Django ajax search responds with 404 status
0
I'm trying to make a simple search using ajax in my django application.
I have the following model:
class Ingredient(models.Model):
name = models.CharField(max_length=200)
And here's my javascript:
function search_success(data){
$('#search_results').hmtl(data);
}
$(document).ready(function () {
$("#id_ingredient").on('change', function () {
update_unities();
});
$('#search_ing').on('keyup', function(){
$.ajax({
url: '/ajax/search/',
data: {
'search_text': $('#search_ing').val(),
},
dataType: 'html',
success: search_success,
});
});
});
In my urls.py, I added the following:
path('ajax/search', views.search_ingredients, name='search_ingredients')
And in my view, I defined the following function:
def search_ingredients(request):
if request.method == "POST":
search_text = request.POST['search_text']
else:
search_text = ''
ingredients = Ingredient.objects.filter(title__contains=search_text)
return render('recipe/search_ingredient.html', {'ingredients' : ingredients})
I'm getting a 404 error on my request, can someone help me out?
EDIT: Here's my folder structure.
.
├── admin.py
├── apps.py
├── forms.py
├── migrations
│ ├── omitted
├── models.py
├── static
│ └── css
│ └── recipe.css
├── templates
│ └── recipe
│ ├── base.html
│ ├── recipe_add_ingredient.html
│ ├── recipe_detail.html
│ ├── recipe_edit.html
│ ├── recipe_list.html
│ └── search_ingredient.html
├── tests.py
├── urls.py
└── views.py
jquery ajax django
asked Nov 22 '18 at 23:16
LucLuc
338
|
show 4 more comments
0
I'm trying to make a simple search using ajax in my django application.
I have the following model:
class Ingredient(models.Model):
name = models.CharField(max_length=200)
And here's my javascript:
function search_success(data){
$('#search_results').hmtl(data);
}
$(document).ready(function () {
$("#id_ingredient").on('change', function () {
update_unities();
});
$('#search_ing').on('keyup', function(){
$.ajax({
url: '/ajax/search/',
data: {
'search_text': $('#search_ing').val(),
},
dataType: 'html',
success: search_success,
});
});
});
In my urls.py, I added the following:
path('ajax/search', views.search_ingredients, name='search_ingredients')
And in my view, I defined the following function:
def search_ingredients(request):
if request.method == "POST":
search_text = request.POST['search_text']
else:
search_text = ''
ingredients = Ingredient.objects.filter(title__contains=search_text)
return render('recipe/search_ingredient.html', {'ingredients' : ingredients})
I'm getting a 404 error on my request, can someone help me out?
EDIT: Here's my folder structure.
.
├── admin.py
├── apps.py
├── forms.py
├── migrations
│ ├── omitted
├── models.py
├── static
│ └── css
│ └── recipe.css
├── templates
│ └── recipe
│ ├── base.html
│ ├── recipe_add_ingredient.html
│ ├── recipe_detail.html
│ ├── recipe_edit.html
│ ├── recipe_list.html
│ └── search_ingredient.html
├── tests.py
├── urls.py
└── views.py
jquery ajax django
asked Nov 22 '18 at 23:16
LucLuc
338
You omitted the trailing slash in yourpathline.
– Selcuk
Nov 22 '18 at 23:21
@Selcuk you mean just doing path('ajax/search/', ...) ? Do you have any other idea? I added it and still getting the same error, I will edit my question with the folder structure.
– Luc
Nov 22 '18 at 23:25
1
Yes, that was my suggestion. I suggest you to enable DEBUG and visit the URL (http://localhost/ajax/search/) manually to see what is wrong.
– Selcuk
Nov 22 '18 at 23:28
Your terminal should show you the exact URL you are requesting. Very likely, you are just a folder up/down from where you should be.
– WayBehind
Nov 22 '18 at 23:29
@WayBehind Yea, I noticed I had two things wrong (updated on question) and when I access the url that's being requested I get a TemplateDoesNotExist and it points to this line in my views: return render('recipe/search_ingredients.html', {'ingredients' : ingredients}). You have any idea or anything that could help?
– Luc
Nov 22 '18 at 23:40
|
show 4 more comments
0
0
0
I'm trying to make a simple search using ajax in my django application.
I have the following model:
class Ingredient(models.Model):
name = models.CharField(max_length=200)
And here's my javascript:
function search_success(data){
$('#search_results').hmtl(data);
}
$(document).ready(function () {
$("#id_ingredient").on('change', function () {
update_unities();
});
$('#search_ing').on('keyup', function(){
$.ajax({
url: '/ajax/search/',
data: {
'search_text': $('#search_ing').val(),
},
dataType: 'html',
success: search_success,
});
});
});
In my urls.py, I added the following:
path('ajax/search', views.search_ingredients, name='search_ingredients')
And in my view, I defined the following function:
def search_ingredients(request):
if request.method == "POST":
search_text = request.POST['search_text']
else:
search_text = ''
ingredients = Ingredient.objects.filter(title__contains=search_text)
return render('recipe/search_ingredient.html', {'ingredients' : ingredients})
I'm getting a 404 error on my request, can someone help me out?
EDIT: Here's my folder structure.
.
├── admin.py
├── apps.py
├── forms.py
├── migrations
│ ├── omitted
├── models.py
├── static
│ └── css
│ └── recipe.css
├── templates
│ └── recipe
│ ├── base.html
│ ├── recipe_add_ingredient.html
│ ├── recipe_detail.html
│ ├── recipe_edit.html
│ ├── recipe_list.html
│ └── search_ingredient.html
├── tests.py
├── urls.py
└── views.py
jquery ajax django
asked Nov 22 '18 at 23:16
LucLuc
338
I'm trying to make a simple search using ajax in my django application.
I have the following model:
class Ingredient(models.Model):
name = models.CharField(max_length=200)
And here's my javascript:
function search_success(data){
$('#search_results').hmtl(data);
}
$(document).ready(function () {
$("#id_ingredient").on('change', function () {
update_unities();
});
$('#search_ing').on('keyup', function(){
$.ajax({
url: '/ajax/search/',
data: {
'search_text': $('#search_ing').val(),
},
dataType: 'html',
success: search_success,
});
});
});
In my urls.py, I added the following:
path('ajax/search', views.search_ingredients, name='search_ingredients')
And in my view, I defined the following function:
def search_ingredients(request):
if request.method == "POST":
search_text = request.POST['search_text']
else:
search_text = ''
ingredients = Ingredient.objects.filter(title__contains=search_text)
return render('recipe/search_ingredient.html', {'ingredients' : ingredients})
I'm getting a 404 error on my request, can someone help me out?
EDIT: Here's my folder structure.
.
├── admin.py
├── apps.py
├── forms.py
├── migrations
│ ├── omitted
├── models.py
├── static
│ └── css
│ └── recipe.css
├── templates
│ └── recipe
│ ├── base.html
│ ├── recipe_add_ingredient.html
│ ├── recipe_detail.html
│ ├── recipe_edit.html
│ ├── recipe_list.html
│ └── search_ingredient.html
├── tests.py
├── urls.py
└── views.py
jquery ajax django
jquery ajax django
asked Nov 22 '18 at 23:16
LucLuc
338
asked Nov 22 '18 at 23:16
LucLuc
338
edited Nov 22 '18 at 23:41
Luc
asked Nov 22 '18 at 23:16
LucLuc
338
asked Nov 22 '18 at 23:16
LucLuc
338
asked Nov 22 '18 at 23:16
LucLuc
338
338
You omitted the trailing slash in yourpathline.
– Selcuk
Nov 22 '18 at 23:21
@Selcuk you mean just doing path('ajax/search/', ...) ? Do you have any other idea? I added it and still getting the same error, I will edit my question with the folder structure.
– Luc
Nov 22 '18 at 23:25
1
Yes, that was my suggestion. I suggest you to enable DEBUG and visit the URL (http://localhost/ajax/search/) manually to see what is wrong.
– Selcuk
Nov 22 '18 at 23:28
Your terminal should show you the exact URL you are requesting. Very likely, you are just a folder up/down from where you should be.
– WayBehind
Nov 22 '18 at 23:29
@WayBehind Yea, I noticed I had two things wrong (updated on question) and when I access the url that's being requested I get a TemplateDoesNotExist and it points to this line in my views: return render('recipe/search_ingredients.html', {'ingredients' : ingredients}). You have any idea or anything that could help?
– Luc
Nov 22 '18 at 23:40
|
show 4 more comments
You omitted the trailing slash in yourpathline.
– Selcuk
Nov 22 '18 at 23:21
@Selcuk you mean just doing path('ajax/search/', ...) ? Do you have any other idea? I added it and still getting the same error, I will edit my question with the folder structure.
– Luc
Nov 22 '18 at 23:25
1
Yes, that was my suggestion. I suggest you to enable DEBUG and visit the URL (http://localhost/ajax/search/) manually to see what is wrong.
– Selcuk
Nov 22 '18 at 23:28
Your terminal should show you the exact URL you are requesting. Very likely, you are just a folder up/down from where you should be.
– WayBehind
Nov 22 '18 at 23:29
@WayBehind Yea, I noticed I had two things wrong (updated on question) and when I access the url that's being requested I get a TemplateDoesNotExist and it points to this line in my views: return render('recipe/search_ingredients.html', {'ingredients' : ingredients}). You have any idea or anything that could help?
– Luc
Nov 22 '18 at 23:40
You omitted the trailing slash in your
path line.– Selcuk
Nov 22 '18 at 23:21
You omitted the trailing slash in your
path line.– Selcuk
Nov 22 '18 at 23:21
@Selcuk you mean just doing path('ajax/search/', ...) ? Do you have any other idea? I added it and still getting the same error, I will edit my question with the folder structure.
– Luc
Nov 22 '18 at 23:25
@Selcuk you mean just doing path('ajax/search/', ...) ? Do you have any other idea? I added it and still getting the same error, I will edit my question with the folder structure.
– Luc
Nov 22 '18 at 23:25
1
1
Yes, that was my suggestion. I suggest you to enable DEBUG and visit the URL (
http://localhost/ajax/search/) manually to see what is wrong.– Selcuk
Nov 22 '18 at 23:28
Yes, that was my suggestion. I suggest you to enable DEBUG and visit the URL (
http://localhost/ajax/search/) manually to see what is wrong.– Selcuk
Nov 22 '18 at 23:28
Your terminal should show you the exact URL you are requesting. Very likely, you are just a folder up/down from where you should be.
– WayBehind
Nov 22 '18 at 23:29
Your terminal should show you the exact URL you are requesting. Very likely, you are just a folder up/down from where you should be.
– WayBehind
Nov 22 '18 at 23:29
@WayBehind Yea, I noticed I had two things wrong (updated on question) and when I access the url that's being requested I get a TemplateDoesNotExist and it points to this line in my views: return render('recipe/search_ingredients.html', {'ingredients' : ingredients}). You have any idea or anything that could help?
– Luc
Nov 22 '18 at 23:40
@WayBehind Yea, I noticed I had two things wrong (updated on question) and when I access the url that's being requested I get a TemplateDoesNotExist and it points to this line in my views: return render('recipe/search_ingredients.html', {'ingredients' : ingredients}). You have any idea or anything that could help?
– Luc
Nov 22 '18 at 23:40
|
show 4 more comments
1 Answer
1
active
oldest
votes
0
fist of all:
change this:
path('ajax/search', views.search_ingredients, name='search_ingredients')
by this:
path('ajax/search/', views.search_ingredients, name='search_ingredients')
check the trailing slash at the end of the expression:
in the return statement of your view function, it should start with the request:
return render(request, 'recipe/search_ingredient.html', {'ingredients' : ingredients})
I hope it can help you
answered Nov 23 '18 at 6:03
ensarmanensarman
406
Thanks for the answer @ensarman but unfortunately it didn't solve it. I'm still getting the same 404 error. Any other idea? I can share my github where I have the whole code if you wanna take a look.
– Luc
Nov 23 '18 at 10:28
ok let me see...
– ensarman
Nov 23 '18 at 16:43
add a comment |
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0
fist of all:
change this:
path('ajax/search', views.search_ingredients, name='search_ingredients')
by this:
path('ajax/search/', views.search_ingredients, name='search_ingredients')
check the trailing slash at the end of the expression:
in the return statement of your view function, it should start with the request:
return render(request, 'recipe/search_ingredient.html', {'ingredients' : ingredients})
I hope it can help you
answered Nov 23 '18 at 6:03
ensarmanensarman
406
Thanks for the answer @ensarman but unfortunately it didn't solve it. I'm still getting the same 404 error. Any other idea? I can share my github where I have the whole code if you wanna take a look.
– Luc
Nov 23 '18 at 10:28
ok let me see...
– ensarman
Nov 23 '18 at 16:43
add a comment |
0
fist of all:
change this:
path('ajax/search', views.search_ingredients, name='search_ingredients')
by this:
path('ajax/search/', views.search_ingredients, name='search_ingredients')
check the trailing slash at the end of the expression:
in the return statement of your view function, it should start with the request:
return render(request, 'recipe/search_ingredient.html', {'ingredients' : ingredients})
I hope it can help you
answered Nov 23 '18 at 6:03
ensarmanensarman
406
Thanks for the answer @ensarman but unfortunately it didn't solve it. I'm still getting the same 404 error. Any other idea? I can share my github where I have the whole code if you wanna take a look.
– Luc
Nov 23 '18 at 10:28
ok let me see...
– ensarman
Nov 23 '18 at 16:43
add a comment |
0
0
0
fist of all:
change this:
path('ajax/search', views.search_ingredients, name='search_ingredients')
by this:
path('ajax/search/', views.search_ingredients, name='search_ingredients')
check the trailing slash at the end of the expression:
in the return statement of your view function, it should start with the request:
return render(request, 'recipe/search_ingredient.html', {'ingredients' : ingredients})
I hope it can help you
answered Nov 23 '18 at 6:03
ensarmanensarman
406
fist of all:
change this:
path('ajax/search', views.search_ingredients, name='search_ingredients')
by this:
path('ajax/search/', views.search_ingredients, name='search_ingredients')
check the trailing slash at the end of the expression:
in the return statement of your view function, it should start with the request:
return render(request, 'recipe/search_ingredient.html', {'ingredients' : ingredients})
I hope it can help you
answered Nov 23 '18 at 6:03
ensarmanensarman
406
answered Nov 23 '18 at 6:03
ensarmanensarman
406
answered Nov 23 '18 at 6:03
ensarmanensarman
406
answered Nov 23 '18 at 6:03
ensarmanensarman
406
406
Thanks for the answer @ensarman but unfortunately it didn't solve it. I'm still getting the same 404 error. Any other idea? I can share my github where I have the whole code if you wanna take a look.
– Luc
Nov 23 '18 at 10:28
ok let me see...
– ensarman
Nov 23 '18 at 16:43
add a comment |
Thanks for the answer @ensarman but unfortunately it didn't solve it. I'm still getting the same 404 error. Any other idea? I can share my github where I have the whole code if you wanna take a look.
– Luc
Nov 23 '18 at 10:28
ok let me see...
– ensarman
Nov 23 '18 at 16:43
Thanks for the answer @ensarman but unfortunately it didn't solve it. I'm still getting the same 404 error. Any other idea? I can share my github where I have the whole code if you wanna take a look.
– Luc
Nov 23 '18 at 10:28
Thanks for the answer @ensarman but unfortunately it didn't solve it. I'm still getting the same 404 error. Any other idea? I can share my github where I have the whole code if you wanna take a look.
– Luc
Nov 23 '18 at 10:28
ok let me see...
– ensarman
Nov 23 '18 at 16:43
ok let me see...
– ensarman
Nov 23 '18 at 16:43
add a comment |
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You omitted the trailing slash in your
pathline.– Selcuk
Nov 22 '18 at 23:21
@Selcuk you mean just doing path('ajax/search/', ...) ? Do you have any other idea? I added it and still getting the same error, I will edit my question with the folder structure.
– Luc
Nov 22 '18 at 23:25
1
Yes, that was my suggestion. I suggest you to enable DEBUG and visit the URL (
http://localhost/ajax/search/) manually to see what is wrong.– Selcuk
Nov 22 '18 at 23:28
Your terminal should show you the exact URL you are requesting. Very likely, you are just a folder up/down from where you should be.
– WayBehind
Nov 22 '18 at 23:29
@WayBehind Yea, I noticed I had two things wrong (updated on question) and when I access the url that's being requested I get a TemplateDoesNotExist and it points to this line in my views: return render('recipe/search_ingredients.html', {'ingredients' : ingredients}). You have any idea or anything that could help?
– Luc
Nov 22 '18 at 23:40