create date object by hours and minutes
0
I want to setup a setTimeout function and need to calculate the seconds for the callback. Let's say I want to execute a function at 12:00 (HH-MM) I have to calculate the timespan up to this time. If the time has already passed the next day is relevant.
I get the current date time with new Date()
I know I can calculate the timespan in seconds by using
const difference = dateTimeOne.getTime() - dateTimeTwo.getTime();
const differenceInSeconds = difference / 1000;
Is there a way creating a second date object by passing in the hours and minutes or do I have to calculate it on my own?
An example would be new Date('12:45')
javascript date datetime
asked Nov 22 '18 at 13:32
MHComputechMHComputech
26213
add a comment |
0
I want to setup a setTimeout function and need to calculate the seconds for the callback. Let's say I want to execute a function at 12:00 (HH-MM) I have to calculate the timespan up to this time. If the time has already passed the next day is relevant.
I get the current date time with new Date()
I know I can calculate the timespan in seconds by using
const difference = dateTimeOne.getTime() - dateTimeTwo.getTime();
const differenceInSeconds = difference / 1000;
Is there a way creating a second date object by passing in the hours and minutes or do I have to calculate it on my own?
An example would be new Date('12:45')
javascript date datetime
asked Nov 22 '18 at 13:32
MHComputechMHComputech
26213
add a comment |
0
0
0
I want to setup a setTimeout function and need to calculate the seconds for the callback. Let's say I want to execute a function at 12:00 (HH-MM) I have to calculate the timespan up to this time. If the time has already passed the next day is relevant.
I get the current date time with new Date()
I know I can calculate the timespan in seconds by using
const difference = dateTimeOne.getTime() - dateTimeTwo.getTime();
const differenceInSeconds = difference / 1000;
Is there a way creating a second date object by passing in the hours and minutes or do I have to calculate it on my own?
An example would be new Date('12:45')
javascript date datetime
asked Nov 22 '18 at 13:32
MHComputechMHComputech
26213
I want to setup a setTimeout function and need to calculate the seconds for the callback. Let's say I want to execute a function at 12:00 (HH-MM) I have to calculate the timespan up to this time. If the time has already passed the next day is relevant.
I get the current date time with new Date()
I know I can calculate the timespan in seconds by using
const difference = dateTimeOne.getTime() - dateTimeTwo.getTime();
const differenceInSeconds = difference / 1000;
Is there a way creating a second date object by passing in the hours and minutes or do I have to calculate it on my own?
An example would be new Date('12:45')
javascript date datetime
javascript date datetime
asked Nov 22 '18 at 13:32
MHComputechMHComputech
26213
asked Nov 22 '18 at 13:32
MHComputechMHComputech
26213
asked Nov 22 '18 at 13:32
MHComputechMHComputech
26213
asked Nov 22 '18 at 13:32
MHComputechMHComputech
26213
asked Nov 22 '18 at 13:32
MHComputechMHComputech
26213
26213
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
2
var minutes = 42;
for (var hours = 1; hours < 24; hours+=3) {
var newAlarm = setAlarm(hours, minutes);
out(newAlarm)
}
function out(date) {
var now = new Date()
if (date.getDate() != now.getDate()) {
console.log('tomorrow: ' + date.getHours() + ":" + date.getMinutes())
} else {
console.log('today: ' + date.getHours() + ":" + date.getMinutes())
}
}
function setAlarm(hours, minutes) {
var now = new Date();
var dateTarget = new Date();
dateTarget.setHours(hours)
dateTarget.setMinutes(minutes)
dateTarget.setSeconds(0)
dateTarget.setMilliseconds(0)
if (dateTarget < now) {
dateTarget.setDate(dateTarget.getDate()+1)
}
return dateTarget
}See this Documentation on MDN
answered Nov 22 '18 at 13:37
yunzenyunzen
20.5k84979
almost, if the time has already passed I have to set the day to next day. That's why I asked if I have to do it manually
– MHComputech
Nov 22 '18 at 13:42
add a comment |
2
You can manipulate the date and then check whether it is in the past. If it is, just add another day.
const d = new Date();
d.setHours(12);
d.setMinutes(0);
d.setSeconds(0);
d.setMilliseconds(0);
if (d < new Date()) {
d.setDate(d.getDate() + 1);
}
console.log(d);answered Nov 22 '18 at 13:54
strstr
17.4k65579
add a comment |
0
It's possible, but you need to provide the whole time string (which we can get from calling Date() and add the missing part):
const time = '12:45'
const current = new Date()
const dateTimeTwo = new Date(`${current.getFullYear()}-${current.getMonth()+1}-${current.getDate()} ${time}`)
answered Nov 22 '18 at 13:46
BitczeBitcze
92
thanks for your answer. I think @HerrSerker provided a cleaner solution. But as I mentioned I have to consider the next day if the time has already passed
– MHComputech
Nov 22 '18 at 13:48
Note that you are not using a valid datetime string which will fail in certain browsers (e.g. Safari).
– str
Nov 22 '18 at 13:58
That's right, sorry. @str's solution is the correct one.
– Bitcze
Nov 22 '18 at 14:02
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
var minutes = 42;
for (var hours = 1; hours < 24; hours+=3) {
var newAlarm = setAlarm(hours, minutes);
out(newAlarm)
}
function out(date) {
var now = new Date()
if (date.getDate() != now.getDate()) {
console.log('tomorrow: ' + date.getHours() + ":" + date.getMinutes())
} else {
console.log('today: ' + date.getHours() + ":" + date.getMinutes())
}
}
function setAlarm(hours, minutes) {
var now = new Date();
var dateTarget = new Date();
dateTarget.setHours(hours)
dateTarget.setMinutes(minutes)
dateTarget.setSeconds(0)
dateTarget.setMilliseconds(0)
if (dateTarget < now) {
dateTarget.setDate(dateTarget.getDate()+1)
}
return dateTarget
}See this Documentation on MDN
answered Nov 22 '18 at 13:37
yunzenyunzen
20.5k84979
almost, if the time has already passed I have to set the day to next day. That's why I asked if I have to do it manually
– MHComputech
Nov 22 '18 at 13:42
add a comment |
2
var minutes = 42;
for (var hours = 1; hours < 24; hours+=3) {
var newAlarm = setAlarm(hours, minutes);
out(newAlarm)
}
function out(date) {
var now = new Date()
if (date.getDate() != now.getDate()) {
console.log('tomorrow: ' + date.getHours() + ":" + date.getMinutes())
} else {
console.log('today: ' + date.getHours() + ":" + date.getMinutes())
}
}
function setAlarm(hours, minutes) {
var now = new Date();
var dateTarget = new Date();
dateTarget.setHours(hours)
dateTarget.setMinutes(minutes)
dateTarget.setSeconds(0)
dateTarget.setMilliseconds(0)
if (dateTarget < now) {
dateTarget.setDate(dateTarget.getDate()+1)
}
return dateTarget
}See this Documentation on MDN
answered Nov 22 '18 at 13:37
yunzenyunzen
20.5k84979
almost, if the time has already passed I have to set the day to next day. That's why I asked if I have to do it manually
– MHComputech
Nov 22 '18 at 13:42
add a comment |
2
2
2
var minutes = 42;
for (var hours = 1; hours < 24; hours+=3) {
var newAlarm = setAlarm(hours, minutes);
out(newAlarm)
}
function out(date) {
var now = new Date()
if (date.getDate() != now.getDate()) {
console.log('tomorrow: ' + date.getHours() + ":" + date.getMinutes())
} else {
console.log('today: ' + date.getHours() + ":" + date.getMinutes())
}
}
function setAlarm(hours, minutes) {
var now = new Date();
var dateTarget = new Date();
dateTarget.setHours(hours)
dateTarget.setMinutes(minutes)
dateTarget.setSeconds(0)
dateTarget.setMilliseconds(0)
if (dateTarget < now) {
dateTarget.setDate(dateTarget.getDate()+1)
}
return dateTarget
}See this Documentation on MDN
answered Nov 22 '18 at 13:37
yunzenyunzen
20.5k84979
var minutes = 42;
for (var hours = 1; hours < 24; hours+=3) {
var newAlarm = setAlarm(hours, minutes);
out(newAlarm)
}
function out(date) {
var now = new Date()
if (date.getDate() != now.getDate()) {
console.log('tomorrow: ' + date.getHours() + ":" + date.getMinutes())
} else {
console.log('today: ' + date.getHours() + ":" + date.getMinutes())
}
}
function setAlarm(hours, minutes) {
var now = new Date();
var dateTarget = new Date();
dateTarget.setHours(hours)
dateTarget.setMinutes(minutes)
dateTarget.setSeconds(0)
dateTarget.setMilliseconds(0)
if (dateTarget < now) {
dateTarget.setDate(dateTarget.getDate()+1)
}
return dateTarget
}See this Documentation on MDN
var minutes = 42;
for (var hours = 1; hours < 24; hours+=3) {
var newAlarm = setAlarm(hours, minutes);
out(newAlarm)
}
function out(date) {
var now = new Date()
if (date.getDate() != now.getDate()) {
console.log('tomorrow: ' + date.getHours() + ":" + date.getMinutes())
} else {
console.log('today: ' + date.getHours() + ":" + date.getMinutes())
}
}
function setAlarm(hours, minutes) {
var now = new Date();
var dateTarget = new Date();
dateTarget.setHours(hours)
dateTarget.setMinutes(minutes)
dateTarget.setSeconds(0)
dateTarget.setMilliseconds(0)
if (dateTarget < now) {
dateTarget.setDate(dateTarget.getDate()+1)
}
return dateTarget
}var minutes = 42;
for (var hours = 1; hours < 24; hours+=3) {
var newAlarm = setAlarm(hours, minutes);
out(newAlarm)
}
function out(date) {
var now = new Date()
if (date.getDate() != now.getDate()) {
console.log('tomorrow: ' + date.getHours() + ":" + date.getMinutes())
} else {
console.log('today: ' + date.getHours() + ":" + date.getMinutes())
}
}
function setAlarm(hours, minutes) {
var now = new Date();
var dateTarget = new Date();
dateTarget.setHours(hours)
dateTarget.setMinutes(minutes)
dateTarget.setSeconds(0)
dateTarget.setMilliseconds(0)
if (dateTarget < now) {
dateTarget.setDate(dateTarget.getDate()+1)
}
return dateTarget
}answered Nov 22 '18 at 13:37
yunzenyunzen
20.5k84979
edited Nov 22 '18 at 14:02
answered Nov 22 '18 at 13:37
yunzenyunzen
20.5k84979
answered Nov 22 '18 at 13:37
yunzenyunzen
20.5k84979
answered Nov 22 '18 at 13:37
yunzenyunzen
20.5k84979
20.5k84979
almost, if the time has already passed I have to set the day to next day. That's why I asked if I have to do it manually
– MHComputech
Nov 22 '18 at 13:42
add a comment |
almost, if the time has already passed I have to set the day to next day. That's why I asked if I have to do it manually
– MHComputech
Nov 22 '18 at 13:42
almost, if the time has already passed I have to set the day to next day. That's why I asked if I have to do it manually
– MHComputech
Nov 22 '18 at 13:42
almost, if the time has already passed I have to set the day to next day. That's why I asked if I have to do it manually
– MHComputech
Nov 22 '18 at 13:42
add a comment |
2
You can manipulate the date and then check whether it is in the past. If it is, just add another day.
const d = new Date();
d.setHours(12);
d.setMinutes(0);
d.setSeconds(0);
d.setMilliseconds(0);
if (d < new Date()) {
d.setDate(d.getDate() + 1);
}
console.log(d);answered Nov 22 '18 at 13:54
strstr
17.4k65579
add a comment |
2
You can manipulate the date and then check whether it is in the past. If it is, just add another day.
const d = new Date();
d.setHours(12);
d.setMinutes(0);
d.setSeconds(0);
d.setMilliseconds(0);
if (d < new Date()) {
d.setDate(d.getDate() + 1);
}
console.log(d);answered Nov 22 '18 at 13:54
strstr
17.4k65579
add a comment |
2
2
2
You can manipulate the date and then check whether it is in the past. If it is, just add another day.
const d = new Date();
d.setHours(12);
d.setMinutes(0);
d.setSeconds(0);
d.setMilliseconds(0);
if (d < new Date()) {
d.setDate(d.getDate() + 1);
}
console.log(d);answered Nov 22 '18 at 13:54
strstr
17.4k65579
You can manipulate the date and then check whether it is in the past. If it is, just add another day.
const d = new Date();
d.setHours(12);
d.setMinutes(0);
d.setSeconds(0);
d.setMilliseconds(0);
if (d < new Date()) {
d.setDate(d.getDate() + 1);
}
console.log(d);const d = new Date();
d.setHours(12);
d.setMinutes(0);
d.setSeconds(0);
d.setMilliseconds(0);
if (d < new Date()) {
d.setDate(d.getDate() + 1);
}
console.log(d);const d = new Date();
d.setHours(12);
d.setMinutes(0);
d.setSeconds(0);
d.setMilliseconds(0);
if (d < new Date()) {
d.setDate(d.getDate() + 1);
}
console.log(d);answered Nov 22 '18 at 13:54
strstr
17.4k65579
edited Nov 22 '18 at 14:00
answered Nov 22 '18 at 13:54
strstr
17.4k65579
answered Nov 22 '18 at 13:54
strstr
17.4k65579
answered Nov 22 '18 at 13:54
strstr
17.4k65579
17.4k65579
add a comment |
add a comment |
0
It's possible, but you need to provide the whole time string (which we can get from calling Date() and add the missing part):
const time = '12:45'
const current = new Date()
const dateTimeTwo = new Date(`${current.getFullYear()}-${current.getMonth()+1}-${current.getDate()} ${time}`)
answered Nov 22 '18 at 13:46
BitczeBitcze
92
thanks for your answer. I think @HerrSerker provided a cleaner solution. But as I mentioned I have to consider the next day if the time has already passed
– MHComputech
Nov 22 '18 at 13:48
Note that you are not using a valid datetime string which will fail in certain browsers (e.g. Safari).
– str
Nov 22 '18 at 13:58
That's right, sorry. @str's solution is the correct one.
– Bitcze
Nov 22 '18 at 14:02
add a comment |
0
It's possible, but you need to provide the whole time string (which we can get from calling Date() and add the missing part):
const time = '12:45'
const current = new Date()
const dateTimeTwo = new Date(`${current.getFullYear()}-${current.getMonth()+1}-${current.getDate()} ${time}`)
answered Nov 22 '18 at 13:46
BitczeBitcze
92
thanks for your answer. I think @HerrSerker provided a cleaner solution. But as I mentioned I have to consider the next day if the time has already passed
– MHComputech
Nov 22 '18 at 13:48
Note that you are not using a valid datetime string which will fail in certain browsers (e.g. Safari).
– str
Nov 22 '18 at 13:58
That's right, sorry. @str's solution is the correct one.
– Bitcze
Nov 22 '18 at 14:02
add a comment |
0
0
0
It's possible, but you need to provide the whole time string (which we can get from calling Date() and add the missing part):
const time = '12:45'
const current = new Date()
const dateTimeTwo = new Date(`${current.getFullYear()}-${current.getMonth()+1}-${current.getDate()} ${time}`)
answered Nov 22 '18 at 13:46
BitczeBitcze
92
It's possible, but you need to provide the whole time string (which we can get from calling Date() and add the missing part):
const time = '12:45'
const current = new Date()
const dateTimeTwo = new Date(`${current.getFullYear()}-${current.getMonth()+1}-${current.getDate()} ${time}`)
answered Nov 22 '18 at 13:46
BitczeBitcze
92
answered Nov 22 '18 at 13:46
BitczeBitcze
92
answered Nov 22 '18 at 13:46
BitczeBitcze
92
answered Nov 22 '18 at 13:46
BitczeBitcze
92
92
thanks for your answer. I think @HerrSerker provided a cleaner solution. But as I mentioned I have to consider the next day if the time has already passed
– MHComputech
Nov 22 '18 at 13:48
Note that you are not using a valid datetime string which will fail in certain browsers (e.g. Safari).
– str
Nov 22 '18 at 13:58
That's right, sorry. @str's solution is the correct one.
– Bitcze
Nov 22 '18 at 14:02
add a comment |
thanks for your answer. I think @HerrSerker provided a cleaner solution. But as I mentioned I have to consider the next day if the time has already passed
– MHComputech
Nov 22 '18 at 13:48
Note that you are not using a valid datetime string which will fail in certain browsers (e.g. Safari).
– str
Nov 22 '18 at 13:58
That's right, sorry. @str's solution is the correct one.
– Bitcze
Nov 22 '18 at 14:02
thanks for your answer. I think @HerrSerker provided a cleaner solution. But as I mentioned I have to consider the next day if the time has already passed
– MHComputech
Nov 22 '18 at 13:48
thanks for your answer. I think @HerrSerker provided a cleaner solution. But as I mentioned I have to consider the next day if the time has already passed
– MHComputech
Nov 22 '18 at 13:48
Note that you are not using a valid datetime string which will fail in certain browsers (e.g. Safari).
– str
Nov 22 '18 at 13:58
Note that you are not using a valid datetime string which will fail in certain browsers (e.g. Safari).
– str
Nov 22 '18 at 13:58
That's right, sorry. @str's solution is the correct one.
– Bitcze
Nov 22 '18 at 14:02
That's right, sorry. @str's solution is the correct one.
– Bitcze
Nov 22 '18 at 14:02
add a comment |
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