Select-Object append after variable
I have weird behavior.
This line works just fine (output => te001):
Get-Content $SourceTxtDbFile | ConvertFrom-String -Delimiter "_" -PropertyNames DbVersion, ScriptNumber | Where-Object {$_.DbVersion -eq "1.2.0.0"} | Select-Object {"te"+$_.ScriptNumber }
but I need to be after the $_ variable so this doesn't work (blank output):
Get-Content $SourceTxtDbFile | ConvertFrom-String -Delimiter "_" -PropertyNames DbVersion, ScriptNumber | Where-Object {$_.DbVersion -eq "1.2.0.0"} | Select-Object {$_.ScriptNumber + "te"}
Why?
powershell
|
show 3 more comments
I have weird behavior.
This line works just fine (output => te001):
Get-Content $SourceTxtDbFile | ConvertFrom-String -Delimiter "_" -PropertyNames DbVersion, ScriptNumber | Where-Object {$_.DbVersion -eq "1.2.0.0"} | Select-Object {"te"+$_.ScriptNumber }
but I need to be after the $_ variable so this doesn't work (blank output):
Get-Content $SourceTxtDbFile | ConvertFrom-String -Delimiter "_" -PropertyNames DbVersion, ScriptNumber | Where-Object {$_.DbVersion -eq "1.2.0.0"} | Select-Object {$_.ScriptNumber + "te"}
Why?
powershell
Is there an object named001te
(taking your example) present?
– TobyU
Nov 22 '18 at 13:25
No there is not...
– Stefan0309
Nov 22 '18 at 13:29
Then how should that possible work? What do you want to achieve at the end?
– TobyU
Nov 22 '18 at 13:29
Well, I have Get-Content that reads the file. I am doing here a split by '_' and I am asking Where-Object {$_DbVersion -eq "1.2.0.0"} select those objects..those lines..It perfectly works without appended string at the end..
– Stefan0309
Nov 22 '18 at 13:33
I just think that it isnt right concatenation at the end as it at the begging..maybe I need to put some escape char or something..
– Stefan0309
Nov 22 '18 at 13:35
|
show 3 more comments
I have weird behavior.
This line works just fine (output => te001):
Get-Content $SourceTxtDbFile | ConvertFrom-String -Delimiter "_" -PropertyNames DbVersion, ScriptNumber | Where-Object {$_.DbVersion -eq "1.2.0.0"} | Select-Object {"te"+$_.ScriptNumber }
but I need to be after the $_ variable so this doesn't work (blank output):
Get-Content $SourceTxtDbFile | ConvertFrom-String -Delimiter "_" -PropertyNames DbVersion, ScriptNumber | Where-Object {$_.DbVersion -eq "1.2.0.0"} | Select-Object {$_.ScriptNumber + "te"}
Why?
powershell
I have weird behavior.
This line works just fine (output => te001):
Get-Content $SourceTxtDbFile | ConvertFrom-String -Delimiter "_" -PropertyNames DbVersion, ScriptNumber | Where-Object {$_.DbVersion -eq "1.2.0.0"} | Select-Object {"te"+$_.ScriptNumber }
but I need to be after the $_ variable so this doesn't work (blank output):
Get-Content $SourceTxtDbFile | ConvertFrom-String -Delimiter "_" -PropertyNames DbVersion, ScriptNumber | Where-Object {$_.DbVersion -eq "1.2.0.0"} | Select-Object {$_.ScriptNumber + "te"}
Why?
powershell
powershell
asked Nov 22 '18 at 13:22
Stefan0309Stefan0309
363425
363425
Is there an object named001te
(taking your example) present?
– TobyU
Nov 22 '18 at 13:25
No there is not...
– Stefan0309
Nov 22 '18 at 13:29
Then how should that possible work? What do you want to achieve at the end?
– TobyU
Nov 22 '18 at 13:29
Well, I have Get-Content that reads the file. I am doing here a split by '_' and I am asking Where-Object {$_DbVersion -eq "1.2.0.0"} select those objects..those lines..It perfectly works without appended string at the end..
– Stefan0309
Nov 22 '18 at 13:33
I just think that it isnt right concatenation at the end as it at the begging..maybe I need to put some escape char or something..
– Stefan0309
Nov 22 '18 at 13:35
|
show 3 more comments
Is there an object named001te
(taking your example) present?
– TobyU
Nov 22 '18 at 13:25
No there is not...
– Stefan0309
Nov 22 '18 at 13:29
Then how should that possible work? What do you want to achieve at the end?
– TobyU
Nov 22 '18 at 13:29
Well, I have Get-Content that reads the file. I am doing here a split by '_' and I am asking Where-Object {$_DbVersion -eq "1.2.0.0"} select those objects..those lines..It perfectly works without appended string at the end..
– Stefan0309
Nov 22 '18 at 13:33
I just think that it isnt right concatenation at the end as it at the begging..maybe I need to put some escape char or something..
– Stefan0309
Nov 22 '18 at 13:35
Is there an object named
001te
(taking your example) present?– TobyU
Nov 22 '18 at 13:25
Is there an object named
001te
(taking your example) present?– TobyU
Nov 22 '18 at 13:25
No there is not...
– Stefan0309
Nov 22 '18 at 13:29
No there is not...
– Stefan0309
Nov 22 '18 at 13:29
Then how should that possible work? What do you want to achieve at the end?
– TobyU
Nov 22 '18 at 13:29
Then how should that possible work? What do you want to achieve at the end?
– TobyU
Nov 22 '18 at 13:29
Well, I have Get-Content that reads the file. I am doing here a split by '_' and I am asking Where-Object {$_DbVersion -eq "1.2.0.0"} select those objects..those lines..It perfectly works without appended string at the end..
– Stefan0309
Nov 22 '18 at 13:33
Well, I have Get-Content that reads the file. I am doing here a split by '_' and I am asking Where-Object {$_DbVersion -eq "1.2.0.0"} select those objects..those lines..It perfectly works without appended string at the end..
– Stefan0309
Nov 22 '18 at 13:33
I just think that it isnt right concatenation at the end as it at the begging..maybe I need to put some escape char or something..
– Stefan0309
Nov 22 '18 at 13:35
I just think that it isnt right concatenation at the end as it at the begging..maybe I need to put some escape char or something..
– Stefan0309
Nov 22 '18 at 13:35
|
show 3 more comments
1 Answer
1
active
oldest
votes
Change
$_.ScriptNumber + "te"
to
"$($_.ScriptNumber)te"
so that $_.ScriptNumber
is used as a string
instead of an integer
@TobyU I rushed to give you a vote up, but I ahve Invalid parameters in my output. Just saying Invalid parameters CHANGE {LOGON | PORT | USER} I dont know what is that..
– Stefan0309
Nov 22 '18 at 14:18
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Change
$_.ScriptNumber + "te"
to
"$($_.ScriptNumber)te"
so that $_.ScriptNumber
is used as a string
instead of an integer
@TobyU I rushed to give you a vote up, but I ahve Invalid parameters in my output. Just saying Invalid parameters CHANGE {LOGON | PORT | USER} I dont know what is that..
– Stefan0309
Nov 22 '18 at 14:18
add a comment |
Change
$_.ScriptNumber + "te"
to
"$($_.ScriptNumber)te"
so that $_.ScriptNumber
is used as a string
instead of an integer
@TobyU I rushed to give you a vote up, but I ahve Invalid parameters in my output. Just saying Invalid parameters CHANGE {LOGON | PORT | USER} I dont know what is that..
– Stefan0309
Nov 22 '18 at 14:18
add a comment |
Change
$_.ScriptNumber + "te"
to
"$($_.ScriptNumber)te"
so that $_.ScriptNumber
is used as a string
instead of an integer
Change
$_.ScriptNumber + "te"
to
"$($_.ScriptNumber)te"
so that $_.ScriptNumber
is used as a string
instead of an integer
edited Nov 22 '18 at 14:17
answered Nov 22 '18 at 13:42
TobyUTobyU
2,3031921
2,3031921
@TobyU I rushed to give you a vote up, but I ahve Invalid parameters in my output. Just saying Invalid parameters CHANGE {LOGON | PORT | USER} I dont know what is that..
– Stefan0309
Nov 22 '18 at 14:18
add a comment |
@TobyU I rushed to give you a vote up, but I ahve Invalid parameters in my output. Just saying Invalid parameters CHANGE {LOGON | PORT | USER} I dont know what is that..
– Stefan0309
Nov 22 '18 at 14:18
@TobyU I rushed to give you a vote up, but I ahve Invalid parameters in my output. Just saying Invalid parameters CHANGE {LOGON | PORT | USER} I dont know what is that..
– Stefan0309
Nov 22 '18 at 14:18
@TobyU I rushed to give you a vote up, but I ahve Invalid parameters in my output. Just saying Invalid parameters CHANGE {LOGON | PORT | USER} I dont know what is that..
– Stefan0309
Nov 22 '18 at 14:18
add a comment |
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Is there an object named
001te
(taking your example) present?– TobyU
Nov 22 '18 at 13:25
No there is not...
– Stefan0309
Nov 22 '18 at 13:29
Then how should that possible work? What do you want to achieve at the end?
– TobyU
Nov 22 '18 at 13:29
Well, I have Get-Content that reads the file. I am doing here a split by '_' and I am asking Where-Object {$_DbVersion -eq "1.2.0.0"} select those objects..those lines..It perfectly works without appended string at the end..
– Stefan0309
Nov 22 '18 at 13:33
I just think that it isnt right concatenation at the end as it at the begging..maybe I need to put some escape char or something..
– Stefan0309
Nov 22 '18 at 13:35