replace array elements with elements of a list in NumPy
I have a NumPy array and I converted it into a matrix called string_matrix where each element is a string.
Now I want to convert each element in string_matrix to letters. The number in matrix are the index of the list alp.
So I want this output : string_matrix = [['l' 'i' 'a']['a' 'f' 'b']['u' 'e' 'k']]
alp = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z",""]
matrix = numpy.array([[11, 8, 0],[0, 5, 1],[20, 4, 10]])
string_matrix = numpy.array(["%.f" % v for v in matrix.reshape(matrix.size)])
string_matrix = string_matrix.reshape(matrix.shape)
python numpy matrix
asked Nov 24 '18 at 17:46
WaterploofWaterploof
474
add a comment |
I have a NumPy array and I converted it into a matrix called string_matrix where each element is a string.
Now I want to convert each element in string_matrix to letters. The number in matrix are the index of the list alp.
So I want this output : string_matrix = [['l' 'i' 'a']['a' 'f' 'b']['u' 'e' 'k']]
alp = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z",""]
matrix = numpy.array([[11, 8, 0],[0, 5, 1],[20, 4, 10]])
string_matrix = numpy.array(["%.f" % v for v in matrix.reshape(matrix.size)])
string_matrix = string_matrix.reshape(matrix.shape)
python numpy matrix
asked Nov 24 '18 at 17:46
WaterploofWaterploof
474
add a comment |
I have a NumPy array and I converted it into a matrix called string_matrix where each element is a string.
Now I want to convert each element in string_matrix to letters. The number in matrix are the index of the list alp.
So I want this output : string_matrix = [['l' 'i' 'a']['a' 'f' 'b']['u' 'e' 'k']]
alp = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z",""]
matrix = numpy.array([[11, 8, 0],[0, 5, 1],[20, 4, 10]])
string_matrix = numpy.array(["%.f" % v for v in matrix.reshape(matrix.size)])
string_matrix = string_matrix.reshape(matrix.shape)
python numpy matrix
asked Nov 24 '18 at 17:46
WaterploofWaterploof
474
I have a NumPy array and I converted it into a matrix called string_matrix where each element is a string.
Now I want to convert each element in string_matrix to letters. The number in matrix are the index of the list alp.
So I want this output : string_matrix = [['l' 'i' 'a']['a' 'f' 'b']['u' 'e' 'k']]
alp = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z",""]
matrix = numpy.array([[11, 8, 0],[0, 5, 1],[20, 4, 10]])
string_matrix = numpy.array(["%.f" % v for v in matrix.reshape(matrix.size)])
string_matrix = string_matrix.reshape(matrix.shape)
python numpy matrix
python numpy matrix
asked Nov 24 '18 at 17:46
WaterploofWaterploof
474
asked Nov 24 '18 at 17:46
WaterploofWaterploof
474
asked Nov 24 '18 at 17:46
WaterploofWaterploof
474
asked Nov 24 '18 at 17:46
WaterploofWaterploof
474
asked Nov 24 '18 at 17:46
WaterploofWaterploof
474
474
add a comment |
add a comment |
1 Answer
1
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oldest
votes
You can index into the alp list with your matrix, you need to make alp a numpy array first:
numpy.array(alp)[matrix]
Output:
array([['l', 'i', 'a'],
['a', 'f', 'b'],
['u', 'e', 'k']], dtype='<U1')
This uses numpy's advanced indexing. You can find more details here if you want to read up on it.
answered Nov 24 '18 at 17:51
Jacques KvamJacques Kvam
1,26311121
Is it possible to use a loop instead of this numpy's advanced indexing ?
– Waterploof
Nov 24 '18 at 18:27
Yea you can loop over the elements of the matrix and index into alp with its individual elements, rows, or columns. What do you want to loop over?
– Jacques Kvam
Nov 24 '18 at 18:31
Over its individual elements but I solved this problem, thank you
– Waterploof
Nov 25 '18 at 12:31
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can index into the alp list with your matrix, you need to make alp a numpy array first:
numpy.array(alp)[matrix]
Output:
array([['l', 'i', 'a'],
['a', 'f', 'b'],
['u', 'e', 'k']], dtype='<U1')
This uses numpy's advanced indexing. You can find more details here if you want to read up on it.
answered Nov 24 '18 at 17:51
Jacques KvamJacques Kvam
1,26311121
Is it possible to use a loop instead of this numpy's advanced indexing ?
– Waterploof
Nov 24 '18 at 18:27
Yea you can loop over the elements of the matrix and index into alp with its individual elements, rows, or columns. What do you want to loop over?
– Jacques Kvam
Nov 24 '18 at 18:31
Over its individual elements but I solved this problem, thank you
– Waterploof
Nov 25 '18 at 12:31
add a comment |
You can index into the alp list with your matrix, you need to make alp a numpy array first:
numpy.array(alp)[matrix]
Output:
array([['l', 'i', 'a'],
['a', 'f', 'b'],
['u', 'e', 'k']], dtype='<U1')
This uses numpy's advanced indexing. You can find more details here if you want to read up on it.
answered Nov 24 '18 at 17:51
Jacques KvamJacques Kvam
1,26311121
Is it possible to use a loop instead of this numpy's advanced indexing ?
– Waterploof
Nov 24 '18 at 18:27
Yea you can loop over the elements of the matrix and index into alp with its individual elements, rows, or columns. What do you want to loop over?
– Jacques Kvam
Nov 24 '18 at 18:31
Over its individual elements but I solved this problem, thank you
– Waterploof
Nov 25 '18 at 12:31
add a comment |
You can index into the alp list with your matrix, you need to make alp a numpy array first:
numpy.array(alp)[matrix]
Output:
array([['l', 'i', 'a'],
['a', 'f', 'b'],
['u', 'e', 'k']], dtype='<U1')
This uses numpy's advanced indexing. You can find more details here if you want to read up on it.
answered Nov 24 '18 at 17:51
Jacques KvamJacques Kvam
1,26311121
You can index into the alp list with your matrix, you need to make alp a numpy array first:
numpy.array(alp)[matrix]
Output:
array([['l', 'i', 'a'],
['a', 'f', 'b'],
['u', 'e', 'k']], dtype='<U1')
This uses numpy's advanced indexing. You can find more details here if you want to read up on it.
answered Nov 24 '18 at 17:51
Jacques KvamJacques Kvam
1,26311121
edited Nov 24 '18 at 17:59
answered Nov 24 '18 at 17:51
Jacques KvamJacques Kvam
1,26311121
answered Nov 24 '18 at 17:51
Jacques KvamJacques Kvam
1,26311121
answered Nov 24 '18 at 17:51
Jacques KvamJacques Kvam
1,26311121
1,26311121
Is it possible to use a loop instead of this numpy's advanced indexing ?
– Waterploof
Nov 24 '18 at 18:27
Yea you can loop over the elements of the matrix and index into alp with its individual elements, rows, or columns. What do you want to loop over?
– Jacques Kvam
Nov 24 '18 at 18:31
Over its individual elements but I solved this problem, thank you
– Waterploof
Nov 25 '18 at 12:31
add a comment |
Is it possible to use a loop instead of this numpy's advanced indexing ?
– Waterploof
Nov 24 '18 at 18:27
Yea you can loop over the elements of the matrix and index into alp with its individual elements, rows, or columns. What do you want to loop over?
– Jacques Kvam
Nov 24 '18 at 18:31
Over its individual elements but I solved this problem, thank you
– Waterploof
Nov 25 '18 at 12:31
Is it possible to use a loop instead of this numpy's advanced indexing ?
– Waterploof
Nov 24 '18 at 18:27
Is it possible to use a loop instead of this numpy's advanced indexing ?
– Waterploof
Nov 24 '18 at 18:27
Yea you can loop over the elements of the matrix and index into alp with its individual elements, rows, or columns. What do you want to loop over?
– Jacques Kvam
Nov 24 '18 at 18:31
Yea you can loop over the elements of the matrix and index into alp with its individual elements, rows, or columns. What do you want to loop over?
– Jacques Kvam
Nov 24 '18 at 18:31
Over its individual elements but I solved this problem, thank you
– Waterploof
Nov 25 '18 at 12:31
Over its individual elements but I solved this problem, thank you
– Waterploof
Nov 25 '18 at 12:31
add a comment |
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