How to create Object in the class implementing HandlerInterceptor to access it from anywhere for that reqest
I am having situation like: in the preHandle() method of the class implementing HandlerInterceptor, i am having sessionId getting in the incoming HttpServletRequest object request. now using this session id i am fetching userInfo from the DB. the same info i have to use somewhere else like service layer to process the request.
It would be very helpful if anyone of you help me out to achieve it. Thanks in advance.
spring-mvc spring-security
asked Nov 20 at 15:18
Rohit
146
add a comment |
I am having situation like: in the preHandle() method of the class implementing HandlerInterceptor, i am having sessionId getting in the incoming HttpServletRequest object request. now using this session id i am fetching userInfo from the DB. the same info i have to use somewhere else like service layer to process the request.
It would be very helpful if anyone of you help me out to achieve it. Thanks in advance.
spring-mvc spring-security
asked Nov 20 at 15:18
Rohit
146
add a comment |
I am having situation like: in the preHandle() method of the class implementing HandlerInterceptor, i am having sessionId getting in the incoming HttpServletRequest object request. now using this session id i am fetching userInfo from the DB. the same info i have to use somewhere else like service layer to process the request.
It would be very helpful if anyone of you help me out to achieve it. Thanks in advance.
spring-mvc spring-security
asked Nov 20 at 15:18
Rohit
146
I am having situation like: in the preHandle() method of the class implementing HandlerInterceptor, i am having sessionId getting in the incoming HttpServletRequest object request. now using this session id i am fetching userInfo from the DB. the same info i have to use somewhere else like service layer to process the request.
It would be very helpful if anyone of you help me out to achieve it. Thanks in advance.
spring-mvc spring-security
spring-mvc spring-security
asked Nov 20 at 15:18
Rohit
146
asked Nov 20 at 15:18
Rohit
146
asked Nov 20 at 15:18
Rohit
146
asked Nov 20 at 15:18
Rohit
146
asked Nov 20 at 15:18
Rohit
146
146
add a comment |
add a comment |
1 Answer
1
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You can use a ThreadLocal to store a reference to a user that will only be accessible to the current thread of execution.
https://docs.oracle.com/javase/7/docs/api/java/lang/ThreadLocal.html
You can wrap this in a context class so that in your service you can access the current user via the static call: User user = UserContextUtils.getUser();
UserContextUtils:
public class UserContextUtils {
private static final ThreadLocal<User> CONTEXT = new ThreadLocal<>();
public static void setUser(User user) {
CONTEXT.set(user);
}
public static User getUser() {
return CONTEXT.get();
}
public static void clear() {
CONTEXT.remove();
}
}
The Interceptor:
public class MyHandlerInterceptor implements HandlerInterceptor {
@Override
public boolean preHandle(HttpServletRequest request,
HttpServletResponse response, Object handler)
throws Exception {
User user = null;// get user from the database.
UserContextUtils.setUser(user);
return true;
}
@Override
public void afterCompletion(HttpServletRequest request,
HttpServletResponse response, Object handler,
Exception ex) {
// as some web servers re-use threads, you must ensure that the
// context is cleared on completion either here or elsewhere.
UserContextUtils.clear();
}
@Override
public void postHandle(HttpServletRequest request,
HttpServletResponse response, Object handler,
ModelAndView modelAndView) throws Exception {
}
}
answered Nov 20 at 19:09
Alan Hay
15.2k22769
Thanks a lot Alan. it worked for me :)
– Rohit
Nov 21 at 4:41
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use a ThreadLocal to store a reference to a user that will only be accessible to the current thread of execution.
https://docs.oracle.com/javase/7/docs/api/java/lang/ThreadLocal.html
You can wrap this in a context class so that in your service you can access the current user via the static call: User user = UserContextUtils.getUser();
UserContextUtils:
public class UserContextUtils {
private static final ThreadLocal<User> CONTEXT = new ThreadLocal<>();
public static void setUser(User user) {
CONTEXT.set(user);
}
public static User getUser() {
return CONTEXT.get();
}
public static void clear() {
CONTEXT.remove();
}
}
The Interceptor:
public class MyHandlerInterceptor implements HandlerInterceptor {
@Override
public boolean preHandle(HttpServletRequest request,
HttpServletResponse response, Object handler)
throws Exception {
User user = null;// get user from the database.
UserContextUtils.setUser(user);
return true;
}
@Override
public void afterCompletion(HttpServletRequest request,
HttpServletResponse response, Object handler,
Exception ex) {
// as some web servers re-use threads, you must ensure that the
// context is cleared on completion either here or elsewhere.
UserContextUtils.clear();
}
@Override
public void postHandle(HttpServletRequest request,
HttpServletResponse response, Object handler,
ModelAndView modelAndView) throws Exception {
}
}
answered Nov 20 at 19:09
Alan Hay
15.2k22769
Thanks a lot Alan. it worked for me :)
– Rohit
Nov 21 at 4:41
add a comment |
You can use a ThreadLocal to store a reference to a user that will only be accessible to the current thread of execution.
https://docs.oracle.com/javase/7/docs/api/java/lang/ThreadLocal.html
You can wrap this in a context class so that in your service you can access the current user via the static call: User user = UserContextUtils.getUser();
UserContextUtils:
public class UserContextUtils {
private static final ThreadLocal<User> CONTEXT = new ThreadLocal<>();
public static void setUser(User user) {
CONTEXT.set(user);
}
public static User getUser() {
return CONTEXT.get();
}
public static void clear() {
CONTEXT.remove();
}
}
The Interceptor:
public class MyHandlerInterceptor implements HandlerInterceptor {
@Override
public boolean preHandle(HttpServletRequest request,
HttpServletResponse response, Object handler)
throws Exception {
User user = null;// get user from the database.
UserContextUtils.setUser(user);
return true;
}
@Override
public void afterCompletion(HttpServletRequest request,
HttpServletResponse response, Object handler,
Exception ex) {
// as some web servers re-use threads, you must ensure that the
// context is cleared on completion either here or elsewhere.
UserContextUtils.clear();
}
@Override
public void postHandle(HttpServletRequest request,
HttpServletResponse response, Object handler,
ModelAndView modelAndView) throws Exception {
}
}
answered Nov 20 at 19:09
Alan Hay
15.2k22769
Thanks a lot Alan. it worked for me :)
– Rohit
Nov 21 at 4:41
add a comment |
You can use a ThreadLocal to store a reference to a user that will only be accessible to the current thread of execution.
https://docs.oracle.com/javase/7/docs/api/java/lang/ThreadLocal.html
You can wrap this in a context class so that in your service you can access the current user via the static call: User user = UserContextUtils.getUser();
UserContextUtils:
public class UserContextUtils {
private static final ThreadLocal<User> CONTEXT = new ThreadLocal<>();
public static void setUser(User user) {
CONTEXT.set(user);
}
public static User getUser() {
return CONTEXT.get();
}
public static void clear() {
CONTEXT.remove();
}
}
The Interceptor:
public class MyHandlerInterceptor implements HandlerInterceptor {
@Override
public boolean preHandle(HttpServletRequest request,
HttpServletResponse response, Object handler)
throws Exception {
User user = null;// get user from the database.
UserContextUtils.setUser(user);
return true;
}
@Override
public void afterCompletion(HttpServletRequest request,
HttpServletResponse response, Object handler,
Exception ex) {
// as some web servers re-use threads, you must ensure that the
// context is cleared on completion either here or elsewhere.
UserContextUtils.clear();
}
@Override
public void postHandle(HttpServletRequest request,
HttpServletResponse response, Object handler,
ModelAndView modelAndView) throws Exception {
}
}
answered Nov 20 at 19:09
Alan Hay
15.2k22769
You can use a ThreadLocal to store a reference to a user that will only be accessible to the current thread of execution.
https://docs.oracle.com/javase/7/docs/api/java/lang/ThreadLocal.html
You can wrap this in a context class so that in your service you can access the current user via the static call: User user = UserContextUtils.getUser();
UserContextUtils:
public class UserContextUtils {
private static final ThreadLocal<User> CONTEXT = new ThreadLocal<>();
public static void setUser(User user) {
CONTEXT.set(user);
}
public static User getUser() {
return CONTEXT.get();
}
public static void clear() {
CONTEXT.remove();
}
}
The Interceptor:
public class MyHandlerInterceptor implements HandlerInterceptor {
@Override
public boolean preHandle(HttpServletRequest request,
HttpServletResponse response, Object handler)
throws Exception {
User user = null;// get user from the database.
UserContextUtils.setUser(user);
return true;
}
@Override
public void afterCompletion(HttpServletRequest request,
HttpServletResponse response, Object handler,
Exception ex) {
// as some web servers re-use threads, you must ensure that the
// context is cleared on completion either here or elsewhere.
UserContextUtils.clear();
}
@Override
public void postHandle(HttpServletRequest request,
HttpServletResponse response, Object handler,
ModelAndView modelAndView) throws Exception {
}
}
answered Nov 20 at 19:09
Alan Hay
15.2k22769
answered Nov 20 at 19:09
Alan Hay
15.2k22769
answered Nov 20 at 19:09
Alan Hay
15.2k22769
answered Nov 20 at 19:09
Alan Hay
15.2k22769
15.2k22769
Thanks a lot Alan. it worked for me :)
– Rohit
Nov 21 at 4:41
add a comment |
Thanks a lot Alan. it worked for me :)
– Rohit
Nov 21 at 4:41
Thanks a lot Alan. it worked for me :)
– Rohit
Nov 21 at 4:41
Thanks a lot Alan. it worked for me :)
– Rohit
Nov 21 at 4:41
add a comment |
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