How much time does it take for a broken magnet to recover its poles?












1












$begingroup$


I understand that when you cut a magnet you end up with 2 magnets but I wonder how much time does it take to the magnetic domains to rearange and form the new pole. I know the answer may vary depending on the size of the magnet, the material, and some other variable so I'm searching for an answer as general as possible and how the variables may affect the answer.






electromagnetism







share|cite|improve this question









$endgroup$

















    1












    $begingroup$


    I understand that when you cut a magnet you end up with 2 magnets but I wonder how much time does it take to the magnetic domains to rearange and form the new pole. I know the answer may vary depending on the size of the magnet, the material, and some other variable so I'm searching for an answer as general as possible and how the variables may affect the answer.






    electromagnetism







    share|cite|improve this question









    $endgroup$















      1












      1








      1





      $begingroup$


      I understand that when you cut a magnet you end up with 2 magnets but I wonder how much time does it take to the magnetic domains to rearange and form the new pole. I know the answer may vary depending on the size of the magnet, the material, and some other variable so I'm searching for an answer as general as possible and how the variables may affect the answer.






      electromagnetism







      share|cite|improve this question









      $endgroup$




      I understand that when you cut a magnet you end up with 2 magnets but I wonder how much time does it take to the magnetic domains to rearange and form the new pole. I know the answer may vary depending on the size of the magnet, the material, and some other variable so I'm searching for an answer as general as possible and how the variables may affect the answer.






      electromagnetism




      electromagnetism






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked 2 hours ago









      Diego Rodríguez CidDiego Rodríguez Cid

      214




      214






















          2 Answers
          2






          active

          oldest

          votes


















          3












          $begingroup$

          It takes zero time because no domains need to rearrange when a permanent magnet breaks in two. The spins in each half are still aligned and still produce a magnetic field.



          The idea that magnets have “poles” is a misconception. There are no magnetic poles in nature, or at least none that we have found. (And physicists have looked hard for them.) This is the meaning of one of Maxwell’s equations,



          $$nablacdotmathbf{B}=0.$$



          The magnetic field lines of a magnet are loops than run through the interior of the magnet and then loop back around outside. The so-called “poles” are just where the field lines happen to emerge from the interior to the exterior, or return back inside. When you break a magnet, the field lines simply come out and go in in two new places, so that each half has its own loops and its own “poles”.






          share|cite|improve this answer











          $endgroup$













          • $begingroup$
            Or, to use using the nomenclature "poles" for the places dense field emerges from the interior to the exterior, the field was running through the body of the magnet all along, so anywhere you break it both of the new ends will be places where dense field emerges...
            $endgroup$
            – dmckee♦
            1 hour ago



















          0












          $begingroup$

          I believe you seem to be worried about the effect of the physical disturbances on the domain arrangement caused by the cutting process. If my assumption is right, then to return both derivatives to their former glory (being much of half of the strength of the original), I'll recommend keeping them in a relatively stronger magnetic field, making sure they are aligned for a decent amount of time. This will repair the fallout domains that has been supposedly disoriented by the cutting process.






          share|cite|improve this answer









          $endgroup$













            Your Answer





            StackExchange.ifUsing("editor", function () {
            return StackExchange.using("mathjaxEditing", function () {
            StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
            StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
            });
            });
            }, "mathjax-editing");

            StackExchange.ready(function() {
            var channelOptions = {
            tags: "".split(" "),
            id: "151"
            };
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function() {
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled) {
            StackExchange.using("snippets", function() {
            createEditor();
            });
            }
            else {
            createEditor();
            }
            });

            function createEditor() {
            StackExchange.prepareEditor({
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: false,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: null,
            bindNavPrevention: true,
            postfix: "",
            imageUploader: {
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            },
            noCode: true, onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            });


            }
            });














            draft saved

            draft discarded


















            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f464256%2fhow-much-time-does-it-take-for-a-broken-magnet-to-recover-its-poles%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown

























            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            3












            $begingroup$

            It takes zero time because no domains need to rearrange when a permanent magnet breaks in two. The spins in each half are still aligned and still produce a magnetic field.



            The idea that magnets have “poles” is a misconception. There are no magnetic poles in nature, or at least none that we have found. (And physicists have looked hard for them.) This is the meaning of one of Maxwell’s equations,



            $$nablacdotmathbf{B}=0.$$



            The magnetic field lines of a magnet are loops than run through the interior of the magnet and then loop back around outside. The so-called “poles” are just where the field lines happen to emerge from the interior to the exterior, or return back inside. When you break a magnet, the field lines simply come out and go in in two new places, so that each half has its own loops and its own “poles”.






            share|cite|improve this answer











            $endgroup$













            • $begingroup$
              Or, to use using the nomenclature "poles" for the places dense field emerges from the interior to the exterior, the field was running through the body of the magnet all along, so anywhere you break it both of the new ends will be places where dense field emerges...
              $endgroup$
              – dmckee♦
              1 hour ago
















            3












            $begingroup$

            It takes zero time because no domains need to rearrange when a permanent magnet breaks in two. The spins in each half are still aligned and still produce a magnetic field.



            The idea that magnets have “poles” is a misconception. There are no magnetic poles in nature, or at least none that we have found. (And physicists have looked hard for them.) This is the meaning of one of Maxwell’s equations,



            $$nablacdotmathbf{B}=0.$$



            The magnetic field lines of a magnet are loops than run through the interior of the magnet and then loop back around outside. The so-called “poles” are just where the field lines happen to emerge from the interior to the exterior, or return back inside. When you break a magnet, the field lines simply come out and go in in two new places, so that each half has its own loops and its own “poles”.






            share|cite|improve this answer











            $endgroup$













            • $begingroup$
              Or, to use using the nomenclature "poles" for the places dense field emerges from the interior to the exterior, the field was running through the body of the magnet all along, so anywhere you break it both of the new ends will be places where dense field emerges...
              $endgroup$
              – dmckee♦
              1 hour ago














            3












            3








            3





            $begingroup$

            It takes zero time because no domains need to rearrange when a permanent magnet breaks in two. The spins in each half are still aligned and still produce a magnetic field.



            The idea that magnets have “poles” is a misconception. There are no magnetic poles in nature, or at least none that we have found. (And physicists have looked hard for them.) This is the meaning of one of Maxwell’s equations,



            $$nablacdotmathbf{B}=0.$$



            The magnetic field lines of a magnet are loops than run through the interior of the magnet and then loop back around outside. The so-called “poles” are just where the field lines happen to emerge from the interior to the exterior, or return back inside. When you break a magnet, the field lines simply come out and go in in two new places, so that each half has its own loops and its own “poles”.






            share|cite|improve this answer











            $endgroup$



            It takes zero time because no domains need to rearrange when a permanent magnet breaks in two. The spins in each half are still aligned and still produce a magnetic field.



            The idea that magnets have “poles” is a misconception. There are no magnetic poles in nature, or at least none that we have found. (And physicists have looked hard for them.) This is the meaning of one of Maxwell’s equations,



            $$nablacdotmathbf{B}=0.$$



            The magnetic field lines of a magnet are loops than run through the interior of the magnet and then loop back around outside. The so-called “poles” are just where the field lines happen to emerge from the interior to the exterior, or return back inside. When you break a magnet, the field lines simply come out and go in in two new places, so that each half has its own loops and its own “poles”.







            share|cite|improve this answer














            share|cite|improve this answer



            share|cite|improve this answer








            edited 1 hour ago

























            answered 2 hours ago









            G. SmithG. Smith

            8,56611426




            8,56611426












            • $begingroup$
              Or, to use using the nomenclature "poles" for the places dense field emerges from the interior to the exterior, the field was running through the body of the magnet all along, so anywhere you break it both of the new ends will be places where dense field emerges...
              $endgroup$
              – dmckee♦
              1 hour ago


















            • $begingroup$
              Or, to use using the nomenclature "poles" for the places dense field emerges from the interior to the exterior, the field was running through the body of the magnet all along, so anywhere you break it both of the new ends will be places where dense field emerges...
              $endgroup$
              – dmckee♦
              1 hour ago
















            $begingroup$
            Or, to use using the nomenclature "poles" for the places dense field emerges from the interior to the exterior, the field was running through the body of the magnet all along, so anywhere you break it both of the new ends will be places where dense field emerges...
            $endgroup$
            – dmckee♦
            1 hour ago




            $begingroup$
            Or, to use using the nomenclature "poles" for the places dense field emerges from the interior to the exterior, the field was running through the body of the magnet all along, so anywhere you break it both of the new ends will be places where dense field emerges...
            $endgroup$
            – dmckee♦
            1 hour ago











            0












            $begingroup$

            I believe you seem to be worried about the effect of the physical disturbances on the domain arrangement caused by the cutting process. If my assumption is right, then to return both derivatives to their former glory (being much of half of the strength of the original), I'll recommend keeping them in a relatively stronger magnetic field, making sure they are aligned for a decent amount of time. This will repair the fallout domains that has been supposedly disoriented by the cutting process.






            share|cite|improve this answer









            $endgroup$


















              0












              $begingroup$

              I believe you seem to be worried about the effect of the physical disturbances on the domain arrangement caused by the cutting process. If my assumption is right, then to return both derivatives to their former glory (being much of half of the strength of the original), I'll recommend keeping them in a relatively stronger magnetic field, making sure they are aligned for a decent amount of time. This will repair the fallout domains that has been supposedly disoriented by the cutting process.






              share|cite|improve this answer









              $endgroup$
















                0












                0








                0





                $begingroup$

                I believe you seem to be worried about the effect of the physical disturbances on the domain arrangement caused by the cutting process. If my assumption is right, then to return both derivatives to their former glory (being much of half of the strength of the original), I'll recommend keeping them in a relatively stronger magnetic field, making sure they are aligned for a decent amount of time. This will repair the fallout domains that has been supposedly disoriented by the cutting process.






                share|cite|improve this answer









                $endgroup$



                I believe you seem to be worried about the effect of the physical disturbances on the domain arrangement caused by the cutting process. If my assumption is right, then to return both derivatives to their former glory (being much of half of the strength of the original), I'll recommend keeping them in a relatively stronger magnetic field, making sure they are aligned for a decent amount of time. This will repair the fallout domains that has been supposedly disoriented by the cutting process.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered 1 hour ago









                TechDroidTechDroid

                1317




                1317






























                    draft saved

                    draft discarded




















































                    Thanks for contributing an answer to Physics Stack Exchange!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid …



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    Use MathJax to format equations. MathJax reference.


                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function () {
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f464256%2fhow-much-time-does-it-take-for-a-broken-magnet-to-recover-its-poles%23new-answer', 'question_page');
                    }
                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    -

                    Popular posts from this blog

                    Costa Masnaga

                    Image
                    .mw-parser-output .avviso .mbox-text-div>div,.mw-parser-output .avviso .mbox-text-full-div>div{font-size:90%}.mw-parser-output .avviso .mbox-image div{width:52px}.mw-parser-output .avviso .mbox-text-full-div .hide-when-compact{display:block} Questa voce o sezione sull'argomento Lombardia non cita le fonti necessarie o quelle presenti sono insufficienti . Puoi migliorare questa voce aggiungendo citazioni da fonti attendibili secondo le linee guida sull'uso delle fonti. Segui i suggerimenti del progetto di riferimento. Costa Masnaga comune Localizzazione Stato   Italia Regione Lombardia Provincia Lecco Amministrazione Sindaco Sabina Panzeri (Al centro il cittadino) dall'08/06/2009 Territorio Coordinate 45°46′N 9°17′E  /  45.766667°N 9.283333°E 45.766667; 9.283333  ( Costa Masnaga ) Coordinate: 45°46′N 9°17′E  /  45.766667°N 9.283333°E 45.766667; 9.283333  ( Costa Masnaga ) Altitudine 318 m s.l.m...
                    Read more

                    Fotorealismo

                    Image
                    Guerrino Boatto, Venice's St. Barnaba Church and canal Il fotorealismo è un genere di pittura basato sull'uso di una o più fotografie dalle quali l'artista prende le informazioni necessarie da utilizzare poi nel processo della creazione dell'opera, in genere ad olio o ad acrilico, al fine di avere un aspetto finale il più simile possibile alla fotografia. Indice 1 Storia 2 Lista dei fotorealisti 3 Note 4 Voci correlate 5 Altri progetti Storia | Il fotorealismo è un movimento che nasce negli Stati Uniti d'America alla fine degli anni sessanta [1] sulla scia della Pop Art [2] [3] [4] , e insieme condividono il carattere reazionario verso la travolgente ascesa dei media, che alla metà del ventesimo secolo si trasforma in un fenomeno di massa talmente imponente da minacciare il valore dell'immagine nell'arte. [5] [6] Ne consegue così che, colto il gesto d'inizio che fu della Pop Art, i fotorealisti aprono ad un ...
                    Read more

                    Sidney Franklin

                    Image
                    Questa voce sull'argomento registi statunitensi è solo un abbozzo . Contribuisci a migliorarla secondo le convenzioni di Wikipedia. Sidney Franklin, foto di Carl Van Vechten Oscar alla memoria Irving G. Thalberg 1943 Sidney Franklin , all'anagrafe Sidney Arnold Franklin , (San Francisco, 21 marzo 1893 – Santa Monica, 18 maggio 1972), è stato un regista, produttore cinematografico e attore statunitense. Il 20 giugno 1963, si sposò con l'attrice australiana Enid Bennett. Il matrimonio durò fino alla morte dell'attrice, il 14 maggio 1969 [1] Indice 1 Filmografia 1.1 Regista 1.2 Aiuto regia (parziale) 1.3 Produttore 1.4 Attore (parziale) 2 Note 3 Altri progetti 4 Collegamenti esterni Filmografia | Regista | The Baby , co-regia Chester M. Franklin (1915) The Rivals , co-regia Chester M. Franklin (1915) Little Dick's First Case , co-regia Chester M. Franklin (1915) Her Filmland Hero , co-...
                    Read more