String contains non-overlapping letter pairs
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I was trying my hand at learning Elixir via ancient adventofcode puzzles and was trying to write a function to satisfy this requirement:
It contains a pair of any two letters that appears at least twice in
the string without overlapping, like xyxy (xy) or aabcdefgaa (aa), but
not like aaa (aa, but it overlaps).
Here is what I came up with, but it feels like it might be unwieldy. Is there a way to make it more elegant?
def has_non_overlapping_pair(string) do
0..String.length(string)-2
|> Enum.map(fn n ->
String.slice(string, n, 2)
end)
|> Enum.reduce(["_"], fn pair, acc ->
if pair == hd(acc) do ["_"|acc]
else [pair|acc] end
end)
|> count_occurrences
|> Map.delete("_")
|> Map.values
|> Enum.any?(fn val -> val > 1 end)
end
strings elixir
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I was trying my hand at learning Elixir via ancient adventofcode puzzles and was trying to write a function to satisfy this requirement:
It contains a pair of any two letters that appears at least twice in
the string without overlapping, like xyxy (xy) or aabcdefgaa (aa), but
not like aaa (aa, but it overlaps).
Here is what I came up with, but it feels like it might be unwieldy. Is there a way to make it more elegant?
def has_non_overlapping_pair(string) do
0..String.length(string)-2
|> Enum.map(fn n ->
String.slice(string, n, 2)
end)
|> Enum.reduce(["_"], fn pair, acc ->
if pair == hd(acc) do ["_"|acc]
else [pair|acc] end
end)
|> count_occurrences
|> Map.delete("_")
|> Map.values
|> Enum.any?(fn val -> val > 1 end)
end
strings elixir
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add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I was trying my hand at learning Elixir via ancient adventofcode puzzles and was trying to write a function to satisfy this requirement:
It contains a pair of any two letters that appears at least twice in
the string without overlapping, like xyxy (xy) or aabcdefgaa (aa), but
not like aaa (aa, but it overlaps).
Here is what I came up with, but it feels like it might be unwieldy. Is there a way to make it more elegant?
def has_non_overlapping_pair(string) do
0..String.length(string)-2
|> Enum.map(fn n ->
String.slice(string, n, 2)
end)
|> Enum.reduce(["_"], fn pair, acc ->
if pair == hd(acc) do ["_"|acc]
else [pair|acc] end
end)
|> count_occurrences
|> Map.delete("_")
|> Map.values
|> Enum.any?(fn val -> val > 1 end)
end
strings elixir
New contributor
I was trying my hand at learning Elixir via ancient adventofcode puzzles and was trying to write a function to satisfy this requirement:
It contains a pair of any two letters that appears at least twice in
the string without overlapping, like xyxy (xy) or aabcdefgaa (aa), but
not like aaa (aa, but it overlaps).
Here is what I came up with, but it feels like it might be unwieldy. Is there a way to make it more elegant?
def has_non_overlapping_pair(string) do
0..String.length(string)-2
|> Enum.map(fn n ->
String.slice(string, n, 2)
end)
|> Enum.reduce(["_"], fn pair, acc ->
if pair == hd(acc) do ["_"|acc]
else [pair|acc] end
end)
|> count_occurrences
|> Map.delete("_")
|> Map.values
|> Enum.any?(fn val -> val > 1 end)
end
strings elixir
strings elixir
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edited 15 mins ago
Jamal♦
30.2k11115226
30.2k11115226
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asked 9 hours ago
thesunneversets
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