id : 'def',
out_time: <student_registered_out_time>,
date_r: <date_in_ISO_FORMAT>
}
I want to print the total amount of time spend by student having a particular student_id
(let's say abc
) for particular day. For e.g the output should be
{
'student_id' : 'abc',
'total_time_spent': 'total_time_spent_in_minutes'
'date': date
}
Thanks in Advance.
I have tried the following though.
db.student_details.aggregate([
{
$match: {
date_r: {
$gte: ISODate("2018-11-01T00:00:00.000Z"),
$lt: ISODate("2018-11-31T23:59:59.000Z")
} ,
student_id : 'abc',
}
}, {
$group: {
total: {
$sum: <confused_about_this_part>
}
}
}
]);
mongodb mongodb-query aggregation
add a comment |
I am using MongoDB 3.4.18. I have the following collection name : student_details
. The data inside it looks like this :
{
_id : ObjectID(generated_id),
in_time : <student_registered_in_time>
student_id : 'abc',
out_time: <student_registered_out_time>,
date_r: <date_in_ISO_FORMAT>
} ,
{
_id : ObjectID(generated_id),
in_time : <student_registered_in_time>
student_id : 'def',
out_time: <student_registered_out_time>,
date_r: <date_in_ISO_FORMAT>
}
I want to print the total amount of time spend by student having a particular student_id
(let's say abc
) for particular day. For e.g the output should be
{
'student_id' : 'abc',
'total_time_spent': 'total_time_spent_in_minutes'
'date': date
}
Thanks in Advance.
I have tried the following though.
db.student_details.aggregate([
{
$match: {
date_r: {
$gte: ISODate("2018-11-01T00:00:00.000Z"),
$lt: ISODate("2018-11-31T23:59:59.000Z")
} ,
student_id : 'abc',
}
}, {
$group: {
total: {
$sum: <confused_about_this_part>
}
}
}
]);
mongodb mongodb-query aggregation
will there be multiple in/outs for particular day?
– Prabhat Mishra
Nov 26 '18 at 9:56
@PrabhatMishra yes. For the same student_id there can be multiple in and outs.
– Aniket Maithani
Nov 26 '18 at 10:03
Could you post the actual sample data from your mongo database
– Anthony Winzlet
Nov 26 '18 at 17:23
add a comment |
I am using MongoDB 3.4.18. I have the following collection name : student_details
. The data inside it looks like this :
{
_id : ObjectID(generated_id),
in_time : <student_registered_in_time>
student_id : 'abc',
out_time: <student_registered_out_time>,
date_r: <date_in_ISO_FORMAT>
} ,
{
_id : ObjectID(generated_id),
in_time : <student_registered_in_time>
student_id : 'def',
out_time: <student_registered_out_time>,
date_r: <date_in_ISO_FORMAT>
}
I want to print the total amount of time spend by student having a particular student_id
(let's say abc
) for particular day. For e.g the output should be
{
'student_id' : 'abc',
'total_time_spent': 'total_time_spent_in_minutes'
'date': date
}
Thanks in Advance.
I have tried the following though.
db.student_details.aggregate([
{
$match: {
date_r: {
$gte: ISODate("2018-11-01T00:00:00.000Z"),
$lt: ISODate("2018-11-31T23:59:59.000Z")
} ,
student_id : 'abc',
}
}, {
$group: {
total: {
$sum: <confused_about_this_part>
}
}
}
]);
mongodb mongodb-query aggregation
I am using MongoDB 3.4.18. I have the following collection name : student_details
. The data inside it looks like this :
{
_id : ObjectID(generated_id),
in_time : <student_registered_in_time>
student_id : 'abc',
out_time: <student_registered_out_time>,
date_r: <date_in_ISO_FORMAT>
} ,
{
_id : ObjectID(generated_id),
in_time : <student_registered_in_time>
student_id : 'def',
out_time: <student_registered_out_time>,
date_r: <date_in_ISO_FORMAT>
}
I want to print the total amount of time spend by student having a particular student_id
(let's say abc
) for particular day. For e.g the output should be
{
'student_id' : 'abc',
'total_time_spent': 'total_time_spent_in_minutes'
'date': date
}
Thanks in Advance.
I have tried the following though.
db.student_details.aggregate([
{
$match: {
date_r: {
$gte: ISODate("2018-11-01T00:00:00.000Z"),
$lt: ISODate("2018-11-31T23:59:59.000Z")
} ,
student_id : 'abc',
}
}, {
$group: {
total: {
$sum: <confused_about_this_part>
}
}
}
]);
mongodb mongodb-query aggregation
mongodb mongodb-query aggregation
asked Nov 26 '18 at 7:29
Aniket MaithaniAniket Maithani
120110
120110
will there be multiple in/outs for particular day?
– Prabhat Mishra
Nov 26 '18 at 9:56
@PrabhatMishra yes. For the same student_id there can be multiple in and outs.
– Aniket Maithani
Nov 26 '18 at 10:03
Could you post the actual sample data from your mongo database
– Anthony Winzlet
Nov 26 '18 at 17:23
add a comment |
will there be multiple in/outs for particular day?
– Prabhat Mishra
Nov 26 '18 at 9:56
@PrabhatMishra yes. For the same student_id there can be multiple in and outs.
– Aniket Maithani
Nov 26 '18 at 10:03
Could you post the actual sample data from your mongo database
– Anthony Winzlet
Nov 26 '18 at 17:23
will there be multiple in/outs for particular day?
– Prabhat Mishra
Nov 26 '18 at 9:56
will there be multiple in/outs for particular day?
– Prabhat Mishra
Nov 26 '18 at 9:56
@PrabhatMishra yes. For the same student_id there can be multiple in and outs.
– Aniket Maithani
Nov 26 '18 at 10:03
@PrabhatMishra yes. For the same student_id there can be multiple in and outs.
– Aniket Maithani
Nov 26 '18 at 10:03
Could you post the actual sample data from your mongo database
– Anthony Winzlet
Nov 26 '18 at 17:23
Could you post the actual sample data from your mongo database
– Anthony Winzlet
Nov 26 '18 at 17:23
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53476457%2fhow-to-get-total-duration-for-all-object-in-a-collection-in-mongodb%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53476457%2fhow-to-get-total-duration-for-all-object-in-a-collection-in-mongodb%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
will there be multiple in/outs for particular day?
– Prabhat Mishra
Nov 26 '18 at 9:56
@PrabhatMishra yes. For the same student_id there can be multiple in and outs.
– Aniket Maithani
Nov 26 '18 at 10:03
Could you post the actual sample data from your mongo database
– Anthony Winzlet
Nov 26 '18 at 17:23