After filtering, how to select and remove visible rows in Excel?












0














ActiveSheet.Range("$A$1:$O$1464").AutoFilter Field:=7, Criteria1:="promo"
ActiveSheet.Range("$A$1:$O$1464").AutoFilter Field:=12, Criteria1:="="
Rows("2:2").Select
Range(Selection, Selection.End(xlDown)).Select
Selection.Delete Shift:=xlUp


I would like to select the visible rows after filtering. I read up some post which uses .SpecialCells(xlCellTypeVisible) but I not sure how to amend my existing code.










share|improve this question





























    0














    ActiveSheet.Range("$A$1:$O$1464").AutoFilter Field:=7, Criteria1:="promo"
    ActiveSheet.Range("$A$1:$O$1464").AutoFilter Field:=12, Criteria1:="="
    Rows("2:2").Select
    Range(Selection, Selection.End(xlDown)).Select
    Selection.Delete Shift:=xlUp


    I would like to select the visible rows after filtering. I read up some post which uses .SpecialCells(xlCellTypeVisible) but I not sure how to amend my existing code.










    share|improve this question



























      0












      0








      0







      ActiveSheet.Range("$A$1:$O$1464").AutoFilter Field:=7, Criteria1:="promo"
      ActiveSheet.Range("$A$1:$O$1464").AutoFilter Field:=12, Criteria1:="="
      Rows("2:2").Select
      Range(Selection, Selection.End(xlDown)).Select
      Selection.Delete Shift:=xlUp


      I would like to select the visible rows after filtering. I read up some post which uses .SpecialCells(xlCellTypeVisible) but I not sure how to amend my existing code.










      share|improve this question















      ActiveSheet.Range("$A$1:$O$1464").AutoFilter Field:=7, Criteria1:="promo"
      ActiveSheet.Range("$A$1:$O$1464").AutoFilter Field:=12, Criteria1:="="
      Rows("2:2").Select
      Range(Selection, Selection.End(xlDown)).Select
      Selection.Delete Shift:=xlUp


      I would like to select the visible rows after filtering. I read up some post which uses .SpecialCells(xlCellTypeVisible) but I not sure how to amend my existing code.







      excel vba filter worksheet






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 20 at 10:14









      Amessihel

      1,9631723




      1,9631723










      asked Nov 20 at 9:54









      chee seng ng

      248




      248
























          2 Answers
          2






          active

          oldest

          votes


















          0














          You can do it this way (after filtering):



          ' Update: don't select the header
          Activesheet.Range("$A$2:$O$1464").SpecialCells(xlCellTypeVisible).Select
          Selection.EntireRow.Delete





          share|improve this answer























          • I tried replacing my last 2 line with your code. It shows compile error: Expected: list separator or
            – chee seng ng
            Nov 20 at 10:42










          • It kinda work but my column header got delete as well. Anyway to delete 2nd row onwards?
            – chee seng ng
            Nov 20 at 11:05










          • Yes it work perfectly! Thank you for your help.
            – chee seng ng
            Nov 22 at 4:11



















          -1














          'Put after this to your filter code
          If Application.WorksheetFunction.Subtotal(3, Range("A1:A1464")) > 1 then
          Range("$A$2:$A$1464").EntireRow.Select
          Selection.SpecialCells(xlCellTypeVisible).Select
          Selection.Delete Shift:=xlUp
          else
          Msgbox "Criteria not found"
          end if





          share|improve this answer





















          • While this might answer the authors question, it lacks some explaining words and/or links to documentation. Raw code snippets are not very helpful without some phrases around them. You may also find how to write a good answer very helpful. Please edit your answer - From Review
            – Nick
            Nov 21 at 3:11











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          2 Answers
          2






          active

          oldest

          votes








          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0














          You can do it this way (after filtering):



          ' Update: don't select the header
          Activesheet.Range("$A$2:$O$1464").SpecialCells(xlCellTypeVisible).Select
          Selection.EntireRow.Delete





          share|improve this answer























          • I tried replacing my last 2 line with your code. It shows compile error: Expected: list separator or
            – chee seng ng
            Nov 20 at 10:42










          • It kinda work but my column header got delete as well. Anyway to delete 2nd row onwards?
            – chee seng ng
            Nov 20 at 11:05










          • Yes it work perfectly! Thank you for your help.
            – chee seng ng
            Nov 22 at 4:11
















          0














          You can do it this way (after filtering):



          ' Update: don't select the header
          Activesheet.Range("$A$2:$O$1464").SpecialCells(xlCellTypeVisible).Select
          Selection.EntireRow.Delete





          share|improve this answer























          • I tried replacing my last 2 line with your code. It shows compile error: Expected: list separator or
            – chee seng ng
            Nov 20 at 10:42










          • It kinda work but my column header got delete as well. Anyway to delete 2nd row onwards?
            – chee seng ng
            Nov 20 at 11:05










          • Yes it work perfectly! Thank you for your help.
            – chee seng ng
            Nov 22 at 4:11














          0












          0








          0






          You can do it this way (after filtering):



          ' Update: don't select the header
          Activesheet.Range("$A$2:$O$1464").SpecialCells(xlCellTypeVisible).Select
          Selection.EntireRow.Delete





          share|improve this answer














          You can do it this way (after filtering):



          ' Update: don't select the header
          Activesheet.Range("$A$2:$O$1464").SpecialCells(xlCellTypeVisible).Select
          Selection.EntireRow.Delete






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 20 at 11:10

























          answered Nov 20 at 10:26









          Amessihel

          1,9631723




          1,9631723












          • I tried replacing my last 2 line with your code. It shows compile error: Expected: list separator or
            – chee seng ng
            Nov 20 at 10:42










          • It kinda work but my column header got delete as well. Anyway to delete 2nd row onwards?
            – chee seng ng
            Nov 20 at 11:05










          • Yes it work perfectly! Thank you for your help.
            – chee seng ng
            Nov 22 at 4:11


















          • I tried replacing my last 2 line with your code. It shows compile error: Expected: list separator or
            – chee seng ng
            Nov 20 at 10:42










          • It kinda work but my column header got delete as well. Anyway to delete 2nd row onwards?
            – chee seng ng
            Nov 20 at 11:05










          • Yes it work perfectly! Thank you for your help.
            – chee seng ng
            Nov 22 at 4:11
















          I tried replacing my last 2 line with your code. It shows compile error: Expected: list separator or
          – chee seng ng
          Nov 20 at 10:42




          I tried replacing my last 2 line with your code. It shows compile error: Expected: list separator or
          – chee seng ng
          Nov 20 at 10:42












          It kinda work but my column header got delete as well. Anyway to delete 2nd row onwards?
          – chee seng ng
          Nov 20 at 11:05




          It kinda work but my column header got delete as well. Anyway to delete 2nd row onwards?
          – chee seng ng
          Nov 20 at 11:05












          Yes it work perfectly! Thank you for your help.
          – chee seng ng
          Nov 22 at 4:11




          Yes it work perfectly! Thank you for your help.
          – chee seng ng
          Nov 22 at 4:11













          -1














          'Put after this to your filter code
          If Application.WorksheetFunction.Subtotal(3, Range("A1:A1464")) > 1 then
          Range("$A$2:$A$1464").EntireRow.Select
          Selection.SpecialCells(xlCellTypeVisible).Select
          Selection.Delete Shift:=xlUp
          else
          Msgbox "Criteria not found"
          end if





          share|improve this answer





















          • While this might answer the authors question, it lacks some explaining words and/or links to documentation. Raw code snippets are not very helpful without some phrases around them. You may also find how to write a good answer very helpful. Please edit your answer - From Review
            – Nick
            Nov 21 at 3:11
















          -1














          'Put after this to your filter code
          If Application.WorksheetFunction.Subtotal(3, Range("A1:A1464")) > 1 then
          Range("$A$2:$A$1464").EntireRow.Select
          Selection.SpecialCells(xlCellTypeVisible).Select
          Selection.Delete Shift:=xlUp
          else
          Msgbox "Criteria not found"
          end if





          share|improve this answer





















          • While this might answer the authors question, it lacks some explaining words and/or links to documentation. Raw code snippets are not very helpful without some phrases around them. You may also find how to write a good answer very helpful. Please edit your answer - From Review
            – Nick
            Nov 21 at 3:11














          -1












          -1








          -1






          'Put after this to your filter code
          If Application.WorksheetFunction.Subtotal(3, Range("A1:A1464")) > 1 then
          Range("$A$2:$A$1464").EntireRow.Select
          Selection.SpecialCells(xlCellTypeVisible).Select
          Selection.Delete Shift:=xlUp
          else
          Msgbox "Criteria not found"
          end if





          share|improve this answer












          'Put after this to your filter code
          If Application.WorksheetFunction.Subtotal(3, Range("A1:A1464")) > 1 then
          Range("$A$2:$A$1464").EntireRow.Select
          Selection.SpecialCells(xlCellTypeVisible).Select
          Selection.Delete Shift:=xlUp
          else
          Msgbox "Criteria not found"
          end if






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 20 at 11:06









          Manoj Babu

          312




          312












          • While this might answer the authors question, it lacks some explaining words and/or links to documentation. Raw code snippets are not very helpful without some phrases around them. You may also find how to write a good answer very helpful. Please edit your answer - From Review
            – Nick
            Nov 21 at 3:11


















          • While this might answer the authors question, it lacks some explaining words and/or links to documentation. Raw code snippets are not very helpful without some phrases around them. You may also find how to write a good answer very helpful. Please edit your answer - From Review
            – Nick
            Nov 21 at 3:11
















          While this might answer the authors question, it lacks some explaining words and/or links to documentation. Raw code snippets are not very helpful without some phrases around them. You may also find how to write a good answer very helpful. Please edit your answer - From Review
          – Nick
          Nov 21 at 3:11




          While this might answer the authors question, it lacks some explaining words and/or links to documentation. Raw code snippets are not very helpful without some phrases around them. You may also find how to write a good answer very helpful. Please edit your answer - From Review
          – Nick
          Nov 21 at 3:11


















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