Sorting xml file alphabetically by name tag
I have several large xml files in the following format:
<item>
<name>Name 1</name>
<info>Details 1</info>
</item>
<item>
<name>Name 3</name>
<info>Details 3</info>
</item>
<item>
<name>Name 2</name>
<info>Details 2</info>
</item>
Over time of adding to these it has become ugly. I would like to sort them alphabetically by name tag. I have searched here and found a few different python scripts but they did not work for me. Here is one example of what I've tried:
import xml.etree.ElementTree as ET
tree = ET.parse("test.xml")
container = tree.find("item")
data =
for elem in container:
key = elem.findtext("name")
data.append((key, elem))
data.sort()
container[:] = [item[-1] for item in data]
tree.write("test-out.xml")
print "File Written"
Thanks for any help
xml sorting alphabetical
asked Nov 26 '18 at 1:51
Bobby PetersBobby Peters
697
add a comment |
I have several large xml files in the following format:
<item>
<name>Name 1</name>
<info>Details 1</info>
</item>
<item>
<name>Name 3</name>
<info>Details 3</info>
</item>
<item>
<name>Name 2</name>
<info>Details 2</info>
</item>
Over time of adding to these it has become ugly. I would like to sort them alphabetically by name tag. I have searched here and found a few different python scripts but they did not work for me. Here is one example of what I've tried:
import xml.etree.ElementTree as ET
tree = ET.parse("test.xml")
container = tree.find("item")
data =
for elem in container:
key = elem.findtext("name")
data.append((key, elem))
data.sort()
container[:] = [item[-1] for item in data]
tree.write("test-out.xml")
print "File Written"
Thanks for any help
xml sorting alphabetical
asked Nov 26 '18 at 1:51
Bobby PetersBobby Peters
697
add a comment |
I have several large xml files in the following format:
<item>
<name>Name 1</name>
<info>Details 1</info>
</item>
<item>
<name>Name 3</name>
<info>Details 3</info>
</item>
<item>
<name>Name 2</name>
<info>Details 2</info>
</item>
Over time of adding to these it has become ugly. I would like to sort them alphabetically by name tag. I have searched here and found a few different python scripts but they did not work for me. Here is one example of what I've tried:
import xml.etree.ElementTree as ET
tree = ET.parse("test.xml")
container = tree.find("item")
data =
for elem in container:
key = elem.findtext("name")
data.append((key, elem))
data.sort()
container[:] = [item[-1] for item in data]
tree.write("test-out.xml")
print "File Written"
Thanks for any help
xml sorting alphabetical
asked Nov 26 '18 at 1:51
Bobby PetersBobby Peters
697
I have several large xml files in the following format:
<item>
<name>Name 1</name>
<info>Details 1</info>
</item>
<item>
<name>Name 3</name>
<info>Details 3</info>
</item>
<item>
<name>Name 2</name>
<info>Details 2</info>
</item>
Over time of adding to these it has become ugly. I would like to sort them alphabetically by name tag. I have searched here and found a few different python scripts but they did not work for me. Here is one example of what I've tried:
import xml.etree.ElementTree as ET
tree = ET.parse("test.xml")
container = tree.find("item")
data =
for elem in container:
key = elem.findtext("name")
data.append((key, elem))
data.sort()
container[:] = [item[-1] for item in data]
tree.write("test-out.xml")
print "File Written"
Thanks for any help
xml sorting alphabetical
xml sorting alphabetical
asked Nov 26 '18 at 1:51
Bobby PetersBobby Peters
697
asked Nov 26 '18 at 1:51
Bobby PetersBobby Peters
697
asked Nov 26 '18 at 1:51
Bobby PetersBobby Peters
697
asked Nov 26 '18 at 1:51
Bobby PetersBobby Peters
697
asked Nov 26 '18 at 1:51
Bobby PetersBobby Peters
697
697
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You really need to have XQuery or XSLT in your toolkit for this kind of job.
In XQuery:
<items>{
for $i in //item order by $i/name return $i
}</items>
In XSLT (1.0 or later):
<items xsl:version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:for-each select="//item">
<xsl:sort select="name"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</items>
answered Nov 26 '18 at 9:05
Michael KayMichael Kay
111k663119
Thank you so much. XQuery worked like a charm.
– Bobby Peters
Nov 27 '18 at 1:17
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You really need to have XQuery or XSLT in your toolkit for this kind of job.
In XQuery:
<items>{
for $i in //item order by $i/name return $i
}</items>
In XSLT (1.0 or later):
<items xsl:version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:for-each select="//item">
<xsl:sort select="name"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</items>
answered Nov 26 '18 at 9:05
Michael KayMichael Kay
111k663119
Thank you so much. XQuery worked like a charm.
– Bobby Peters
Nov 27 '18 at 1:17
add a comment |
You really need to have XQuery or XSLT in your toolkit for this kind of job.
In XQuery:
<items>{
for $i in //item order by $i/name return $i
}</items>
In XSLT (1.0 or later):
<items xsl:version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:for-each select="//item">
<xsl:sort select="name"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</items>
answered Nov 26 '18 at 9:05
Michael KayMichael Kay
111k663119
Thank you so much. XQuery worked like a charm.
– Bobby Peters
Nov 27 '18 at 1:17
add a comment |
You really need to have XQuery or XSLT in your toolkit for this kind of job.
In XQuery:
<items>{
for $i in //item order by $i/name return $i
}</items>
In XSLT (1.0 or later):
<items xsl:version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:for-each select="//item">
<xsl:sort select="name"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</items>
answered Nov 26 '18 at 9:05
Michael KayMichael Kay
111k663119
You really need to have XQuery or XSLT in your toolkit for this kind of job.
In XQuery:
<items>{
for $i in //item order by $i/name return $i
}</items>
In XSLT (1.0 or later):
<items xsl:version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:for-each select="//item">
<xsl:sort select="name"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</items>
answered Nov 26 '18 at 9:05
Michael KayMichael Kay
111k663119
answered Nov 26 '18 at 9:05
Michael KayMichael Kay
111k663119
answered Nov 26 '18 at 9:05
Michael KayMichael Kay
111k663119
answered Nov 26 '18 at 9:05
Michael KayMichael Kay
111k663119
111k663119
Thank you so much. XQuery worked like a charm.
– Bobby Peters
Nov 27 '18 at 1:17
add a comment |
Thank you so much. XQuery worked like a charm.
– Bobby Peters
Nov 27 '18 at 1:17
Thank you so much. XQuery worked like a charm.
– Bobby Peters
Nov 27 '18 at 1:17
Thank you so much. XQuery worked like a charm.
– Bobby Peters
Nov 27 '18 at 1:17
add a comment |
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