String contains non-overlapping letter pairs











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I was trying my hand at learning Elixir via ancient adventofcode puzzles and was trying to write a function to satisfy this requirement:




It contains a pair of any two letters that appears at least twice in
the string without overlapping, like xyxy (xy) or aabcdefgaa (aa), but
not like aaa (aa, but it overlaps).




Here is what I came up with, but it feels like it might be unwieldy. Is there a way to make it more elegant?



  def has_non_overlapping_pair(string) do
0..String.length(string)-2
|> Enum.map(fn n ->
String.slice(string, n, 2)
end)
|> Enum.reduce(["_"], fn pair, acc ->
if pair == hd(acc) do ["_"|acc]
else [pair|acc] end
end)
|> count_occurrences
|> Map.delete("_")
|> Map.values
|> Enum.any?(fn val -> val > 1 end)
end









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    up vote
    2
    down vote

    favorite












    I was trying my hand at learning Elixir via ancient adventofcode puzzles and was trying to write a function to satisfy this requirement:




    It contains a pair of any two letters that appears at least twice in
    the string without overlapping, like xyxy (xy) or aabcdefgaa (aa), but
    not like aaa (aa, but it overlaps).




    Here is what I came up with, but it feels like it might be unwieldy. Is there a way to make it more elegant?



      def has_non_overlapping_pair(string) do
    0..String.length(string)-2
    |> Enum.map(fn n ->
    String.slice(string, n, 2)
    end)
    |> Enum.reduce(["_"], fn pair, acc ->
    if pair == hd(acc) do ["_"|acc]
    else [pair|acc] end
    end)
    |> count_occurrences
    |> Map.delete("_")
    |> Map.values
    |> Enum.any?(fn val -> val > 1 end)
    end









    share|improve this question









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      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      I was trying my hand at learning Elixir via ancient adventofcode puzzles and was trying to write a function to satisfy this requirement:




      It contains a pair of any two letters that appears at least twice in
      the string without overlapping, like xyxy (xy) or aabcdefgaa (aa), but
      not like aaa (aa, but it overlaps).




      Here is what I came up with, but it feels like it might be unwieldy. Is there a way to make it more elegant?



        def has_non_overlapping_pair(string) do
      0..String.length(string)-2
      |> Enum.map(fn n ->
      String.slice(string, n, 2)
      end)
      |> Enum.reduce(["_"], fn pair, acc ->
      if pair == hd(acc) do ["_"|acc]
      else [pair|acc] end
      end)
      |> count_occurrences
      |> Map.delete("_")
      |> Map.values
      |> Enum.any?(fn val -> val > 1 end)
      end









      share|improve this question









      New contributor




      thesunneversets is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      I was trying my hand at learning Elixir via ancient adventofcode puzzles and was trying to write a function to satisfy this requirement:




      It contains a pair of any two letters that appears at least twice in
      the string without overlapping, like xyxy (xy) or aabcdefgaa (aa), but
      not like aaa (aa, but it overlaps).




      Here is what I came up with, but it feels like it might be unwieldy. Is there a way to make it more elegant?



        def has_non_overlapping_pair(string) do
      0..String.length(string)-2
      |> Enum.map(fn n ->
      String.slice(string, n, 2)
      end)
      |> Enum.reduce(["_"], fn pair, acc ->
      if pair == hd(acc) do ["_"|acc]
      else [pair|acc] end
      end)
      |> count_occurrences
      |> Map.delete("_")
      |> Map.values
      |> Enum.any?(fn val -> val > 1 end)
      end






      strings elixir






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      edited 15 mins ago









      Jamal

      30.2k11115226




      30.2k11115226






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      asked 9 hours ago









      thesunneversets

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      1112




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