Randomize strings in a list
Dim myRandom As New Random
Dim myList As New List(Of String)(New String() {"A", "B", "C"})
myList.OrderBy(Function(i) myRandom.Next).ToList()
For k As Integer = 0 To 2
MessageBox.Show(myList.Item(k))
Next
When you run the code, you will see that the MessageBoxes show A,B,C.
I want MessageBoxes show B,C,A or C,B,A or A,C,B or A,B,C or B,A,C or C,A,B according to randomized result.
Note: Using Linq is a must.
vb.net winforms linq random
add a comment |
Dim myRandom As New Random
Dim myList As New List(Of String)(New String() {"A", "B", "C"})
myList.OrderBy(Function(i) myRandom.Next).ToList()
For k As Integer = 0 To 2
MessageBox.Show(myList.Item(k))
Next
When you run the code, you will see that the MessageBoxes show A,B,C.
I want MessageBoxes show B,C,A or C,B,A or A,C,B or A,B,C or B,A,C or C,A,B according to randomized result.
Note: Using Linq is a must.
vb.net winforms linq random
1
https://stackoverflow.com/questions/108819/best-way-to-randomize-an-array-with-net
– mahlatse
Nov 22 '18 at 9:40
add a comment |
Dim myRandom As New Random
Dim myList As New List(Of String)(New String() {"A", "B", "C"})
myList.OrderBy(Function(i) myRandom.Next).ToList()
For k As Integer = 0 To 2
MessageBox.Show(myList.Item(k))
Next
When you run the code, you will see that the MessageBoxes show A,B,C.
I want MessageBoxes show B,C,A or C,B,A or A,C,B or A,B,C or B,A,C or C,A,B according to randomized result.
Note: Using Linq is a must.
vb.net winforms linq random
Dim myRandom As New Random
Dim myList As New List(Of String)(New String() {"A", "B", "C"})
myList.OrderBy(Function(i) myRandom.Next).ToList()
For k As Integer = 0 To 2
MessageBox.Show(myList.Item(k))
Next
When you run the code, you will see that the MessageBoxes show A,B,C.
I want MessageBoxes show B,C,A or C,B,A or A,C,B or A,B,C or B,A,C or C,A,B according to randomized result.
Note: Using Linq is a must.
vb.net winforms linq random
vb.net winforms linq random
edited Nov 22 '18 at 16:27
Danny Scofield
asked Nov 22 '18 at 9:24
Danny ScofieldDanny Scofield
113
113
1
https://stackoverflow.com/questions/108819/best-way-to-randomize-an-array-with-net
– mahlatse
Nov 22 '18 at 9:40
add a comment |
1
https://stackoverflow.com/questions/108819/best-way-to-randomize-an-array-with-net
– mahlatse
Nov 22 '18 at 9:40
1
1
https://stackoverflow.com/questions/108819/best-way-to-randomize-an-array-with-net
– mahlatse
Nov 22 '18 at 9:40
https://stackoverflow.com/questions/108819/best-way-to-randomize-an-array-with-net
– mahlatse
Nov 22 '18 at 9:40
add a comment |
1 Answer
1
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oldest
votes
The issue is that your code doesn't make any changes to myList. A LINQ query ALWAYS generates a new list. You need to assign the result of ToList back to your myList variable, i.e.
myList = myList.OrderBy(Function(i) myRandom.Next).ToList()
add a comment |
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1 Answer
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1 Answer
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active
oldest
votes
active
oldest
votes
active
oldest
votes
The issue is that your code doesn't make any changes to myList. A LINQ query ALWAYS generates a new list. You need to assign the result of ToList back to your myList variable, i.e.
myList = myList.OrderBy(Function(i) myRandom.Next).ToList()
add a comment |
The issue is that your code doesn't make any changes to myList. A LINQ query ALWAYS generates a new list. You need to assign the result of ToList back to your myList variable, i.e.
myList = myList.OrderBy(Function(i) myRandom.Next).ToList()
add a comment |
The issue is that your code doesn't make any changes to myList. A LINQ query ALWAYS generates a new list. You need to assign the result of ToList back to your myList variable, i.e.
myList = myList.OrderBy(Function(i) myRandom.Next).ToList()
The issue is that your code doesn't make any changes to myList. A LINQ query ALWAYS generates a new list. You need to assign the result of ToList back to your myList variable, i.e.
myList = myList.OrderBy(Function(i) myRandom.Next).ToList()
answered Nov 22 '18 at 11:23
jmcilhinneyjmcilhinney
25.6k22032
25.6k22032
add a comment |
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1
https://stackoverflow.com/questions/108819/best-way-to-randomize-an-array-with-net
– mahlatse
Nov 22 '18 at 9:40