interweaving an array's values - js
$begingroup$
I've written a function to sort an array that'd interweave an array's values in the way of if you had two separate arrays [1,2,3,4,5] on one side and [6,7,8,9,0] on the other and it becomes [1, 6, 2, 7, 3, 8, 4, 9, 5, 0].
The code works, but I'm wondering how it can be cleaned up and be more performant without the need for three additional arrays and to see if it can be done on the cards array itself.
let data = [1,2,3,4,5,6,7,8,9,0];
const interweave = data => {
const _data = ;
const l = data.slice(0, data.length / 2);
const r = data.slice(data.length / 2, data.length);
if (l.length === r.length) {
for (let i = 0; i < l.length; i++) {
_data.push(l[i], r[i]);
}
}
return _data;
}
interweave(data);javascript shuffle
asked 1 hour ago
totalnoobtotalnoob
1435
$endgroup$
add a comment |
$begingroup$
I've written a function to sort an array that'd interweave an array's values in the way of if you had two separate arrays [1,2,3,4,5] on one side and [6,7,8,9,0] on the other and it becomes [1, 6, 2, 7, 3, 8, 4, 9, 5, 0].
The code works, but I'm wondering how it can be cleaned up and be more performant without the need for three additional arrays and to see if it can be done on the cards array itself.
let data = [1,2,3,4,5,6,7,8,9,0];
const interweave = data => {
const _data = ;
const l = data.slice(0, data.length / 2);
const r = data.slice(data.length / 2, data.length);
if (l.length === r.length) {
for (let i = 0; i < l.length; i++) {
_data.push(l[i], r[i]);
}
}
return _data;
}
interweave(data);javascript shuffle
asked 1 hour ago
totalnoobtotalnoob
1435
$endgroup$
$begingroup$
I wouldn't call this deck shuffled. It all depends on your definition of shuffling.
$endgroup$
– vnp
22 mins ago
$begingroup$
@vnp, updated the wording
$endgroup$
– totalnoob
14 mins ago
add a comment |
$begingroup$
I've written a function to sort an array that'd interweave an array's values in the way of if you had two separate arrays [1,2,3,4,5] on one side and [6,7,8,9,0] on the other and it becomes [1, 6, 2, 7, 3, 8, 4, 9, 5, 0].
The code works, but I'm wondering how it can be cleaned up and be more performant without the need for three additional arrays and to see if it can be done on the cards array itself.
let data = [1,2,3,4,5,6,7,8,9,0];
const interweave = data => {
const _data = ;
const l = data.slice(0, data.length / 2);
const r = data.slice(data.length / 2, data.length);
if (l.length === r.length) {
for (let i = 0; i < l.length; i++) {
_data.push(l[i], r[i]);
}
}
return _data;
}
interweave(data);javascript shuffle
asked 1 hour ago
totalnoobtotalnoob
1435
$endgroup$
I've written a function to sort an array that'd interweave an array's values in the way of if you had two separate arrays [1,2,3,4,5] on one side and [6,7,8,9,0] on the other and it becomes [1, 6, 2, 7, 3, 8, 4, 9, 5, 0].
The code works, but I'm wondering how it can be cleaned up and be more performant without the need for three additional arrays and to see if it can be done on the cards array itself.
let data = [1,2,3,4,5,6,7,8,9,0];
const interweave = data => {
const _data = ;
const l = data.slice(0, data.length / 2);
const r = data.slice(data.length / 2, data.length);
if (l.length === r.length) {
for (let i = 0; i < l.length; i++) {
_data.push(l[i], r[i]);
}
}
return _data;
}
interweave(data);let data = [1,2,3,4,5,6,7,8,9,0];
const interweave = data => {
const _data = ;
const l = data.slice(0, data.length / 2);
const r = data.slice(data.length / 2, data.length);
if (l.length === r.length) {
for (let i = 0; i < l.length; i++) {
_data.push(l[i], r[i]);
}
}
return _data;
}
interweave(data);let data = [1,2,3,4,5,6,7,8,9,0];
const interweave = data => {
const _data = ;
const l = data.slice(0, data.length / 2);
const r = data.slice(data.length / 2, data.length);
if (l.length === r.length) {
for (let i = 0; i < l.length; i++) {
_data.push(l[i], r[i]);
}
}
return _data;
}
interweave(data);javascript shuffle
javascript shuffle
asked 1 hour ago
totalnoobtotalnoob
1435
asked 1 hour ago
totalnoobtotalnoob
1435
edited 18 mins ago
totalnoob
asked 1 hour ago
totalnoobtotalnoob
1435
asked 1 hour ago
totalnoobtotalnoob
1435
asked 1 hour ago
totalnoobtotalnoob
1435
1435
$begingroup$
I wouldn't call this deck shuffled. It all depends on your definition of shuffling.
$endgroup$
– vnp
22 mins ago
$begingroup$
@vnp, updated the wording
$endgroup$
– totalnoob
14 mins ago
add a comment |
$begingroup$
I wouldn't call this deck shuffled. It all depends on your definition of shuffling.
$endgroup$
– vnp
22 mins ago
$begingroup$
@vnp, updated the wording
$endgroup$
– totalnoob
14 mins ago
$begingroup$
I wouldn't call this deck shuffled. It all depends on your definition of shuffling.
$endgroup$
– vnp
22 mins ago
$begingroup$
I wouldn't call this deck shuffled. It all depends on your definition of shuffling.
$endgroup$
– vnp
22 mins ago
$begingroup$
@vnp, updated the wording
$endgroup$
– totalnoob
14 mins ago
$begingroup$
@vnp, updated the wording
$endgroup$
– totalnoob
14 mins ago
add a comment |
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$begingroup$
I wouldn't call this deck shuffled. It all depends on your definition of shuffling.
$endgroup$
– vnp
22 mins ago
$begingroup$
@vnp, updated the wording
$endgroup$
– totalnoob
14 mins ago