How to find second,third,etc maximum peak of list











up vote
2
down vote

favorite












I need to find all values of peaks.
I have Table with 10000 elements in it and I plot a graphic using ListPlot.
enter image description here



Then I tried to find peaks:



tbl1 = Table[tbl[[i, 2]], {i, 1, Length[tbl]}];

gA = Max[tbl1]

gAm = Part[tbl, Position[tbl1 , gA ][[1, 1]], 1]


Here tbl my Table with Data
And get:



0.15

8.751


So I find the last peak starting. How I can find other?
enter image description here
I upload a .txt file with data to my google drive
here .



I also tried to use FindPeaks but it's wrong:



peakpositions = FindPeaks[tbl[[All, 2]]]



{{116, 0.}, {1441, 0.}}




peakwavelengths = tbl[[#1, 1]] & @@@ peakpositions



{0.115, 1.44}




ListPlot[tbl, PlotRange -> All, GridLines -> {peakwavelengths, None}, 

GridLinesStyle -> Directive[Red, Thick]]


enter image description here






plotting list-manipulation mathematical-optimization peak-detection







share|improve this question




















  • 1




    Did you try FindPeaks?
    – J42161217
    5 hours ago










  • Yes, I did. I added the result above.
    – John
    5 hours ago















up vote
2
down vote

favorite












I need to find all values of peaks.
I have Table with 10000 elements in it and I plot a graphic using ListPlot.
enter image description here



Then I tried to find peaks:



tbl1 = Table[tbl[[i, 2]], {i, 1, Length[tbl]}];

gA = Max[tbl1]

gAm = Part[tbl, Position[tbl1 , gA ][[1, 1]], 1]


Here tbl my Table with Data
And get:



0.15

8.751


So I find the last peak starting. How I can find other?
enter image description here
I upload a .txt file with data to my google drive
here .



I also tried to use FindPeaks but it's wrong:



peakpositions = FindPeaks[tbl[[All, 2]]]



{{116, 0.}, {1441, 0.}}




peakwavelengths = tbl[[#1, 1]] & @@@ peakpositions



{0.115, 1.44}




ListPlot[tbl, PlotRange -> All, GridLines -> {peakwavelengths, None}, 

GridLinesStyle -> Directive[Red, Thick]]


enter image description here






plotting list-manipulation mathematical-optimization peak-detection







share|improve this question




















  • 1




    Did you try FindPeaks?
    – J42161217
    5 hours ago










  • Yes, I did. I added the result above.
    – John
    5 hours ago













up vote
2
down vote

favorite









up vote
2
down vote

favorite











I need to find all values of peaks.
I have Table with 10000 elements in it and I plot a graphic using ListPlot.
enter image description here



Then I tried to find peaks:



tbl1 = Table[tbl[[i, 2]], {i, 1, Length[tbl]}];

gA = Max[tbl1]

gAm = Part[tbl, Position[tbl1 , gA ][[1, 1]], 1]


Here tbl my Table with Data
And get:



0.15

8.751


So I find the last peak starting. How I can find other?
enter image description here
I upload a .txt file with data to my google drive
here .



I also tried to use FindPeaks but it's wrong:



peakpositions = FindPeaks[tbl[[All, 2]]]



{{116, 0.}, {1441, 0.}}




peakwavelengths = tbl[[#1, 1]] & @@@ peakpositions



{0.115, 1.44}




ListPlot[tbl, PlotRange -> All, GridLines -> {peakwavelengths, None}, 

GridLinesStyle -> Directive[Red, Thick]]


enter image description here






plotting list-manipulation mathematical-optimization peak-detection







share|improve this question















I need to find all values of peaks.
I have Table with 10000 elements in it and I plot a graphic using ListPlot.
enter image description here



Then I tried to find peaks:



tbl1 = Table[tbl[[i, 2]], {i, 1, Length[tbl]}];

gA = Max[tbl1]

gAm = Part[tbl, Position[tbl1 , gA ][[1, 1]], 1]


Here tbl my Table with Data
And get:



0.15

8.751


So I find the last peak starting. How I can find other?
enter image description here
I upload a .txt file with data to my google drive
here .



I also tried to use FindPeaks but it's wrong:



peakpositions = FindPeaks[tbl[[All, 2]]]



{{116, 0.}, {1441, 0.}}




peakwavelengths = tbl[[#1, 1]] & @@@ peakpositions



{0.115, 1.44}




ListPlot[tbl, PlotRange -> All, GridLines -> {peakwavelengths, None}, 

GridLinesStyle -> Directive[Red, Thick]]


enter image description here






plotting list-manipulation mathematical-optimization peak-detection




plotting list-manipulation mathematical-optimization peak-detection






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 5 hours ago

























asked 5 hours ago









John

1996




1996








  • 1




    Did you try FindPeaks?
    – J42161217
    5 hours ago










  • Yes, I did. I added the result above.
    – John
    5 hours ago














  • 1




    Did you try FindPeaks?
    – J42161217
    5 hours ago










  • Yes, I did. I added the result above.
    – John
    5 hours ago








1




1




Did you try FindPeaks?
– J42161217
5 hours ago




Did you try FindPeaks?
– J42161217
5 hours ago












Yes, I did. I added the result above.
– John
5 hours ago




Yes, I did. I added the result above.
– John
5 hours ago










2 Answers
2






active

oldest

votes

















up vote
3
down vote



accepted










jumps = tbl[[1 + Flatten@Position[Sign@Differences[tbl[[All, 2]]], 1]]]



{{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}




ListStepPlot[tbl,  Epilog -> {Red, PointSize[Large], Point[jumps]}, 

 GridLines -> Transpose[jumps]]


enter image description here






share|improve this answer




























    up vote
    2
    down vote













    Pick[tbl,Join[{0},Sign@Differences[Last/@tbl]],1]



    {{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}







    share|improve this answer





















      Your Answer





      StackExchange.ifUsing("editor", function () {
      return StackExchange.using("mathjaxEditing", function () {
      StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
      StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
      });
      });
      }, "mathjax-editing");

      StackExchange.ready(function() {
      var channelOptions = {
      tags: "".split(" "),
      id: "387"
      };
      initTagRenderer("".split(" "), "".split(" "), channelOptions);

      StackExchange.using("externalEditor", function() {
      // Have to fire editor after snippets, if snippets enabled
      if (StackExchange.settings.snippets.snippetsEnabled) {
      StackExchange.using("snippets", function() {
      createEditor();
      });
      }
      else {
      createEditor();
      }
      });

      function createEditor() {
      StackExchange.prepareEditor({
      heartbeatType: 'answer',
      convertImagesToLinks: false,
      noModals: true,
      showLowRepImageUploadWarning: true,
      reputationToPostImages: null,
      bindNavPrevention: true,
      postfix: "",
      imageUploader: {
      brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
      contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
      allowUrls: true
      },
      onDemand: true,
      discardSelector: ".discard-answer"
      ,immediatelyShowMarkdownHelp:true
      });


      }
      });














       

      draft saved


      draft discarded


















      StackExchange.ready(
      function () {
      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f186752%2fhow-to-find-second-third-etc-maximum-peak-of-list%23new-answer', 'question_page');
      }
      );

      Post as a guest















      Required, but never shown

























      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      3
      down vote



      accepted










      jumps = tbl[[1 + Flatten@Position[Sign@Differences[tbl[[All, 2]]], 1]]]



      {{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}




      ListStepPlot[tbl,  Epilog -> {Red, PointSize[Large], Point[jumps]}, 
      
 GridLines -> Transpose[jumps]]


      enter image description here






      share|improve this answer

























        up vote
        3
        down vote



        accepted










        jumps = tbl[[1 + Flatten@Position[Sign@Differences[tbl[[All, 2]]], 1]]]



        {{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}




        ListStepPlot[tbl,  Epilog -> {Red, PointSize[Large], Point[jumps]}, 
        
 GridLines -> Transpose[jumps]]


        enter image description here






        share|improve this answer























          up vote
          3
          down vote



          accepted







          up vote
          3
          down vote



          accepted






          jumps = tbl[[1 + Flatten@Position[Sign@Differences[tbl[[All, 2]]], 1]]]



          {{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}




          ListStepPlot[tbl,  Epilog -> {Red, PointSize[Large], Point[jumps]}, 
          
 GridLines -> Transpose[jumps]]


          enter image description here






          share|improve this answer












          jumps = tbl[[1 + Flatten@Position[Sign@Differences[tbl[[All, 2]]], 1]]]



          {{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}




          ListStepPlot[tbl,  Epilog -> {Red, PointSize[Large], Point[jumps]}, 
          
 GridLines -> Transpose[jumps]]


          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 5 hours ago









          kglr

          173k8194400




          173k8194400






















              up vote
              2
              down vote













              Pick[tbl,Join[{0},Sign@Differences[Last/@tbl]],1]



              {{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}







              share|improve this answer

























                up vote
                2
                down vote













                Pick[tbl,Join[{0},Sign@Differences[Last/@tbl]],1]



                {{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}







                share|improve this answer























                  up vote
                  2
                  down vote










                  up vote
                  2
                  down vote









                  Pick[tbl,Join[{0},Sign@Differences[Last/@tbl]],1]



                  {{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}







                  share|improve this answer












                  Pick[tbl,Join[{0},Sign@Differences[Last/@tbl]],1]



                  {{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}








                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 4 hours ago









                  J42161217

                  3,177219




                  3,177219






























                       

                      draft saved


                      draft discarded



















































                       


                      draft saved


                      draft discarded














                      StackExchange.ready(
                      function () {
                      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f186752%2fhow-to-find-second-third-etc-maximum-peak-of-list%23new-answer', 'question_page');
                      }
                      );

                      Post as a guest















                      Required, but never shown





















































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown

































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown







                      -

                      Popular posts from this blog

                      Costa Masnaga

                      Image
                      .mw-parser-output .avviso .mbox-text-div>div,.mw-parser-output .avviso .mbox-text-full-div>div{font-size:90%}.mw-parser-output .avviso .mbox-image div{width:52px}.mw-parser-output .avviso .mbox-text-full-div .hide-when-compact{display:block} Questa voce o sezione sull'argomento Lombardia non cita le fonti necessarie o quelle presenti sono insufficienti . Puoi migliorare questa voce aggiungendo citazioni da fonti attendibili secondo le linee guida sull'uso delle fonti. Segui i suggerimenti del progetto di riferimento. Costa Masnaga comune Localizzazione Stato   Italia Regione Lombardia Provincia Lecco Amministrazione Sindaco Sabina Panzeri (Al centro il cittadino) dall'08/06/2009 Territorio Coordinate 45°46′N 9°17′E  /  45.766667°N 9.283333°E 45.766667; 9.283333  ( Costa Masnaga ) Coordinate: 45°46′N 9°17′E  /  45.766667°N 9.283333°E 45.766667; 9.283333  ( Costa Masnaga ) Altitudine 318 m s.l.m...
                      Read more

                      Fotorealismo

                      Image
                      Guerrino Boatto, Venice's St. Barnaba Church and canal Il fotorealismo è un genere di pittura basato sull'uso di una o più fotografie dalle quali l'artista prende le informazioni necessarie da utilizzare poi nel processo della creazione dell'opera, in genere ad olio o ad acrilico, al fine di avere un aspetto finale il più simile possibile alla fotografia. Indice 1 Storia 2 Lista dei fotorealisti 3 Note 4 Voci correlate 5 Altri progetti Storia | Il fotorealismo è un movimento che nasce negli Stati Uniti d'America alla fine degli anni sessanta [1] sulla scia della Pop Art [2] [3] [4] , e insieme condividono il carattere reazionario verso la travolgente ascesa dei media, che alla metà del ventesimo secolo si trasforma in un fenomeno di massa talmente imponente da minacciare il valore dell'immagine nell'arte. [5] [6] Ne consegue così che, colto il gesto d'inizio che fu della Pop Art, i fotorealisti aprono ad un ...
                      Read more

                      Sidney Franklin

                      Image
                      Questa voce sull'argomento registi statunitensi è solo un abbozzo . Contribuisci a migliorarla secondo le convenzioni di Wikipedia. Sidney Franklin, foto di Carl Van Vechten Oscar alla memoria Irving G. Thalberg 1943 Sidney Franklin , all'anagrafe Sidney Arnold Franklin , (San Francisco, 21 marzo 1893 – Santa Monica, 18 maggio 1972), è stato un regista, produttore cinematografico e attore statunitense. Il 20 giugno 1963, si sposò con l'attrice australiana Enid Bennett. Il matrimonio durò fino alla morte dell'attrice, il 14 maggio 1969 [1] Indice 1 Filmografia 1.1 Regista 1.2 Aiuto regia (parziale) 1.3 Produttore 1.4 Attore (parziale) 2 Note 3 Altri progetti 4 Collegamenti esterni Filmografia | Regista | The Baby , co-regia Chester M. Franklin (1915) The Rivals , co-regia Chester M. Franklin (1915) Little Dick's First Case , co-regia Chester M. Franklin (1915) Her Filmland Hero , co-...
                      Read more