How to understand what part of my Java loop outputs the asterisk?
-2
Can anyone please tell me which part outputs the number in front of the * signs? Is it the methods or the output?
import java.util.*;
public class PrintTriangle3 {
public static void main(String args) {
Scanner sc = new Scanner(System.in);
System.out.println("enter number");
int number = sc.nextInt();
int i = 1;
while(i <= number) {
System.out.println(printLine(number));
number--;
}
i++;
}
public static int printLine(int number) {
for(int j = 1; j <= number; j++) {
System.out.print("*");
}
return number;
}
}
java loops methods
edited Nov 25 '18 at 22:23
halfer
14.7k758115
asked Nov 25 '18 at 14:48
eric eric
1
add a comment |
-2
Can anyone please tell me which part outputs the number in front of the * signs? Is it the methods or the output?
import java.util.*;
public class PrintTriangle3 {
public static void main(String args) {
Scanner sc = new Scanner(System.in);
System.out.println("enter number");
int number = sc.nextInt();
int i = 1;
while(i <= number) {
System.out.println(printLine(number));
number--;
}
i++;
}
public static int printLine(int number) {
for(int j = 1; j <= number; j++) {
System.out.print("*");
}
return number;
}
}
java loops methods
edited Nov 25 '18 at 22:23
halfer
14.7k758115
asked Nov 25 '18 at 14:48
eric eric
1
Try auto-formatting your code. Its behavior will be far more clear then.
– EpicPandaForce
Nov 25 '18 at 14:51
System.out.println(printLine(number));?
– Guy
Nov 25 '18 at 14:52
just print the * sign.
– eric
Nov 25 '18 at 15:50
add a comment |
-2
-2
-2
Can anyone please tell me which part outputs the number in front of the * signs? Is it the methods or the output?
import java.util.*;
public class PrintTriangle3 {
public static void main(String args) {
Scanner sc = new Scanner(System.in);
System.out.println("enter number");
int number = sc.nextInt();
int i = 1;
while(i <= number) {
System.out.println(printLine(number));
number--;
}
i++;
}
public static int printLine(int number) {
for(int j = 1; j <= number; j++) {
System.out.print("*");
}
return number;
}
}
java loops methods
edited Nov 25 '18 at 22:23
halfer
14.7k758115
asked Nov 25 '18 at 14:48
eric eric
1
Can anyone please tell me which part outputs the number in front of the * signs? Is it the methods or the output?
import java.util.*;
public class PrintTriangle3 {
public static void main(String args) {
Scanner sc = new Scanner(System.in);
System.out.println("enter number");
int number = sc.nextInt();
int i = 1;
while(i <= number) {
System.out.println(printLine(number));
number--;
}
i++;
}
public static int printLine(int number) {
for(int j = 1; j <= number; j++) {
System.out.print("*");
}
return number;
}
}
java loops methods
java loops methods
edited Nov 25 '18 at 22:23
halfer
14.7k758115
asked Nov 25 '18 at 14:48
eric eric
1
edited Nov 25 '18 at 22:23
halfer
14.7k758115
asked Nov 25 '18 at 14:48
eric eric
1
edited Nov 25 '18 at 22:23
halfer
14.7k758115
edited Nov 25 '18 at 22:23
halfer
14.7k758115
edited Nov 25 '18 at 22:23
halfer
14.7k758115
14.7k758115
asked Nov 25 '18 at 14:48
eric eric
1
asked Nov 25 '18 at 14:48
eric eric
1
asked Nov 25 '18 at 14:48
eric eric
1
1
Try auto-formatting your code. Its behavior will be far more clear then.
– EpicPandaForce
Nov 25 '18 at 14:51
System.out.println(printLine(number));?
– Guy
Nov 25 '18 at 14:52
just print the * sign.
– eric
Nov 25 '18 at 15:50
add a comment |
Try auto-formatting your code. Its behavior will be far more clear then.
– EpicPandaForce
Nov 25 '18 at 14:51
System.out.println(printLine(number));?
– Guy
Nov 25 '18 at 14:52
just print the * sign.
– eric
Nov 25 '18 at 15:50
Try auto-formatting your code. Its behavior will be far more clear then.
– EpicPandaForce
Nov 25 '18 at 14:51
Try auto-formatting your code. Its behavior will be far more clear then.
– EpicPandaForce
Nov 25 '18 at 14:51
System.out.println(printLine(number));?– Guy
Nov 25 '18 at 14:52
System.out.println(printLine(number));?– Guy
Nov 25 '18 at 14:52
just print the * sign.
– eric
Nov 25 '18 at 15:50
just print the * sign.
– eric
Nov 25 '18 at 15:50
add a comment |
1 Answer
1
active
oldest
votes
0
You are printing the number that return from the method. You can change it like this so you won't print the return value of the method,
import java.util.*;
public class Main {
public static void main(String args) {
Scanner sc = new Scanner(System.in);
System.out.println("enter number");
int number = sc.nextInt();
int i = 1;
while (i <= number) {
printLine(number);
System.out.println();
number--;
}
i++;
}
public static int printLine(int number) {
for (int j = 1; j <= number; j++) {
System.out.print("*");
}
return number;
}
}
This was the part where you have print the number that returned by the method,
System.out.println(printLine(number));
Also you can change the type of that method to void since you don't need to return that value
answered Nov 25 '18 at 14:51
SandSand
1,7192722
thanks a lot!!! didn't expect to be answered so fast.
– eric
Nov 25 '18 at 15:52
@eric You're welcome.
– Sand
Nov 25 '18 at 15:53
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53468678%2fhow-to-understand-what-part-of-my-java-loop-outputs-the-asterisk%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
You are printing the number that return from the method. You can change it like this so you won't print the return value of the method,
import java.util.*;
public class Main {
public static void main(String args) {
Scanner sc = new Scanner(System.in);
System.out.println("enter number");
int number = sc.nextInt();
int i = 1;
while (i <= number) {
printLine(number);
System.out.println();
number--;
}
i++;
}
public static int printLine(int number) {
for (int j = 1; j <= number; j++) {
System.out.print("*");
}
return number;
}
}
This was the part where you have print the number that returned by the method,
System.out.println(printLine(number));
Also you can change the type of that method to void since you don't need to return that value
answered Nov 25 '18 at 14:51
SandSand
1,7192722
thanks a lot!!! didn't expect to be answered so fast.
– eric
Nov 25 '18 at 15:52
@eric You're welcome.
– Sand
Nov 25 '18 at 15:53
add a comment |
0
You are printing the number that return from the method. You can change it like this so you won't print the return value of the method,
import java.util.*;
public class Main {
public static void main(String args) {
Scanner sc = new Scanner(System.in);
System.out.println("enter number");
int number = sc.nextInt();
int i = 1;
while (i <= number) {
printLine(number);
System.out.println();
number--;
}
i++;
}
public static int printLine(int number) {
for (int j = 1; j <= number; j++) {
System.out.print("*");
}
return number;
}
}
This was the part where you have print the number that returned by the method,
System.out.println(printLine(number));
Also you can change the type of that method to void since you don't need to return that value
answered Nov 25 '18 at 14:51
SandSand
1,7192722
thanks a lot!!! didn't expect to be answered so fast.
– eric
Nov 25 '18 at 15:52
@eric You're welcome.
– Sand
Nov 25 '18 at 15:53
add a comment |
0
0
0
You are printing the number that return from the method. You can change it like this so you won't print the return value of the method,
import java.util.*;
public class Main {
public static void main(String args) {
Scanner sc = new Scanner(System.in);
System.out.println("enter number");
int number = sc.nextInt();
int i = 1;
while (i <= number) {
printLine(number);
System.out.println();
number--;
}
i++;
}
public static int printLine(int number) {
for (int j = 1; j <= number; j++) {
System.out.print("*");
}
return number;
}
}
This was the part where you have print the number that returned by the method,
System.out.println(printLine(number));
Also you can change the type of that method to void since you don't need to return that value
answered Nov 25 '18 at 14:51
SandSand
1,7192722
You are printing the number that return from the method. You can change it like this so you won't print the return value of the method,
import java.util.*;
public class Main {
public static void main(String args) {
Scanner sc = new Scanner(System.in);
System.out.println("enter number");
int number = sc.nextInt();
int i = 1;
while (i <= number) {
printLine(number);
System.out.println();
number--;
}
i++;
}
public static int printLine(int number) {
for (int j = 1; j <= number; j++) {
System.out.print("*");
}
return number;
}
}
This was the part where you have print the number that returned by the method,
System.out.println(printLine(number));
Also you can change the type of that method to void since you don't need to return that value
answered Nov 25 '18 at 14:51
SandSand
1,7192722
answered Nov 25 '18 at 14:51
SandSand
1,7192722
answered Nov 25 '18 at 14:51
SandSand
1,7192722
answered Nov 25 '18 at 14:51
SandSand
1,7192722
1,7192722
thanks a lot!!! didn't expect to be answered so fast.
– eric
Nov 25 '18 at 15:52
@eric You're welcome.
– Sand
Nov 25 '18 at 15:53
add a comment |
thanks a lot!!! didn't expect to be answered so fast.
– eric
Nov 25 '18 at 15:52
@eric You're welcome.
– Sand
Nov 25 '18 at 15:53
thanks a lot!!! didn't expect to be answered so fast.
– eric
Nov 25 '18 at 15:52
thanks a lot!!! didn't expect to be answered so fast.
– eric
Nov 25 '18 at 15:52
@eric You're welcome.
– Sand
Nov 25 '18 at 15:53
@eric You're welcome.
– Sand
Nov 25 '18 at 15:53
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53468678%2fhow-to-understand-what-part-of-my-java-loop-outputs-the-asterisk%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Try auto-formatting your code. Its behavior will be far more clear then.
– EpicPandaForce
Nov 25 '18 at 14:51
System.out.println(printLine(number));?– Guy
Nov 25 '18 at 14:52
just print the * sign.
– eric
Nov 25 '18 at 15:50