Vector push_back & pop_back
0
I'm working on an assignment. I have coded the assignment and everything is working as it should, except my output is missing a digit. I also attached the sample output. After inputting a a mathematical expression into a string, for example 35 * 4 - 6 / (9 + 3), a digit is dropped. In normal order, the 3 will be missing. In reverse order, the 9 will be missing. I am not understanding why this happening.
Any help, or I would prefer some guidance, would be appreciated. Am I using the push_back incorrectly? The code is as follows:
#include<iostream>
#include<string>
#include<vector>
using namespace std;
vector<string> split(string);
vector<string> splitback(string);
int main()
{
vector<string> vectorExpression;
string expression;
cout << "Enter an expression :";
getline(cin, expression);
vectorExpression = split(expression);
for (int i = 0; i < vectorExpression.size(); i++)
{
cout << vectorExpression[i] << endl;
}
cout << endl;
vectorExpression = splitback(expression);
for (int i = 0; i < vectorExpression.size(); i++)
{
cout << vectorExpression[i] << endl;
}
system("pause");
return 0;
}
vector<string> split(string expression)
{
vector<string> splitExpression;
string digit = "",
x = "";
for (int i = 0; i < expression.size(); i++)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = digit + expression[i];
}
else if (expression[i] != ' ')
{
x = "";
x = x + expression[i];
splitExpression.push_back(x);
}
else
{
if (digit.size() > 0)
{
splitExpression.push_back(digit);
digit = "";
}
}
}
if (digit.size() > 0)
{
splitExpression.push_back(digit);
}
return splitExpression;
}
vector<string> splitback(string expression)
{
vector<string> splitBackExpression;
string number = "",
x = "";
for (int i = expression.size() - 1; i >= 0; i--)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
number = expression[i] + number;
}
else if (expression[i] != ' ')
{
x = "";
x = x + expression[i];
splitBackExpression.push_back(x);
}
if (number.size() > 0)
{
splitBackExpression.push_back(number);
number = "";
}
}
return splitBackExpression;
}
c++ vector
edited Dec 1 '18 at 10:31
Cœur
18.4k9109148
asked Nov 23 '18 at 23:38
NalaedgeNalaedge
34
add a comment |
0
I'm working on an assignment. I have coded the assignment and everything is working as it should, except my output is missing a digit. I also attached the sample output. After inputting a a mathematical expression into a string, for example 35 * 4 - 6 / (9 + 3), a digit is dropped. In normal order, the 3 will be missing. In reverse order, the 9 will be missing. I am not understanding why this happening.
Any help, or I would prefer some guidance, would be appreciated. Am I using the push_back incorrectly? The code is as follows:
#include<iostream>
#include<string>
#include<vector>
using namespace std;
vector<string> split(string);
vector<string> splitback(string);
int main()
{
vector<string> vectorExpression;
string expression;
cout << "Enter an expression :";
getline(cin, expression);
vectorExpression = split(expression);
for (int i = 0; i < vectorExpression.size(); i++)
{
cout << vectorExpression[i] << endl;
}
cout << endl;
vectorExpression = splitback(expression);
for (int i = 0; i < vectorExpression.size(); i++)
{
cout << vectorExpression[i] << endl;
}
system("pause");
return 0;
}
vector<string> split(string expression)
{
vector<string> splitExpression;
string digit = "",
x = "";
for (int i = 0; i < expression.size(); i++)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = digit + expression[i];
}
else if (expression[i] != ' ')
{
x = "";
x = x + expression[i];
splitExpression.push_back(x);
}
else
{
if (digit.size() > 0)
{
splitExpression.push_back(digit);
digit = "";
}
}
}
if (digit.size() > 0)
{
splitExpression.push_back(digit);
}
return splitExpression;
}
vector<string> splitback(string expression)
{
vector<string> splitBackExpression;
string number = "",
x = "";
for (int i = expression.size() - 1; i >= 0; i--)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
number = expression[i] + number;
}
else if (expression[i] != ' ')
{
x = "";
x = x + expression[i];
splitBackExpression.push_back(x);
}
if (number.size() > 0)
{
splitBackExpression.push_back(number);
number = "";
}
}
return splitBackExpression;
}
c++ vector
edited Dec 1 '18 at 10:31
Cœur
18.4k9109148
asked Nov 23 '18 at 23:38
NalaedgeNalaedge
34
I am missing something here......I'm still losing a 1 digit. IF you view the attached picture, you'll see what I am speaking of.
– Nalaedge
Nov 24 '18 at 6:33
Do not add a solution in the question itself: I've rollbacked your edit. Please find your solution in the revision history and post it as an answer of its own.
– Cœur
Dec 1 '18 at 10:33
add a comment |
0
0
0
I'm working on an assignment. I have coded the assignment and everything is working as it should, except my output is missing a digit. I also attached the sample output. After inputting a a mathematical expression into a string, for example 35 * 4 - 6 / (9 + 3), a digit is dropped. In normal order, the 3 will be missing. In reverse order, the 9 will be missing. I am not understanding why this happening.
Any help, or I would prefer some guidance, would be appreciated. Am I using the push_back incorrectly? The code is as follows:
#include<iostream>
#include<string>
#include<vector>
using namespace std;
vector<string> split(string);
vector<string> splitback(string);
int main()
{
vector<string> vectorExpression;
string expression;
cout << "Enter an expression :";
getline(cin, expression);
vectorExpression = split(expression);
for (int i = 0; i < vectorExpression.size(); i++)
{
cout << vectorExpression[i] << endl;
}
cout << endl;
vectorExpression = splitback(expression);
for (int i = 0; i < vectorExpression.size(); i++)
{
cout << vectorExpression[i] << endl;
}
system("pause");
return 0;
}
vector<string> split(string expression)
{
vector<string> splitExpression;
string digit = "",
x = "";
for (int i = 0; i < expression.size(); i++)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = digit + expression[i];
}
else if (expression[i] != ' ')
{
x = "";
x = x + expression[i];
splitExpression.push_back(x);
}
else
{
if (digit.size() > 0)
{
splitExpression.push_back(digit);
digit = "";
}
}
}
if (digit.size() > 0)
{
splitExpression.push_back(digit);
}
return splitExpression;
}
vector<string> splitback(string expression)
{
vector<string> splitBackExpression;
string number = "",
x = "";
for (int i = expression.size() - 1; i >= 0; i--)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
number = expression[i] + number;
}
else if (expression[i] != ' ')
{
x = "";
x = x + expression[i];
splitBackExpression.push_back(x);
}
if (number.size() > 0)
{
splitBackExpression.push_back(number);
number = "";
}
}
return splitBackExpression;
}
c++ vector
edited Dec 1 '18 at 10:31
Cœur
18.4k9109148
asked Nov 23 '18 at 23:38
NalaedgeNalaedge
34
I'm working on an assignment. I have coded the assignment and everything is working as it should, except my output is missing a digit. I also attached the sample output. After inputting a a mathematical expression into a string, for example 35 * 4 - 6 / (9 + 3), a digit is dropped. In normal order, the 3 will be missing. In reverse order, the 9 will be missing. I am not understanding why this happening.
Any help, or I would prefer some guidance, would be appreciated. Am I using the push_back incorrectly? The code is as follows:
#include<iostream>
#include<string>
#include<vector>
using namespace std;
vector<string> split(string);
vector<string> splitback(string);
int main()
{
vector<string> vectorExpression;
string expression;
cout << "Enter an expression :";
getline(cin, expression);
vectorExpression = split(expression);
for (int i = 0; i < vectorExpression.size(); i++)
{
cout << vectorExpression[i] << endl;
}
cout << endl;
vectorExpression = splitback(expression);
for (int i = 0; i < vectorExpression.size(); i++)
{
cout << vectorExpression[i] << endl;
}
system("pause");
return 0;
}
vector<string> split(string expression)
{
vector<string> splitExpression;
string digit = "",
x = "";
for (int i = 0; i < expression.size(); i++)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = digit + expression[i];
}
else if (expression[i] != ' ')
{
x = "";
x = x + expression[i];
splitExpression.push_back(x);
}
else
{
if (digit.size() > 0)
{
splitExpression.push_back(digit);
digit = "";
}
}
}
if (digit.size() > 0)
{
splitExpression.push_back(digit);
}
return splitExpression;
}
vector<string> splitback(string expression)
{
vector<string> splitBackExpression;
string number = "",
x = "";
for (int i = expression.size() - 1; i >= 0; i--)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
number = expression[i] + number;
}
else if (expression[i] != ' ')
{
x = "";
x = x + expression[i];
splitBackExpression.push_back(x);
}
if (number.size() > 0)
{
splitBackExpression.push_back(number);
number = "";
}
}
return splitBackExpression;
}
c++ vector
c++ vector
edited Dec 1 '18 at 10:31
Cœur
18.4k9109148
asked Nov 23 '18 at 23:38
NalaedgeNalaedge
34
edited Dec 1 '18 at 10:31
Cœur
18.4k9109148
asked Nov 23 '18 at 23:38
NalaedgeNalaedge
34
edited Dec 1 '18 at 10:31
Cœur
18.4k9109148
edited Dec 1 '18 at 10:31
Cœur
18.4k9109148
edited Dec 1 '18 at 10:31
Cœur
18.4k9109148
18.4k9109148
asked Nov 23 '18 at 23:38
NalaedgeNalaedge
34
asked Nov 23 '18 at 23:38
NalaedgeNalaedge
34
asked Nov 23 '18 at 23:38
NalaedgeNalaedge
34
34
I am missing something here......I'm still losing a 1 digit. IF you view the attached picture, you'll see what I am speaking of.
– Nalaedge
Nov 24 '18 at 6:33
Do not add a solution in the question itself: I've rollbacked your edit. Please find your solution in the revision history and post it as an answer of its own.
– Cœur
Dec 1 '18 at 10:33
add a comment |
I am missing something here......I'm still losing a 1 digit. IF you view the attached picture, you'll see what I am speaking of.
– Nalaedge
Nov 24 '18 at 6:33
Do not add a solution in the question itself: I've rollbacked your edit. Please find your solution in the revision history and post it as an answer of its own.
– Cœur
Dec 1 '18 at 10:33
I am missing something here......I'm still losing a 1 digit. IF you view the attached picture, you'll see what I am speaking of.
– Nalaedge
Nov 24 '18 at 6:33
I am missing something here......I'm still losing a 1 digit. IF you view the attached picture, you'll see what I am speaking of.
– Nalaedge
Nov 24 '18 at 6:33
Do not add a solution in the question itself: I've rollbacked your edit. Please find your solution in the revision history and post it as an answer of its own.
– Cœur
Dec 1 '18 at 10:33
Do not add a solution in the question itself: I've rollbacked your edit. Please find your solution in the revision history and post it as an answer of its own.
– Cœur
Dec 1 '18 at 10:33
add a comment |
2 Answers
2
active
oldest
votes
0
Your split function is wrong, you forget to add digits, correct one would be
vector<string> split(string expression)
{
vector<string> splitExpression;
string digit = "",
x = "";
for (int i = 0; i < expression.size(); i++)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = digit + expression[i];
}
else
{
// don't forget digit if there was one
if (digit.size() > 0)
{
splitExpression.push_back(digit);
digit = "";
}
// also add what comes next if not a whitespace
if (expression[i] != ' ')
{
x = expression[i];
splitExpression.push_back(x);
}
}
}
if (digit.size() > 0)
{
splitExpression.push_back(digit);
}
return splitExpression;
}
answered Nov 24 '18 at 6:50
SilmathoronSilmathoron
1,0461921
splitExpression.push_back(expression[i]) does not accept the expression[i].
– Nalaedge
Nov 24 '18 at 14:01
Wrap it in to_string or assign it to x as before
– Silmathoron
Nov 24 '18 at 14:07
add a comment |
0
Here is the final answer to my own question, or at least the solution I came up with the help from here.
#include<iostream>
#include<string>
#include<vector>
using namespace std;
vector<string> split(const string&);
vector<string> splitback(const string&);
int main()
{
vector<string> forwardExpression,
reverseExpression;
string expression;
cout << "Enter an expression :";
getline(cin, expression);
//////////////////////////////////////////////////
// FORWARD DISPLAY OF EXPRESSION //
//////////////////////////////////////////////////
forwardExpression = split(expression);
cout << "'" << expression << "'" << " split into individual entities forwards
yields:" << endl;
cout << endl;
for (int i = 0; i < forwardExpression.size(); i++)
{
cout << forwardExpression[i] << endl;
}
cout << endl;
//////////////////////////////////////////////////
// BACKWARD DISPLAY OF EXPRESSION //
//////////////////////////////////////////////////
reverseExpression = splitback(expression);
cout << "'" << expression << "'" << " split into individual entities
backwards yields:" << endl;
cout << endl;
for (int i = 0; i < reverseExpression.size(); i++)
{
cout << reverseExpression[i] << endl;
}
cout << endl;
system("pause");
return 0;
}
//////////////////////////////////////////////////
// FORWARD FUNCTION OF EXPRESSION //
//////////////////////////////////////////////////
vector<string> split(const string &expression)
{
vector<string> splitExpression;
string digit = "",
x = "";
for (int i = 0; i < expression.size(); i++)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = digit + expression[i];
}
else
{
if (digit.size() > 0)
{
splitExpression.push_back(digit);
digit = "";
}
if (expression[i] != ' ')
{
x = expression[i];
splitExpression.push_back(x);
}
}
}
if (digit.size() > 0)
{
splitExpression.push_back(digit);
}
return splitExpression;
}
//////////////////////////////////////////////////
// BACKWARD FUNCTION OF EXPRESSION //
//////////////////////////////////////////////////
vector<string> splitback(const string &expression)
{
vector<string> splitBackExpression;
string digit = "",
x = "";
for (int i = expression.size() - 1; i >= 0; i--)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = expression[i] + digit;
}
else
{
if (digit.size() > 0)
{
splitBackExpression.push_back(digit);
digit = "";
}
if (expression[i] != ' ')
{
x = expression[i];
splitBackExpression.push_back(x);
}
}
}
if (digit.size() > 0)
{
splitBackExpression.push_back(digit);
}
return splitBackExpression;
}
answered Dec 2 '18 at 13:20
NalaedgeNalaedge
34
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Your split function is wrong, you forget to add digits, correct one would be
vector<string> split(string expression)
{
vector<string> splitExpression;
string digit = "",
x = "";
for (int i = 0; i < expression.size(); i++)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = digit + expression[i];
}
else
{
// don't forget digit if there was one
if (digit.size() > 0)
{
splitExpression.push_back(digit);
digit = "";
}
// also add what comes next if not a whitespace
if (expression[i] != ' ')
{
x = expression[i];
splitExpression.push_back(x);
}
}
}
if (digit.size() > 0)
{
splitExpression.push_back(digit);
}
return splitExpression;
}
answered Nov 24 '18 at 6:50
SilmathoronSilmathoron
1,0461921
splitExpression.push_back(expression[i]) does not accept the expression[i].
– Nalaedge
Nov 24 '18 at 14:01
Wrap it in to_string or assign it to x as before
– Silmathoron
Nov 24 '18 at 14:07
add a comment |
0
Your split function is wrong, you forget to add digits, correct one would be
vector<string> split(string expression)
{
vector<string> splitExpression;
string digit = "",
x = "";
for (int i = 0; i < expression.size(); i++)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = digit + expression[i];
}
else
{
// don't forget digit if there was one
if (digit.size() > 0)
{
splitExpression.push_back(digit);
digit = "";
}
// also add what comes next if not a whitespace
if (expression[i] != ' ')
{
x = expression[i];
splitExpression.push_back(x);
}
}
}
if (digit.size() > 0)
{
splitExpression.push_back(digit);
}
return splitExpression;
}
answered Nov 24 '18 at 6:50
SilmathoronSilmathoron
1,0461921
splitExpression.push_back(expression[i]) does not accept the expression[i].
– Nalaedge
Nov 24 '18 at 14:01
Wrap it in to_string or assign it to x as before
– Silmathoron
Nov 24 '18 at 14:07
add a comment |
0
0
0
Your split function is wrong, you forget to add digits, correct one would be
vector<string> split(string expression)
{
vector<string> splitExpression;
string digit = "",
x = "";
for (int i = 0; i < expression.size(); i++)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = digit + expression[i];
}
else
{
// don't forget digit if there was one
if (digit.size() > 0)
{
splitExpression.push_back(digit);
digit = "";
}
// also add what comes next if not a whitespace
if (expression[i] != ' ')
{
x = expression[i];
splitExpression.push_back(x);
}
}
}
if (digit.size() > 0)
{
splitExpression.push_back(digit);
}
return splitExpression;
}
answered Nov 24 '18 at 6:50
SilmathoronSilmathoron
1,0461921
Your split function is wrong, you forget to add digits, correct one would be
vector<string> split(string expression)
{
vector<string> splitExpression;
string digit = "",
x = "";
for (int i = 0; i < expression.size(); i++)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = digit + expression[i];
}
else
{
// don't forget digit if there was one
if (digit.size() > 0)
{
splitExpression.push_back(digit);
digit = "";
}
// also add what comes next if not a whitespace
if (expression[i] != ' ')
{
x = expression[i];
splitExpression.push_back(x);
}
}
}
if (digit.size() > 0)
{
splitExpression.push_back(digit);
}
return splitExpression;
}
answered Nov 24 '18 at 6:50
SilmathoronSilmathoron
1,0461921
edited Nov 24 '18 at 14:11
answered Nov 24 '18 at 6:50
SilmathoronSilmathoron
1,0461921
answered Nov 24 '18 at 6:50
SilmathoronSilmathoron
1,0461921
answered Nov 24 '18 at 6:50
SilmathoronSilmathoron
1,0461921
1,0461921
splitExpression.push_back(expression[i]) does not accept the expression[i].
– Nalaedge
Nov 24 '18 at 14:01
Wrap it in to_string or assign it to x as before
– Silmathoron
Nov 24 '18 at 14:07
add a comment |
splitExpression.push_back(expression[i]) does not accept the expression[i].
– Nalaedge
Nov 24 '18 at 14:01
Wrap it in to_string or assign it to x as before
– Silmathoron
Nov 24 '18 at 14:07
splitExpression.push_back(expression[i]) does not accept the expression[i].
– Nalaedge
Nov 24 '18 at 14:01
splitExpression.push_back(expression[i]) does not accept the expression[i].
– Nalaedge
Nov 24 '18 at 14:01
Wrap it in to_string or assign it to x as before
– Silmathoron
Nov 24 '18 at 14:07
Wrap it in to_string or assign it to x as before
– Silmathoron
Nov 24 '18 at 14:07
add a comment |
0
Here is the final answer to my own question, or at least the solution I came up with the help from here.
#include<iostream>
#include<string>
#include<vector>
using namespace std;
vector<string> split(const string&);
vector<string> splitback(const string&);
int main()
{
vector<string> forwardExpression,
reverseExpression;
string expression;
cout << "Enter an expression :";
getline(cin, expression);
//////////////////////////////////////////////////
// FORWARD DISPLAY OF EXPRESSION //
//////////////////////////////////////////////////
forwardExpression = split(expression);
cout << "'" << expression << "'" << " split into individual entities forwards
yields:" << endl;
cout << endl;
for (int i = 0; i < forwardExpression.size(); i++)
{
cout << forwardExpression[i] << endl;
}
cout << endl;
//////////////////////////////////////////////////
// BACKWARD DISPLAY OF EXPRESSION //
//////////////////////////////////////////////////
reverseExpression = splitback(expression);
cout << "'" << expression << "'" << " split into individual entities
backwards yields:" << endl;
cout << endl;
for (int i = 0; i < reverseExpression.size(); i++)
{
cout << reverseExpression[i] << endl;
}
cout << endl;
system("pause");
return 0;
}
//////////////////////////////////////////////////
// FORWARD FUNCTION OF EXPRESSION //
//////////////////////////////////////////////////
vector<string> split(const string &expression)
{
vector<string> splitExpression;
string digit = "",
x = "";
for (int i = 0; i < expression.size(); i++)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = digit + expression[i];
}
else
{
if (digit.size() > 0)
{
splitExpression.push_back(digit);
digit = "";
}
if (expression[i] != ' ')
{
x = expression[i];
splitExpression.push_back(x);
}
}
}
if (digit.size() > 0)
{
splitExpression.push_back(digit);
}
return splitExpression;
}
//////////////////////////////////////////////////
// BACKWARD FUNCTION OF EXPRESSION //
//////////////////////////////////////////////////
vector<string> splitback(const string &expression)
{
vector<string> splitBackExpression;
string digit = "",
x = "";
for (int i = expression.size() - 1; i >= 0; i--)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = expression[i] + digit;
}
else
{
if (digit.size() > 0)
{
splitBackExpression.push_back(digit);
digit = "";
}
if (expression[i] != ' ')
{
x = expression[i];
splitBackExpression.push_back(x);
}
}
}
if (digit.size() > 0)
{
splitBackExpression.push_back(digit);
}
return splitBackExpression;
}
answered Dec 2 '18 at 13:20
NalaedgeNalaedge
34
add a comment |
0
Here is the final answer to my own question, or at least the solution I came up with the help from here.
#include<iostream>
#include<string>
#include<vector>
using namespace std;
vector<string> split(const string&);
vector<string> splitback(const string&);
int main()
{
vector<string> forwardExpression,
reverseExpression;
string expression;
cout << "Enter an expression :";
getline(cin, expression);
//////////////////////////////////////////////////
// FORWARD DISPLAY OF EXPRESSION //
//////////////////////////////////////////////////
forwardExpression = split(expression);
cout << "'" << expression << "'" << " split into individual entities forwards
yields:" << endl;
cout << endl;
for (int i = 0; i < forwardExpression.size(); i++)
{
cout << forwardExpression[i] << endl;
}
cout << endl;
//////////////////////////////////////////////////
// BACKWARD DISPLAY OF EXPRESSION //
//////////////////////////////////////////////////
reverseExpression = splitback(expression);
cout << "'" << expression << "'" << " split into individual entities
backwards yields:" << endl;
cout << endl;
for (int i = 0; i < reverseExpression.size(); i++)
{
cout << reverseExpression[i] << endl;
}
cout << endl;
system("pause");
return 0;
}
//////////////////////////////////////////////////
// FORWARD FUNCTION OF EXPRESSION //
//////////////////////////////////////////////////
vector<string> split(const string &expression)
{
vector<string> splitExpression;
string digit = "",
x = "";
for (int i = 0; i < expression.size(); i++)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = digit + expression[i];
}
else
{
if (digit.size() > 0)
{
splitExpression.push_back(digit);
digit = "";
}
if (expression[i] != ' ')
{
x = expression[i];
splitExpression.push_back(x);
}
}
}
if (digit.size() > 0)
{
splitExpression.push_back(digit);
}
return splitExpression;
}
//////////////////////////////////////////////////
// BACKWARD FUNCTION OF EXPRESSION //
//////////////////////////////////////////////////
vector<string> splitback(const string &expression)
{
vector<string> splitBackExpression;
string digit = "",
x = "";
for (int i = expression.size() - 1; i >= 0; i--)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = expression[i] + digit;
}
else
{
if (digit.size() > 0)
{
splitBackExpression.push_back(digit);
digit = "";
}
if (expression[i] != ' ')
{
x = expression[i];
splitBackExpression.push_back(x);
}
}
}
if (digit.size() > 0)
{
splitBackExpression.push_back(digit);
}
return splitBackExpression;
}
answered Dec 2 '18 at 13:20
NalaedgeNalaedge
34
add a comment |
0
0
0
Here is the final answer to my own question, or at least the solution I came up with the help from here.
#include<iostream>
#include<string>
#include<vector>
using namespace std;
vector<string> split(const string&);
vector<string> splitback(const string&);
int main()
{
vector<string> forwardExpression,
reverseExpression;
string expression;
cout << "Enter an expression :";
getline(cin, expression);
//////////////////////////////////////////////////
// FORWARD DISPLAY OF EXPRESSION //
//////////////////////////////////////////////////
forwardExpression = split(expression);
cout << "'" << expression << "'" << " split into individual entities forwards
yields:" << endl;
cout << endl;
for (int i = 0; i < forwardExpression.size(); i++)
{
cout << forwardExpression[i] << endl;
}
cout << endl;
//////////////////////////////////////////////////
// BACKWARD DISPLAY OF EXPRESSION //
//////////////////////////////////////////////////
reverseExpression = splitback(expression);
cout << "'" << expression << "'" << " split into individual entities
backwards yields:" << endl;
cout << endl;
for (int i = 0; i < reverseExpression.size(); i++)
{
cout << reverseExpression[i] << endl;
}
cout << endl;
system("pause");
return 0;
}
//////////////////////////////////////////////////
// FORWARD FUNCTION OF EXPRESSION //
//////////////////////////////////////////////////
vector<string> split(const string &expression)
{
vector<string> splitExpression;
string digit = "",
x = "";
for (int i = 0; i < expression.size(); i++)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = digit + expression[i];
}
else
{
if (digit.size() > 0)
{
splitExpression.push_back(digit);
digit = "";
}
if (expression[i] != ' ')
{
x = expression[i];
splitExpression.push_back(x);
}
}
}
if (digit.size() > 0)
{
splitExpression.push_back(digit);
}
return splitExpression;
}
//////////////////////////////////////////////////
// BACKWARD FUNCTION OF EXPRESSION //
//////////////////////////////////////////////////
vector<string> splitback(const string &expression)
{
vector<string> splitBackExpression;
string digit = "",
x = "";
for (int i = expression.size() - 1; i >= 0; i--)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = expression[i] + digit;
}
else
{
if (digit.size() > 0)
{
splitBackExpression.push_back(digit);
digit = "";
}
if (expression[i] != ' ')
{
x = expression[i];
splitBackExpression.push_back(x);
}
}
}
if (digit.size() > 0)
{
splitBackExpression.push_back(digit);
}
return splitBackExpression;
}
answered Dec 2 '18 at 13:20
NalaedgeNalaedge
34
Here is the final answer to my own question, or at least the solution I came up with the help from here.
#include<iostream>
#include<string>
#include<vector>
using namespace std;
vector<string> split(const string&);
vector<string> splitback(const string&);
int main()
{
vector<string> forwardExpression,
reverseExpression;
string expression;
cout << "Enter an expression :";
getline(cin, expression);
//////////////////////////////////////////////////
// FORWARD DISPLAY OF EXPRESSION //
//////////////////////////////////////////////////
forwardExpression = split(expression);
cout << "'" << expression << "'" << " split into individual entities forwards
yields:" << endl;
cout << endl;
for (int i = 0; i < forwardExpression.size(); i++)
{
cout << forwardExpression[i] << endl;
}
cout << endl;
//////////////////////////////////////////////////
// BACKWARD DISPLAY OF EXPRESSION //
//////////////////////////////////////////////////
reverseExpression = splitback(expression);
cout << "'" << expression << "'" << " split into individual entities
backwards yields:" << endl;
cout << endl;
for (int i = 0; i < reverseExpression.size(); i++)
{
cout << reverseExpression[i] << endl;
}
cout << endl;
system("pause");
return 0;
}
//////////////////////////////////////////////////
// FORWARD FUNCTION OF EXPRESSION //
//////////////////////////////////////////////////
vector<string> split(const string &expression)
{
vector<string> splitExpression;
string digit = "",
x = "";
for (int i = 0; i < expression.size(); i++)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = digit + expression[i];
}
else
{
if (digit.size() > 0)
{
splitExpression.push_back(digit);
digit = "";
}
if (expression[i] != ' ')
{
x = expression[i];
splitExpression.push_back(x);
}
}
}
if (digit.size() > 0)
{
splitExpression.push_back(digit);
}
return splitExpression;
}
//////////////////////////////////////////////////
// BACKWARD FUNCTION OF EXPRESSION //
//////////////////////////////////////////////////
vector<string> splitback(const string &expression)
{
vector<string> splitBackExpression;
string digit = "",
x = "";
for (int i = expression.size() - 1; i >= 0; i--)
{
if (expression[i] >= '0' && expression[i] <= '9')
{
digit = expression[i] + digit;
}
else
{
if (digit.size() > 0)
{
splitBackExpression.push_back(digit);
digit = "";
}
if (expression[i] != ' ')
{
x = expression[i];
splitBackExpression.push_back(x);
}
}
}
if (digit.size() > 0)
{
splitBackExpression.push_back(digit);
}
return splitBackExpression;
}
answered Dec 2 '18 at 13:20
NalaedgeNalaedge
34
answered Dec 2 '18 at 13:20
NalaedgeNalaedge
34
answered Dec 2 '18 at 13:20
NalaedgeNalaedge
34
answered Dec 2 '18 at 13:20
NalaedgeNalaedge
34
34
add a comment |
add a comment |
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I am missing something here......I'm still losing a 1 digit. IF you view the attached picture, you'll see what I am speaking of.
– Nalaedge
Nov 24 '18 at 6:33
Do not add a solution in the question itself: I've rollbacked your edit. Please find your solution in the revision history and post it as an answer of its own.
– Cœur
Dec 1 '18 at 10:33