How to find points M and N such that AM=CN=BC only with a straight edge and a compass?












4














The following code is my attempt to find M and N such that AM=CN=BC.



documentclass[pstricks,border=12pt]{standalone}
usepackage{pst-eucl,pst-calculate}
begin{document}
defx{pscalculate{6-3.3541}}
begin{pspicture}[showgrid](-1,-1)(8,8)
pstGeonode[PosAngle={180,90,0,-90}](1,2){B}(2.5,5){C}(6,2){A}(x,2){M}
pspolygon(B)(C)(A)
pstRotation[PosAngle=90,RotAngle=75.9638]{C}{B}[N]

psGetDistanceAB[xShift=-8,yShift=4](B)(C){M}
psGetAngleABC[AngleValue=true,MarkAngleRadius=.5,LabelSep=0.5,%
ShowWedge=false,xShift=-5,yShift=7,arrows=->](B)(C)(A){}

end{pspicture}
end{document}


enter image description here



However, I am trying not to use psGetDistanceAB and psGetAngleABC.



Question



How to get M and N such that AM=CN=BC only with a compass and a straight edge?










share|improve this question





























    4














    The following code is my attempt to find M and N such that AM=CN=BC.



    documentclass[pstricks,border=12pt]{standalone}
    usepackage{pst-eucl,pst-calculate}
    begin{document}
    defx{pscalculate{6-3.3541}}
    begin{pspicture}[showgrid](-1,-1)(8,8)
    pstGeonode[PosAngle={180,90,0,-90}](1,2){B}(2.5,5){C}(6,2){A}(x,2){M}
    pspolygon(B)(C)(A)
    pstRotation[PosAngle=90,RotAngle=75.9638]{C}{B}[N]

    psGetDistanceAB[xShift=-8,yShift=4](B)(C){M}
    psGetAngleABC[AngleValue=true,MarkAngleRadius=.5,LabelSep=0.5,%
    ShowWedge=false,xShift=-5,yShift=7,arrows=->](B)(C)(A){}

    end{pspicture}
    end{document}


    enter image description here



    However, I am trying not to use psGetDistanceAB and psGetAngleABC.



    Question



    How to get M and N such that AM=CN=BC only with a compass and a straight edge?










    share|improve this question



























      4












      4








      4







      The following code is my attempt to find M and N such that AM=CN=BC.



      documentclass[pstricks,border=12pt]{standalone}
      usepackage{pst-eucl,pst-calculate}
      begin{document}
      defx{pscalculate{6-3.3541}}
      begin{pspicture}[showgrid](-1,-1)(8,8)
      pstGeonode[PosAngle={180,90,0,-90}](1,2){B}(2.5,5){C}(6,2){A}(x,2){M}
      pspolygon(B)(C)(A)
      pstRotation[PosAngle=90,RotAngle=75.9638]{C}{B}[N]

      psGetDistanceAB[xShift=-8,yShift=4](B)(C){M}
      psGetAngleABC[AngleValue=true,MarkAngleRadius=.5,LabelSep=0.5,%
      ShowWedge=false,xShift=-5,yShift=7,arrows=->](B)(C)(A){}

      end{pspicture}
      end{document}


      enter image description here



      However, I am trying not to use psGetDistanceAB and psGetAngleABC.



      Question



      How to get M and N such that AM=CN=BC only with a compass and a straight edge?










      share|improve this question















      The following code is my attempt to find M and N such that AM=CN=BC.



      documentclass[pstricks,border=12pt]{standalone}
      usepackage{pst-eucl,pst-calculate}
      begin{document}
      defx{pscalculate{6-3.3541}}
      begin{pspicture}[showgrid](-1,-1)(8,8)
      pstGeonode[PosAngle={180,90,0,-90}](1,2){B}(2.5,5){C}(6,2){A}(x,2){M}
      pspolygon(B)(C)(A)
      pstRotation[PosAngle=90,RotAngle=75.9638]{C}{B}[N]

      psGetDistanceAB[xShift=-8,yShift=4](B)(C){M}
      psGetAngleABC[AngleValue=true,MarkAngleRadius=.5,LabelSep=0.5,%
      ShowWedge=false,xShift=-5,yShift=7,arrows=->](B)(C)(A){}

      end{pspicture}
      end{document}


      enter image description here



      However, I am trying not to use psGetDistanceAB and psGetAngleABC.



      Question



      How to get M and N such that AM=CN=BC only with a compass and a straight edge?







      pstricks pst-eucl






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 13 mins ago









      God Must Be Crazy

      5,58511039




      5,58511039










      asked 3 hours ago









      chishimotoji

      783216




      783216






















          3 Answers
          3






          active

          oldest

          votes


















          3














          documentclass[pstricks,border=12pt]{standalone}
          usepackage{pst-eucl,pst-calculate,textcomp}
          begin{document}
          begin{pspicture}[showgrid](-1,-1)(8,8)
          pstTriangle[PosAngle={180,90,0}](1,2){B}(2.5,5){C}(6,2){A}
          pstInterLC[PointSymbolB=none,PointName=none]{A}{C}{C}{B}{N}{N0}uput[0](N){N}
          pstInterLC[PointSymbolB=none,PointName=none,
          Radius=pstDistCalc{sqrt((2.5-1)^2+(5-2)^2)}]{B}{A}{A}{}{M}{M0}uput[-90](M){M}
          psarc[origin={C}]{->}(C){0.5}{(B)}{(N)}uput{5mm}[-10](C){75.9636textdegree}
          end{pspicture}
          end{document}


          enter image description here






          share|improve this answer



















          • 1




            Radius=pstDistCalc{sqrt((2.5-1)^2+(5-2)^2)} is also possible.
            – Herbert
            10 mins ago










          • Trivial comments: M and N have not been converted to math mode.
            – God Must Be Crazy
            2 mins ago



















          2














          The shorter the code the more beautiful it becomes.



          documentclass[pstricks,12pt]{standalone}
          usepackage{pst-eucl}

          begin{document}
          begin{pspicture}(0,1)(7,6)
          pstTriangle[PosAngle={180,90,0}](1,2){B}(2.5,5){C}(6,2){A}
          pstInterLC[PointSymbolB=none,PointNameB=,PosAngle=45]{A}{C}{C}{B}{N}{x}
          pstTranslation[PointName=none,PointSymbol=none]{B}{A}{C}[C']
          pstInterLC[PointNameA=,PointSymbolA=none,PosAngleB=-90]{A}{B}{A}{C'}{y}{M}
          pstMarkAngle[arrows=->,MarkAngleRadius=1.1,LabelSep=.8]{B}{C}{A}{scriptsize$75.96^circ$}
          end{pspicture}
          end{document}


          enter image description here



          Notes



          PointNameA and PointNameB cannot be assigned none but empty. It looks like a bug.






          share|improve this answer































            1














            An alternative tikz version:



            documentclass[tikz,border=12pt]{standalone}
            usetikzlibrary{calc,bending,arrows.meta,quotes,angles}
            usepackage{textcomp}
            begin{document}

            begin{tikzpicture}[dot/.style={fill,circle,inner sep=1.2pt},>= Stealth]footnotesize
            pgfmathsetmacroBC{sqrt(1.5*1.5+3*3)}
            pgfmathsetmacroAC{sqrt(3.5*3.5+3*3)}
            draw (1,2)coordinate[dot,label=left:$B$](b)--(2.5,5)coordinate[dot,label=above:$C$](c)--(6,2)coordinate[dot,label=right:$A$](a)--cycle;
            node at ([xshift=-BC cm]a) [dot,label=below:$M$] {};
            node at ($(c)!BC/AC!(a)$) [dot,label=right:$N$] {};
            pic["75.96textdegree",draw,->,angle eccentricity=.7,angle radius=1cm] {angle=b--c--a};
            end{tikzpicture}

            end{document}



            enter image description here







            share|improve this answer























            • Thank you for your answer with TikZ.
              – chishimotoji
              33 mins ago













            Your Answer








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            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            3














            documentclass[pstricks,border=12pt]{standalone}
            usepackage{pst-eucl,pst-calculate,textcomp}
            begin{document}
            begin{pspicture}[showgrid](-1,-1)(8,8)
            pstTriangle[PosAngle={180,90,0}](1,2){B}(2.5,5){C}(6,2){A}
            pstInterLC[PointSymbolB=none,PointName=none]{A}{C}{C}{B}{N}{N0}uput[0](N){N}
            pstInterLC[PointSymbolB=none,PointName=none,
            Radius=pstDistCalc{sqrt((2.5-1)^2+(5-2)^2)}]{B}{A}{A}{}{M}{M0}uput[-90](M){M}
            psarc[origin={C}]{->}(C){0.5}{(B)}{(N)}uput{5mm}[-10](C){75.9636textdegree}
            end{pspicture}
            end{document}


            enter image description here






            share|improve this answer



















            • 1




              Radius=pstDistCalc{sqrt((2.5-1)^2+(5-2)^2)} is also possible.
              – Herbert
              10 mins ago










            • Trivial comments: M and N have not been converted to math mode.
              – God Must Be Crazy
              2 mins ago
















            3














            documentclass[pstricks,border=12pt]{standalone}
            usepackage{pst-eucl,pst-calculate,textcomp}
            begin{document}
            begin{pspicture}[showgrid](-1,-1)(8,8)
            pstTriangle[PosAngle={180,90,0}](1,2){B}(2.5,5){C}(6,2){A}
            pstInterLC[PointSymbolB=none,PointName=none]{A}{C}{C}{B}{N}{N0}uput[0](N){N}
            pstInterLC[PointSymbolB=none,PointName=none,
            Radius=pstDistCalc{sqrt((2.5-1)^2+(5-2)^2)}]{B}{A}{A}{}{M}{M0}uput[-90](M){M}
            psarc[origin={C}]{->}(C){0.5}{(B)}{(N)}uput{5mm}[-10](C){75.9636textdegree}
            end{pspicture}
            end{document}


            enter image description here






            share|improve this answer



















            • 1




              Radius=pstDistCalc{sqrt((2.5-1)^2+(5-2)^2)} is also possible.
              – Herbert
              10 mins ago










            • Trivial comments: M and N have not been converted to math mode.
              – God Must Be Crazy
              2 mins ago














            3












            3








            3






            documentclass[pstricks,border=12pt]{standalone}
            usepackage{pst-eucl,pst-calculate,textcomp}
            begin{document}
            begin{pspicture}[showgrid](-1,-1)(8,8)
            pstTriangle[PosAngle={180,90,0}](1,2){B}(2.5,5){C}(6,2){A}
            pstInterLC[PointSymbolB=none,PointName=none]{A}{C}{C}{B}{N}{N0}uput[0](N){N}
            pstInterLC[PointSymbolB=none,PointName=none,
            Radius=pstDistCalc{sqrt((2.5-1)^2+(5-2)^2)}]{B}{A}{A}{}{M}{M0}uput[-90](M){M}
            psarc[origin={C}]{->}(C){0.5}{(B)}{(N)}uput{5mm}[-10](C){75.9636textdegree}
            end{pspicture}
            end{document}


            enter image description here






            share|improve this answer














            documentclass[pstricks,border=12pt]{standalone}
            usepackage{pst-eucl,pst-calculate,textcomp}
            begin{document}
            begin{pspicture}[showgrid](-1,-1)(8,8)
            pstTriangle[PosAngle={180,90,0}](1,2){B}(2.5,5){C}(6,2){A}
            pstInterLC[PointSymbolB=none,PointName=none]{A}{C}{C}{B}{N}{N0}uput[0](N){N}
            pstInterLC[PointSymbolB=none,PointName=none,
            Radius=pstDistCalc{sqrt((2.5-1)^2+(5-2)^2)}]{B}{A}{A}{}{M}{M0}uput[-90](M){M}
            psarc[origin={C}]{->}(C){0.5}{(B)}{(N)}uput{5mm}[-10](C){75.9636textdegree}
            end{pspicture}
            end{document}


            enter image description here







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 8 mins ago

























            answered 1 hour ago









            Herbert

            269k24408717




            269k24408717








            • 1




              Radius=pstDistCalc{sqrt((2.5-1)^2+(5-2)^2)} is also possible.
              – Herbert
              10 mins ago










            • Trivial comments: M and N have not been converted to math mode.
              – God Must Be Crazy
              2 mins ago














            • 1




              Radius=pstDistCalc{sqrt((2.5-1)^2+(5-2)^2)} is also possible.
              – Herbert
              10 mins ago










            • Trivial comments: M and N have not been converted to math mode.
              – God Must Be Crazy
              2 mins ago








            1




            1




            Radius=pstDistCalc{sqrt((2.5-1)^2+(5-2)^2)} is also possible.
            – Herbert
            10 mins ago




            Radius=pstDistCalc{sqrt((2.5-1)^2+(5-2)^2)} is also possible.
            – Herbert
            10 mins ago












            Trivial comments: M and N have not been converted to math mode.
            – God Must Be Crazy
            2 mins ago




            Trivial comments: M and N have not been converted to math mode.
            – God Must Be Crazy
            2 mins ago











            2














            The shorter the code the more beautiful it becomes.



            documentclass[pstricks,12pt]{standalone}
            usepackage{pst-eucl}

            begin{document}
            begin{pspicture}(0,1)(7,6)
            pstTriangle[PosAngle={180,90,0}](1,2){B}(2.5,5){C}(6,2){A}
            pstInterLC[PointSymbolB=none,PointNameB=,PosAngle=45]{A}{C}{C}{B}{N}{x}
            pstTranslation[PointName=none,PointSymbol=none]{B}{A}{C}[C']
            pstInterLC[PointNameA=,PointSymbolA=none,PosAngleB=-90]{A}{B}{A}{C'}{y}{M}
            pstMarkAngle[arrows=->,MarkAngleRadius=1.1,LabelSep=.8]{B}{C}{A}{scriptsize$75.96^circ$}
            end{pspicture}
            end{document}


            enter image description here



            Notes



            PointNameA and PointNameB cannot be assigned none but empty. It looks like a bug.






            share|improve this answer




























              2














              The shorter the code the more beautiful it becomes.



              documentclass[pstricks,12pt]{standalone}
              usepackage{pst-eucl}

              begin{document}
              begin{pspicture}(0,1)(7,6)
              pstTriangle[PosAngle={180,90,0}](1,2){B}(2.5,5){C}(6,2){A}
              pstInterLC[PointSymbolB=none,PointNameB=,PosAngle=45]{A}{C}{C}{B}{N}{x}
              pstTranslation[PointName=none,PointSymbol=none]{B}{A}{C}[C']
              pstInterLC[PointNameA=,PointSymbolA=none,PosAngleB=-90]{A}{B}{A}{C'}{y}{M}
              pstMarkAngle[arrows=->,MarkAngleRadius=1.1,LabelSep=.8]{B}{C}{A}{scriptsize$75.96^circ$}
              end{pspicture}
              end{document}


              enter image description here



              Notes



              PointNameA and PointNameB cannot be assigned none but empty. It looks like a bug.






              share|improve this answer


























                2












                2








                2






                The shorter the code the more beautiful it becomes.



                documentclass[pstricks,12pt]{standalone}
                usepackage{pst-eucl}

                begin{document}
                begin{pspicture}(0,1)(7,6)
                pstTriangle[PosAngle={180,90,0}](1,2){B}(2.5,5){C}(6,2){A}
                pstInterLC[PointSymbolB=none,PointNameB=,PosAngle=45]{A}{C}{C}{B}{N}{x}
                pstTranslation[PointName=none,PointSymbol=none]{B}{A}{C}[C']
                pstInterLC[PointNameA=,PointSymbolA=none,PosAngleB=-90]{A}{B}{A}{C'}{y}{M}
                pstMarkAngle[arrows=->,MarkAngleRadius=1.1,LabelSep=.8]{B}{C}{A}{scriptsize$75.96^circ$}
                end{pspicture}
                end{document}


                enter image description here



                Notes



                PointNameA and PointNameB cannot be assigned none but empty. It looks like a bug.






                share|improve this answer














                The shorter the code the more beautiful it becomes.



                documentclass[pstricks,12pt]{standalone}
                usepackage{pst-eucl}

                begin{document}
                begin{pspicture}(0,1)(7,6)
                pstTriangle[PosAngle={180,90,0}](1,2){B}(2.5,5){C}(6,2){A}
                pstInterLC[PointSymbolB=none,PointNameB=,PosAngle=45]{A}{C}{C}{B}{N}{x}
                pstTranslation[PointName=none,PointSymbol=none]{B}{A}{C}[C']
                pstInterLC[PointNameA=,PointSymbolA=none,PosAngleB=-90]{A}{B}{A}{C'}{y}{M}
                pstMarkAngle[arrows=->,MarkAngleRadius=1.1,LabelSep=.8]{B}{C}{A}{scriptsize$75.96^circ$}
                end{pspicture}
                end{document}


                enter image description here



                Notes



                PointNameA and PointNameB cannot be assigned none but empty. It looks like a bug.







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 49 mins ago

























                answered 1 hour ago









                God Must Be Crazy

                5,58511039




                5,58511039























                    1














                    An alternative tikz version:



                    documentclass[tikz,border=12pt]{standalone}
                    usetikzlibrary{calc,bending,arrows.meta,quotes,angles}
                    usepackage{textcomp}
                    begin{document}

                    begin{tikzpicture}[dot/.style={fill,circle,inner sep=1.2pt},>= Stealth]footnotesize
                    pgfmathsetmacroBC{sqrt(1.5*1.5+3*3)}
                    pgfmathsetmacroAC{sqrt(3.5*3.5+3*3)}
                    draw (1,2)coordinate[dot,label=left:$B$](b)--(2.5,5)coordinate[dot,label=above:$C$](c)--(6,2)coordinate[dot,label=right:$A$](a)--cycle;
                    node at ([xshift=-BC cm]a) [dot,label=below:$M$] {};
                    node at ($(c)!BC/AC!(a)$) [dot,label=right:$N$] {};
                    pic["75.96textdegree",draw,->,angle eccentricity=.7,angle radius=1cm] {angle=b--c--a};
                    end{tikzpicture}

                    end{document}



                    enter image description here







                    share|improve this answer























                    • Thank you for your answer with TikZ.
                      – chishimotoji
                      33 mins ago


















                    1














                    An alternative tikz version:



                    documentclass[tikz,border=12pt]{standalone}
                    usetikzlibrary{calc,bending,arrows.meta,quotes,angles}
                    usepackage{textcomp}
                    begin{document}

                    begin{tikzpicture}[dot/.style={fill,circle,inner sep=1.2pt},>= Stealth]footnotesize
                    pgfmathsetmacroBC{sqrt(1.5*1.5+3*3)}
                    pgfmathsetmacroAC{sqrt(3.5*3.5+3*3)}
                    draw (1,2)coordinate[dot,label=left:$B$](b)--(2.5,5)coordinate[dot,label=above:$C$](c)--(6,2)coordinate[dot,label=right:$A$](a)--cycle;
                    node at ([xshift=-BC cm]a) [dot,label=below:$M$] {};
                    node at ($(c)!BC/AC!(a)$) [dot,label=right:$N$] {};
                    pic["75.96textdegree",draw,->,angle eccentricity=.7,angle radius=1cm] {angle=b--c--a};
                    end{tikzpicture}

                    end{document}



                    enter image description here







                    share|improve this answer























                    • Thank you for your answer with TikZ.
                      – chishimotoji
                      33 mins ago
















                    1












                    1








                    1






                    An alternative tikz version:



                    documentclass[tikz,border=12pt]{standalone}
                    usetikzlibrary{calc,bending,arrows.meta,quotes,angles}
                    usepackage{textcomp}
                    begin{document}

                    begin{tikzpicture}[dot/.style={fill,circle,inner sep=1.2pt},>= Stealth]footnotesize
                    pgfmathsetmacroBC{sqrt(1.5*1.5+3*3)}
                    pgfmathsetmacroAC{sqrt(3.5*3.5+3*3)}
                    draw (1,2)coordinate[dot,label=left:$B$](b)--(2.5,5)coordinate[dot,label=above:$C$](c)--(6,2)coordinate[dot,label=right:$A$](a)--cycle;
                    node at ([xshift=-BC cm]a) [dot,label=below:$M$] {};
                    node at ($(c)!BC/AC!(a)$) [dot,label=right:$N$] {};
                    pic["75.96textdegree",draw,->,angle eccentricity=.7,angle radius=1cm] {angle=b--c--a};
                    end{tikzpicture}

                    end{document}



                    enter image description here







                    share|improve this answer














                    An alternative tikz version:



                    documentclass[tikz,border=12pt]{standalone}
                    usetikzlibrary{calc,bending,arrows.meta,quotes,angles}
                    usepackage{textcomp}
                    begin{document}

                    begin{tikzpicture}[dot/.style={fill,circle,inner sep=1.2pt},>= Stealth]footnotesize
                    pgfmathsetmacroBC{sqrt(1.5*1.5+3*3)}
                    pgfmathsetmacroAC{sqrt(3.5*3.5+3*3)}
                    draw (1,2)coordinate[dot,label=left:$B$](b)--(2.5,5)coordinate[dot,label=above:$C$](c)--(6,2)coordinate[dot,label=right:$A$](a)--cycle;
                    node at ([xshift=-BC cm]a) [dot,label=below:$M$] {};
                    node at ($(c)!BC/AC!(a)$) [dot,label=right:$N$] {};
                    pic["75.96textdegree",draw,->,angle eccentricity=.7,angle radius=1cm] {angle=b--c--a};
                    end{tikzpicture}

                    end{document}



                    enter image description here








                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited 32 mins ago

























                    answered 35 mins ago









                    AboAmmar

                    32.9k22882




                    32.9k22882












                    • Thank you for your answer with TikZ.
                      – chishimotoji
                      33 mins ago




















                    • Thank you for your answer with TikZ.
                      – chishimotoji
                      33 mins ago


















                    Thank you for your answer with TikZ.
                    – chishimotoji
                    33 mins ago






                    Thank you for your answer with TikZ.
                    – chishimotoji
                    33 mins ago




















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