JQuery ajax request to php won't execute?
2
I need to load items from MySQL to a select element. so i wrote an ajax code and a php code. the problem is anywhere of the php code doesn't execute. no errors also. (the url is correct).
please help me.
Here is the jQuery code
$('#loadButton').click(function () {
console.log("clicked"); //this prints
$.ajax({
url: "api/service/RoomTypeService.php",
method: "POST",
async: true,
data: "&operation=getAll",
dataType: "json"
}).done(function (resp) {
alert(resp);
console.log(resp);
for (let i = 0; i < resp.length; i++) {
alert(resp); //this won't run
let roomType = resp[i];
$('#roomTypeCombo').append('<option>' + roomType[1] + '</option>');
}
});
});
and this is complete php code
<?php
require_once __DIR__."/../dto/RoomTypeDTO.php";
require_once __DIR__."/../business/impl/RoomTypeBOimpl.php";
echo "Here in service"; //doesn't execute
$roomTypeBo=new RoomTypeBOimpl();
$method=$_SERVER['REQUEST_METHOD'];
switch ($method){
case "POST":
$operation=$_POST["operation"];
switch ($operation){
case "getAll":
echo json_encode($roomTypeBo->getAllRoomTypes());
break;
}
break;
case "GET":
}
php jquery ajax
asked Nov 24 '18 at 14:09
Tharindu ErangaTharindu Eranga
266
|
show 7 more comments
2
I need to load items from MySQL to a select element. so i wrote an ajax code and a php code. the problem is anywhere of the php code doesn't execute. no errors also. (the url is correct).
please help me.
Here is the jQuery code
$('#loadButton').click(function () {
console.log("clicked"); //this prints
$.ajax({
url: "api/service/RoomTypeService.php",
method: "POST",
async: true,
data: "&operation=getAll",
dataType: "json"
}).done(function (resp) {
alert(resp);
console.log(resp);
for (let i = 0; i < resp.length; i++) {
alert(resp); //this won't run
let roomType = resp[i];
$('#roomTypeCombo').append('<option>' + roomType[1] + '</option>');
}
});
});
and this is complete php code
<?php
require_once __DIR__."/../dto/RoomTypeDTO.php";
require_once __DIR__."/../business/impl/RoomTypeBOimpl.php";
echo "Here in service"; //doesn't execute
$roomTypeBo=new RoomTypeBOimpl();
$method=$_SERVER['REQUEST_METHOD'];
switch ($method){
case "POST":
$operation=$_POST["operation"];
switch ($operation){
case "getAll":
echo json_encode($roomTypeBo->getAllRoomTypes());
break;
}
break;
case "GET":
}
php jquery ajax
asked Nov 24 '18 at 14:09
Tharindu ErangaTharindu Eranga
266
change thisdata: "&operation=getAll",todata: {operation: "getAll"},(which won't solve not reaching "Here in service", though. I know)
– Jeff
Nov 24 '18 at 14:11
When you call the php script directly in browser, do you then see "Here in service"? And what do you see now in network tab as return after executing the ajax?
– Jeff
Nov 24 '18 at 14:13
Why do you think the php part isn't executed? Did you check the network tab of the developer tools?
– Andreas
Nov 24 '18 at 14:31
@Jeff. Thanks. The result prints in network tab. But it doesn't come to done method. So i added a fail method in ajax and now it runs instead of done.
– Tharindu Eranga
Nov 24 '18 at 14:41
Thefailhandler (one of its arguments) will tell you what the problem is
– Andreas
Nov 24 '18 at 14:42
|
show 7 more comments
2
2
2
I need to load items from MySQL to a select element. so i wrote an ajax code and a php code. the problem is anywhere of the php code doesn't execute. no errors also. (the url is correct).
please help me.
Here is the jQuery code
$('#loadButton').click(function () {
console.log("clicked"); //this prints
$.ajax({
url: "api/service/RoomTypeService.php",
method: "POST",
async: true,
data: "&operation=getAll",
dataType: "json"
}).done(function (resp) {
alert(resp);
console.log(resp);
for (let i = 0; i < resp.length; i++) {
alert(resp); //this won't run
let roomType = resp[i];
$('#roomTypeCombo').append('<option>' + roomType[1] + '</option>');
}
});
});
and this is complete php code
<?php
require_once __DIR__."/../dto/RoomTypeDTO.php";
require_once __DIR__."/../business/impl/RoomTypeBOimpl.php";
echo "Here in service"; //doesn't execute
$roomTypeBo=new RoomTypeBOimpl();
$method=$_SERVER['REQUEST_METHOD'];
switch ($method){
case "POST":
$operation=$_POST["operation"];
switch ($operation){
case "getAll":
echo json_encode($roomTypeBo->getAllRoomTypes());
break;
}
break;
case "GET":
}
php jquery ajax
asked Nov 24 '18 at 14:09
Tharindu ErangaTharindu Eranga
266
I need to load items from MySQL to a select element. so i wrote an ajax code and a php code. the problem is anywhere of the php code doesn't execute. no errors also. (the url is correct).
please help me.
Here is the jQuery code
$('#loadButton').click(function () {
console.log("clicked"); //this prints
$.ajax({
url: "api/service/RoomTypeService.php",
method: "POST",
async: true,
data: "&operation=getAll",
dataType: "json"
}).done(function (resp) {
alert(resp);
console.log(resp);
for (let i = 0; i < resp.length; i++) {
alert(resp); //this won't run
let roomType = resp[i];
$('#roomTypeCombo').append('<option>' + roomType[1] + '</option>');
}
});
});
and this is complete php code
<?php
require_once __DIR__."/../dto/RoomTypeDTO.php";
require_once __DIR__."/../business/impl/RoomTypeBOimpl.php";
echo "Here in service"; //doesn't execute
$roomTypeBo=new RoomTypeBOimpl();
$method=$_SERVER['REQUEST_METHOD'];
switch ($method){
case "POST":
$operation=$_POST["operation"];
switch ($operation){
case "getAll":
echo json_encode($roomTypeBo->getAllRoomTypes());
break;
}
break;
case "GET":
}
php jquery ajax
php jquery ajax
asked Nov 24 '18 at 14:09
Tharindu ErangaTharindu Eranga
266
asked Nov 24 '18 at 14:09
Tharindu ErangaTharindu Eranga
266
asked Nov 24 '18 at 14:09
Tharindu ErangaTharindu Eranga
266
asked Nov 24 '18 at 14:09
Tharindu ErangaTharindu Eranga
266
asked Nov 24 '18 at 14:09
Tharindu ErangaTharindu Eranga
266
266
change thisdata: "&operation=getAll",todata: {operation: "getAll"},(which won't solve not reaching "Here in service", though. I know)
– Jeff
Nov 24 '18 at 14:11
When you call the php script directly in browser, do you then see "Here in service"? And what do you see now in network tab as return after executing the ajax?
– Jeff
Nov 24 '18 at 14:13
Why do you think the php part isn't executed? Did you check the network tab of the developer tools?
– Andreas
Nov 24 '18 at 14:31
@Jeff. Thanks. The result prints in network tab. But it doesn't come to done method. So i added a fail method in ajax and now it runs instead of done.
– Tharindu Eranga
Nov 24 '18 at 14:41
Thefailhandler (one of its arguments) will tell you what the problem is
– Andreas
Nov 24 '18 at 14:42
|
show 7 more comments
change thisdata: "&operation=getAll",todata: {operation: "getAll"},(which won't solve not reaching "Here in service", though. I know)
– Jeff
Nov 24 '18 at 14:11
When you call the php script directly in browser, do you then see "Here in service"? And what do you see now in network tab as return after executing the ajax?
– Jeff
Nov 24 '18 at 14:13
Why do you think the php part isn't executed? Did you check the network tab of the developer tools?
– Andreas
Nov 24 '18 at 14:31
@Jeff. Thanks. The result prints in network tab. But it doesn't come to done method. So i added a fail method in ajax and now it runs instead of done.
– Tharindu Eranga
Nov 24 '18 at 14:41
Thefailhandler (one of its arguments) will tell you what the problem is
– Andreas
Nov 24 '18 at 14:42
change this
data: "&operation=getAll", to data: {operation: "getAll"}, (which won't solve not reaching "Here in service", though. I know)– Jeff
Nov 24 '18 at 14:11
change this
data: "&operation=getAll", to data: {operation: "getAll"}, (which won't solve not reaching "Here in service", though. I know)– Jeff
Nov 24 '18 at 14:11
When you call the php script directly in browser, do you then see "Here in service"? And what do you see now in network tab as return after executing the ajax?
– Jeff
Nov 24 '18 at 14:13
When you call the php script directly in browser, do you then see "Here in service"? And what do you see now in network tab as return after executing the ajax?
– Jeff
Nov 24 '18 at 14:13
Why do you think the php part isn't executed? Did you check the network tab of the developer tools?
– Andreas
Nov 24 '18 at 14:31
Why do you think the php part isn't executed? Did you check the network tab of the developer tools?
– Andreas
Nov 24 '18 at 14:31
@Jeff. Thanks. The result prints in network tab. But it doesn't come to done method. So i added a fail method in ajax and now it runs instead of done.
– Tharindu Eranga
Nov 24 '18 at 14:41
@Jeff. Thanks. The result prints in network tab. But it doesn't come to done method. So i added a fail method in ajax and now it runs instead of done.
– Tharindu Eranga
Nov 24 '18 at 14:41
The
fail handler (one of its arguments) will tell you what the problem is– Andreas
Nov 24 '18 at 14:42
The
fail handler (one of its arguments) will tell you what the problem is– Andreas
Nov 24 '18 at 14:42
|
show 7 more comments
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change this
data: "&operation=getAll",todata: {operation: "getAll"},(which won't solve not reaching "Here in service", though. I know)– Jeff
Nov 24 '18 at 14:11
When you call the php script directly in browser, do you then see "Here in service"? And what do you see now in network tab as return after executing the ajax?
– Jeff
Nov 24 '18 at 14:13
Why do you think the php part isn't executed? Did you check the network tab of the developer tools?
– Andreas
Nov 24 '18 at 14:31
@Jeff. Thanks. The result prints in network tab. But it doesn't come to done method. So i added a fail method in ajax and now it runs instead of done.
– Tharindu Eranga
Nov 24 '18 at 14:41
The
failhandler (one of its arguments) will tell you what the problem is– Andreas
Nov 24 '18 at 14:42