Function that behaves differently depending on which type classes the argument belong to
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1
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In Haskell, is there any way to declare function it behaves differently depending on whether the type of a argument is an instance of specific type class?
For example, can I define genericShow in the following example?
-- If type `a` is an instance of `Show`.
genericShow :: Show a => a -> String
genericShow = show
-- If type `a` is not an instance of `Show`.
genericShow :: a -> String
genericShow _ = "(Cannot be shown)"
> genericShow 3
"3"
> genericShow const
"(Cannot be shown)"
haskell
asked Nov 19 at 1:01
user3749167
616
add a comment |
up vote
1
down vote
favorite
In Haskell, is there any way to declare function it behaves differently depending on whether the type of a argument is an instance of specific type class?
For example, can I define genericShow in the following example?
-- If type `a` is an instance of `Show`.
genericShow :: Show a => a -> String
genericShow = show
-- If type `a` is not an instance of `Show`.
genericShow :: a -> String
genericShow _ = "(Cannot be shown)"
> genericShow 3
"3"
> genericShow const
"(Cannot be shown)"
haskell
asked Nov 19 at 1:01
user3749167
616
6
(1) Closely related: Check whether a type is an instance of Show in Haskell?; Use specialized implementation if a class instance is available. I'm not closing against those now because I'm not sure about which kind of answer would best fit here. (2) In the context of those two questions, the constraints-emerge package is also worth a shout. (3) In any case, as those discussions suggest, this isn't something to be undertaken lightly.
– duplode
Nov 19 at 2:35
It helps me. Thanks a lot!
– user3749167
Nov 19 at 9:27
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
In Haskell, is there any way to declare function it behaves differently depending on whether the type of a argument is an instance of specific type class?
For example, can I define genericShow in the following example?
-- If type `a` is an instance of `Show`.
genericShow :: Show a => a -> String
genericShow = show
-- If type `a` is not an instance of `Show`.
genericShow :: a -> String
genericShow _ = "(Cannot be shown)"
> genericShow 3
"3"
> genericShow const
"(Cannot be shown)"
haskell
asked Nov 19 at 1:01
user3749167
616
In Haskell, is there any way to declare function it behaves differently depending on whether the type of a argument is an instance of specific type class?
For example, can I define genericShow in the following example?
-- If type `a` is an instance of `Show`.
genericShow :: Show a => a -> String
genericShow = show
-- If type `a` is not an instance of `Show`.
genericShow :: a -> String
genericShow _ = "(Cannot be shown)"
> genericShow 3
"3"
> genericShow const
"(Cannot be shown)"
haskell
haskell
asked Nov 19 at 1:01
user3749167
616
asked Nov 19 at 1:01
user3749167
616
asked Nov 19 at 1:01
user3749167
616
asked Nov 19 at 1:01
user3749167
616
asked Nov 19 at 1:01
user3749167
616
616
6
(1) Closely related: Check whether a type is an instance of Show in Haskell?; Use specialized implementation if a class instance is available. I'm not closing against those now because I'm not sure about which kind of answer would best fit here. (2) In the context of those two questions, the constraints-emerge package is also worth a shout. (3) In any case, as those discussions suggest, this isn't something to be undertaken lightly.
– duplode
Nov 19 at 2:35
It helps me. Thanks a lot!
– user3749167
Nov 19 at 9:27
add a comment |
6
(1) Closely related: Check whether a type is an instance of Show in Haskell?; Use specialized implementation if a class instance is available. I'm not closing against those now because I'm not sure about which kind of answer would best fit here. (2) In the context of those two questions, the constraints-emerge package is also worth a shout. (3) In any case, as those discussions suggest, this isn't something to be undertaken lightly.
– duplode
Nov 19 at 2:35
It helps me. Thanks a lot!
– user3749167
Nov 19 at 9:27
6
6
(1) Closely related: Check whether a type is an instance of Show in Haskell?; Use specialized implementation if a class instance is available. I'm not closing against those now because I'm not sure about which kind of answer would best fit here. (2) In the context of those two questions, the constraints-emerge package is also worth a shout. (3) In any case, as those discussions suggest, this isn't something to be undertaken lightly.
– duplode
Nov 19 at 2:35
(1) Closely related: Check whether a type is an instance of Show in Haskell?; Use specialized implementation if a class instance is available. I'm not closing against those now because I'm not sure about which kind of answer would best fit here. (2) In the context of those two questions, the constraints-emerge package is also worth a shout. (3) In any case, as those discussions suggest, this isn't something to be undertaken lightly.
– duplode
Nov 19 at 2:35
It helps me. Thanks a lot!
– user3749167
Nov 19 at 9:27
It helps me. Thanks a lot!
– user3749167
Nov 19 at 9:27
add a comment |
1 Answer
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up vote
1
down vote
No.
The closest you can get is to use Overlapping instances, with a catch-all instance for anything not having a more specific Show instance.
instance {-# OVERLAPPABLE #-} Show a where
show _ = "(Cannot be shown)"
Overlapping instances come with lots of caveats: see topics like 'orphan instances', 'Incoherent instances'. That's particularly awkward with Prelude classes like Show, because there's likely to be lots of instances hidden away in libraries.
As @duplode says, there are many dangers. Almost certainly there's a better way to achieve whatever it is you think you want.
answered Nov 19 at 8:56
AntC
542210
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
No.
The closest you can get is to use Overlapping instances, with a catch-all instance for anything not having a more specific Show instance.
instance {-# OVERLAPPABLE #-} Show a where
show _ = "(Cannot be shown)"
Overlapping instances come with lots of caveats: see topics like 'orphan instances', 'Incoherent instances'. That's particularly awkward with Prelude classes like Show, because there's likely to be lots of instances hidden away in libraries.
As @duplode says, there are many dangers. Almost certainly there's a better way to achieve whatever it is you think you want.
answered Nov 19 at 8:56
AntC
542210
add a comment |
up vote
1
down vote
No.
The closest you can get is to use Overlapping instances, with a catch-all instance for anything not having a more specific Show instance.
instance {-# OVERLAPPABLE #-} Show a where
show _ = "(Cannot be shown)"
Overlapping instances come with lots of caveats: see topics like 'orphan instances', 'Incoherent instances'. That's particularly awkward with Prelude classes like Show, because there's likely to be lots of instances hidden away in libraries.
As @duplode says, there are many dangers. Almost certainly there's a better way to achieve whatever it is you think you want.
answered Nov 19 at 8:56
AntC
542210
add a comment |
up vote
1
down vote
up vote
1
down vote
No.
The closest you can get is to use Overlapping instances, with a catch-all instance for anything not having a more specific Show instance.
instance {-# OVERLAPPABLE #-} Show a where
show _ = "(Cannot be shown)"
Overlapping instances come with lots of caveats: see topics like 'orphan instances', 'Incoherent instances'. That's particularly awkward with Prelude classes like Show, because there's likely to be lots of instances hidden away in libraries.
As @duplode says, there are many dangers. Almost certainly there's a better way to achieve whatever it is you think you want.
answered Nov 19 at 8:56
AntC
542210
No.
The closest you can get is to use Overlapping instances, with a catch-all instance for anything not having a more specific Show instance.
instance {-# OVERLAPPABLE #-} Show a where
show _ = "(Cannot be shown)"
Overlapping instances come with lots of caveats: see topics like 'orphan instances', 'Incoherent instances'. That's particularly awkward with Prelude classes like Show, because there's likely to be lots of instances hidden away in libraries.
As @duplode says, there are many dangers. Almost certainly there's a better way to achieve whatever it is you think you want.
answered Nov 19 at 8:56
AntC
542210
answered Nov 19 at 8:56
AntC
542210
answered Nov 19 at 8:56
AntC
542210
answered Nov 19 at 8:56
AntC
542210
542210
add a comment |
add a comment |
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6
(1) Closely related: Check whether a type is an instance of Show in Haskell?; Use specialized implementation if a class instance is available. I'm not closing against those now because I'm not sure about which kind of answer would best fit here. (2) In the context of those two questions, the constraints-emerge package is also worth a shout. (3) In any case, as those discussions suggest, this isn't something to be undertaken lightly.
– duplode
Nov 19 at 2:35
It helps me. Thanks a lot!
– user3749167
Nov 19 at 9:27